I need help on this

The net force is 5 N and the class that won is Mrs. Wade's class (Option B)

We can obtain the net force by using the following formula:

Net force = Opposite force - force of pull

Now, we shall determine the net force as illustrated below:

Net force = Opposite force - force of pull

Net force = Mrs. Wade’s class - Mrs. Hankinson’s class

Net force = 105 - 100

Net force = 5 N

From the above calculation, we can say that the net force is 5 N and the class that won given the above data is Mrs. Wade’s class

Therefore, the correct answer to the question is:

5 N, Mrs. Wade's class (Option B)

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it is 20 4×5 trust me i did this for like 30 min

If all pipelines are round and of the same elevation as the question suggests, then point B's gauge pressure is 11.5 KPa.

Distance above water level is known as elevation. Elevations are often expressed in feet or meters. On charts, they can be represented by contour lines that link points of the same elevation, by colours, or by numbers that indicate the precise elevations of specific places on the Planet's surface.

From continuity equation:

Velocity of water at B = (2*pi*3²)/[2*pi*1²] =9 m/s

then from Bernoulli equation;

v² /2 + φ + p/ρ =constant

ρ=1000 kg/m³

3²/2 +φ +50000/1000 = 9²/2 +φ +P/1000

Therefore,

Pressure at B = 11.5 KPa

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The complete question is-

The 3.0 cm-diameter water line in the figure splits into two 1.0 cm-diameter pipes. All pipes are circular and at the same elevation. At point A, the water speed is 2.0 m/s and the gauge pressure is 50 kPa.

What is the gauge pressure at point B?

A spring will therefore need 72 J of work to stretch an additional 4 cm from its equilibrium length if it takes 9 J to stretch it that far.

The length of a multi-mode optical fiber required to achieve a static mode distribution from a particular excitation condition is known as the equilibrium length, and it is sometimes used to characterize stationary mode distributions. There is a location where the weight and spring force are equal in magnitude but in the opposite direction. The equilibrium position is where you are at this moment. There is a net force known as the restoring force that is directed toward the equilibrium position if the mass is in any other position.

F = -kx. The proportional constant k is referred to as the "spring constant". It gauges the stiffness of the spring. When a spring is stretched or compressed to a length that differs by an amount equal to or greater than x, it produces a force F = -kx in the direction of its equilibrium position. From its equilibrium length.

Knowing that the results of the work done to lengthen the springs will be reported as

U=1/2kx

so here we have

9= 1/2 k〖(0.02)〗^2

so we have

K=45000N/m

Now, we must locate the work completed to extend the spring from x = 2 cm to x = 4 cm

here we have

U=1/2 k(x 2/1-x 2/2

now we have

U=1/2(45000)(〖0.06)〗^2-〖0.02〗^2)

U= 72J

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The Hypnotic Induction Profile (HIP) or the eye roll test, first proposed by Herbert Spiegel, is a simple test to loosely determine if a person is susceptible to hypnosis. A person is asked to roll their eyes upward. The degree to which the iris and cornea are seen is measured.

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The acceleration will be 0.2m/s^2 while the velocity will be 1m/s

Force = 300N

Mass = 1500kg

Time = 5 seconds

We know that

Force = ma

a = F/m

a = 300/1500

a = 0.2 m/s^2

Also, the expression for Velocity is given as

Ft = mv

300*5 = 1500*v

Making velocity the subject of the formula we have

1500 = 1500*v

v = 1 m/s

The rate of change of an object's velocity with respect to time is defined as acceleration.

Acceleration implies that the speed is changing, but this is not always the case. When an object moves in a circular path at a constant speed, it is still accelerating because its velocity direction changes.

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The angle measure of angle B = 25° and angle C = 65° and angle D = 25°.

The given parameters are;

The orientation of the two mirrors = At right angle to each other

The laser light is directed at one of the mirror

The measure of angle, A = 25°

The measures of angle B, C, and D are found as follows;

We have;

∠A = ∠B = 25°, by angle of incidence equals angle of reflection

∠B = 25°

∠B + ∠C = 90° by sum of the acute angles of a right triangle

25° + ∠C = 90°

∴ ∠C = 90° - 25° = 65°

∠C = 65°

∠E = ∠C = 65° by angle of incidence equals angle of reflection

∴ ∠E = 65°

Line 'L' is perpendicular to the second mirror, therefore, the angle between line 'L' and the second mirror = 90° = ∠E + ∠D

∠E + ∠D = 90°,  by angle sum property

Therefore;

65° + ∠D = 90°

∴ ∠D = 90° - 65° = 25°

∠D = 25°

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Part A. The midway magnitude of the electric field is 17.2 * 10³ N/C.

Part B. The electric field intensity is 47.17 * 10³ N/C N/C when the wire shape is a circle.

The intensity of an Electric Field

Given this, the wire length is 9.50 cm and the charge density is 125 nC/m.

Part A

The electric field at the wires halfway is

E = q/4πε * 1/ (z(z²/a²+1)¹/²)

Where E is the intensity of the electric field, 8.85*10⁻¹² is the permittivity, z is 5.5 cm, a is the midpoint, 9.5/2 cm, and q is the charge density.

Substituting the value in the above equation

E = 17.2 * 10³N/C

The midway magnitude of the electric field is 17.2 * 10³ N/C

Part B

When the wire is a circle then, the charge density at the wire is

Q = q*l

Q= 1.235 * 10⁻⁸ * 0.095

Q = 1.235*10⁻⁸ C

And to calculate the radius

r = l/2π

r = 9.50/ 2*3.14

r = 1.512cm

r = 0.015m

The electric field density at the midpoint of the circle is,

E = Q/4π * z(z²+r²)¹/² * E

Substituting the values in the above equation, we get

E = 47.17 * 10³ N/C

The electric field intensity is 47.17 * 10³ N/C N/C when the wire shape is a circle.

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Different landforms are created during the process of water erosion, which flows water downhill. Rills, gullies, streams, rivers, tributaries, waterfalls, floodplains, meanders, lakes, and other natural features

What are the names of a river's beginning and end?

The source and mouth of a river are its beginning and closing, respectively. Before they get to the river's mouth, numerous rivers and streams will converge. The smaller streams and rivers are referred to as tributaries.

A river's beginning is at its mouth, correct?

The mouth of a river is where it flows into an ocean, a lake, or another river. River mouths are extremely dynamic places. The flow of a river collects material from the river, debris through bank erosion, and

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The amount of force that hit the wall is 200N.

Force is a physical quantity that denotes ability to push, pull, twist or accelerate a body and which has a direction.

The force can be calculated by multiplying the mass by the acceleration as follows:

Force = mass × acceleration

According to this question, an object of 20kg accelerates at 10 m/s² into a wall. The force applied is as follows:

Force = 20kg × 10m/s² = 200N

Therefore, 200N is the force applied by the object on the wall.

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Average force acting on Purley is -1749m/[tex]s^{2}[/tex].

What is Newton's second law of motion?

According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction. A body's momentum is determined by multiplying its mass by its speed.

Given,

According to newton's second law of motion:

F =ma

Purley's initial speed = 173km/h

Final speed = 0

Distance traveled = 0.66 m

So, [tex]v_{i}[/tex] = 172 km/h × 1 hr/3600 s × 1000m/1km

[tex]v_{i}[/tex] = 48.1 m/s

By using kinematics

[tex]v^{2} f[/tex] = [tex]v^{2} i[/tex] + 2ad

[tex]0^{2}[/tex] = 48.[tex]1^{2}[/tex] + 2a(0.66)

-1.32a = 2309

a= -1749 m/[tex]s^{2}[/tex]

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Answer: 3.81 m/s^2.

Explanation: use the equation for acceleration, which is a = (F - f)/m. In this case, we are given the force applied by Marvin (F), the force of friction (f), and the mass of the dresser (m). Plugging in the given values, we get a = (90 N - 24 N)/(52.8 kg) = 3.81 m/s^2.

The answer to the question is 5.66 feet for the channel's diameter after 2 if it is 12 feet wide at 1.

Simply expressed, upstream activities comprise the discovery and production of petroleum and natural gas, whereas downstream activities relate to the procedures used from the extraction phase until the product is given to the client in the desired shape.

[tex]$$\begin{aligned}& F r_1=\frac{V_1}{\sqrt{g V_1}}=0.5 \text {, or } \sqrt{g Y_1}=2.0 V_1 \\& \text { and } \\& F_{r_2}=\frac{V_2}{\sqrt{g y_2}}=3.0 \text { where } y_2=0.5 y_1 \\& \text { Thus, } \frac{V_2}{\sqrt{0.5 g Y_1}}=3.0 \text {, or } \sqrt{g y_1}=V_2 /(3 \sqrt{0.5}) \\& \text { By equating Eq. (1) and }(2) ; 2.0 V_1=V_2 /(3 \sqrt{0.5}) \\& \text { or } \\& V_2=4.24 V_1\end{aligned}$$[/tex]

However,

[tex]$Q_1=Q_2$[/tex] or [tex]$b_1 y_1 V_1=b_2 y_2 V_2$[/tex]

where [tex]$b=$[/tex] channel width. Thus, with [tex]$b_1=12 \mathrm{ft}$[/tex]

(12ft)y₁(V₁) = b₂(0.5y₁)(4.24V₁) or b₂ = 12ft/0.5(4.24) = 5.66ft

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The complete question is-

In flowing from section 1 to section 2 along an open channel, the water depth decreases by a factor of 2 and the Froude number changes from a subcritical value of 0.5 to a supercritical value of 3.0. Determine the channel width at 2 if it is 12 ft. wide at 1.

The acceleration of the crate is 0 m/s2.

This is because the force applied is equal to the force of friction between the crate and the floor, so the crate is not accelerating. The force of friction is equal to the force applied, and since no acceleration is occurring, the force must be equal to the mass of the crate multiplied by the acceleration of gravity (9.81 m/s2).

This means that the force applied (1 N) is equal to the mass of the crate (27 kg) multiplied by the acceleration of gravity (9.81 m/s2). Therefore, the acceleration of the crate is 0 m/s2.

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Since impulse is defined as a change in momentum, we may conclude that since all autos are based on magnitude, their initial momentum and ultimate momentum are the same. Automobile 6 = Automobile 4>(Automobile 2 = Automobile 3>Automobile 1> Automobile 5

Magnitude is a term used in physics to describe an object's maximal size and direction. Magnitude is a factor that is shared by both scalar and vector quantities. We are aware that by definition, scalar quantities are those with only magnitude. It displays an object's size, direction, or motion in absolute or relative terms. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.

One is roughly 10 times greater than the other if two integers are separated by one order of magnitude. They differ by a factor of around 100 if they are separated by two orders of magnitude. The greater value is less than 10 times the smaller value when two numbers are of the same order of magnitude.

Automobile-1 Mass= 2000kg = 5m/s

Automobile-2 Mass= 1000kg = 10m/s

Automobile-3 Mass= 500kg = 20m/s

Automobile-4 Mass= 4000kg = 5m/s

Automobile-5 Mass= 500kg = 10m/s

Automobile-6 Mass= 1000kg = 20m/s

Since we now understand that each car's momentum is the result of its mass and velocity, we will have

Automobile-1

P₁ = m × v

P₁ = (2000)(5)

P₁ = 2 × 10⁴kgm/s

Automobile-2

P₂ = m × v

P₂ = (1000)(10)

P₂ = 10⁴kgm/s

Automobile-3

P₃ = m × v

P₃ = (500)(20)

P₃ = 10⁴kgm/s

Automobile-4

P₄ = m × v

P₄ = (4000)(5)

P₄ = 2 × 10⁵kgm/s

Automobile-5

P₅ = m × v

P₅ = (500)(10)

P₅ = 10³kgm/s

Automobile-6

P₆ = m × v

P₆ = (1000)(20)

P₆ = 2 × 10⁵kgm/s

Then the momentum is:

Automobile 6 = Automobile 4>(Automobile 2 = Automobile 3>Automobile 1> Automobile 5

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Strain energy is defined as the energy stored in a body due to deformation. The strain energy per unit volume is known as strain energy density and the area under the stress-strain curve towards the point of deformation.

The concept that the information applies to is illustrated below:

Dark matter:

Detected through its gravitational attraction

Has mass

Most common forms of mass in the halo of the Milky way galaxy, likely to consist of subatomic particles.

Dark energy:

Inferred to exist from the measured acceleration of the universe's expansion.

The proposed source of a universal repulsive force.

Dark matter and dark energy:

The universe contains more of this than it contains matter made from atoms.

We do not know what it is made of.

Neither:

Blocks light from stars behind it, 'dark' because it emits only infrared light.

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The correct option is, The distance calculated to each globular cluster was too large, and thus his size for the Milky Way was too large.

What main conclusion did Shapley draw from his measurements of the distances to the globular clusters?
Shapley concluded (and other astronomers have since verified) that the center of the distribution of globular clusters is the center of the Milky Way as well, so our galaxy looks like a flat disk of stars embedded in a spherical cloud, or 'halo,' of globular clusters.

How did Shapley estimate the location of the Sun in the Milky Way?
Harlow Shapley determined the position of the Sun in the galaxy by measuring the distances to 93 globular clusters of stars.

What is a globular star cluster?
Globular clusters are stable, tightly bound clusters of tens of thousands to millions of stars. They are associated with all types of galaxies. Globular clusters are typically much larger than open clusters and are tightly gravitationally bound.

What are the characteristics of the stars in globular clusters?
Globular clusters are densely packed collections of ancient stars. Roughly spherical in shape, they contain hundreds of thousands, and sometimes millions, of stars. Studying them helps astronomers estimate the age of the universe or figure out where the center of a galaxy lies.

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