I need serious help with this one.







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A ball's position, in meters, as it travels every second is 282.5 sec.

Combining things and counting them as one big group is done through addition. In math, addition is the process of adding two or more integers together. Addends are the numbers that are added, while the total refers to the outcome of the operation. The sum is the entire value, and the addends are the integers that are being added. The mathematical operation of addition is the process of adding two or more numbers together to determine the total, or sum.

Given that,

The position function s(t) = 2.3t² + 225.

The velocity of the ball after 5 seconds is

s(t) = 2.3t² + 225.

t= 5

s(5) = 2.3(5)² + 225.

s(5) = 2.3(25) + 225.

s(5)= 57.5+ 225

s(5)= 282.5

Therefore,  it travels every second is 282.5 sec.

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The equation of each line using function notation is:

1. C. f(x) = 3x - 1.

2. D. f(x) = x.

3. D. f(x) = 4x + 4.

4. B. f(x) = -3/2x - 2

To use function notation, substitute the value of the slope (m) and the value of the y-intercept (b) into f(x) = mx + b.

Slope (m) = rise/run.

Y-intercept (b) is the point on the y-axis when the line intercepts the y-axis.

1. Slope (m) = rise/run = 3/1

Slope (m) = 3

Y-intercept (b) of the line = -1.

Substitute m = 3, and b = -1 into f(x) = mx + b:

f(x) = 3x - 1

The equation is: C. f(x) = 3x - 1.

2.  Slope (m) = rise/run = 2/2

Slope (m) = 1

Y-intercept (b) of the line = 0.

Substitute m = 1, and b = 0 into f(x) = mx + b:

f(x) = (1)x + 0

f(x) = x

The equation is: D. f(x) = x.

3. Slope (m) = rise/run = 4/1

Slope (m) = 4

Y-intercept (b) of the line = 4.

Substitute m = 4 and b = 4 into f(x) = mx + b:

f(x) = 4x + 4

The equation is: D. f(x) = 4x + 4.

4. Slope (m) = rise/run = -3/2

Slope (m) = -3/2

Y-intercept (b) of the line = -2.

Substitute m = -3/2 and b = -2 into f(x) = mx + b:

f(x) = -3/2x - 2

The equation is: B. f(x) = -3/2x - 2

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Answer:

44, 54, 82. Acute

Step-by-step explanation:

x + x + 10 + 2x - 6 = 180 (Triangle Sum Theorem)

4x + 4 = 180 (Combine Like Terms)

4x = 176 (Subtraction Property of Equality)

x = 44 (Division Property of Equality)

Now that we have found the value of x, we need to substitute it with the provided angles.

∡1 = x = 44°

∡2 = x + 10 = 54°

∡3 = 2x - 6 = 2(44) - 6 = 82°

So, the answer is an Acute triangle (Option 4).

Main Answer:

[tex]x=\frac{-2\±\sqrt{10}}{3}[/tex]

Explanation:

The given equation is,

[tex]3x^{2} +4x=2[/tex]

The

The quadratic formula to find the value of x for the equation [tex]ax^{2} +bx+c=0[/tex]  is,

[tex]x=\frac{-b\±\sqrt{b^{2}-4ac}}{2a}[/tex]

The values are,

a = 3, b = 4, c = -2

Now, substitute the values of a, b and c

[tex]x=\frac{-4\±\sqrt{(4)^{2}-4(3)(-2)}}{2(3)}[/tex]

[tex]x=\frac{-4\±\sqrt{16-12(-2)}}{6}[/tex]

[tex]x=\frac{-4\±\sqrt{40}}{6}[/tex]

[tex]x=\frac{-4\±2\sqrt{10}}{6}[/tex]

[tex]x=\frac{2(-2\±\sqrt{10})}{6}[/tex]

[tex]x=\frac{-2\±\sqrt{10}}{3}[/tex]

The average fraction of students in  Mr. Zanker's class and  Mr. Haynes  who went on the field trip is 11/8.

From the question, the fraction of the students in Mr. Zanker's class that attended the field trip is  3/4.

The  fraction of the students in  Mr. Haynes class that attended the field trip is 5/8 .

Then the we can calculate the average fraction of student in the class of the two teacher is

= (3/4 + 5/8) = 11/8.

Therefore, the average fraction of the number of the student can be calculated as 11/8.

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The number of vegetable bearing plants are : 0.45x, where x is the total number of plants.

A fraction in mathematics represents a portion or element of the whole. It represents the appropriate parts of the totality. A fraction is made up of two parts: the numerator and the denominator. The number at the top is the numerator, and the number at the bottom is the denominator. The numerator indicates the number of equal parts that were actually taken, whereas the denominator shows the total number of equal parts in the whole.

Let x be the initial plant population.

Now that 1/10 of plants bear fruit, the quantity of fruit-bearing plants is equal to 0.1x.

Plants remaining then equal x - 0.1x = 0.9x.

Once more, because half of the remaining plants give flowers, the number of flower-bearing plants is equal to 0.5(0.9x) = 0.45x.

As a result, the number of plants left is equal to 0.9x - 0.45x = 0.45x.

Given that all remaining plants produce veggies, the number of plants that do so is equal to 0.45.

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By doing multiply of = [tex]\frac{2}{3}[/tex] with =[tex]\frac{-3}{2}[/tex] we get -1 .

Algebra is one of the areas of mathematics where mathematical expressions can be used to represent situations or problems. In order for a mathematical statement to make sense, it must have mathematical operations like addition, subtraction, multiplication, and division as well as variables like x, y, and z. Every branch of mathematics, including calculus, trigonometry, and coordinate geometry, uses algebra. The equation 2x + 4 = 8 is a simple algebraic formula.Mathematical branch known as algebra deals with symbols and arithmetic operations on them. These symbols are referred to be variables since they lack set values. We frequently observe specific values that change in our day-to-day situations. However, there is a continuing need to depict these shifting values. These values are frequently represented in algebra by symbols, which are known as variables, such as x, y, z, p, or q. In order to determine the values, additional arithmetic operations such as addition, subtraction, multiplication, and division are performed on these symbols.

Given that : = [tex]\frac{2}{3}[/tex]  x ___ = -1

[tex]\frac{2}{3}[/tex] ×[tex]\frac{-3}{2}[/tex]

=-1

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By combining numerical or algebraic expressions that share a basis, distributing exponents among products and quotients, and simplifying powers of powers, one can exploit the properties of integer exponents to create similar expressions.

Based on the information, it's important to simply transfer the base and exponent to the other side of the fraction line, change the exponent to positive, and you have an analogous expression.

For example, the expression 2/3² can be illustrated to an equivalent expression as:

2/3² = 2 / (3 × 3)

= 2/9

This shows how the exponent has been used to form the new value.

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Six students measure the acceleration of an object in free fall. The students want to state that the absolute deviation for each measured value x from the mean is at most d is 0.86.

The average of absolute deviations from a central point makes up the average absolute deviation (AAD) of a data collection. It is a statistical summary of the statistical variability or dispersion. A mean, median, mode, or the result of any other central tendency measure or any reference value associated with the specified data set can all serve as the central point in the general form. The mean absolute deviation and the median absolute deviation are part of AAD (both abbreviated as MAD).

Find the mean of the data set first, then use that value to calculate the mean absolute deviation of the data. Divide the total number of data values by the sum of the individual data values. Assess the magnitude of the absolute difference between each data point and and the mean.

The measured data is

x = [10.56, 9.52, 9.73, 9.80, 9.78, 10.91]

There are 6 measurements.

Calculate the mean.

m = (10.56+9.52+9.73+9.80+9.78+10.91)/6 = 10.05

Calculate deviations from the mean.

y = |x - m|

  = [0.51, 0.53, 0.32, 0.25, 0.27, 0.86]

The greatest deviation from mean is d = 0.86.

Calculate the average absolute deviation.

(0.51+0.53+0.32+0.25+0.27+0.86)/6 = 0.4567

The answer is: d = 0.86

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The most appropriate choice for HCF and LCM will be given by

The other number is 120

What is HCF and LCM?

HCF of two numbers A and B is the highest common factor of A and B. HCF is the highest number which divides both A and B.

LCM of two numbers A and B is the lowest common multiple of A and B. LCM is the least number which is divided by both A and B.

Here,

Let the other number be [tex]x[/tex]

HCF of 90 and [tex]x[/tex] = 30

LCM of 90 and [tex]x[/tex] = 360

Product  of HCF and LCM = 30 [tex]\times[/tex] 360

Product of 90 and [tex]x[/tex] = 90 [tex]\times[/tex] [tex]x[/tex]

By the problem,

                         90 [tex]\times[/tex] [tex]x[/tex] = 30 [tex]\times[/tex] 360

                                  [tex]x = \frac{360 \times 30}{90}[/tex]

                                  [tex]x = 120[/tex]

The other number is 120

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The value of the expression given as (3x + 2.05) + (-x + 1.09) + (2x) + (x) is 5x  + 3.14

Expressions are mathematical statements that are represented by variables, coefficients and operators

The expression is given as

(3x + 2.05) + (-x + 1.09) + (2x) + (x)

Start by opening the brackets

(3x + 2.05) + (-x + 1.09) + (2x) + (x) = 3x + 2.05 - x + 1.09 + 2x + x

Next, we collect the like terms

(3x + 2.05) + (-x + 1.09) + (2x) + (x) = 3x - x + 2x + x  + 2.05 + 1.09

Next, we evaluate the like terms

(3x + 2.05) + (-x + 1.09) + (2x) + (x) = 5x  + 3.14

Hence, the value of the expression is 5x  + 3.14

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Possible question

What is (3x + 2.05) + (-x + 1.09) + (2x) + (x)

We have a vertical and a horizontal lines, the equations are:

Line A: x = -5  (vertical one)

Line B: y = -5  (horizontal one)

Remember that the general linear equation in the slope-intercept form is:

y = a*x + b

Where a is the slope and b is the y-intercept.

If the line passes through the points (x₁, y₁) and (x₂, y₂) then the slope is:

a = (y₂ - y₁)/(x₂ - x₁)

Now, line A passes through  (–5, –2), (–5, 7), then the slope is:

a = (7 + 2)/(-5 + 5) = 9/0

Notice that if we divide by zero, the slope tends to infinity, so we have a vertical line.

In this case, the line A will be x = -5.

Now line B passes through points: (7, –5), (–2, –5)

Then the slope is:

a = (-5 + 5)/(-2 - 7) = 0/-9 = 0

Then the line is:

y = 0*x + b

And passes through (7, –5), then:

-5 = 0*7 + b

-5 = b

So this line is y = -5.

Concluding, we have:

Line A: x = -5

Line B: y = -5

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Answer:

Line A: no slope

The equation of line A is x = -5

Line B has a slope of 0

The equation of line B is y = -5

Step-by-step explanation:

I did it already :)

The horizontal asymptote of the function is y=36 and vertical asymptote is x = 6 and its end behavior is f(x)→6.

As the independent variable approaches a certain value, the function approaches asymptotes, but does not cross them. They could be angled, vertical, or horizontal.

ascending asymptotes

There will be a vertical asymptote at x=a if the denominator factor of a rational function, (x - a), is not matched by the same factor in the numerator.

horizontal asymptotes:

When x is large, the value of a rational function approaches the ratio of the highest-degree terms in the numerator and denominator.

Given the function is f(x) = 6x/x-36

limx→±∞ 6x/x-36

= limx→±∞ 6/1-36/x

= 6 ⇒ horizontal asymptote: y = 6

Consider denominator = 0 ↔ x-36 = 0 ↔ x=36

limx→₊₂₅ 6x/x-36

= 6×36/0⁺ = ∞ ⇒ vertical asymptote: x = 36

End behavior of f(x):

As x → -∞ or x → ∞, f(x) → 6.

Hence we get the asymptote and the end behavior of the function.

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Answer:

Flynn stays at the trampoline park for an additional 3 hours.

Step-by-step explanation:

30 - 12 = 18

18 / 6 = 3

As for the "Select the equation that represents the given situation" I don't know what this really means so I didn't do that. Sorry.

Answer:

slope(m) is -4

Step-by-step explanation:

[tex]m=\frac{-17-(-1)}{5-1} \\\\m=\frac{-16}{4} \\\\m=\frac{-4}{1} \\\\m=-4[/tex]

now substitute with one of the points

y=mx+b

-1=-4+b

+4  +4

3=b

now you have both m and b

y=-4x+3

The distance that's required to be kept geo either side will be 4.258 inches.

From the information, Foster is centering a photo that is 7 1/5 inches wide on a scrapbook page that is 16 inches wide.

It should be noted that 7 1/2 is the same as 7.5. Therefore,we can subtract and this will be:

= 16 - 7.5

= 8.5

Since we know that the scrapbook is 8.5 inches wider,we will divide the width by 2 to get the distance of either side and this will be:

= 8.5 / 2

= 4.25

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Foster is centering a photo that is 7 1/5 inches wide on a scrapbook page that is 16 inches wide. How far from each side go the page did he put the picture?

The average rate of change on the interval [2, 4] is 56

Here we have the function:

f(x) = 2x^3 + 1

And we want to find the rate of change on the interval [2, 4].

Remember that for a function f(x) the rate of change on an interval [a, b] is.

R = ( f(b) - f(a))/(b - a)

Then in this case, the rate of change is:

R = [ f(4) - f(2)]/[4 - 2] = ( 2*4^3 + 1 - 2*2^3 - 1)/2 = (4^3 - 2^3) = 56

So the rate is 56.

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The probability of happening of the events either B or C is [tex]\frac{2}{3}[/tex]

The probability that event A or event B happens is equal to the

probability that A happens plus the probability that B happens minus the probability that both happen. If events A and B are mutually exclusive, then the probability that event A or B happens is simply the sum of the probabilities. Given that

A = rolling a number greater than four

B = rolling an even number

C = rolling a multiple of 3

So,

P(A) = [tex]\frac{2}{6} =\frac{1}{3}[/tex]

P(B)=[tex]\frac{3}{6} =\frac{1}{2}[/tex]

P(C) = [tex]\frac{2}{6} =\frac{1}{3}[/tex]

Now, We have to find the probability of occurence of either event B or C

So, We know that

P(B or C ) = P(B) + P(C) + P(B or C)

P(B or C )= [tex]\frac{3}{6} +\frac{2}{6} -\frac{1}{6} =\frac{4}{6}[/tex]

P(BorC)= [tex]\frac{2}{3}[/tex]

Therefore, the probability of occurence of either event B or C is [tex]\frac{2}{3}[/tex].

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The time shown by the speedometer with speed of 10 m/s is 1 s.

The time shown by the speedometer with speed of 20 m/s is 1 s.

The time shown by the speedometer with speed of 30 m/s is 1 s.

The time read by the speedometer is given as;

t = 3 s.

The speedometer has low precision and as such we can do value approximation.

For the speedometer showing the speed 10 m/s. The time is calculated as, t = (v - u)/g

where g = 10 m/s²

t = (10 - 0)/10

t₁ = 1 seconds

For the speedometer showing the speed 20 m/s. The time is calculated as, t = (v - u)/g

where g = 10 m/s²

t = (20 - 0)/10

t₂ = 2 seconds

For the speedometer showing the speed 30 m/s. The time is calculated as, t = (v - u)/g

where g = 10 m/s²

t = (30 - 0)/10

t₂ = 3 seconds

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Answer:

Step-by-step explanation:

[tex]\displaystyle\\8 > \frac{x}{4}(x+5)-3[/tex]

Answer: angle CPB is an acute angle.

Answer: C. ∠CPB is the correct answer.

Step-by-step explanation:

Answer:

The test where Ella got 13/15 has the higher ratio of correctly spelled words to total words.

Step-by-step explanation:

On the last week's test, Ella got a 16/20, which equates to 80% correctly spelled words compared to total words. On this week's test, she got a 13/15, which equates to 86.6% correctly spelled words compared to total words. Since 86.6 > 80, the test where Ella got a 13/15 has the higher ratio.

The given exponential function represents the growth in function with a percentage increase as 57.3%.

Given we have the exponential function as :

y=8800(1.573)ˣ

it is in the form of: y=k.aˣ

therefore, if a>2 then the function represents growth.

and if a<1 then the function represents decay.

now, x=1.573

1.573 > 1

so, the function represents change in growth.

therefore, 1.573 - 1

= 0.573

= 57.3%

hence the change in growth of the function is increased by 57.3%.

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The greatest common factor, GCF, of the given terms is 2a⁴b

From the question, we are to determine the GCF of the given expressions. GCF means Greatest common factor

The given expressions are 18a^4b^9c^2 and 34a^6b^5 and 22a^8bc^7

First, we will write the expressions properly

The given expressions are 18a⁴b⁹c² and 34a⁶b⁵ and 22a⁸bc⁷

To determine the GCF of the expressions, we will express each one of them as a product of their factors

That is,

18a⁴b⁹c² = 2 × 3 × 3 × a × a × a × a × b × b × b × b × b × b × b × b × b × c × c

34a⁶b⁵ = 2 × 17 × a × a × a × a × a × a × b × b × b × b × b

22a⁸bc⁷ = 2 × 11 × a × a × a × a × a × a × a × a × b × c × c × c × c × c × c × c

Hence, the GCF is 2 × a × a × a × a × b = 2a⁴b

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After James adds stamps , the ratio of number of stamps in James's collection to the number of stamps in Roy's collection is 2:3 , the correct option is (D) 2:3  .

In the question ,

it is given that

Number of stamps that James has = 6 stamps

Number of stamps Roy has = 12 stamps

also , James adds 2 stamp to his collection ,

So number of stamps in James collection become = 8 stamps

So the ratio of number of stamps in James's collection to the number of stamps in Roy's collection is given by

= (number of stamps in James's collection)/(umber of stamps in Roy's collection)

Substituting the values , we get

= 8/12

Simplifying , we get

=2/3

Therefore , After James adds stamps , the ratio of number of stamps in James's collection to the number of stamps in Roy's collection is 2:3 , the correct option is (D) 2:3  .

The given question is incomplete , the complete question is

James has 6 stamps in his stamp collection. Roy has 12 stamps in his stamp collection. James adds 2 stamps to his stamp collection. After James adds these stamps, what is the ratio of the number of stamps in James's collection to the number of stamps in Roy’s collection?

(A) 1 : 2

(B) 2 : 1

(C) 3 : 2

(D) 2 : 3

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Answer:

Angle EDC = 180 - 90 - 30 = 60° (sum of angles in triangle add up to 180°)

Angle ADC + angle DCB = 180° (interior angles, AB//CD)

59 + 60 + 30 + angle ECB = 180

Angle ECB = 180 - 59 - 60 - 30 = 31°

The differences-of-means ​estimator, denoted by E(Y|X=1) -E(Y|X=0), is an estimator of the causal effect of X on Y because the differences-of-means estimator​ estimates that (A) the change in the expectation of Y as a result of an observation being in the treatment group as opposed to the control group.

So, in the given situation: The differences-of-means estimator estimates the change in the expectation of Y as a result of an observation being in the treatment group as opposed to the control group, and is denoted by E(Y|X=1) -E(Y|X=0).

Therefore, the differences-of-means ​estimator, denoted by E(Y|X=1) -E(Y|X=0), is an estimator of the causal effect of X on Y because the differences-of-means estimator​ estimates that (A) the change in the expectation of Y as a result of an observation being in the treatment group as opposed to the control group.

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The complete question is given below;
Suppose you have a binary randomized controlled experiment designed to measure the causal effect of X on Y. Let the control group be identified by X​ = 0 and the treatment group by X​ = 1.

The differences-of-means ​estimator, denoted by E(Y|X=1) -E(Y|X=0), is an estimator of the causal effect of X on Y because the differences-of-means estimator​ estimates:

A. the change in the expectation of Y as a result of an observation being in the treatment group as opposed to the control group.

B. the expectation of Y for observations within the control group.

C. the expectation of Y for observations within the treatment group.

D. All of the above.

-3/2<h<0 is the answer.

Given,

1+5h <h+1 <7+5h

Solution:

1+5h <h+1 <7+5h

If a < u <b, then a<u , u<b

Therefore,

1+5h <h+1  and h+1 <7+5h

1+5h <h+1

1+5h= h+1

4h = 0

h = 0

Therefore,

h<0

h+1 <7+5h

h+1 = 7+5h

4h = -6

h = -3/2

h > -3/2

Combine the intervals

h<0 and h> -3/2

By combining the above two, we get

-3/2<h<0

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Answer: b 67

Step-by-step explanation:

180-152 is 28

28+85=113

180-113=67

Answer:

B) 67°

Step-by-step explanation:

 The exterior angle of a triangle equals the sum of opposite interior angles.

      85 +  x = 152

Subtract 85 from both sides,

                x = 152 - 85

                x = 67°

Answer:

lol

Step-by-step explanation:

I dunno my brain isn't braining