I Need Help Please And Thank You.

Answer: I thin The first one 2r+3r+9

Step-by-step explanation: Because he scored a number of 2 port shots which means he scored more than one but the 9 points is just 9 points from free throws which gives only 1 point each and 3 port shots and much as 2 point shots so 3r also

2r+3r+ just 9

T probability of rolling doubles after 45 tosses is 0.156

To do this, we enter the data values in a graphing calculator.

From graphing calculator, we have the following summary:

The regression equation is

y = bx + a

Where

b = SP/SSX = 1375/8250 = 0.16667

a = MY - bMX = 8.7 - (0.17*55) = -0.46667

So, we have:

y = 0.16667x - 0.46667

Approximate

y = 0.167x - 0.467

When the number of tosses is 45, we have:

y = 0.167 * 45 - 0.467

Evaluate

y = 7.048

Approximate

y = 7

45 tosses gives 7 doubles.

So, the probability is:

P = 7/45

Evaluate

P = 0.156

Hence, the probability of rolling doubles after 45 tosses is 0.156

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Answer:

x = 32

Step-by-step explanation:

Angle <X and angle <Z is has same measure because they are congruent angles so we can write the following equation:

6x - 60 = 2x + 68 transfer like terms to the same side of the equation

6x - 2x = 68 + 60 subtract/add

4x = 128 divide both sides by 4

x = 32

To find the measure of angle <Z and length of WY replace x with the value we found

WY = 3*32 + 5

WY = 101

m<Z = 2*32 + 68

m<Z = 132

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Equation:}[/tex]

[tex]\mathbf{4t^2 - 2t - s}[/tex]

[tex]\huge\textbf{Solving:}[/tex]

[tex]\mathbf{4t^2 - 2t - s}[/tex]

[tex]\mathbf{= 4(4)^2 - 2(4) - 5}[/tex]

[tex]\mathbf{= 4(4\times 4) - 2(4) - 5}[/tex]

[tex]\mathbf{= 4(16) - 2(4) - 5}[/tex]

[tex]\mathbf{= 64 - 2(4) - 5}[/tex]

[tex]\mathbf{= 64 - 8 - 5}[/tex]

[tex]\mathbf{= 56 - 5}[/tex]

[tex]\mathbf{= 51}[/tex]

[tex]\huge\textbf{Answer:}[/tex]

[tex]\huge\boxed{\textsf{Option B. 51}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

The median in the box plot is: 31

Q1 (lower quartile) = 26

The median is the value at the vertical line that divides the box.

The Q1 (lower quartile) is the value at the beginning of the edge of the box.

Thus, from the given box plot, we have the following:

Median = 31

Q1 (lower quartile) = 26

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Since 2704 = 2⁴ × 13², we need [tex]m = 13[/tex] and [tex]n=2[/tex], since this gives

[tex]\dfrac{2704m}n = \dfrac{2^4 \times 13^2 \times 13}2 = 2^3 \times 13^3 = 26^3[/tex]

The values of m and n that make 2704 × m/n a perfect cube are:

m = 13 and n = 2.

We have,

We can start by factoring 2704, which is 52².

So we have:

= 2704 × m/n

= 52² × m/n

= (2² × 13²) × m/n

For the expression to be a perfect cube, we need all the prime factors to appear in groups of three.

Since 2 and 13 appear only once each, we need to find another factor that appears twice.

Since m and n are both prime, and the fraction m/n is simplified, there are only two possible values for m and n:

m = 2 and n = 13, or

m = 13 and n = 2

Let's try the first case:

2704 × m/n = 2704 × 2/13 = 416

416 is not a perfect cube, so this case does not work.

Now let's try the second case:

2704 × m/n = 2704 × 13/2 = 17696

17696 is 28³, which is a perfect cube.

Therefore,

The values of m and n that make 2704 × m/n a perfect cube are:

m = 13 and n = 2.

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The required algebraic expression is Y = 3X + 2

This table describe the  relation between x and y

x =  2  3    4   5      

y =  8  11   14  17

Alegebraic expression consists of constant and variable. eg x, y, z etc.

As the data given in the table, we conclude that:

1) The difference in the values of y is 3.

2) When we multiply this difference by x and add 2 it gives the next value of y.

so the from above discussion Y = 3X + 2

Thus, The required algebraic expression is  Y = 3X + 2

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Helen is incorrect, the pressure decreases by greater than 20% and percent decrease is 23.80%.

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

Pressure before the change:

Area = 20 square cm = 0.002 square meters

P = 70/0.002 = 35000 N/m²

The force is increased by 10 newtons. The area is increased by 10cm²

New pressure = (70+10)/(0.003) = 26,666.667 N/m²

Percent decrease = [(35000 - 26,666.667)/35000]×100

= 23.80% (pressure decrease by 23.80%)

Thus, Helen is incorrect, the pressure decreases by greater than 20% and percent decrease is 23.80%.

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the length of the shorter side is:L  = 13.125cm

In the longer side we have 8 segments.

We know that the side measures 35 cm, then each one of the 8 segments measures:

35cm/8 = 4.375cm

Now, we can see that in the shorter side we have 3 of these segments.

Then the length of the shorter side is:

L  = 3*(4.375cm) = 13.125cm

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Answer:

S = {2, 2, 5, 5, 11}

Step-by-step explanation:

So you can partially build a data set given this information. There is going to be 5 positive numbers and the median is going to be 5 so the data set is going to have 5 in the middle which should look like this

S = {a, b, 5, c, d} where a, b, c, d are the other values. Since it has a mode of 2 and 5 that means that the occurrences of 2 and 5 will be equal, otherwise it would only have 1 mode. and they have to appear at least twice since if they only appeared once, there would either be another mode, or the data set would have 5 modes.

So the data set is going to look like this

S = {2, 2, 5, 5, d}

Now the only thing left to do is calculate d. This is where you use the mean to determine the last value. The mean can be calculated as

(the sum of the data set) / (the amount of values in the data set)

Since we know the mean you can set up an equation to find the value of d

[tex]5 = \frac{2+2+5+5+d}{5}\\5=\frac{14+d}{5}\\25=14+d\\11=d[/tex]

so the last value is 11. This gives you the complete data set of 5 positive integers

S = {2, 2, 5, 5, 11}

Answer:

x = 17deg

Step-by-step explanation:

Let angle y be the unknown angle IN THE TRIANGLE.

Angle y = 180 - 90 - 73

= 17deg

Angle x = Angle y (Alternate angles on 2 parallel lines)

Angle x = 17 deg

Answer:

17° is the answer.

Based on the information given, the bisected angle, quadrilateral, and congruent angles will be explained.

It should be noted that a quadrilateral simply means a closed shape that has four sides and four angles. These include square, rectangle, parallelogram, etc.

A bisected angle simply illustrates a line that splits an angle onto two equal angles.

Congruent segments are the segments that have the same length.

The diagrams are attached accordingly.

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Answer:

A. The sloped graph doesn't represent the verbal description because the slope is 1 hot dog per 4 min

Step-by-step explanation:

B. Option b is valid response of the verbal description because the statements say Katie starts with 3 bonus hotdogs and then eats 4 hotdogs/min. This is the slope-int of the verbal description.

C. &D. When you substitute the table values of x into the slope-int equation, you should get the y-values listed in the table

Hope it helps!

Answer: m=n=3

Step-by-step explanation:

Reflecting across the y=0, in other words, the x-axis, means

[tex](x,y) \longrightarrow (x,-y)[/tex]

So, [tex]p(m,5-n) \longrightarrow p'(m,n-5)=p'(2m-3, 2n-8)[/tex]

This gives us the system

[tex]m=2m-3 \longrightarrow \boxed{m=3}\\\\n-5=2n-8 \longrightarrow \boxed{n=3}[/tex]

The expression of function g(x) is [tex]|\frac {x - 1}2| + 3[/tex]

The function is given as:

[tex]f(x) = |x|[/tex]

When the function is compressed horizontally by a factor of 2, the rule is:

f'(x) = f(x/2)

So, we have:

[tex]f(x) = |\frac x2|[/tex]

When the function is shifted left by 1 unit, the rule is:

f"(x) = f(x + 1)

So, we have:

[tex]f'(x) = |\frac {x - 1}2|[/tex]

When the function is shifted up by 3 units, the rule is:

g(x) = f"(x) + 3

So, we have:

[tex]g(x) = |\frac {x - 1}2| + 3[/tex]

Hence, the expression of function g(x) is [tex]|\frac {x - 1}2| + 3[/tex]

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Answer: 4

Step-by-step explanation:

Step-by-step explanation:

The equation of a circle is usually in the form: [tex](x-h)^2+(y-k)^2=r^2[/tex] where (h, k) is the center and r is the radius. With the information you provided you would have the equation: [tex](x+3)^2+(y-4)^2=16[/tex]. I'm a bit confused by "solve the equation of a circle" do you mean solve for y? if so you would just do

Original Equation:

[tex](x+3)^2+(y-4)^2=16[/tex]

Subtract (x+3)^2 from both sides

[tex](y-4)^2=-(x+3)^2+16[/tex]

Take the square root of both sides

[tex]y-4 = \pm\sqrt{-(x+3)^2+16}[/tex]

add 4 to both sides

[tex]y=\pm(\sqrt{-(x+3)^2+16})+4[/tex]

and then just change the sign to negative or positive depending on what half of the circle you want

Let's take this problem step-by-step:

I will assume that you want the standard form of the equation of the circle:

      ⇒ standard form: [tex](x-h)^2 +(y-k)^2=r^2[/tex]

LEt's plug in the known values

   [tex](x-(-3))^2+(y-4)^2 = 4^2\\(x+3)^2+(y-4)^2=16[/tex]

Answer: (x+3)² + (y-4)² = 16

Hope that helps!

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The angle between the lines joining the origin to the points of intersection of the degenerated elipse and the straight line is approximately 136.635°.

We have the graphs of a degenerated ellipse and a line, which intercept each other at points (x₁, y₁) = (-0.293, 1.121) and (x₂, y₂) = (- 1.707, - 3.121). A representation of the situation is shown in the image attached below.

Now we find the angle between the two lines by dot product:

[tex]\cos \theta = \frac{(- 0.293, 1.121)\,\bullet \,(- 1.707, - 3.121)}{1.159 \,\cdot\, 3.557}[/tex]

[tex]\cos \theta = - 0.727[/tex]

θ ≈ 136.635°

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Answer:

B. 20

Step-by-step explanation:

Cos a = b/c

Cos 53° = b/25

b = 25 × 0,6 = 15

x = √(25² - 15²)

x = √(625 - 225)

x = √400

x = 20

Answer:

50 %

Step-by-step explanation:

i think this is the answer

The solution of the equation is 5477x + 12y = -56

Given the equation;

-8 -48-4y-8y = -x + 5480x

First, we collect like terms

-56 - 12y = 5477x

Collect the numbers with variables together

-56 = 5477x + 12y

Thus, the solution of the equation is 5477x + 12y = -56

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The number which when substituted in a polynomial makes its value zero is called the zero of the polynomial.

The zero of a polynomial can be defined as the points where the polynomial becomes zero as a whole.

In other words, The zeros of a polynomial p(x) are the values of x which satisfy the equation p(x) = 0

For example, the zero of the polynomial f(x) = x³- 12x²+ 20x is  x = 0 or x = 10 or x = 2.

This is because f(x) = o when we substitute those x values.

Therefore, the number which when substituted in a polynomial makes its value zero is called the zero of the polynomial.

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The inequality equation of the lines are given as x + 2y ≤ 5 and 3x + y ≤ 4. Then the correct option is C.

Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

The graph is given below.

From the graph, equation of the lines are given as

x + 2y = 5 and 3x + y = 4

But for the inequality is shown in the graph. Then the inequality equation of the lines are given as

x + 2y ≤ 5 and 3x + y ≤ 4

Then the correct option is C.

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Answer:

[tex](x-5)^2+(y+4)^2=100[/tex]

Step-by-step explanation:

Equation of a circle

[tex](x-a)^2+(y-b)^2=r^2[/tex]

where:

Given:

Substitute the given values into the circle equation and solve for r:

[tex]\implies r^2=(-3-5)^2+(2-(-4))^2[/tex]

[tex]\implies r^2=(-8)^2+(6)^2[/tex]

[tex]\implies r^2=64+36[/tex]

[tex]\implies r^2=100[/tex]

[tex]\implies r=\sqrt{100}[/tex]

[tex]\implies r=10[/tex]

Substitute the given center and the found value of r into the circle equation to create the equation of the circle:

[tex]\implies (x-5)^2+(y-(-4))^2=10^2[/tex]

[tex]\implies (x-5)^2+(y+4)^2=100[/tex]

Answer:

250

Step-by-step explanation:

mp=sp+d%of mp

x = 200+20÷100×x

100x-20x = 20000

x= 250

Step-by-step explanation:

A. ______________________$

Answer:

x=5

Step-by-step explanation:

these two angles are the same so set both equations equal to each other and solve for x.

[tex]23x-5=21x+5\\23x=21x+10\\2x=10\\x=5[/tex]

1. set equations equal to each other

2. add 5 to both sides

3. subtract 21x from both sides

4. divide both sides by 2 to get x alone

5. x=5

The three positive integer that has mean of 5 and range of 10 will be 0, 5, 10.

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

Let the three positive number be (a – d), (a), and (a + d).

Then the mean of the number will be 5. Then we have

5 = (a – d + a + a + d) / 3

5 = (3a) / 3

a = 5

Then the range will be 10. Then we have

(a + d) – (a – d) = 10

   a + d – a + d = 10

                   2d = 10

                     d = 5

Then the three positive integer that has mean of 5 and range of 10 will be 0, 5, 10.

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The attitude of Taylor in the given scenario can be classified as a; Watchdog

From the given narration about Taylor, we can see that she understood the laws applying to whales and knew what the whaling industry would be doing wrong, when they do so.  

Now, considering the fact that Taylor is not old enough to make a difference, politically, she has to tell others and keep an eye out. Thus, with this attitude, we can classify her to be a watchdog

The complete question is;

Taylor, a seventh grader at Juno Middle School, loves whales. She believes it is her duty to understand all laws that apply to the whaling industry and how this will affect the whales. She spends much time researching how officials are or aren't enforcing those laws. Taylor reports her findings to friends and family who can vote.

Taylor would be considered a;

A) watchdog

B) legal representative

C) leader of an interest group

D) member of the media

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:y = x + 3 [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

Calculate slope (m) using two points -

[tex]\qquad \tt \rightarrow \:m = \dfrac{rise}{run} [/tex]

[tex]\qquad \tt \rightarrow \:m = \dfrac{4 - 3}{1 - 0} [/tex]

[tex]\qquad \tt \rightarrow \:m = {1}[/tex]

Y - intercept (c) = 3

[tex] \large\textsf{Equation of line : } [/tex]

[tex]\qquad \tt \rightarrow \:y = mx + c[/tex]

[tex]\qquad \tt \rightarrow \:y = 1(x) + 3[/tex]

[tex]\qquad \tt \rightarrow \:y = x + 3[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞