If A= -3, B= -7, C= 5, and D= 2, what does AB - CD= Question options: A.11 B.31 C. -11 D. -15

Answer:

wouldnt it be 4,4?

Step-by-step explanation:

Answer:

Step-by-step explanation:

Calculate the distance between two points by filling in the x and y values of both coordinates. How do you find the distance between two points? Distance Formula : Example: For two points, (3,2) and (15, 10) the distance is calculated as: Distance = 14.42 (rounded to the nearest 100th)

Answer: t=-5

Step-by-step explanation:

if 10t=-50, you have to solve for the equation. to solve, you have to get the variable by itself. to get the variable by itself, you have to divide both sides by 10. 10t/10=-50/10. t=-5

Answer:

a) 3

Step-by-step explanation:

3+10= 13

hope this helped :)

Answer:

A. 3

Step-by-step explanation:

? + 10 = 13

? = 13 - 10

? = 3

Answer:

Ray, Line, Transversal?, Plane, Segment

Step-by-step explanation:

Answer:

Hey there!

6x+1+3=8x+1

6x+4=8x+1

6x+3=8x

3=2x

x=1.5

6(1.5)+1

10

SR is 10 units long.

Let me know if this helps :)

Answer:

L =80

w=60

Step-by-step explanation:

P =280

L =w +20

=>L +w=280 :2 =140

w+20+w=140

2w=140 - 20

2w =120

w=120 :2 =60

L=60 +20 =80

P =2L +2w

P =2 ×80 +2 ×60

P=160 +120

P=280

Answer:

L = 80    ,   w=60

Step-by-step explanation:

l= w+20

perimeter: l+w+l+w=280

Plug in the value of L in place of L

(w+20)+w+(w+20)+w=280

Combine Like terms

and then separate the variables and knowns by subracting 40 from both sides

4w+40=280

     -40   -40

Divide by 4 from both sides so (W) would be alone

4w=240

÷4     ÷4

You solved half the question now

               w = 60

Remember the L at the top

we now know the value of W

so

L=(60)+20

L=80

just to be sure

80+80+60+60=280

you are welcome

Answer:

no

Step-by-step explanation:

its just like a positive number + a positive number cannot equil a negitive number.

Answer:

x>6;x>2 or just x>2 if u combine intervals

Step-by-step explanation:

x^2-8x+12>0

factor: (x-6)(x-2)>0

split: x-6>0; x-2>0

add 6 and 2: x>6;x>2

combine intervals: x>2

Answer:

x = 1/3

Step-by-step explanation:

Answer:

-1/2

Step-by-step explanation:

Answer:

common denominator

6

1/3 - 5/6 difference

-1/2

Step-by-step explanation:

hope I wasn't to late

have a good day guys

:)

Answer:

The amount of monthly installments is $267.30

Step-by-step explanation:

Here, we are interested in calculating the amount of the monthly is installments.

To get the amount of the installments, we need to calculate the sum of the interest and the amount borrowed.

Mathematically,

Simple interest = PRT/100

from the question;

P = principal which is the amount borrowed = $10,000

R = rate = 3.5%

T = time = 42 months = 42/12 = 3.5 years

Substitute these values into the formula for simple interest;

We have ;

S.I = (10,000 * 3.5 * 3.5)/100 = $1,225

So the total amount to

payback = interest + principal = 1225 + 10,000 = 11,225

So the amount of installments will be ;

The amount to payback/number of months

Mathematically that would be ; 11,225/42 = $267.26 which is approximately $267.30 per month

Answer: c

Step-by-step explanation:

Answer:

31

Step-by-step explanation:

Answer:

Step-by-step explanation

Answer:

w=5

Step-by-step explanation:

8w=40

/8    /8

w=5

Answer:  see proof below

Step-by-step explanation:

Given: A + B + C = π                     →  A = π - (B + C)

                                                     → B + C = π - A

Use the Pythagorean Identity: cos² A + sin² A = 1   →  sin² A = 1 - cos² A

Use Double Angle Identities: cos 2A = 2 cos² A - 1 → cos² A = (cos 2A + 1)/2

                                             → cos A = 1 - 2 sin² (A/2)    

Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]

Use Cofunction Identities:  cos (π/2 - A) = sin (A)

                                             sin (π/2 - A) = cos A

                                             cos (-A) = cos (A)

Proof LHS → RHS:

[tex]\text{LHS:}\qquad \qquad \sin^2\bigg(\dfrac{B}{2}\bigg)+\sin^2 \bigg(\dfrac{C}{2}\bigg)-\sin^2\bigg(\dfrac{A}{2}\bigg)[/tex]

[tex]\text{Pythagorean:}\qquad 1-\cos^2 \bigg(\dfrac{B}{2}\bigg)+1-\cos^2 \bigg(\dfrac{C}{2}\bigg)-\bigg[1-\cos^2 \bigg(\dfrac{A}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =1-\cos^2 \bigg(\dfrac{B}{2}\bigg)-\cos^2 \bigg(\dfrac{C}{2}\bigg)+\cos^2 \bigg(\dfrac{A}{2}\bigg)[/tex]

[tex]\text{Double Angle:}\quad 1-\bigg(\dfrac{\cos(2\cdot \frac{B}{2})+1}{2}\bigg)-\bigg(\dfrac{\cos (2\cdot \frac{C}{2})+1}{2}\bigg)+\bigg(\dfrac{\cos (2\cdot \frac{A}{2})+1}{2}\bigg)\\\\\\.\qquad \qquad \qquad =1-\dfrac{\cos B}{2}-\dfrac{1}{2}-\dfrac{\cos C}{2}-\dfrac{1}{2}+\dfrac{\cos A}{2}+\dfrac{1}{2}\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}[1-(\cos B+\cos C)+\cos A][/tex]

[tex]\text{Sum to Product:}\qquad \dfrac{1}{2}\bigg(1-\bigg[2\cos \bigg(\dfrac{B+C}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)\bigg]+\cos A\bigg)[/tex]

[tex]\text{Given:}\qquad \dfrac{1}{2}\bigg(1-\bigg[2\cos \bigg(\dfrac{\pi -A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)\bigg]+\cos A\bigg)[/tex]

[tex]\text{Cofunction:}\qquad \dfrac{1}{2}\bigg(1-\bigg[2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)\bigg]+\cos A\bigg)[/tex]    

[tex]\text{Double Angle:}\qquad \dfrac{1}{2}\bigg[1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)+1-2\sin^2 \bigg(\dfrac{A}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}\bigg[2-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)-2\sin^2 \bigg(\dfrac{A}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =1-\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B-C}{2}\bigg)-\sin^2 \bigg(\dfrac{A}{2}\bigg)[/tex]

[tex]\text{Factor:}\qquad \qquad 1-\sin \bigg(\dfrac{A}{2}\bigg)\bigg[ \cos \bigg(\dfrac{B-C}{2}\bigg)-\sin \bigg(\dfrac{A}{2}\bigg)\bigg][/tex]

[tex]\text{Given:}\qquad \qquad 1-\sin \bigg(\dfrac{A}{2}\bigg)\bigg[ \cos \bigg(\dfrac{B-C}{2}\bigg)-\sin \bigg(\dfrac{\pi -(B+C)}{2}\bigg)\bigg][/tex]

[tex]\text{Cofunction:}\qquad 1-\sin \bigg(\dfrac{A}{2}\bigg)\bigg[ \cos \bigg(\dfrac{B-C}{2}\bigg)+\cos \bigg(\dfrac{B+C}{2}\bigg)\bigg][/tex]

[tex]\text{Sum to Product:}\ 1-\sin \bigg(\dfrac{A}{2}\bigg)\cdot 2 \cos \bigg(\dfrac{(B-C)+(B-C)}{2\cdot 2}\bigg)\cdot \cos \bigg(\dfrac{(B-C)-(B+C)}{2\cdot 2}\bigg)\\\\\\.\qquad \qquad \qquad =1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(-\dfrac{C}{2}\bigg)[/tex][tex]\text{Cofunction:}\qquad =1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{LHS = RHS:}\quad \checkmark\\\\\quad 1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(\dfrac{C}{2}\bigg)=1-2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \cos \bigg(\dfrac{B}{2}\bigg)\cdot \cos \bigg(\dfrac{C}{2}\bigg)\quad[/tex]

Answer:

So this is scientific notation what you do is

2.9x10^5 so you put however many zeros the is powered to 10. See there is a 5 It has to be behind or in front of the decimal you might be saying how do you know if its behind or in front well negative is in front and positive is behind .

290,000 there was a number already behind the decimal so there you go 5 number behind the decimal.  

Same for the second one

290,000  870,000 is your answers so now you add hem together

1,160,000 is your final answer

Step-by-step explanation:

Answer:

Step-by-step explanation:

5000000

+ 2000

5002000 (Answer)

Answer:

X is less than seven

Step-by-step explanation:

"<" means less than, and shows that x is less than 7

Hey there! I'm happy to help!

Order of operations is PEMDAS. Parentheses comes first.

(-4+2)=-2

So, now we have -5-(-2)2

The next available option is multiplication.

-5-(-4)

Now we do addition and subtraction.

-5+4

-1.

Have a wonderful day! :D

Answer:

Step-by-step explanation:

1/2

Answer: X=15

Step-by-step explanation:

GH+HJ= GJ

27+27=4x-6

54=4x-6

60=4x

15=x

Answer:

x=30

Step-by-step explanation:

Answer:

Yes!

Step-by-step explanation:

Answer:

this is what I found hope its correct!‍♀️

Answer:

Midpoint: [tex](\frac{3}{2} ,0 )[/tex]

Step-by-step explanation:

Midpoint Formula: [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]

Step 1: Define variables

x₁ = 7

x₂ = -4

y₁ = -2

y₂ = 2

Step 2: Plug into midpoint formula

[tex](\frac{7-4}{2} ,\frac{-2+2}{2} )[/tex]

Step 3: Simplify/Evaluate

[tex](\frac{3}{2} ,\frac{0}{2} )[/tex]

[tex](\frac{3}{2} ,0 )[/tex]