I took a picture of my problem.

Answer:

B. The velocity of an object

c. The mass of an object

Explanation:

Answer:

2. deer

Explanation:

The lion, spider, and snake eat meat or to an extent.

Deer don't eat meat

Answer:

deer :)

Explanation:

The rest are basically carnivores

Explanation:

the weight of the people inside the bus

Answer:

hope this helps  : )

Explanation:

brainliest plz

Answer:

Plastics being consumed by fish and passing toxic compounds to the humans eat the fish.

Explanation:

I did that answer and got it right.

Answer:

Plastics being consumed by fish and passing toxic compounds to the humans that eat the fish.

Explanation:

Answer:

A solar eclipse results when the moon passes in between the earth and the sun hiding the sun fully or partly for some time. A lunar eclipse occurs when the earth passes in between the moon and the sun casting its shadow on the moon and thus hiding it fully or partly for some time.

Explanation:

your welcome

Answer:

3 m/s east

Explanation:

I took a test a got it right

Answer:

3 m/s east

Explanation:

Answer:

The force is 1250-N

Explanation:

Generally according to Newtons third law , which states that for every action there is an equal and opposite reaction

 Now considering the question, the action here is the force applied by the ninja while the reaction is the force applied by the oak and from Newton law both of these action are equal but opposite to each other.

Hence the force applied by the the piece of oak on the fist is 1250 N

Answer:

a = 0.50 m/s²

v = 6.0 m/s

Explanation:

Step 1: Given data

Step 2: Calculate the acceleration

We will use the following suvat equation.

s = u × t + 1/2 × a × t²

s = 0 × 12.0 s + 1/2 × a × (12.0 s)²

36 m = a × 72.0 s²

a = 0.50 m/s²

Step 3: Calculate the final velocity

We will use the following suvat equation.

v = u + a × t

v = 0 + 0.50 m/s² × 12.0 s

v = 6.0 m/s

they're all right, because he just took a lap and went back to the same starting point,

Answer:

The speed and height at 0 sec are 20 m/s and 0 m.

The speed and height at 1 sec are 10.2 m/s and 15.1 m.

The speed and height at 2 sec are 0.4 m/s and 20.4 m.

The speed and height at 3 sec are 9.4 m/s and 15.9 m.

The speed and height at 4 sec are 19.2 m/s and 1.6 m.

Explanation:

Given that,

Initial speed = 20 m/s

Suppose, given time in charge are t= 0, 1, 2, 3, 4 sec

At t=0 sec,

We need to calculate the velocity and height

Using equation of motion

[tex]v=u-gt[/tex]

Put the value into the formula

[tex]v=20-9.8\times0[/tex]

[tex]v=20\ m/s[/tex]

Now, using second equation of motion

[tex]h=ut-\dfrac{1}{2}gt^2[/tex]

Put the value into the formula

[tex]h=20\times 0-\dfrac{1}{2}\times9.8\times0[/tex]

[tex]h=0\ m[/tex]

At t=1 sec,

We need to calculate the velocity and height

Using equation of motion

[tex]v=u-gt[/tex]

Put the value into the formula

[tex]v=20-9.8\times1[/tex]

[tex]v=10.2\ m/s[/tex]

Now, using second equation of motion

[tex]h=ut-\dfrac{1}{2}gt^2[/tex]

Put the value into the formula

[tex]h=20\times1-\dfrac{1}{2}\times9.8\times1^2[/tex]

[tex]h=15.1\ m[/tex]

At t=2 sec,

We need to calculate the velocity and height

Using equation of motion

[tex]v=u-gt[/tex]

Put the value into the formula

[tex]v=20-9.8\times2[/tex]

[tex]v=0.4\ m/s[/tex]

Now, using second equation of motion

[tex]h=ut-\dfrac{1}{2}gt^2[/tex]

Put the value into the formula

[tex]h=20\times2-\dfrac{1}{2}\times9.8\times2^2[/tex]

[tex]h=20.4\ m[/tex]

At t=3 sec,

We need to calculate the velocity and height

Using equation of motion

[tex]v=u-gt[/tex]

Put the value into the formula

[tex]v=20-9.8\times3[/tex]

[tex]v=-9.4\ m/s[/tex]

Negative sign shows the opposite direction of motion

Now, using second equation of motion

[tex]h=ut-\dfrac{1}{2}gt^2[/tex]

Put the value into the formula

[tex]h=20\times3-\dfrac{1}{2}\times9.8\times3^2[/tex]

[tex]h=15.9\ m[/tex]

At t=4 sec

We need to calculate the velocity and height

Using equation of motion

[tex]v=u-gt[/tex]

Put the value into th formula

[tex]v=20-9.8\times4[/tex]

[tex]v=-19.2\ m/s[/tex]

Negative sign shows the opposite direction of motion

Now, using second equation of motion

[tex]h=ut-\dfrac{1}{2}gt^2[/tex]

Put the value into the formula

[tex]h=20\times4-\dfrac{1}{2}\times9.8\times4^2[/tex]

[tex]h=1.6\ m[/tex]

So, The ball has hit the ground at 5 sec.

Hence, The speed and height at 0 sec are 20 m/s and 0 m.

The speed and height at 1 sec are 10.2 m/s and 15.1 m.

The speed and height at 2 sec are 0.4 m/s and 20.4 m.

The speed and height at 3 sec are 9.4 m/s and 15.9 m.

The speed and height at 4 sec are 19.2 m/s and 1.6 m.

Answer:

F = 600N

Explanation:

F = m x a

F = Force

m = mass

a = acceleration

F = 0.14 x 600 = 84N

Answer:

B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.

Explanation:

From Physics we get that resultant velocity of an airplane is the sum of an absolute velocity and a relative velocity, that is:

[tex]\vec v_{A} = \vec v_{W}+\vec v_{A/W}[/tex] (Eq. 1)

Where:

[tex]\vec v_{W}[/tex] - Wind velocity, measured in meters per second.

[tex]\vec v_{A/W}[/tex] - Airplance velocity relative to wind, measured in meters per second.

[tex]\vec v_{A}[/tex] - Airplane velocity, measured in meters per second.

If we assume that [tex]\vec v_{W} = 20\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex] (The airplane flies with the wind), [tex]\vec v_{A/W} = 130\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex], then the resultant velocity of the airplane is:

[tex]\vec v_{A} = 20\,\hat{i}+130\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex]

[tex]\vec v_{A} = 150\,\hat{i}\,\,\,\left[\frac{m}{s} \right][/tex]

Therefore, correct answer is B.

Answer:

B. The wind is blowing at 20 m/s. The airplane is flying with the wind at 130 m/s.

Explanation:

Answer:

Explanation:

the search for authenticity in films, motivated Hollywood to use more realism in special effects.

Answer:

4 m/s

Explanation:jus did on edgu 2020

The momentum of the cyclist and bicycle at this point is 211.2 kg·m/s, calculated by multiplying their combined mass (88 kg) by their velocity (2.4 m/s). The correct answer is C.

For more questions on momentum

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Answer:

E = V / d       125 V / .018 m = 6940 V/m     electric field

F = E Q       force on Q due to E

F = E n e     where n is the number of electrons in Q

m g = E n e

n = m g / E e     where n is the number of electrons e needed to support drop

n = 1.6 * 10E-16 * 9.8 / (6940 * 1.6 * 10E-19)

n = 1.41

Since n needs to be an integral number of charges, the drop would

not be suspended (motionless under these conditions).

Answer:

Since the two vectors form a right angle, no components need to be found for the resultant vector - we already have them!

Vector R's x-component = 3.00 units

Vector R's y-component = 4.00 units

To solve for the magnitude of the displacement, use the distance formula: Square Root of [(3)^2 + (4)^2], which equals 5 units.

To solve for the direction of the displacement, plug in -4 (remember where it was pointing) for y and 3 for x. Tan-1(-4/3) = -53.13°, or 53.13° south of east.Please Mark as Brilliant

The magnitude of vector C is |C| = 3 and It is directed along the negative x - axis.

A vector quantity is a quantity with both magnitude and direction.

Given is vector A is 7.00 units in length and points along the positive x-axis. and vector B is 5.00 units in length and points along the negative x-axis.

Vector A = 7 a[x]

Vector B = - 5 a[x]

Therefore, the given expression to be evaluated is -

C = A + 2B

C = 7 a[x] + 2(- 5 a[x])

C = 7 a[x] - 10 a[x]

C = - 3 a[x]

So, the magnitude of vector C is -

|C| = 3

It is directed along the negative x - axis.

Therefore, the magnitude of vector C is |C| = 3 and It is directed along the negative x - axis.

To solve more questions on Vectors, visit the link below-

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Answer:

about 2.5 seconds depending on if he jumps up and out or if he jumps out.

Explanation:

Answer:

The question of analog vs. digital audio is one of the more hotly debated questions in the world of music, film and media today. Does digital sound better? Does analog sound better? Is there even a noticeable difference?

It’s impossible to understand the difference completely without understanding what distinguishes analog audio from digital audio. A full discussion of these terms is best left to your curriculum and discussions with your mentor in the studio. For now, though, here’s a brief explanation of what these two words mean, and the differences between them.

Analog refers to a continuously changing representation of a continuously variable quantity. Digital, however, refers to representing these variable quantities in terms of actual numbers, or digits. The last two sentences seem a bit complex, but let’s try to simplify them with an example. If you consider the numbers 1 and 2 on a number line, there are actually an infinite number of points between 1 and 2. This is what analog represents—the infinite number of possibilities between 1 and 2. Digital, on the other hand, only looks at certain number of fixed points along the line between 1 and 2 (for example, 1 ¼, 1 ½, 1 ¾, and 2).

Can you see the difference? Digital takes a few “snapshots” of the number line, while analog takes the whole line into account.

As another example, think of analog vs. digital as the difference between seeing something in real life and watching it on film. When we see something happen in real life, there are no “spaces” between what we see, so we’re watching it happen in analog. Film, however, is actually a series of still photographs that are taken in rapid-fire intervals, and when we see them in succession, it tricks our minds into thinking we’re seeing a continuous flow of movement. So in a manner of speaking, when we watch the event happen on film, we’re watching it digitally, because we’re watching increments of the event, rather than the whole thing in fluid motion. (Not to be confused with digital video vs. film, which is another discussion completely!)

Let’s bring this idea into audio, music, and the studio. Sound occurs naturally in analog–that is to say, sound occurs in a continuous set of waves that we hear with the human ear. (Think of it as a “wavy” line with an infinite number of points along it.) When we capture that sound in a way that represents all the possible frequencies, we’re recording in analog; when we use computers to translate the sound into a series of numbers that approximate what we’re hearing, we’re recording in digital.

Thus, a purely analog recording would be something that was recorded on tape and produced using manual equipment to mix, master and press into a vinyl LP. A purely digital recording would be recorded on a computer program such as Pro Tools, mixed, mastered and produced digitally, and eventually burned onto a CD as an MP3 or audio file.

The most ironic aspect of the debate about digital vs. analog recording is that nowadays a lot of music is a combination of the two.  For example, you might record a song onto analog tape, but mix and master it digitally, or release it on the Internet as an MP3.

So what’s the difference in quality between analog and digital? The idea between digital recording is that our ears and brains technically can’t determine the spaces between the digital values, just like our brains interpret film as continuous motion. However, to many people, analog sound tends to be warmer, has more texture and is thought to capture a truer representation of the actual sound. Digital is felt to be somewhat cold, technical and perhaps lacking in analog’s nuance.

However digital is much cheaper. Recording an album with analog technology can require a whole studio full of equipment, but with digital recording technology, it’s possible to record a whole album in a bedroom on a laptop. And whereas analog technology can wear out or be damaged, digital media can last for an indefinite length of time.

Today many recording artists, both major and independent, record using a mixture of digital and analog techniques. While analog audio does give warmth and a truer sound quality, digital is cheaper to work with and offers more control over the finished product.

Answer:

magnitude and direction e.g acceleration,displacement

Answer:

Same as loop #2

Explanation:

The magnitude of emf in loop #1 is the same as that of loop #2

Answer:

The magnitude of the displacement is  [tex]H = 14.14 \ km[/tex]

Explanation:

From the question we are told that

  The distance of the car to north is  d =  10 km

   The distance of car to the west is  w =  - 10 \  km

The negative sign is because the direction is  west

Generally applying Pythagoras theorem , the displacement is  

         [tex]H = \sqrt{d^2 + w^2}[/tex]

=>      [tex]H = \sqrt{(10)^2 + (-10)^2}[/tex]

=>     [tex]H = 14.14 \ km[/tex]

Answer: height, mass, and acceleration.

Explanation:

Answer:

height, mass, and acceleration.

or a,b,f

Explanation:

Answer:

C. Capacitance

Explanation:

right on EDGE2021

Answer:

A. 1st law.

Explanation:

Newton's first law of motion states that, an object or body will continue to be at rest or experience a uniform motion in a straight line at constant speed provided there's no action of an external force. Thus, unless compelled to change its state by an external force, a body will continue to be at rest or experience a uniform motion in a straight line.

The Newton's first law of motion is also known as the law of inertia; which is the tendency of a body to be at rest unless acted upon by an external force.

In this scenario, you are standing in a subway train and the train suddenly stops but your body continues to move forward. This is in accordance with Newton's first law of motion.

Hence, the sudden stoppage of the train generates a force which acts on the body thereby causing the passenger to tip or move forward.

Answer:

[tex] s = 1,003 \: m[/tex]

Explanation:

[tex]s = \frac{1}{2} (u + v)t = \frac{1}{2} (12 + 47)34 \\ s = 1,003 \: m[/tex]