I need help I don’t understand please help

Answer:

The answer is 2 or A

sorry if wrong

Answer:

The answer is actually 50

Step-by-step explanation:

Based on the given conditions

formulate:

150 × 25% ÷ (1 - 25%)

150 × 0.35 = 37.5

1 - 0.25 0.75

Rewrite the fraction

3750 = 50

75

The value of (8 kg 300 g 120 mg) − (3 kg 500 g 480 mg) is; 4 kg 799 g 640 mg

We want to find the value of;

(8 kg 300 g 120 mg) − (3 kg 500 g 480 mg)

First of all, let us convert all units to kg as;

120 mg = 0.00012 kg

300 g = 0.3 kg

Thus;

8 kg 300 g 120 mg = 8 + 0.3 + 0.00012 = 8.30012 kg

Similarly, converting the second expression;

480 mg = 0.00048 kg

500 g = 0.5 kg

Thus;

3 kg 500 g 480 mg = 3 + 0.5 + 0.00048 = 3.50048 kg

Thus, we have;

8.30012 kg - 3.50048 kg = 4.77964 kg

Breaking down this gives;

4 kg 799 g 640 mg

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The greatest whole possible whole number length of the unknown side is 9 inches.

Let us have:

H = biggest side of the triangle

And let we get  A and B as rest of the two sides.

Then we get:

If

[tex]A^2 + B^2 < C^2[/tex]

then the triangle is acute

Two sides of an acute triangle measure as 5 inches and 8 inches

The length of the longest side is unknown.

We have to find the length of the unknown side

WE know that the longest side of any triangle is a hypotenuse

For an acute triangle we know:

[tex]A^2 + B^2 < C^2[/tex]

Here in this sum,

a = 5 inches

b = 8 inches

c = ?

Substituting we get,

[tex]A^2 + B^2 < C^2\\\\5^2 + 8^2 < C^2\\\\25 + 64= C^2[/tex]

c < 9

Hence, The greatest whole possible whole number length of the unknown side is 9 inches.

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Answer:

[tex]\huge\boxed{\bf\:2\sqrt{5} \:\: units }[/tex]

Step-by-step explanation:

We have a figure given in the shape of a square with a diagonal (x) passing from one edge to another. We need to find the measure of its diagonal if the side of the square is [tex]\sqrt{10}[/tex] units.

We know that, a square has all equal sides. Then, all the sides of the square will be equal to [tex]\sqrt{10}[/tex] units.

Now, let's find the diagonal.

To find the diagonal of a sqaure from one of its sides, we need to know the formula ⟶ Diagonal = side [tex]\bf\:\sqrt{2}[/tex].

By using this formula,

[tex]Diagonal (x)\\= side *\sqrt{2} \\= \sqrt{10} *\sqrt{2}\\ = \sqrt{5*2*2} \\= \boxed{\bf\:2\sqrt{5} \:units}[/tex]

→ The diagonal of the square = 2√5 units.

[tex]\rule{150pt}{2pt}[/tex]

A number is divided in the ratio of 5:9. If the first part is 35, the number will be 7.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

A number is divided in the ratio of 5:9. If the first part is 35, then we need to find the number.​

By unitary method

5x = 35

x = 7

Then the other number will be

9x = 9(7)

= 63

Thus, A number is divided in the ratio of 5:9. If the first part is 35, the number will be 7.

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Answer:

Arrange the following number in descendig otder

hope you can understand

Answer:

[tex] \frac{7}{9} \times 5 \frac{2}{5} = \frac{21}{5} \\ [/tex]

Step-by-step explanation:

[tex]5 \frac{2}{5} = \frac{5 \times 5 + 2}{5} = \frac{27}{5} \\ [/tex]

[tex] \frac{7}{9} \times \frac{27}{5} \\ [/tex]

[tex] \frac{7 \times 27}{9 \times 5} \\ [/tex]

[tex] \frac{7 \times 3}{5} = \frac{21}{5} \\ [/tex]

The total amount paid for the article is Rs2782

The given parameters are:

Article = Rs 2750

VAT = Rs 32

The amount paid is calculated using:

Amount = Article + VAT

This gives

Amount = 2750 + 32

Evaluate

Amount = 2782

Hence, the total amount paid for the article is Rs2782

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The interval which the function is negative is (-∞, -6)

The equation of the function is given as:

[tex]g(x) = \sqrt[3]{x + 6}[/tex]

When the function is negative.

It means that g(x) is less than 0

i.e. g(x) < 0

So, we have:

[tex]\sqrt[3]{x + 6} < 0[/tex]

Take the cube of both sides

x + 6 < 0

Subtract 6 from both sides

x < -6

The above represents a value from negative infinity to -6

i.e.  (-∞, -6)

Hence, the interval which the function is negative is (-∞, -6)

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Answer:

-0.16875 or -27/16

Step-by-step explanation:

multiply whole numbers with denominator and add with numerator then divide

so it turns into (9/2) divided by (-8/3)

then use the keep change flip method

(9/2) x (-3/8)

now multiply

-27/16 or -0.16875

Answer:

FH = 15

Step-by-step explanation:

 G is lying between the point F & H on the line FH.

So, the distance of FH will be given by the sum of distance of FG and GH.

FH  = FG + GH

      = 10 + 5

      = 15

The linear function which computes the total cost C (in dollars) to deliver x cubic yards of mulch is C(x) = 44x + 22

Using the slope-intercept form (y = mx +b),

The delivery charge of $22 is a constant and will represent the y-intercept.

The $44 per cubic yard of mulch will represent the slope.

Therefore,

C(x) = 44x + 22

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The sum of squares of the lengths  of the triangle is 130 and the square of the length of the hypotenuse is 65

This is a triangle with 3 sides and one side is called the hypotenuse which faces one of the angles 90°

Analysis:

distance between two points = [tex]\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }[/tex]

distance AB with coordinates A(-2,4) B(5,0) = [tex]\sqrt{(5 - -2)^{2} + (0 - 4)^{2} }[/tex] = [tex]\sqrt{65}[/tex]

distance AC with coordinates A ( -2,4) C(2,6) = [tex]\sqrt{(2--2)^{2} + (6-4)^{2} }[/tex] = [tex]\sqrt{20}[/tex]

distance BC with coordinates B(5,0)  C(2,6) = [tex]\sqrt{(2-5)^{2} + (6-0)^{2} }[/tex] = [tex]\sqrt{45}[/tex]

sum of squares of the lengths = [tex](\sqrt{45} )^{2}[/tex] + [tex](\sqrt{65}) ^{2}[/tex] + [tex](\sqrt{20}) ^{2}[/tex] = 65 + 45 + 20 = 130

the square of the length of the hypotenuse = 65

In conclusion, the sum of the squares of the three length is 130 and the square of the hypotenuse is 65

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Answer:

Your friends' school and college

(2x² - 3x) / 7 is the quotient of the given division.

Simplifying procedures is one way to achieve uniformity in job efforts, expenses, and time. It reduces diversity and variation that is pointless, harmful, or unneeded. Parenthesis, exponents, multiplication, division, addition, and subtraction are all referred to as PEMDAS. The order of the letters in PEMDAS informs you what to calculate first, second, third, and so on, until the computation is finished, given two or more operations in a single statement.

To divide by a fraction, we can multiply by its reciprocal. So to simplify the expression:

((2x-3)/x ) / (7/x²)

We can multiply the numerator by the reciprocal of the denominator:

((2x-3)/x ) * (x²/7)

Simplifying this expression, we can cancel out the common factor of x in the numerator and denominator:

(2x-3) * (x/7)

Expanding the product:

(2x² - 3x) / 7

Therefore, the quotient of ((2x-3)/x ) / (7/x^2) is (2x² - 3x) / 7.

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The type of quadrilateral shown is called A kite. The symbols on the sides tell us that two pairs of adjacent sides are equal.

A quadrilateral is defined as a closed shape and a type of polygon that has four sides, four vertices and four angles.

Now, from the attached quadrilateral shown, we can say that it is called a Kite. This is because a kite is a quadrilateral that has 2 pairs of equal-length sides and these sides are adjacent to each other.

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Answer:

this is one of systematic sample and correct option is d

Answer:

1/4

Step-by-step explanation:

[tex]\frac{5}{8}[/tex]x[tex]\frac{4}{10}[/tex]

multiply the numerators and denominators

[tex]\frac{20}{80}[/tex]

simplify

cancel the zeros and get 2/8

then simplify to 1/4

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to multiply 5/8 times 4/10.

[tex]\triangle~\fbox{\bf{KEY:}}[/tex]

///\\\\///\\\\////\\\\///\\\///\\\///\\\////\\\///\\\///\\\///\\\//\\\\////\\\\////\\\\///\\\\///\\\///\\\//\\

                                   Multiplying fractions

Multiply the numerator of one fraction times the numerator of the other fraction:

5×4=20

Same with the denominator:

8×10=80

Put them together:

[tex]\pmb{\cfrac{20}{80}}[/tex]

Divide the numerator and denominator by 20:

[tex]\pmb{\cfrac{1}{4}}[/tex]

Hope it helps you out! :D

Ask in comments if any queries arise.

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~Just a smiley person helping fellow students :)

[tex]\bf{\overline{\underline{\overline{\underline{Maribel\:Peri}}}}[/tex]

Answer:

  W = k·n^(-1/2)

Step-by-step explanation:

When two quantities are proportional, their relationship can be described by the linear equation y = kx, where k is the constant of proportionality.

Saying two quantities are inversely proportional is the same as saying one is proportional to the inverse of the other. Then "inversely proportional to the square root" is the same as "proportional to the inverse of the square root."

__

W is inversely proportional to the square root of n, so we have ...

  [tex]W=k\cdot\dfrac{1}{\sqrt{n}} = \dfrac{k}{n^{\frac{1}{2}}}\\\\\boxed{W=kn^{-\frac{1}{2}}}[/tex]

_____

Additional comment

The rules of exponents let us write the square root as a fractional power, and the inverse as a negative power. Thus our power function ends up with a negative fractional power.

The Power function representing the verbal statement is W = k.[tex]n^{1/2}[/tex].

A power function is in the form of f(x) = kxⁿ, where k = all real numbers and n = all real numbers. You can change the way the graph of a power function looks by changing the values of k and n.

When two quantities are proportional, their relationship can be described by the linear equation y = kx, where k is the constant of proportionality.

Now "inversely proportional to the square root" is the same as "proportional to the inverse of the square root."

According to question,

       W α 1/√n

      W = k/√n

      W = k.[tex]n^{-1/2}[/tex]

Thus, the Power function representing the verbal statement is W = k

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The interest that Joanna earned in the first two months is $4.26.

Interest earned in the first month = future value - amount deposited.

Future value = amount deposited x (1 + monthly interest)

Monthly interest = 6/12 - 0.5% = $252.50

Interest = $252.50 = 250 = $2.50

Interest earned in the second monthly = future value of the first month + amount deposited x (1.005)

(252.50 + 100) x 1.005 = 354.26

Interest = 354.26 = 352.50 = $1.76

Total interest = $1.76 + $2.50 = $4.26

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[tex]\text{First term,}~ a = 8\\\\\text{Common ratio,}~ r= \dfrac{32}8 = 4\\\\\text{nth term} = ar^{n-1} \\\\\text{9th term} = 8\cdot 4^{9-1}\\\\\\~~~~~~~~~~~~~=8 \cdot 4^8\\\\\\~~~~~~~~~~~~~=524288\\\\\text{The 9th of the geometric sequence is 525288.}[/tex]

In trigonometry, secant in a right triangle, is the reciprocal of the cosine of an angle symbol: sec while cosine is in a right triangle, is the ratio of the length of the side adjacent to an acute angle to the length of the hypotenuse.

The cosine of an angle is the ratio of the length of the side adjacent to the angle divided by the length of the hypotenuse of the triangle. The cosine of ∠A will be abbreviated as cos ∠A

The secant of x is 1 divided by the cosine of x: sec x = 1 cos x , and the cosecant of x is defined to be 1 divided by the sine of x: csc x = 1 sin x .

Answer:

Step-by-step explanation:

Suppose a right triangle ABC in which

BC=3 units and AC=5 unit and angle B=90 degree

Let x be the missing angle of right triangle

We know that

Hence, there is no difference between using cosine ratio to solve for a missing angle in a right triangle versus using the secant ratio.

The equation written in standard form represents the number of servings of chicken strips and carrots that Will may have eaten is:

x*110 + y*29 = 333

We know that he consumed a total of 333 calories.

There are x chicken strips and y carrots, so we must have that:

x*110 + y*29 = 333

That is the equation in standard form that we must solve to find how many carrots and how many chicken strips he ate.

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Answer:

1) 600cm^3            2) 10 glasses

Step-by-step explanation:

x = total amount in ml

(3/10)x = 180ml (MILK)

x = 600ml

(2/10)600 = 120ml (TIA MARIA)

(1/2)600 = 300ml (VODKA)

1) 600cm^3

2) 600ml : 60ml = 10 (GLASSES)

[tex]~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{4}v^2\stackrel{\stackrel{b}{\downarrow }}{-16}v\stackrel{\stackrel{c}{\downarrow }}{+7}=0 \qquad \qquad v= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ v= \cfrac{ - (-16) \pm \sqrt { (-16)^2 -4(4)(7)}}{2(4)} \implies v= \cfrac{ 16 \pm \sqrt { 256 -112}}{ 8 } \\\\\\ v=\cfrac{16\pm\sqrt{144}}{8}\implies v=\cfrac{16\pm 12}{8}\implies v= \begin{cases} \frac{7}{2}\\[1em] \frac{1}{2} \end{cases}[/tex]

Answer:

There is a moderate positive linear association between the variables

Step-by-step explanation:

Since 0.5<r<0.7, there is a moderate positive linear association between the variables. The closer r is to 1, the stronger the positive linear association.