I need help. Three different polygons in this shape and explain how I know? Help please thanks!

Answer:

[tex]2a+3[/tex] books

Step-by-step explanation:

Sonya -> [tex]a[/tex] books

Nick -> [tex](a+3)[/tex] books

Total: [tex]a+(a+3)=a+a+3=2a+3[/tex]

Answer:

216/343 or 0.6297 (4dp)

Step-by-step explanation:

Anytime the probability of an event occurs more than once in a particular order (one time after another in the same instance), then the probability is multiplied together. If the probability of him making the shot is 1/7, then the probability of him missing it is 6/7. This is because this is the only other possible outcomes and all outcome probabilities must add to 1 (1-1/7 - 6/7).

So, if he misses it three times in a row then the probability is:

6/7 (probability miss this first time) x 6/7 (probability miss second time) x 6/7 (probability miss 3rd time).

6/7 x 6/7 x 6/7 = 216/343

or 0.6297 (4dp)

Hope this helped!

Answer:

Step-by-step explanation:

-3t + 3 - 7t = -90 - 7

Simplify both sides of the equation

That's

- 10t + 3 = - 97

Using the subtraction property subtract 3 from both sides of the equation

We have

- 10t + 3 - 3 = -97 - 3

- 10t = - 100

Divide both sides by - 10

[tex] \frac{ - 10t}{ - 10} = \frac{ - 100}{ - 10} [/tex]

We have the final answer as

Hope this helps you

Answer:

Step-by-step explanation:

-3t + 3 - 7t = -90 - 7

-10t + 3 = -97

-10t = -100

t = 10

28x + 44y = 964.40

21x + 33y = 723.30

Let's multiply the first equation by 4 and the second by -4

84x + 176y = 3857.6

-84x - 132y = -2893.2

Add the equations together.

0 + 44y = 964.4

Simplify

44y = 964.4

Divide both sides by 44

y = 964.4/44

Since we have the value of y, let's plug 964.4/44 into y for the first equation.

28x + 44(964.4/44) = 964.40

Simplify the left side

28x + 964.4 = 964.4

Subtract 964.4 from both sides

28x = 0

Divide both sides by 0

x = 0

In conclusion,

y = 964.4/44

x = 0

Answer:

I'm not sure if I'm right but you should try X = the x value of the vertex.

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

[tex]\to A={(x,y,z)|3x+8y-5z=2} \\\\\to for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)[/tex]

                                        [tex]=3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)[/tex]

The set A is not part of the subspace [tex]R^3[/tex]

for point B:

[tex]\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)[/tex]

                                             [tex]=-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0[/tex]

[tex]\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon B[/tex]

The set B is part of the subspace [tex]R^3[/tex]

for point C: [tex]\to C={(x,y,z)|x<y<z}[/tex]

In this, the scalar multiplication can't behold

[tex]\to for (-2,-1,2) \varepsilon C[/tex]

[tex]\to -1(-2,-1,2)= (2,1,-1)[/tex] ∉ C

this inequality is not hold

The set C is not a part of the subspace [tex]R^3[/tex]

for point D:

[tex]\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)[/tex]

The scalar multiplication s is not to hold

[tex]\to for (-4, 1,2)\varepsilon D\\\\\to -1(-4,1,2) = (4,-1,-2)[/tex] ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace [tex]R^3[/tex]

For point E:

[tex]\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\[/tex]

The  [tex]x_1, x_2[/tex] is the arbitrary, in which [tex]ax_1+bx_2[/tex]is arbitrary  

[tex]\to a(x_1,0,0)+b(x_2,0,0) \varepsilon E[/tex]

The set E is the part of the subspace [tex]R^3[/tex]

For point F:

[tex]\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon F \\\\\to a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))[/tex]

The [tex]x_1, x_2[/tex] arbitrary so, they have [tex]ax_1+bx_2[/tex] as the arbitrary [tex]\to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F[/tex]

The set F is the subspace of [tex]R^3[/tex]

Answer:

its A

Step-by-step explanation:

Answer:

the answer is about 50 minutes

Step-by-step explanation:

5 ÷ 6 = .83 which is about 50 minutes so each lesson is about 50mins

Answer:

400,000

Step-by-step explanation:

Answer:

The answer to your question: x is -1/3 or 1

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Let x = cost of a loaf of bread ; y = cost of an egg

Dwayne :

1 loaf of bread and 6 eggs :

X + 6y = 4.45 - - - (1)

Sheila :

X + 12y = 5.65 - - - (2)

From (1);

X = 4.45 - 6y

In (2):

(4.45 - 6y) + 12y = 5.65

4.45 + 6y = 5.65

6y = 5.65 - 4.45

6y = 1.2

y = 0.2

From X = 4.45 - 6y:

X = 4.45 - 6(0.2)

X = 4.45 - 1.2

X = 3.25

Cost of a loaf of bread = $3.25

Coat of an egg = $0.2

Answer: the greatest number of trees that ElizaBeth can have in a row is 30

Step-by-step explanation:

given data:

citrus trees = 150

palm trees = 180

As we have to find the greatest number of trees that Elizabeth can have in a​ row, we will find the GCF or greatest common factor.

150 = 2 x 3 x 5 x 5

180 = 2 x 2 x 3 x 3 x 5

Greatest common factor is = 2 x 3 x 5 = 30

Therefore, the largest number of trees that ElizaBeth can have in a row is 30.

Answer:

13

Step-by-step explanation:

you plug in 3 for n

4n+1

4(3)+1

12+1

13

Answer:

slope is zero

Step-by-step explanation:

it is a horizontal line which means the slope all points that lie on the line have a -coordinate

[tex]\huge\boxed{No\;slope}[/tex]

There is no rise over run therefore, there is no slope.

You have to have rise over run to be able to have a slope.

By Gauss's Law the approach of solving sum of a sequence of n terms in arithmetic progression is :

[tex]S_n=\dfrac{n}{2}(a_1+a_n)[/tex]        ......1 )

Here, [tex]a_n = 302[/tex] , [tex]a_1=2[/tex] .

We know :

[tex]a_n=a_1+(n-1)d\\\\302=2+3(n-1)\\\\n = 101[/tex]

Putting, all values in equation 1) we get :

[tex]S_n=\dfrac{101}{2}\times (2+302)\\\\S_n=101\times 152\\\\S_n=15352[/tex]

Therefore, the sum of sequence using Gauss's Law is 15352.

Hence, this is the required solution.

Answer:

8x≤2.40, x ≤ $0.30

Step-by-step explanation:

Answer:

221

Step-by-step explanation:

2-1+5*4*11

2-1+20*11

2-1+220

1+220

221

Answer:

x- intercept is 6 y- intercept is -18

Step-by-step explanation:

Just use the graph, this graph is hard to get the answer but you just have to estimate.

Answer:

N0, an even or odd outcome is equally likely for each roll regardless of what happened in the past

Step-by-step explanation:

Answer:

D. No, an even or odd outcome is equally likely for each roll, regardless of what has happened in the past.

Answer:

x=$200

Step-by-step explanation:

cross-multiply

130=0.65x

Answer: k=1

Step-by-step explanation: Isolate the variable by dividing each side by factors that do not contain the variable.

I hope this helps you out! :)

Step-by-step explanation:

the answer would be k=1

The answer is 5.1 days

60*24= 1440 minutes in one day

7344/1440= 5.093 or 5.1 rounded to the nearest tenth

The value of ( 3 x 1,000 ) - ( 2 x 100 ) is 2,800.

Here,

Given that,  ( 3 x 1,000 ) - ( 2 x 100 )

What is subtraction of two number?

Subtraction is the operation of taking the difference of two numbers.

Now,

Firstly the value of 3 x 1000 = 3000

And, 2 x 100 = 200

⇒ 3000 - 200 = 2800

Hence, The value of ( 3 x 1,000 ) - ( 2 x 100 ) is 2,800.

Learn more about the subtraction visit:

https://brainly.in/question/12241794

#SPJ2

Answer:

36 units^2

Step-by-step explanation:

The area of a triangle is 1/2*base*height. Knowing this is just 2 triangles means you solve for 1 triangle, then multiply that by 2

Answer:

[tex]A=36\text{ units}^2[/tex]

Step-by-step explanation:

The area of a rhombus is given by the formula:

[tex]A=\frac{d_1\cdot d_2}{2}[/tex]

Namely, it is half of one diagonal multiplied by the other diagonal.

So, to find the area, we just need to find the length of AC and BD, multiply them together, and then divide by 2.

To find their lengths, we can use the distance formula. The distance formula is:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]

So, let's find the lengths of each diagonal:

AC:

Point A is (-1,0) and Point C is (-1,-6). Let (-1,0) be (x₁, y₁) and let (-1,-6) be (x₂, y₂). Substitute this into our formula:

[tex]d=\sqrt{(-1-(-1))^2+(-6-0)^2[/tex]

Simplify:

[tex]d=\sqrt{(-1+1)^2+(-6-0)^2[/tex]

Add or subtract:

[tex]d=\sqrt{(0)^2+(-6)^2[/tex]

Square:

[tex]d=\sqrt{36}[/tex]

Take the square root:

[tex]d=6[/tex]

So, the length of diagonal AC is 6.

BD:

Point B is at (5,-3) and Point D is at (-7,-3). Let (5,-3) be (x₁, y₁) and let (-7,-3) be (x₂, y₂). Substitute this into our formula:

[tex]d=\sqrt{(-7-5)^2+(-3-(-3))^2[/tex]

Simplify:

[tex]d=\sqrt{(-7-5)^2+(-3+3)^2[/tex]

Add or subtract:

[tex]d=\sqrt{(-12)^2+(0)^2[/tex]

Square:

[tex]d=\sqrt{144}[/tex]

Take the square root:

[tex]d=12[/tex]

So, our second diagonal is 12 units long.

Now, to find the area, substitute 6 and 12 into our formula. So:

[tex]A=\frac{d_1\cdot d_2}{2}[/tex]

Substitute 6 for d₁ and 12 for d₂. So:

[tex]A=\frac{(6)(12)}{2}[/tex]

Multiply:

[tex]A=\frac{72}{2}[/tex]

Divide:

[tex]A=36\text{ units}^2[/tex]

So, the area of the rhombus is 36 squared units.

And we're done!

Notes:

Of course, instead of using the distance formula, you can also just count :)