I NEED HELP PLEASE THANK YOUUU

Answer:

d is the answer.........

Answer:

30

Explanation:

I believe it's 30 because half of 24 is 12 and that is its half life. And as you know it took 30 minutes to get there.

Answer:

Fe(NO3)3 + 3 NaOH ===》Fe(OH)3 + 3 NaNO3

Answer:

3.1x10^24 it will be in 1 kg of platinum

Answer:

they causes climate change by trapping heat and also they contribute to respiratory diseases from smog and air pollution

Answer:

They add C02 to our atmosphere which can give plants and soils more CO2. It can also make our earths temperature change a ton!

Explanation:

Greenhouse gases produce an increase in the average surface temperature of the earth over time.

Answer:

If the atmospheric pressure is lower than 760 torr, then the boiling temperature will be less than 100equationC.

B. 97.7°C

Explanation:

The question mentions the fact that temperature and pressure are directly proportional. This means that if one quantity is increasing the other increases simultaneously and vice versa.

Hence, if the atmospheric pressure is lower than 760 torr, then the boiling temperature will be less than 100equationC.

From;

PαT

P=kT

Hence

P/T = k

P1/T1 = P2/T2

P1T2 = P2T1

P1 =  760 torr

T1 = 94°C

T2 = ?

P2 = 790 torr

T2 =  P2T1/P1

T2 = 790 * 94/760

T2 = 97.7°C

Answer:

~0.0004

Explanation:

[tex]n=\frac{m}{M}[/tex]

n=0.072/(56+(35.5*3))=0.072/162.5~~0.004

Answer:

c. 5days

Explanation:

there is no question but if it's a graph

the answer is 5days

Answer: your question is easy 21 L

By using ideal gas law the amount of volume will be 21 L.

The general gas equation, commonly known as the ideal gas law, is the state equation of a hypothetical ideal gas.

Calculation of volume by using ideal gas law.

Given data:

P = 5.1 atm

n = 3.7 moles

T = 75°C (273 + 75) = 348 K

V = ?

Put the given data in ideal gas law.

PV = nRT

V = nRT / P

V = 3.7 × 8.31 × 348 / 5.1

V = 2098

V = 21 L

Therefore, By using ideal gas law the amount of volume will be 21 L.

To know more about ideal gas law.

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A 1.26 g sample of He gas has a pressure of 0.123 arm and a volume of 32.6 L, then the temperature of the gas is -117.7 degree C.

Temperature of any gas will be calculated by using the ideal gas equation as:

PV = nRT, where

P = pressure of gas = 0.123 atm

V = volume of gas = 32.6 L

R = universal gas constant = 0.082 L.atm / K.mol

T = temperature of gas = ?

n is moles of He gas and will be calculated as:

n = W/M, where

W = given mass = 1.26g

M = molar mass = 4 g/mol

n = 1.26 / 4 = 0.315 moles

On putting values we get,

T = (0.123)(32.6) / (0.315)(0.082)

T = 155.41 K = 155.41 - 273.15 = -117.7 degree C

Hence required temperature of the helium sample is -117.7 degree C.

To know more about ideal gas equation, visit the below link:

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Answer:

I kinda forgot. I'm sorry if I didn't answer your question.

Explanation:

Answer:

Molarity of HCl = 1.6M

Explanation:

The chemical reaction equation is;

HCl(aq) + NaOH(aq) —> NaCl(aq) + H2O(l)

Now, molarity = number of moles/volume

Thus, for NaOH, we have;

Number of moles = molarity × volume = 2M × (20/1000) L

Number of moles = 0.04 moles

Using the coefficients in the chemical equation above, we can find the corresponding number of moles for HCl.

Number of moles of HCl = 0.04 moles NaOH × (1 mole of HCl/1 mole of HCl) = 0.04 moles of HCl

Thus;

Molarity of HCl = 0.04/(25/1000)

Molarity of HCl = 1.6M

Answer:

H2O

Explanation:

EASIEST FORMULA ON EARTH

Answer:

This lifespan began roughly 4.6 billion years ago, and will continue for about another 4.5 – 5.5 billion years, when it will deplete its supply of hydrogen, helium, and collapse into a white dwarf.

Explanation:

Got this from the internet lol

Answer:

you would more than likely have hot coca.  

Explanation:

Because when its cold out you don't want something cold, its common sense  lol.

Answer:

a) pathogen

b) virus

Explanation:

pathogens are harmful bacteria

viruses depend on the host to survive

Answer:

Beta oxidation of the odd chain heptanoic acid will produce propionyl CoA, which can be converted in several steps to oxaloacetate. Oxaloacetate is the starting material for the process of gluconeogenesis (producing glucose from noncarbohydrate precursors). This gives extra glucose to the first group, so they will be healthier and gain weight. Beta oxidation of the even chain will entirely be oxidized to acetyl Co-A (one of the precursors of the TCA cycle). This will lead to a large excess of ketone bodies instead of glucose for energy, which will lead to the second group being weak and losing weight.

Explanation:

The difference is seen in having an odd chain and an even chain of fatty acids and how they are broken down and used in the body.

Answer:

The alkali metals/group 1 are recognized as a group and family of elements. These elements are metals. Sodium and potassium are examples of elements in this family. Hydrogen is not considered an alkali metal because the gas does not exhibit the typical properties of the group. The largest family of elements consists of transition metals/group 3-12/group 3a. The center of the periodic table contains the transition metals, plus the two rows below the body of the table (lanthanides and actinides) are special transition metals. Even though both are metals, transition metals have higher melting points; they have higher density; they are less reactive with water; they react and form ions with different charges, but Group 1 metals only form 1+ ions. (Hope the is helpful! You can reword it if you want...)

Answer:

net force is 80n ‐40n=40newton

the direction of motion is right

Answer:

There is actually 1 mole in 54.3 g of CO2

Answer:

A methane molecule is made from one carbon atom and four hydrogen atoms. Carbon has a mass of 12.011 u and hydrogen has a mass of 1.008 u. This means that the mass of one methane molecule is 12.011 u + (4 × 1.008u), or 16.043 u. This means that one mole of methane has a mass of 16.043 grams.

メタン分子は、1つの炭素原子と4つの水素原子から作られています。炭素の質量は12.011uで、水素の質量は1.008uです。これは、1つのメタン分子の質量が12.011 u +（4×1.008u）、つまり16.043uであることを意味します。これは、1モルのメタンの質量が16.043グラムであることを意味します。^>^

The mass of 0.10 mole of methane (CH4) is 1.6grams.

The mass of a substance can be calculated by multiplying the number of moles of the substance by its molar mass. That is;

mass = moles × molar mass

According to this question, there are 0.10 mole in methane (CH4). The molar mass of CH4 is 16g/mol.

Mass of CH4 = 0.10 × 16

Mass of methane = 1.6grams.

Therefore, the mass of 0.10 mole of methane (CH4) is 1.6grams.

Learn more about mass at: https://brainly.com/question/19694949

Answer:

63.58 g O

Explanation:

To calculate the mass of O atoms, the number of moles of O atoms are needed and can be calculated as follows:

n (no. of moles) = nA ÷ 6.02 × 10^23

n = 2.393 x 10^24 ÷ 6.02 × 10^23

n = 0.398 × 10^ (24-23)

n = 0.398 × 10^1

n = 3.98moles.

To calculate the mass of Oxygen, we use the following formula:

moles = mass/molar mass

Molar mass of O = 16.

3.98 = m/16

m = 3.98 × 16

m = 63.68grams of Oxygen.

Answer:

Solution given:

[tex]1 mole \:of O=6.023×10^{23} atoms[/tex]

1 mole of O =16g

we have

[tex] 6.023×10^{23} atoms\: of O=16g[/tex]

now

[tex] 2.393 × 10^{24} atoms\: of \:O\\=16/6.023×10^{23}*2.393 x 10^{24}g\\=63.57g[/tex]

63.57g is a required mass of O.

Answer:

I think its the last one

Explanation:

Super sorry if its incorrect.

Explanation:

Common Compounds of Niobium Nb

[Nb+3, Nb+5]

Compound NameFormulaMolar Mass

Niobium(III) OxideNb2O3233.811

Niobium(III) SulfateNb2(SO4)3474.0006

Niobium(V) PhosphateNb3(PO4)5753.576

Niobium(V) BromideNbBr5492.4264

Niobium(V) PentoxideNb2O5265.8098

Niobium OxychlorideNbOCl3215.2648

Niobium(V) IodideNbI5727.4287

Niobium(V) PentachlorideNbCl5270.1714

Niobium(V) ThiocyanateNb(SCN)5383.3184

Niobium(III) ChlorideNbCl3199.2654

Niobium(V) Dihydrogen PhosphateNb(H2PO4)5577.84259

Niobium NitrideNbN106.9131

Niobium(III) DichromateNb2(Cr2O7)3833.77676

Niobium HydroxideNb(OH)3143.9284

Niobium(V) PerchlorateNb(ClO4)5590.15938

Niobium(V) HypochloriteNb(ClO)5350.16838

Niobium(III) HypochloriteNb(ClO)3247.26358

Niobium(V) CarbonateNb2(CO3)5485.85726

Niobium(III) TartrateNb2(C4H4O6)3630.02564

Niobium(III) ChromateNb2(CrO4)3533.79386

Niobium(V) HexafluorosilicateNb2(SiF6)5896.192356