If 3.0 grams of Strontium-90 in a rock sample remained in 1989, approximately how many grams of Strontium-90 were present in the original sample in 1933?

Answers

Answer 1

11.29 grams of strontium-ninety had been gift withinside the unique rock pattern in 1933. Strontium- ninety decays to yttrium-ninety, which in flip decays to solid zirconium.

The isotopes of strontium and yttrium emit beta debris as they decay. The launch of radiation throughout this decay manner reasons situation approximately the protection of strontium and all different radioactive substances. Sr-ninety may be inhaled, however ingestion in meals and water is the best fitness situation. Once withinside the body, Sr-ninety acts like calcium and is effectively included into bones and teeth, wherein it may purpose cancers of the bone, bone marrow, and smooth tissues across the bone.

Strontium has a half-existence of 28.8 years. Therefore,

1989 - 1933 = 56years.

fifty six / 28.eight = 1.94 half-lives

Thus, the amount of the radioisotope closing will double for every half-existence elapsed. transferring backwards in time. Therefore, transferring backwards in time through 1.94 times half-lives, the amount closing will double through 1.94 times.

Thus, the quantity closing in 1933 is 3.0 × (1.ninety four)² = 11.29 grams.

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Related Questions

NEED HELP FOR A TEST
What is the empirical formula
for this compound?
B3H6N3
BH2N
B2H4N2
B3H6N3

Answers

The empirical formula for the given compound B₃H₆N₃ is BH₂N. Therefore, option (1) is correct.

What is the empirical formula?

The empirical formula can be described as the simplest ratio of the number of different atoms present in a compound. The molecular formula of the compound can be defined as the actual number of each atom present in a molecule. This formula is generally used and is also a multiple of the empirical formula of a compound.

The empirical formula provides the ratio of the number of atoms of different elements in a given compound. The percentage composition of a compound gives the empirical formula of that compound.

Given the compound is inorganic benzene which has a molecular formula is  B₃H₆N₃. We can write this molecular formula as (BH₂N)₃. Therefore the empirical formula of the given compound is BH₂N.

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Huda sees an obvious set of fingerprints on a mirror at a crime scene. How can she BEST preserve this evidence?

A.
Sketch the shape of the prints.

B.
Cut the fingerprints out of the mirror.

C.
Use clear tape to lift the prints.

D.
Make a plaster mold of the prints.

Answers

The best way to preserve the fingerprint is by using a clear tape to lift the prints.

The fingerprints help us grab objects and also for grip. the 3 D version of the ridges enables us to pick things up. Patterns on the fingers play a very important role in the fine motor skills of the hands.

One of the most important uses of the fingerprints is to help investigators link one crime scene to another involving the same person. Fingerprint identification also helps investigators to track a criminal's record, their previous arrests and also convictions, which help in sentencing, probation, parole and pardoning decisions.

The print that are left on surfaces such as mirror can be carefully be lifted on a clear tape and can be seen it clearly.

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Which one of the following correctly represents a conjugate acid-base pair?
Select one:
a. H3O+, OH™
b. H₂O, O
c.H₂CO3, CO3²-
d. H₂CO3, HCO3
e. HCI, Cl₂

Answers

A conjugate acid-base pair is represented by H2CO3, HCO3.

Option d is correct.

What exactly are conjugate acid-base pairs?

A conjugate acid-base pair is a pair of substances that differ exclusively in the presence of a proton (H+) according to the Brnsted-Lowry definition of acids and bases. A proton given to a base creates a conjugate acid, while a proton taken away from an acid creates a conjugate base.

Is HCO3's conjugate base CO2?

H2CO3 is created by adding CO2 and water. The hydrogen carbonate ion, which is the same thing, is created when the carbonic acid dissociates, producing a proton (H+) and bicarbonate ion (HCO3(1-)). Since the dissociation's end result is the bicarbonate ion, it is the conjugate BASE.

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Inside the container is an ideal gas at 1.00 atm, 20.0 ∘C, and 1.00 L. This information will apply to the first three parts of this problem.
What will the pressure inside the container become if the piston is moved to the 1.40 L mark while the temperature of the gas is kept constant?

Answers

The pressure inside the container will become 0.71 atm if the piston is moved to the 1.40 L

How do I determine the pressure inside the container?

To obtain the pressure inside the container, we'll begin by listing out the given parameters from the question. This is given below:

Initial pressure (P₁) = 1.00 atmInitial volume (V₁) = 1.00 LTemperature = 20.0 °C = ConstantNew volume (V₂) = 1.40 LPressure inside the container (P₂) = ?

Since the temperature is constant, we can determine the pressure inside the container by using the Boyle's law equation as illustrated below:

P₁V₁ = P₂V₂

1.00 × 1.00 = P₂ × 1.40

1 = P₂ × 1.40

Divide both sides by 1.40

P₂ = 1 / 1.40

P₂ = 0.71 atm

Thus, from the calculation made above, we can conclude that the pressure inside the container is 0.71 atm

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In April, Earth's orbit makes the sun appear to be in the constellation Aries, even though the constellation itself is not visible during the day. In January, Earth's orbit makes the sun appear to be in the constellation Capricorn, even though the constellation itself is not visible during the day. The path the sun follows through the sky includes 12 constellations known as the zodiac.

What is the name given to this path or plane?

(1 point)
Responses

the ecliptic


the celestial equator


the zodiacal path


the solar orbit

Answers

Answer:

The ecliptic.

is the correct answer

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