Hi there!
(A)
For a banked curve, we know that:
∑F = MgsinФ (force due to gravity)
And:
∑F = mv²/r
The cosine of the centripetal force, mv²/r, is involved in the summation of forces, so:
(mv²/r)cosФ = mgsinФ
Simplify the equation:
(v²/r)cosФ = gsinФ
Divide both sides by cosФ:
(v²/r) = gtanФ
Solve for v:
v = √grtanФ
Plug in given values. g ≈ 9.8 m/s²
v = √(9.8 · 120 · tan(15)) = 17.75 m/s
(b)
Incorporating friction, we now can rewrite the sum of forces. Let's first determine the frictional force acting on the car.
As the horizontal component of the centripetal force is the net force, the vertical component works in the direction of the normal force, so we must include it in the calculation of the frictional force.
First, convert 15 km/h to m/s:
15km / h * 1000 m / 1km * 1 h / 3600 sec = 4.167 m/s
Thus:
∑F = mgsinФ - μ(mgcosФ + (mv²/r)sinФ)
mv²/r = mgsinФ - μ(mgcosФ + (mv²/r)sinФ)
Divide all terms by the mass:
v²/r = gsinФ - μ(gcosФ + (v²/r)sinФ)
Solve for μ:
v²/r - gsinФ = - μ(gcosФ + (v²/r)sinФ)
-(v²/r - gsinФ)/(gcosФ + (v²/r)sinФ) = μ
Plug in the given values:
μ = 0.25
is this kinetic energy ---> elastic potential energy OR elastic potential energy ---> kinetic energy ??
Answer:
it is potential energy ---- kinetic energy
a uniform rod 8m long weighing 5kg is supported horizontally by two vertical parallel strings at p and q and at distance 2m and 6m from one end.
Weight of 1kg, 1.5kg and 2kg are attached at distance of 1m 5m and 7m respectively from the same end.
find the tension in each vertical string
Answer:
Fp = 36 N
Fq = 58 N
Explanation:
Let the left end be the reference end with string p closest to it.
Let CCW moments be positive
Sum moments about p to zero
1(9.8)[2 - 1] + Fq[6 - 2] - 5(9.8)[8/2 - 2] - 1.5(9.8)[5 - 2] - 2(9.8)[7 - 2] = 0
Fq[4] = 23.5(9.8)
Fq = 57.575 ≈ 58 N
Sum moments about q to zero
1(9.8)[6 - 1] - Fp[6 - 2] + 5(9.8)[6 - 8/2] + 1.5(9.8)[6 - 5] - 2(9.8)[7 - 6] = 0
Fp = 35.525 N
or
Sum vertical forces to zero
Fp + 57.575 - (9.8)(1 + 1.5 + 2 + 5) = 0
Fp = 35.525 ≈ 36 N
I NEED HELP PLZZZZZZ
A 0.038-kg bullet enters a 3.2-kg watermelon and embeds itself in the melon. The melon is immediately set into motion with a speed of 3.82 m/s. The bullet remains lodged inside the melon. What was the entry speed of the bullet (m/s)?
Hi there!
This is an example of a perfectly inelastic collection, so:
mb = mass of bullet
vb = velocity of bullet
mw = mass of watermelon
v = velocity final
mbvb = (mb + mw)v
Rearrange to solve for the velocity of the bullet:
vb = (mb + mw)v/mb
Plug in values:
vb = (0.038 + 3.2)(3.82)/(0.038) = 325.504 m/s
A simple pendulum oscillates 40 times in 20 second. What is the time period of the pendulum?
The weight of an astronaut plus his space suit on the Moon is only 260 N.
how much is the weight on earth assuming the gravity on the moon is 1.67?
Answer:
2.68
Explanation:
sana maka tulong heheIf a ball is kicked horizontally off of a building at 8.0 m/s, what is the horizontal velocity (vx) after 3
seconds?
The characteristics of the projectile launch allows to find the result for the velocity on the x axis is:
In the horizontal axis there is no acceleration and therefore the speed must be kept constant. The horizontal speed is vₓ = 8.0 m / s
In projectile launching we have an application of kinematics to motion in two dimensions near the surface of the Earth.
In this case, on the vertical axis we have an acceleration directed towards the center of the planet and called the gravity acceleration.
In the horizontal axis or x axis there is not acceleration, except in special cases that we tone is how much the resistance of the air.
Consequently in the horizontal axis there is no acceleration and therefore the speed must be kept constant, the result for the horizontal speed is:
vₓ = 8.0 m / s
Learn more here: brainly.com/question/17228361
Waves can travel but the medium does not "travel" with it, even though they may move up and down.
False
True
Answer:
TRUE
Explanation:
The statement "Waves can travel but the medium does not "travel" with it, even though they may move up and down." is a true statement
Option A is correct
What are Waves?A wave is simply defined as a disturbance in a medium that carries energy from point to point and can take the form of elastic deformation, a change in pressure, magnetic strength, electric potential, or temperature.
In conclusion, Mediums are the pathways or channel for travelling waves
Read more about Wave
https://brainly.com/question/3004869
PLEASE HELP
A student uses a ping pong ball launcher to shoot a projectile across a classroom. the launcher sits at the edge of a table and releases the ping pong ball 1.2 meters above the floor. as the ball leaves the launcher it has a speed of 13 m/s. if 5m/s is in the upwards direction and 12m/s is in the forward direction how far from the base of the table does the ping pong ball land
Answer:
Explanation:
It is hard to imaging that wind resistance is not a factor for such a low mass ball, but we must make that assumption on the first estimate.
s = s₀ + v₀t + ½at²
vertical analysis with floor level as origin
0 = 1.2 + 5t + ½(-9.8)t²
0 = 1.2 + 5t - 4.9t²
quadratic formula positive answer
t = (-5 - √(5² - 4(-4.9)(1.2))) / (2(-4.9))
t = 1.22 s is the flight time
horizontal analysis with launcher as origin
s = 0 + 12(1.22) + ½(0)1.22²
s = 14.6517... 15 m
If a car accelerates from rest at a constant of rate of 5.5m/s^2 north, how long will it take for the car to reach a velocity of 28 m/s north?
Answer:
Explanation:
vo= 0
a=5.5m/s^2
v= 28 m/s
t=?
v=vo+at
at=v-vo
t=(v-vo)/a
t=28/5.5
t=5.09 seconds
The gravitational field strength on earth is 10n/kg. find the weight of an object of mass 25kg
Answer:
250N
Explanation:
weight = Mass(in kg) × Gravitational field strength
25 × 10 = 250N
Answer:
250 N
Explanation:
Refer the attachment for explanation.
Reflect on your new experiences, what made you uncomfortable and what encouraged you. Did you learn anything new about yourself on the trip? Traveling can help you improve. Think about your journey and if it helped you grow in any way.
Answer:
keke
Explanation:
Which of the following types of energy would cause one piece
of metal to be attracted to another?
a heat
b nuclear
c light
d magnetic
CEK- 9. If the speed of sound at 0° C is vo, the velocity at 273° C will be (a) 2 vo (b) 0.5 vo b (c) (d) 0.7 vo 1.4 vo
Answer:
D
Explanation:
273 * 0.6=163.8
vo≈331
the electric field at point 4.00 cm from the axis, measured radially outward from the midpoint of the shell.
A 10 g dime and a 200 g gold coin are dropped from the Empire State Building in
New York at the same time.; if there is no air resistance which hits the ground first?
A.They both hit the ground at the same time
B.Which hits first depends on the weather & temperature of the air.
C.The 200 g gold coin hits the ground first
D.The 10 g dime hits the ground first
Answer:
Explanation:
The both hit the ground at the same time. There is no air resistance and that includes the factors brought up in B.
C and D are both eliminated. If you dropped an 800 kg honda Fit it would hit the ground at the same time as the two coins. When you look at the formulas used to derive time, they look like
d = vi * t + 1/2 a* t^2
vi = 0
the distance to fell is the same for all three masses.
a is the same for all 3 masses.
So when you solve for t, there is no mention of the mass of the object falling. Therefore t is dependent only on the height.
Can air make shadows?
Answer:
Yes, air can indeed make shadows. A shadow occurs when an object in a light beam prevents some of the light from continuing on in the forward direction. When the light beam hits a wall or the ground, a darker shape is visible where less light is hitting the surface. Refraction is responsible.
Explanation:
Here is a clip of an example of air making a shadow
https://www.seeker.com/stories/air-shadows/
Consider three properties of the net force on an object: a magnitude, direction, and angle with respect to the objects path. For the following situation select the choice that indicates wether these quantities are constant or changing during the course of the motion.
1. The magnitude and the angle of the net force with respect to path are constant, but the direction is changing
2. The direction and the angle of the net force with respect to path are constant, but the magnitude is changing.
3. The magnitude and direction of the net force are changing, but the angle of the net force with respect to path is constant.
4. The magnitude, direction, and angle with respect to path for the net force are constant.
5. The magnitude and direction of the net force are constant, but the angle of the net force with respect to path is changing.
Answer:
Explanation:
yeah i dont know i need the answer too
Agents of socialization?
Answer:
agents of socialization are:-
family
peers
school
mass media
100k points pls solve asap or no points
Answer:
Explanation:
You have given us a very weird question. Things do not mesh
If the mass is 500 kg and sits 25 m above the lowest spot on the track, the potential energy is
PE = mgh = 500(9.8)(25) = 122500 Joules,
not the reported 61250 Joules
So either the Joules is incorrect or the mass is supposed to be 250 kg.
In either case, in the absence of friction, the potential energy will convert to kinetic energy.
½mv² = mgh
v = √2gh
which does not involve the use of either Joules or kilograms.
Maximum velocity when starting from rest is
v = √(2(9.8)25) = √490 = 22.135943...
v = 22 m/s
The U.S. uses a household voltage of 110 V. However, electric stoves and dryers are wired with
220 V lines. Which would cause less damage --plugging a 110 V-rated curling iron into a 220 V
outlet, or a German-made 220 V-rated curling iron into a 110 V outlet? Explain. (Note: 110 and
220 V outlets are made in different shapes so that appliances cannot be accidentally
interchanged.)
Answer:
In the United States and neighboring countries, however, household outlets run at 110 or 120 volts. This can pose a serious problem for travelers. Connecting a 220-volt appliance to a 110-volt outlet can damage or destroy the appliance
How much gravitational potential energy is stored in a 2.0kg object that has been raised up to a height of 3.5m
Answer:
68.6 joules
Explanation:
g.p.e=mass × gravity × height
= 2 × 9.8 × 3.5
=68.6 joules
xác định quỹ của chất điểm chuyển động với phương trình chuyển động sau đây
Answer:
pls English
Explanation:
plsss,ಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠ
Your new motorcycle weighs 2580 N.
The acceleration of gravity is 9.8 m/s2.
What is its mass?
Answer in units of kg.
Answer:
answer to your question is 263.26kg
Explanation:
m=f÷a ,m=2580÷9.8=263.26kg
A box of mass 20kg rests on a flat horizontal floor. if the density of air is negligible. Draw a diagram showing forces acting on the box
An object if mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons.
Hi there!
On the object, we know that there are two forces working on the object:
-Force due to gravity (Mg)
-Force due to air resistance
Let the positive direction of the force be downwards (direction of the acceleration)
We can write the summation of forces as:
∑F = Mg - Fa
Plug in values. Let g ≈ 10 m/s²
∑F = 30(10) - 50 = 250N
Find the acceleration using the formula:
∑F = m · a
∑F/m = a
Plug in values:
250/30 = 8.33 m/s²
momentum is conserved it can be transferred but not lost. true or false
Answer: False
explanation: because Total momentum is conserved only if the collision can be considered isolated from the influence of net external forces
Questions
Q1. In this lab the centripetal force is provided by
a) the person’s hand
b) the tube
c) the hanging weight
d) the spinning motion
Q2. If the mass of the stopper were doubled but other things remained the same, the hanging mass would need to be
a) doubled
b) halved
c) tripled
d) quadrupled
Q3. If the velocity of the stopper were doubled, but other things remained the same, the hanging mass would need to be
a) doubled
b) halved
c) tripled
d) quadrupled
Answer:
just doing your module wag asa brainly ok malaki kna
Weight refers to the pull of _________ on an object.
Question 2 options:
mass
gravity
volume
Answer: Weight refers to the force of gravity acting upon an object.
(Answer B)
You throw a ball upward with an initial speed of 3.0 m/s from an initial height of 1.5 m. After you throw the ball, its acceleration is 9.81 m/s downward. Taking upward to be the positive direction, write the position-time equation for the ball's motion
Answer: An object undergoing a constant acceleration can have its motions be described by the kinematic equations. These equations relate the position of the particle, its velocity, acceleration, and time.
Explanation:
Answer:
vf^2=vo^2+2ay(y1-y0)
Explanation: