I dont know how to solve this , I am not familiar with it and am confused.

I Dont Know How To Solve This , I Am Not Familiar With It And Am Confused.

Answers

Answer 1

a) We have to calculate the total reimbursement.

We can list the types of lunches and reimbursements for each:

0. Free lunches: the school served 29,000 free lulnches and will receive $2.68 for each one.

,

1. Reduced-price lunches: the school served 19,000 reduced-price lunchs and will receiv $2.28 for each one.

,

2. Full price lunches: the school seved 51,000 regular-price lunches and will receive $0.25 for each one.

Then, we can calculate the total reimbursement as:

[tex]\begin{gathered} R=29000\cdot2.68+19000\cdot2.28+51000\cdot0.25 \\ R=77720+43320+12750 \\ R=133790 \end{gathered}[/tex]

The lunch reimbursement should be $133,790.

b) The milk reimbursement can be estimated as $0.035 per lunch, so it can be calculated as:

[tex]\begin{gathered} M=(29000+19000+51000)\cdot0.035 \\ M=99000\cdot0.035 \\ M=3465 \end{gathered}[/tex]

The milk reinbursement is $3,465.

c) We can calculate the total reinbursement as the sum of the lunch reinbursement and the milk reinbursement:

[tex]R+M=133790+3465=137255[/tex]

The total reinbursement is $137,255.

d) We can calculate the average reinbursement per lunch dividing the total reinbursement by the number of lunches:

[tex]\frac{T}{L}=\frac{137255}{99000}\approx1.39[/tex]

The average reinbursement is $1.39 per lunch.


Related Questions

Marsha thinks that because 123 is greater than 68, 0.123 must be greater than 0.68. Show and explain why Marsha is incorrect.

Answers

Let's begin by listing out the information given to us:

[tex]\begin{gathered} 123=1\text{0}0 \\ \text{ 20} \\ \text{ 3} \\ 123=1\text{ hundred + 2 tens + 3 units} \\ 68\text{ = 6 (10)} \\ \text{ 8} \\ 68\text{ = 6 tens + 8 units} \end{gathered}[/tex]

To know which is greater between 0.123 To know which i3& 0.68, let's express it in tenth, hundredth & thousandth

[tex]\begin{gathered} 0.123=3\text{ thousandth + 2 hundredth + 1 tenth + 0 unit} \\ 0.123=0.003+0.02+0.1+0 \\ 0.68=\text{ 6 hundredth + 8 tenth + 0 unit} \\ 0.68=0.60+0.08+0 \end{gathered}[/tex]

0.123 has 3 decimal places, which means it is 123/1000

0.68 has 2 decimal places, which means it is 68/100

When you multiply by 100, we have:

0.123 * 100 = 12.3

0.68 * 100 = 68

It becomes very evident that 0.68 is greater than 0.123

Hey can someone please help me with this drag and drop? I’ll give brainliest :)

Answers

Lengths of similar triangles and similar polygons are proportional to each other so, answer to the question in image are-

a. ZY=20

b. X=20.8

c. 9miles

What are similar polygons?

similar polygons are the polygons in which all the corresponding angles are same. Hence, they have same shape. The ratio of sides in any two similar polygons are same. This concept of constant ratio of sides is useful in evaluating the length of sides.

a.    A/a=B/b=C/c = D/d

       WX/HI=ZY/JK

   ZY=20

b.  X=(2.4×39)/4.5

                  X= 20.8

c. If 5cm represents 2miles it implies 1cm represents

1cm=2/5

So, 22.5cm will represent

22.5cm=2/5×22.5

22.5cm=9miles

This means that 22.5cm track represents the distance of 9 miles on map

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An arrow is launched upward with a velocity of 320 feet per second from the top of a 30-foot building. What is the maximum height
attained by the arrow?

Answers

Answer: Maximum height reached is 804.88 m

Step-by-step explanation:

At maximum height velocity is zero

We have equation of motion v² = u² + 2as

    Initial velocity, u = 320 ft/s = 97.536 m/s

    Final velocity, v = 0 m/s    

    Acceleration, a = -9.81 m/s²

    Substituting

                     v² = u² + 2as

                     0² = 97.536² + 2 x  -9.81 x s

                     s = 484.88 m

   So the arrow further a height of 484.88 m

Total height = 320 + 484.88 = 804.88 m

HI there. I need some help with this question. I cannot figure out what the answer is.

Answers

From the question we were given the following:

Area of the square is 19 square units

Area of the circle is 30 square units

Area of intersection is 3 square units.

We are asked to find the area in square units of the entire coloured region.

So,

Are of Square = 19 square units

Are of Circle = 30 square units

Area of Intersection = 3 square units

Area of coloured region = Area of Square + Area of Circle - Area of Intersection

Therefore, Area of coloured region = 19 + 30 - 3

= 46 saqure units.

Ava can run 4/5 of a mile in 4/3 of an hour. How far can she run in 1 hour? *

Answers

Answer:

She can run 3/5 miles in 1 hour

Explanation:

Given that Ava can run 4/5 of a mile in 4/3 of an hour, we want to find how far she can run in 1 hour.

Let x represent the number of miles she can run in one hour.

The statement can be represented in the pair of equations:

[tex]\begin{gathered} \frac{4}{5}miles=\frac{4}{3}\text{hours} \\ \\ x\text{ hour }=1\text{hour} \end{gathered}[/tex]

Using these equations, we have:

[tex]\begin{gathered} \frac{4}{5}=\frac{4}{3}x \\ \\ x=\frac{\frac{4}{5}}{\frac{4}{3}} \\ \\ x=\frac{4}{5}\times\frac{3}{4} \\ \\ =\frac{3}{5} \end{gathered}[/tex]

That is, she can run 3/5 miles in 1 hour

Help Please!
A.
[tex] \frac{3}{4} [/tex]
B.
[tex] \frac{5}{4} [/tex]
C.
[tex] \frac{3}{5} [/tex]
D.
[tex] \frac{4}{5} [/tex]

Answers

This a question my students have problems with

Answer:

Step-by-step explanation:

Soh Cah Toa

S stand for sine, C stand for Cosine and the T stand for Tangent

'o' is the opposite, 'a' stand for adjacent (next to) and h stand for hypotenuse (the longest length of the triangle)

[tex]sin(\theta)=\frac{opposite}{hypotenuse}[/tex]

[tex]cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]

[tex]tan(\theta)=\frac{opposite}{adjacent}[/tex]

We care about angle A and we want sine. So we will use the first equation.

The opposite from A is 3 and the hypotenuse is 5.

[tex]sin(A)=\frac{3}{5}[/tex]

Find an angle θ with 0∘<θ<360∘ that has the same:

Sine function value as 210∘
θ = _____ degrees

Cosine function value as 210∘
θ = ______ degrees

Answers

sin theta = -0.5 degrees

cos theta=-0.86 degrees

hope it helped

A set of data has a mean of 9.6 and a standard deviation of 0.8. What number in the data set would have a z-score of -1.5?

Answers

A set of data has a mean of 9.6 and a standard deviation of 0.8. The number in the data set that would have a z-score of -1.5 is

x =8.4

This is further explained below.

What is the z-score?

The number of normal deviations within which the value of a raw score is either above or below the average value of what is observed or measured is the number that is referred to as the standard score in the field of statistics.

Raw scores that are greater than the mean are assigned positive standard scores, and raw scores that are equal to or lower than the mean are assigned negative standard scores.

Generally, the parameters of the solutionare

[tex]\mu &=9.6 \quad \sigma=0.8 \quad z=-1.5 \\\\z &=\frac{x-\mu}{\sigma} \\\\-1.5 &=\frac{x-9.6}{0.8} \\[/tex]

Where

z=distribution

x=mean

[tex]\sigma[/tex]=standard deviation

u=population mean

Hence, solve for x

x =-1.2+9.6

x =8.4

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If E is the midpoint of DF
with DE = 9x + 24 and
EF = 18x - 39, then find x
and DF.

Answers

Answer:

x=7, DF = 174

Step-by-step explanation:

18x-39=9x+24

9x=63

x=7

:]

4) The measure of one of two supplementary angles is 8 degrees more than three times the other. Find the measure of the larger of the two angles.

Answers

Supplementary angles add 180 degrees.

One of the two angles is 8 degrees more than 3 times the other.

If one of the angles is A and the other is B, then:

[tex]A=8+3B[/tex]

As they are supplementary, they add 180 degrees:

[tex]A+B=180[/tex]

We replace the information of the second equation in the first one and solve:

[tex]\begin{gathered} A=180-B \\ A=8+3B=180-B \\ 8+3B=180-B \\ 4B+B=180-8 \\ 5B=172 \\ B=\frac{172}{5} \\ B=34.4 \end{gathered}[/tex]

Now we can solve for the other angle:

[tex]A=8+3B=8+3(34.4)=8+103.2=111.2[/tex]

The measure of the angles is 34.4 degrees and 111.2 degrees.


In a triple batch of a spice mix, there are 6 teaspoons of garlic powder and 15
teaspoons of salt. Answer the following questions about the mix.

2. How much salt is used with 8 teaspoons of garlic powder

3. If there are 14 teaspoons of spice mix, how much salt is in it.

4. How much More salt is there than garlic powder if 6 teaspoons of garlic powder are use

Answers

The answers of the given questions are:

8 teaspoons of garlic powder are combined with 20 tablespoons of salt.10 teaspoons of salt are included in every 14 teaspoons of spice mixture.If 6 teaspoons of garlic powder are used, there are 15 teaspoons more salt than garlic powder.

What exactly are ratio and proportion?A ratio is an ordered pair of numbers a and b, denoted by the symbol a / b, where b does not equal zero. A proportion is an equation that sets two ratios equal to each other. For example, if there is one boy and three girls, the ratio could be written as: 1: 3 (for every one boy, there are three girls).

Given: There are 6 teaspoons of garlic powder and 15 teaspoons of salt in a triple batch of spice mix.

Let x be the teaspoons of salt.

Salt used with 8 teaspoons of garlic powder:

6/15 = 8/x

x = 20

Therefore, 20 teaspoons of salt is used with 8 teaspoons of garlic powder.

6 + 15 = 21 teaspoons of  spice mix

Salt used in 14 teaspoons of spice mix:

21/15 = 14/x

x = 10 teaspoons of salt.

Therefore, if there are 14 teaspoons of spice mix, 10 teaspoons of salt is there in it.

If 6 teaspoons of garlic powder are used then,

21-6 = 15 teaspoons of more salt is used

Therefore, 15 teaspoons of more salt is there than garlic powder if 6 teaspoons of garlic powder are used.

The answers of the given questions are:

20 teaspoons of salt is used with 8 teaspoons of garlic powder.If there are 14 teaspoons of spice mix, 10 teaspoons of salt is there in it. 15 teaspoons of more salt is there than garlic powder if 6 teaspoons of garlic powder are used.

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√X²+5x+4/X²+8x+16 - X²-3x-4/X²-16

Answers

The expression given as [x²+ 5x + 4]/[x² + 8x + 16] - [x² - 3x - 4]/[x²-16] simplifies to 0

What are expressions?

Expressions are mathematical statements that are represented by variables, coefficients and operators

How to evaluate the expression?

The expression is given as

[x²+ 5x + 4]/[x² + 8x + 16] - [x² - 3x - 4]/[x²-16]

Factorize the expression

So, we have

[x²+ 5x + 4]/[x² + 8x + 16] - [x² - 3x - 4]/[x²-16] = [(x + 4)(x + 1)]/[(x + 4)(x + 4)] - [(x - 4)(x + 1)]/[(x + 4)(x - 4)]

Simplify the common factors

So, we have

[x²+ 5x + 4]/[x² + 8x + 16] - [x² - 3x - 4]/[x²-16] = [(x + 1)]/[(x + 4)] - [(x + 1)]/[(x + 4)]

The terms of the above equation are the same

So, the result of subtracting one from the other is 0

This gives

[x²+ 5x + 4]/[x² + 8x + 16] - [x² - 3x - 4]/[x²-16] = 0

Hence, the value of the expression is 0

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6. The equations of two lines are 6x - y = 2 and 4x - y = -8. What is thevalue of y in the solution for this system of equations?Your answer

Answers

The given system of equations : 6x - y = 2 and 4x - y = -8.

6x - y = 2 ( 1 )

4x - y = -8 ( 2 )

for the value of y, use substitution method:

Solve the equation (1) for y :

6x - y = 2

y = 6x - 2

Susbtitute the value of y in the equation ( 2 )

4x - y = - 8

4x - (6x - 2) = - 8

4x - 6x + 2 = - 8

4x -6x = - 8 - 2

-2x = -10

Divide both side by ( -2)

-2x/(-2) = -10/(-2)

x = 5

Substitute x = 5 in the equation ( 1 )

6x - y = 2

6( 5 ) - y = 2

30 - y = 2

y = 30 - 2

y = 28

So, the value of y is 28

Answer : y = 28

Find the midpoint of the segment with the following endpoints.
(4, 2) and (7, 6)

Answers

The midpoint of the segment with the following endpoints, (4, 2) and
(7, 6) is (5.5, 4).

How to determine the midpoint of a given segment?
The center point of a straight line can be located using the midpoint formula. We can use this midpoint formula to determine the coordinates of the supplied line's midpoint in order to discover its location on a graph. Assuming that the line's endpoints are (x₁, y₁) and (x₂, y₂), the midpoint (a, b) is determined using the following formula:
(a , b) ≡ (((x₁ + x₂)/2), ((y₁ + y₂)/2))

Let the line segment be AB having endpoints as A(4, 2) and B(7, 6);
also let the co-ordinates of midpoint be C = (a, b)
Using the given formula in the available literature,
(a, b) = ((4 + 7)/2, (2 + 6)/2)
Equating parts of the previous equation, we get,
a = (4 + 7)/2 = 11/2 = 5.5
b = (2 + 6)/2 = 4
Thus, the midpoint of the segment is (5.5, 4).

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will give brainlist

Solve the inequality n minus three fifths is less than or equal to negative four sevenths for n.

n is greater than or equal to negative forty one over thirty five
n is less than or equal to negative one over thirty five
n is less than or equal to one over thirty five
n is greater than or equal to forty one over thirty five

Answers

The solution to the given inequality would be n ≤ 1/35 which is the correct answer would be an option (C).

What is inequality?

Inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.

We have to determine the solution of the inequality n minus three-fifths is less than or equal to negative four sevenths for n.

As per the given condition, translate the phrase into an algebraic inequality as :

⇒ n - 3/5 ≤ - (4/7)

⇒ n ≤ 3/5 - (4/7)

⇒ n ≤ (21 - 20)/35

⇒ n ≤ 1/35

Therefore, the solution to the given inequality would be n ≤ 1/35.

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To the nearest tenth of pound Does has need to buy?

Answers

Answer: She needs approximately 142.5 pounds

Explanation:

From the information given,

A pound of fertilizer covers 39 square feet of lawn.

If the lawn measures 5557.4 square feet, then

the number of pounds of fertilizer that she needs to buy = 5557.4/39 = 142.4975

Rounding to the nearest tenth,

She needs approximately 142.5 pounds

Find solutions to the linear equation y=12x+24

Answers

Te solutions to the linear equation given as y = 12x + 24 are (0, 24), (1, 36) and (2, 48)

How to determine the solutions to the linear equation?

From the question, the linear equation is given as

y = 12x + 24

To determine the solutions, we assume values for the variable x and then calculate the y values

Having said that, we have

y = 12x + 24

Set x = 0

So, we have

y = 12 x 0 + 24 = 24

Set x = 1

So, we have

y = 12 x 1 + 24 = 36

Set x = 2

So, we have

y = 12 x 2 + 24 = 48

So, the ordered pairs of the solutions are (0, 24), (1, 36) and (2, 48)

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Simplify the expression √(112x^10 y^13 ). Show your work. please help

Answers

To create the abbreviated expression, combine similar terms by adding them all together. If the expression be [tex]$\sqrt{112 x^{10} y^{13}}$[/tex] then expression exists [tex]$4 \sqrt{7} x^5 y^6 \sqrt{y}$[/tex].

What is meant by an expression?

Solving a math problem is the same thing as simplifying an expression. You basically strive to write an expression as simply as you can when you simplify it. In the conclusion, there shouldn't be any more multiplying, dividing, adding, or removing to do.

Start by recognizing the like terms, or terms with the same variables and exponents, in algebraic formulas. Then, to create the abbreviated expression, combine similar terms by adding them all together.

Let the expression be [tex]$\sqrt{112 x^{10} y^{13}}$[/tex]

separating the roots of the expression, we get

[tex]$\sqrt{112 x^{10} y^{13}}=\sqrt{112} \sqrt{x^{10}} \sqrt{y^{13}}$[/tex]

simplifying the above equation, we get

[tex]$=\sqrt{112} \sqrt{x^{10}} \sqrt{y^{13}}$[/tex]

Simplify [tex]$\sqrt{x^{10}}= x^5$[/tex]

[tex]$=\sqrt{112} x^5 \sqrt{y^{13}}$[/tex]

Simplify [tex]$\sqrt{y^{13}}=y^6 \sqrt{y}$[/tex]

[tex]$=\sqrt{112} x^5 y^6 \sqrt{y}$[/tex]

[tex]$=\sqrt{112}=4 \sqrt{7}$[/tex]

[tex]$=4 \sqrt{7} x^5 y^6 \sqrt{y}$[/tex]

Therefore, the correct answer is [tex]$4 \sqrt{7} x^5 y^6 \sqrt{y}$[/tex].

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A marathon is 46,145 yards (about 26 miles) long. If Terrence has run 23,561 yards, estimate by rounding to thousands the number of yards he needs to run to complete the marathon.Terrence needs to run about ______ yards.

Answers

Given:

The length of the marathon is L= 46,145 yards.

The length covered by terrence is d = 23,561 yrads.

The objective is to find the remaining distance need to cover by terrence.

To calculate the remaining distance, we will use the relation,

[tex]x=L-d[/tex]

On plugging the values in the above relation, we get,

[tex]\begin{gathered} x=46145-23561 \\ =22584\text{ yards} \\ \approx23000\text{ yards} \end{gathered}[/tex]

Hence, Terrence needs to run about 23000 yards.

Find the coefficient of third term of (x + 2)³. A. 40 OB. 10 OC. 20 D. 80 Reset Selection A

Answers

Given:

The expression given is,

[tex]\left(x+2\right)^5[/tex]

Required:

To find the coefficient of the third term.

Explanation:

Let us expand the expression to find the coefficient.

[tex]\begin{gathered} \left(x+2\right)^5 \\ =\frac{5!}{5!}x^52^0+\frac{5!}{4!}x^42^1+\frac{5!}{2!3!}x^32^2+\frac{5!}{3!2!}x^22^3+\frac{5!}{4!1!}x^12^4+\frac{5!}{5!0!}x^02^5 \\ =x^5+10x^4+40x^3+80x^2+80x+32 \end{gathered}[/tex]

Hence, the coefficient of the third term is 40.

Final Answer:

The coefficient of the third term is 40.

Option A is correct.

Starting at sea level, a submarine descended at a constant rate to a depth of −34 mile relative to sea level in 5 minutes.

What was the submarine's depth relative to sea level after the first minute?

Enter your answer as a fraction in simplest form.

Answers

Based on the fact that the submarine's depth was descended to at a constant rate, the submarine's depth relative to sea level with the passing of the first minute was -6⁴/₅ miles

How to find the submarine depth?

The submarine descended at a constant rate to the current depth of -34 miles in 5 minutes. This means that the rate can be found by the formula:
= Current depth / Time

= -34 / 5

= -6.8 miles per minute

After the first minute, the depth is:

= -6.8 x 1

= -6.8 miles

This number in fractions is:

= -6 + 8/10

= -6 + 4 / 5

= -6⁴/₅ miles

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Given H(t)=10-2t^2 , find h^-1 (t), is h (t) one to one ? What does this imply about h^-1(t)

Answers

We have the function:

[tex]H(t)=10-5t^2[/tex]

And we have to find the inverse function.

We can write this as:

[tex]H(H^{-1}(t))=t[/tex]

We can solve this as:

[tex]\begin{gathered} H(H^{-1}(t))=10-2(H^{-1})^3=t \\ 10-2(H^{-1})^3=t \\ 2(H^{-1})^3=10-t \\ (H^{-1})^3=\frac{10-t}{2} \\ H^{-1}=\sqrt[3]{\frac{10-t}{2}}^{} \end{gathered}[/tex]

The inverse function is:

[tex]H^{-1}=\sqrt[3]{\frac{10-t}{2}}^{}[/tex]

The domain of H is all the real numbers, as the domain of H^-1.

if a student scored a 52 on his first test ,make a prediction for his score on the second test .Assume the regression equation is appropriate for the prediction. Round the answer to 2 decimal places.

Answers

Solution

We have the following info given:

x: 75,76, 91, 65,48,75,85,62,51,80,94,43

y: 69, 88, 101, 63, 59, 82, 86, 67, 56, 84, 105, 44

After apply OLS (Ordinary LEast Squares) we got the following regression line:

y= 1.0607x + 0.6442

We want to find the best prediction for a student who scored 52 in the first test so we have this:

y= 1.0607* 52 + 0.6442 = 55.80

Then the best prediction for this case is 55.80

The volume for a rectangular prism is given by the formula V = l · w · h, where l is the length of the prism, w is the width of the prism, and h is the height of the prism.

If the volume of a rectangular prism with a height of 8 inches is 200 cubic inches and the base of the prism is a square, then what is the width of the rectangular prism?
A.
5 inches
B.
12.5 inches
C.
25 inches
D.
40 inches

Answers

If the volume of a rectangular prism with a height of 8 inches is 200 cubic inches and the base of the prism is a square, then the width of the rectangular prism is 5  inches

The volume of the rectangular prism = 200 cubic inches

The height of the rectangular prism = 8 inches

We know the volume of the rectangular prism = l×w×h

Where ls if the length of the base

w is the width of the base

h is the height of the rectangular prism

Given that the base of the prism is a square, then the length of the base is equal to width of the base

Consider

l = w = x

Substitute the values in the equation of volume

x × x × 8 = 200

[tex]x^{2}[/tex] × 8 = 200

[tex]x^{2}[/tex]  = 25

x = 5 inches

Hence, if the volume of a rectangular prism with a height of 8 inches is 200 cubic inches and the base of the prism is a square, then the width of the rectangular prism is 5 inches

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The half life of radium -226 is 1640 years. If a sample contains 200 mg, how many mg will remain after 4000 years?

Answers

[tex]\begin{gathered} The\text{ following function } \\ N=N_oe^{\lambda t}\text{, N=}amount\text{ of radium-226} \\ t=\text{ time} \\ \lambda\text{= constant} \\ \text{Radium -226} \\ \text{half life = 1640 years} \\ U\sin g\text{ last information, we can find the value of }\lambda \\ \frac{N}{N_o}=e^{\lambda t} \\ \\ \ln (\frac{N}{N_o})=\ln (e^{\lambda t}) \\ \\ \ln (\frac{N}{N_o})=\lambda t \\ \frac{N}{N_o}=\frac{1}{2}=0.5 \\ \ln (0.5)=\lambda t \\ \lambda=\frac{\ln(0.5)}{t} \\ \\ \lambda=\frac{\ln(0.5)}{1640} \\ \\ \lambda=-0.000423 \\ Now,\text{ on the case of 200mg of radium -226} \\ N=200e^{-0.000423t} \\ t=4000\text{ years} \\ \\ N=200e^{-0.000423\cdot(4000)} \\ N=36.83 \\ \text{After 4000 years the sample will contain }36.83mg\text{ of radium -226} \end{gathered}[/tex]

I need help with this question but no one is helping me! Can someone please help me​

Answers

Answer:

Step-by-step explanation:

Number of yellow marbles =13

Number of teal marbles  = 13

Two marbles are drawn randomly

Probability that both marbles are teal

Hence the probability that both marbles are teal is 0.026

[tex] \sqrt{25} [/tex]what's the square root

Answers

[tex] \sqrt{25} [/tex] ()

what's the square root ​?

√25 = 5

because 5*5= 25

[tex]\sqrt[]{5\cdot5}=\sqrt[]{5^2}=\text{ 5}[/tex]

________________________

Answer

√25 = 5

Round to the answer to the nearest tenth.18. A 24-foot ladder leaning against a building forms an 18° angle with the side of the building,How far is the base of the ladder from the base of the building?

Answers

In order to solve this problem, first let's draw the corresponding image to the problem:

Then, to calculate the distance x, we can use the sine relation of the angle of 18°.

The sine relation is the length of the opposite side to the angle over the length of the hypotenuse.

So we have:

[tex]\begin{gathered} \sin (18\degree)=\frac{x}{24} \\ \text{0}.309=\frac{x}{24} \\ x=24\cdot0.309 \\ x=7.42 \end{gathered}[/tex]

So the distance wanted is 7.42 ft.

What’s 2,0000000 +3000,00000

Answers

In order to add these two numbers, we need to add the algarisms that are in the same position.

Since the first number has 7 zeros and the second one has 8 zeros, the numbers 2 and 3 will not be added, since they are in different positions (the number 3 has more "value", since it's in a higher position).

So, adding these two numbers, we have:

Therefore the result of this sum is 320,000,000 (three hundred and twenty million).

Use Heron's Area Formula to find the area of the triangle. (Round your answer to two decimal places.) A = 81°, b = 76, c = 39

Answers

First, let's find the measure of the third side, using the law of cosine:

[tex]\begin{gathered} a^2=b^2+c^2-2bc\cdot\cos(A)\\ \\ a^2=76^2+39^2-2\cdot76\cdot39\cdot\cos81°\\ \\ a^2=5776+1521-927.34\\ \\ a^2=6.369.66\\ \\ a=79.81 \end{gathered}[/tex]

Now, let's use Heron's formula to calculate the area:

[tex]\begin{gathered} p=\frac{a+b+c}{2}=97.405\\ \\ A=\sqrt{p(p-a)(p-b)(p-c)}\\ \\ A=1463.75 \end{gathered}[/tex]

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