Chemistry College

How to solve question 2A and 2B

Answers

Answer 1

2A. The mole of HCl used is 3.2 moles

2B. The moles of each product produced as:

3.2 moles of NaCl3.2 moles of CO₂3.2 moles of H₂O

A. How do i determine the mole of HCl used?

The mole of HCl used can be obtained as follow:

NaHCO₃ + HCl -> NaCl + CO₂ + H₂O

From the balanced equation above,

1 mole of NaHCO₃ reacted with 1 mole of HCl

Therefore,

3.2 moles of NaHCO₃ will also react to 3.2 moles of HCl

Thus, the number of mole of HCl used is 3.2 moles

2B. How do i determine the mole of each product?

The mole of each product produced can be obtain as shown:

For NaCl

NaHCO₃ + HCl -> NaCl + CO₂ + H₂O

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of NaCl

Therefore,

3.2 moles of NaHCO₃ will also react to produce 3.2 moles of NaCl

Thus, the mole of NaCl produced is 3.2 moles

For CO₂

NaHCO₃ + HCl -> NaCl + CO₂ + H₂O

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂

Therefore,

3.2 moles of NaHCO₃ will also react to produce 3.2 moles of CO₂

Thus, the mole of CO₂ produced is 3.2 moles

For H₂O

NaHCO₃ + HCl -> NaCl + CO₂ + H₂O

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of H₂O

Therefore,

3.2 moles of NaHCO₃ will also react to produce 3.2 moles of H₂O

Thus, the mole of H₂O produced is 3.2 moles

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Related Questions

1. Using a graduated cylinder, measure out 50 mL water (H2O) and pour it in a 100 mL beaker 2. Using a balance, measure out 5 g of glucose (C6H12O6) 3. Pour the 5 g of glucose into the 50 mL of water 4. Stir the contents of the beaker using a glass rod 5. Using tweezers, count out 15 pieces of iron (Fe) filings 6. Add the iron filings to the beaker 7. Stir the contents of the beaker using a glass rod During which step(s) was the student handling a pure substance? Responses A Steps 1 and 3Steps 1 and 3 B Step 4 onlyStep 4 only C Steps 1, 2, and 5Steps 1, 2, and 5 D Steps 6 and 7Steps 6 and 7

Answers

The step during which the student handling pure substance is : B.) Step 4 only.

During which step was the student handling pure substance?

In step 4, student added 5 grams of glucose to 50 mL of water, which is a pure substance. Glucose is a compound with the chemical formula C₆H₁₂O₆, and it is a pure substance because it consists of only one type of molecule.

In steps 1, 2, and 5, student was handling water, glucose, and iron filings respectively, but these are not pure substances in those steps because they are mixed with other substances or impurities.

In steps 6 and 7, the student added iron filings to beaker and stirred the mixture, but iron filings are not pure substance either because they may contain impurities or other metals in addition to iron.

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Plants go through seasonal changes from summer to fall because temperatures ___________. A: begin to cool daylight hours decrease.
B: begin to cool and daylight hours in increase.
C: warm up in daylight hours decrease.
Or D: warm up, and daylight hours increase.
30 POINTS IF YOU ANSWER THIS QUESTION ALSO, I HAVE 15 MINS
Also, there’s no science so I picked “ chemistry”

Answers

A: begin to cool and daylight hours decrease.

Plants go through seasonal changes from summer to fall because of the changes in temperature and the length of daylight hours. As summer ends and fall begins, temperatures begin to cool down and the days become shorter. This change in temperature and daylight hours triggers physiological changes in plants, such as the slowing down of growth and the production of pigments like anthocyanins, which give leaves their characteristic red and orange colors in the fall. These changes allow the plant to prepare for the colder winter months and conserve energy for the upcoming spring growth season.

Answer:

a. begin to cool and daylight hours decrease

hope this helps ;)

Faculty of Science
Department of Chemistry
8/2019 SECOND SEMESTER EXAMINATIONS
351 STATISTICAL MECHANICS AND THERMODYNAMICS
INSTRUCTIONS: Answer any FOUR questions.
Pluck's constant, h: 6.26 x 1034 J.S
zmann constant, k: 1.38 x 10 JK
nic mass Unit, amu: 1.661 x 10-kg
Nag
3Higi
C₂ (N₂) = 27.9 +0.00418T JK mol
C₂ (H₂) = 29.6+0.00231T JK 'mol
C₂ (NH) 29.9+0.00261T JK 'mol"¹
Gas constant, R: 8.314 JK mol
Avogadro constant, L: 6.022 x 10 mol
Speed of light, C: 2.998 x 10" ms¹¹
1. (a) Deduce the translational, rotational and vibrational mode of motion for the following
molecules: (i) NHs (ii) CO₂ (iii) CH.
(b) Calculate the enthalpy change at 800 °C for the reaction:
2NH
اله
November, 2019
UNIT: 4
Time allowed: 3hrs
All 92.2 kJ/mol
=
2. (a) Sate the equipartition law of energy.
(b) Apply the classical theory in calculating the expected heat capacity at constant pressure
for H₂ and Cl2 molecule given that the experimental value for H₂ is 28.86 JK 'mol and that
of Cle is 34.51 JK 'mol Explain the variation in these values.
(b) What will be the C₂ for a monoatomic gas?

Answers

(a) (i) NH3: Translational, rotational, and vibrational modes of motion.

(ii) CO2: Translational and vibrational mode of motion.

(iii) CH4: Translational, rotational, and vibrational modes of motion.

What is a Vibrational Mode of Motion?

This simply refers to the oscillatory movement of a physical system around its equilibrium position. This phenomenon is characterized by a complex interplay of forces and energy transfer mechanisms, which can lead to a wide range of intriguing dynamical behaviors.

The part b of the first question, the reaction given is incomplete, and the products are missing. Please provide the complete balanced chemical equation for the reaction so that the enthalpy change can be calculated.

Answers

There are approximately 3.59 x [tex]10^{25}[/tex] molecules of [tex]CO_{2}[/tex] in 59.7 moles of [tex]CO_{2}[/tex].

What is Molecules?

Molecules are the smallest units of a chemical compound that retain the chemical properties and characteristics of that compound. They are composed of two or more atoms chemically bonded together. Molecules can be made up of atoms of the same element (as in diatomic molecules like oxygen gas, [tex]O_{2}[/tex]) or different elements (as in water,[tex]H_{2}O[/tex]which consists of two hydrogen atoms and one oxygen atom).

The term "59.7 molecules of [tex]CO_{2}[/tex]" is not a meaningful unit, as molecules are discrete entities and cannot be divided into fractions. However, assuming you meant to ask for the number of molecules in 59.7 moles of [tex]CO_{2}[/tex], we can use Avogadro's number to calculate it.

Avogadro's number is approximately 6.022 x [tex]10^{23}[/tex]molecules/mol, and it represents the number of entities (such as atoms, ions, or molecules) in one mole of a substance.

Given that you have 59.7 moles of [tex]CO_{2}[/tex], we can multiply this value by Avogadro's number to obtain the total number of molecules:

59.7 moles [tex]CO_{2}[/tex] x 6.022 x [tex]10^{23}[/tex] molecules/mol ≈ 3.59 x [tex]10^{25}[/tex] molecules of [tex]CO_{2}[/tex]

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Amount of CuO formed when 63.5 g of copper is heated strongly in air is:

Answers

Amount of Cuo formed when 63.5g of copper is heated strongly in air is
A:The mass of CuO formed when 63.5g of Copper is heated strongly in air is 79.5g

1.How do we determine the mass of Cuo formed ?

For that we have to write the balenced equation of the reaction and it is given below

2Cu + O2 -----> 2CuO

We have to determine mass of Cuo formed from the reaction

Molar mass of Cu = 63.55 g/mol

Mass of Cu from balenced equation = 2*63.55 = 127.1 g

Molar mass of CuO = 79.55 g/mol

Mass of Cuo from balenced equation = 2*79.55 = 159.1g

From balenced equation 127.1g of Cu reacted to form 159.1 g of CuO

Thus ,63.5 g of Cu will react to form = (63.5*159.1)/127.1 = 79.5 g

Mass of CuO formed is 79.5 g

2.How do you find the mass of a compound produced ?

Multiply atomic weight from periodic table of each element by the number of atoms of that element present in the compound . Add it all together and put units of grams/mole after the number

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Question 4 (1 point)

Members of the alkaline earth elements have several things in common.

They are metalloids with two valence electrons.

metals that are not very reactive.

nonmetals and are nonreactive.

metals with two valence electrons.

Answers

Answer:

Explanation:

Alkaline earth elements are a group of six chemical elements in group 2 of the periodic table. They are beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra). These elements have very similar properties: they are all shiny, silvery-white, somewhat reactive metals at standard temperature and pressure.

The correct statement about alkaline earth elements is that they are metals with two valence electrons. They readily lose these two electrons to form cations with a charge of +21.

Using the Ideal Gas equation, if the number of moles is constant, as pressure and volume increase temperature will __________.

Answers

Explanation:

Ideal gas law

PV = n R T If P and V increase then T must increase

( n and R are constant)

5. It is important to make certain that there is no air bubble in the tip of the burette below the stopcock before the initial reading of the liquid level in the burette is taken. If a 0.5ml air bubble is present in the tip of a burette, what percent error in 5-mL, 20-mL, and 25-mL samples will result if the air bubble is dislodged during the dispensing of the samples?

Answers

Answer:

If a 0.5 mL air bubble is present in the tip of a burette, the initial reading will be too high by 0.5 mL. If the air bubble is dislodged during the dispensing of the samples, the final reading will be too low by 0.5 mL. This will result in a systematic error in the volume measurements.

To calculate the percent error in the volume measurements, we can use the formula:

% error = (systematic error / true value) x 100

For a 5-mL sample, the true value is 5 mL. If the air bubble is dislodged, the measured volume will be 4.5 mL, resulting in a systematic error of 0.5 mL. Therefore, the percent error is:

% error = (0.5 / 5) x 100 = 10%

For a 20-mL sample, the true value is 20 mL. If the air bubble is dislodged, the measured volume will be 19.5 mL, resulting in a systematic error of 0.5 mL. Therefore, the percent error is:

% error = (0.5 / 20) x 100 = 2.5%

For a 25-mL sample, the true value is 25 mL. If the air bubble is dislodged, the measured volume will be 24.5 mL, resulting in a systematic error of 0.5 mL. Therefore, the percent error is:

% error = (0.5 / 25) x 100 = 2%

So, the percent error in the volume measurements will be higher for smaller samples, and lower for larger samples.

Final answer:

The percent error for a 5 mL sample is 10%, for a 20 mL sample is 2.5%, and for a 25 mL sample is 2%.

Explanation:

The percent error can be calculated using the formula:

Percent Error = ((Actual Value - Experimental Value) / Actual Value)×100%

In this case, the actual value is the volume of the sample (5 mL, 20 mL, or 25 mL) and the experimental value is the volume obtained if the air bubble is dislodged.

The percent error for a 5 mL sample would be:

Percent Error = ((5 mL - 4.5 mL) / 5 mL ) ×100% = 10%

The percent error for a 20 mL sample would be:

Percent Error =( (20 mL - 19.5 mL) / 20 mL) ×100% = 2.5%

The percent error for a 25 mL sample would be:

Percent Error = ((25 mL - 24.5 mL) / 25 mL) × 100% = 2%

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A sealed container holds 12.0 L of gas
at 2.5 atm pressure. A valve is opened
any some gas escapes. What happens
to the pressure in the container?
A. The pressure remains the same.
B. The pressure increases.
C. The pressure decreases.

Answers

A sealed container holds 12.0 L of gas at 2.5 atm pressure. A valve is opened and some gas escapes. The pressure decreases. Option C is correct.

When a valve is opened in a sealed container of gas, some of the gas molecules inside the container escape.

This means that the total number of gas molecules inside the container decreases, which in turn causes the pressure to decrease. This can be explained by the ideal gas law.

If some gas escapes from the sealed container, the number of gas molecules inside the container decreases.

As a result, the pressure inside the container decreases as well.

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How much of the reagent is left over?

Answers

31.5 g of Sulfuric acid can be produced from the given amounts of Sulfur trioxide and Water.

Why does Sulfur trioxide not dissolve in water but does in Sulfuric acid?

Option 'c' is the right response to this question because sulphur trioxide cannot be directly dissolved in water to create sulphuric acid because doing so produces a thick fog of the acid that is difficult to condense.

Sulfur trioxide + Water → Sulfuric acid

moles of Sulfur trioxide = mass/molar mass = 25.7 g / 80.06 g/mol = 0.321 mol

moles of Water = volume x density/molar mass = 12.7 mL x 1.00 g/mL / 18.02 g/mol = 0.705 mol

The amount of Sulfuric acid that can be produced is equal to the number of moles of Sulfur trioxide, which is 0.321 mol. To convert this to grams, we multiply by the molar mass of Sulfuric acid:

mass of Sulfuric acid = moles of Sulfuric acid x molar mass = 0.321 mol x 98.08 g/mol = 31.5 g

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Why is the sky blue? Explain with good explanation

Answers

The sky appears blue to us because of a phenomenon known as Rayleigh scattering.

Sunlight is made up of many different colors, each with a different wavelength. When sunlight enters Earth's atmosphere, the shorter blue wavelengths are scattered more easily than the longer red wavelengths. This is because the blue light interacts more with the molecules in the air, causing it to be redirected in many different directions.

As a result, when we look up at the sky, we see the blue light being scattered in all directions, giving the sky its blue color. At sunrise and sunset, when the sun is closer to the horizon, the light has to pass through more of the atmosphere, causing more of the blue light to be scattered away and leaving behind the longer red wavelengths, which gives the sky a reddish or orange hue.

Find ΔE for the change in state of 1.0 mol H2O (l) at 79∘C to H2O(g) at 114 ∘C. The heat capacity of H2O(l) = 75.3 J/molK, the heat capacity of H2O(g) = 25.0 J/molK, and the heat of vaporization of H2O is 40.7×103J/mol at 100 ∘C.

Answers

The energy change for the change in state of 1.0 mol H2O (l) at 79∘C to H2O(g) at 114∘C is 42,643 J/mol.

What are heat capacity and specific heat?

The heat capacity of a thing is the amount of energy needed to raise its temperature by one degree Celsius. The amount of energy needed to increase the temperature of 1 gram of a substance by 1oC is known as a substance's specific heat.

We have to calculate the power needed to warm one mole of liquid water from 79∘C to 100∘C:

q1 = nCΔT

= (1.0 mol)(75.3 J/molK)(100-79 K)

= 1593 J

we have to calculate the energy,

q2 = nΔHvap

= (1.0 mol)(40.7×10^3 J/mol)

= 40,700 J

Now, we have to calculate the energy,

q3 = nCΔT

q3 = (1.0 mol)(25.0 J/molK)(114-100 K)

q3 = 350 J

The total energy change is:

ΔE = q1 + q2 + q3

ΔE = 1593 J + 40,700 J + 350 J

ΔE = 42,643 J/mol

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Monster comes in cans that contain 460 mL of the drink. Use your conversion factor above to calculate the amount of caffeine (in mg) in one can of Monster.

Answers

The amount of caffeine in a 16 fl oz can of Monster's Energy Drink is roughly 160 mg, which is regarded as a moderate dose. Caffeinated than the typical coffee drink, which has between 95 and 200 mg per serving.

A Monster can contains how many mg?

How so much caffeine is there in a complete can of Monster. Each 16-ounce can of Monster Energy has a whooping 160 mg of caffeine, more than double the amount in an 8-ounce Red Bull can and up to than double amount commonly encountered in an average coffee drink.

300 mg of caffeine—is that a lot?

What Much of Coffee Is Recommended. Caffeine does not have negative effects on healthy adults when used in moderation, like many other meals, according to Karolin. 300 mg or less per day, or roughly three 8-ounce cups of coffee, is considered a moderate quantity.

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I WILL GIVE 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE

Answers

The solution has a molarity of 0.0924 M.

What is molarity, for instance?

The number of moles of solute per litre of solution is known as molarity.. For instance, water is both the solution and the solute when table salt is dissolved in it. Each mole of sodium chloride weighs 58.44 grammes. 58.44 grammes of sodium chloride are dissolved in one litre of water to produce one molar solution, or 1M.

Moles of solute per litre of solution is known as molarity (M).

Given: moles of NH3 = 0.355, volume of solution = 3.84 L

Molarity = 0.355 moles / 3.84 L = 0.0924 M

Therefore, the molarity of the solution is 0.0924 M.

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use the balance equation for the haber process, repeated below N2(g)+3H2(G)=2NH3(G)
How many moles of ammonia are produced when 5.0 moles of hydrogen reacts with excess nitrogen

Answers

The moles of the ammonia that is produced is 3.33 moles.

What is the number of moles?

Stoichiometry is an important tool in chemical analysis, and it is used in a wide range of industries, including pharmaceuticals, materials science, and environmental science.

The balanced reaction equation in this case can be given as;

[tex]N_{2} (g)+3H_{2} (g)--- > 2NH_{3} (g)[/tex]

If 3 moles of hydrogen produces 2 moles of ammonia

5 moles of hydrogen will produce 5 * 2/3

= 3.33 moles

Thus we have 3.33 moles of ammonia.

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We wish to determine the mass of Mg required to react completely with 250mL of 1.0 M HCI. HCI reacts with Mg according to the
equation below.

2HCl(aq) + Mg(s) → MgCl₂(aq) + H₂(g)

How many moles of HCI are present in 250. mL of 1.0 M HCl?

Answers

The number of moles of HCl present in 250. mL of 1.0 M HCl is 0.250 moles.

How to calculate number of moles?

The number of moles of a substance can be calculated using the following expression;

Molarity = no of moles ÷ volume

According to this question, we were given 250. mL of 1.0 M HCl. The number of moles can be calculated as follows;

no of moles of HCl = 0.250L × 1.0M

no of moles of HCl = 0.250 moles

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Answer: .25

Explanation:

How many moles of HCl are there in 75.0 mL of 0.150 M HCl?

Answers

Explanation:

Each liter of this solution has .15 moles

.075 Liter will have .075 liter * .15 mole/liter = .01125 moles

(round as needed)

Final answer:

To calculate the moles of HCl in 75.0mL of a 0.150M solution, first, convert the volume to liters (0.075L). Then, multiply the molarity by the volume in liters to get the moles. Therefore, there are 0.01125 moles of HCl in the solution.

Explanation:

To find out how many moles of HCl are there in 75.0 mL of 0.150 M HCl, you need to understand the concept of molarity. Molarity (M) is defined as the number of moles of solute per liter of solution. Since molarity is expressed in moles/L, to calculate moles we use the formula: moles = Molarity x Volume(L).

First, convert 75.0mL to Liters by dividing by 1000 to get 0.075L.

Then multiply this volume by the molarity to calculate the moles:

0.150M x 0.075L = 0.01125 moles of HCl.

So, there are 0.01125 moles of HCl in 75.0 mL of 0.150 M HCl solution.

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GaAsO4 what is the ionic compound name

Answers

The ionic compound name of GaAsO4 is gallium arsenate.

Is gallium arsenate covalent or ionic?

By moving three electrons from gallium to arsenic, gallium arsenide (GaAs) might be created as an insulator, however this does not happen. Gallium arsenide is a covalent semiconductor, hence the bonding is more strong sphalerite crystals in this shape are referred to as zinc blende or cubic sphalerite.

Any substance contains ions?

Examples of ionic compounds include salts, oxides, hydroxides, sulphides, and the bulk of inorganic substances.. The electrostatic interaction between the positive and negative ions holds ionic solids together. As an illustration, sodium ions draw chloride ions, and chloride ions draw sodium ions.

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All of the following are unique properties of water except ____
Water has high specific heat.

Water has high heat of vaporization.

Water expands when it freezes.

Water is a non polar molecule.

Answers

Answer:

Water is a non polar molecule

Explanation:

Water interacts differently with charged and polar substances than with nonpolar substances because of the polarity of its own molecules. Water molecules are polar, with partial positive charges on the hydrogens, a partial negative charge on the oxygen, and a bent overall structure.

Mangrove trees grow in swampy areas and have strong roots that hold the soil in place. How is this helpful for the environment?

a

They absorb water from the soil.

b

They overtake the environment.

c

They provide wood for humans.

d

They protect the land from eroding

Answers

Mangrove trees' robust roots aid in stabilizing the soil and preventing soil erosion. This is especially crucial in swampy coastal locations, where the soil is frequently loose and prone to wind and wave erosion. Mangrove trees work to stabilize the coastline and stop land erosion by securing the soil in place.

Mangrove trees also aid in removing contaminants from the water, enhancing the quality of the water in coastal areas while serving as an essential home for a variety of wildlife species. Mangrove trees contribute significantly to environmental protection and are an essential component of coastal ecosystems.

Mangrove trees are crucial for environmental preservation because they hold the soil in place and stop erosion in marshy coastal areas. They also provide crucial habitats for numerous wildlife species, stabilize the coastline, and stop the land from being lost to erosion while enhancing water quality by filtering pollutants from the ocean.

Mangrove trees are an essential part of coastal ecosystems overall, and preserving them is essential for preserving a healthy and sustainable environment.

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Select all answer choices that would result in units of moles.

a) RT/PV
b) PV/RT
c) mass ÷ molar mass
d) molar mass ÷ mass
e) molar mass × mass
f) molarity ÷ volume
g) volume ÷ molarity
h) molarity × volume

Answers

The correct options that will result in mole are option B, C, and H

How do i know which options will result in mole?

To know the options that will result in mole, do the following:

Ideal gas law states as follow:

PV = nRT

Where

P is the pressure V is the volumen is the number of moleR is the gas constantT is the temperature

PV = nRT

Make n the subject by dividing both sides by RT

n = PV / RT (option B)

Mole, mass and molar mass are related according to the following formula:

Mole = mass / molar mass (option C)

Molarity is defined as mole per unit volume as shown below:

Molarity = mole / volume

Make mole the subject by cross multiplying.

Mole = Molarity × volume (option H)

Thus, from the above illustrations, we can conclude that the correct options which will result in mole are option B, C, and H

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An aqueous solution of 4mol/L nitric acid is electrolysed in an electronic cell using graphite electrodes

Answers

2 moles of [tex]O_{2}[/tex] gas and 1 mole of [tex]NO_{2}[/tex] gas would be produced from 2 moles of [tex]HNO_{3}[/tex] during electrolysis.

What is an electrolysis?

Electrolysis of nitric acid using graphite electrodes would result in the following reactions at the anode and cathode:

At the anode (oxidation):

[tex]2HNO_{3}[/tex] + 4 e- → [tex]O_{2}[/tex] + [tex]2NO_{2}[/tex] + [tex]2H_{2}O[/tex]

At the cathode (reduction):

[tex]2H^{+}[/tex] + 2 e- → [tex]H_{2}[/tex](g)

Overall reaction:

[tex]2HNO_{3}[/tex] (aq) +[tex]2H^{+}[/tex](aq) + 4 e- → [tex]O_{2}[/tex](g) + [tex]2NO_{2}[/tex](g) + [tex]2H_{2}O[/tex](l)

This means that for every 2 moles of nitric acid, 1 mole of [tex]O_{2}[/tex] gas is produced. The products of the electrolysis are [tex]O_{2}[/tex] gas, [tex]NO_{2}[/tex] gas, and [tex]H_{2}O[/tex].

The concentration of the nitric acid (4 mol/L) indicates that there are 4 moles of [tex]HNO_{3}[/tex] in 1 liter of solution. To calculate the number of moles of [tex]HNO_{3}[/tex] in a given volume of solution, we can use the following formula:

moles of solute = concentration × volume (in liters)

For example, if we have 500 mL (0.5 L) of the 4 mol/L nitric acid solution, the number of moles of [tex]HNO_{3}[/tex] present would be:

moles of [tex]HNO_{3}[/tex] = 4 mol/L × 0.5 L = 2 moles

Therefore, 2 moles of [tex]O_{2}[/tex] gas and 1 mole of [tex]NO_{2}[/tex] gas would be produced from 2 moles of [tex]HNO_{3}[/tex] during electrolysis.

It's worth noting that the oxidation of nitric acid to form nitrogen dioxide is an exothermic reaction that can produce heat, so the electrolysis may need to be performed under controlled conditions to prevent overheating. Additionally, nitrogen dioxide is a toxic gas that should be handled with care in a well-ventilated area.

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Complete question is: An aqueous solution of 4mol/L nitric acid is electrolysed in an electronic cell using graphite electrodes produced 2 moles of [tex]O_{2}[/tex] gas and 1 mole of [tex]NO_{2}[/tex] gas from 2 moles of [tex]HNO_{3}[/tex] during electrolysis.

How many atoms are in 4.5 moles of neon?

How many miles are in 1.2x1023 atoms of silicon?

How many moles are in 3.4x1023 molecules of CH4?

How many moles are in 5.2x1024 atoms of gold?

How many atoms are in 26.2 moles of cobalt?

How many cookies are in 1.2 mole of cookies?

Answers

The atoms of neon are [tex]27.099 *10^{23}[/tex], moles of silicon are 0.1199 , moles of [tex]CH_{4}[/tex] are 0.56, moles of gold are 8.64, atoms of cobalt are [tex]157.7764*10^{23}[/tex] and number of cookies are [tex]7.2264*10^{23}[/tex].

How to calculate atoms?

Multiplying the number of moles with [tex]6.022*10^{23}[/tex] we will get number of atoms of neon.

Number of atoms= [tex]4.5* 6.022 *10^{23}[/tex]

Number of atoms of neon = [tex]27.099 *10^{23}[/tex]

Moles of silicon?