How to find the net ionic of an equation

The given combustion reaction of ethanol with oxygen can be balanced as follows:

[tex]\rm CH_{3}CH_{2} OH + 3O_{2} \rightarrow 2 CO_{2} + 3 H _{2}O[/tex].

Combustion is a type of reaction in which the a substance reacts with atmospheric oxygen to produce water and carbon dioxide. Hydrocarbons such as alkanes, alkenes and alkanes and other organic compounds such as alcohol.

One mole of ethanol undergoes combustion reaction and produce 2 moles of carbon dioxide and 3 moles of water. The reaction can be balanced and written as follows:

[tex]\rm CH_{3}CH_{2} OH + 3O_{2} \rightarrow 2 CO_{2} + 3 H _{2}O[/tex]

The reaction is balanced on each side and the number of each elements on both sides are equated by multiplying with suitable integers.

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The reaction mechanisms of dissolution processes are discussed for the balanced equation for the recovery of germanium from its oxide ore is GeO2 + heat= Ge+O2(g)

The balanced equation for the recovery of germanium from its oxide ore is GeO2 + heat= Ge+O2(g)

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The balanced equation of combustion of the butane is:

2C₄H₁₀ (g) + 13 O₂ (g)  → 8 CO₂ (g) + 10 H₂O (g)

The volume of the butane, oxygen, CO₂, and water is 44.8 L, 291.2 L, 179.2 L, and 224 L.

The chemical equation is said to be balanced if the number of atoms of each element is equal on both sides of the chemical equation.

The law of conservation of mass should be followed while balancing of a chemical equation.  By obeying this law, the total mass on both sides of the equation will be equal in a balanced chemical equation.

Given the equation is 2 C₄H₁₀(g)  + 13 O₂ (g)  → 8 CO₂ (g) + 10 H₂O (g)

The moles of the butane = 2 mol

The volume of the butane = 2 ×22.4 = 44.8 L

The volume of the oxygen = 13 ×22.4 = 291.2 L

The volume of the carbon dioxide = 8 ×22.4 = 179.2 L

The volume of the water = 10 ×22.4 = 224 L

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Rate of dissociation of a solution is largely depends up on surface area of the solid solute.The correct option is D

Dissociation can be defined as chemical reaction in which a compound breaks apart into two or more components. The general formula for a dissociation reaction follows the form: AB → A + B.

Therefore dissociation reaction may occur when one molecule is divided to form two smaller ones leading to a decrease in energy. Dissociation reactions result in the break down of a large molecule to form smaller products.

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Answer:

4

Explanation:

All numbers in the calculation are to 4 significant figures.

The difference in the oxidation state of chromium in chromate and dichromate salts is 0 as chromium has an oxidation number of +6 in both salts.

Chromates and dichromates are salts of chromic acid and dichromic acid, respectively.

Chromate salts contain the chromate ion, CrO₄²-, and have an intense yellow color. Dichromate salts contain the dichromate ion, Cr₂O₇²−, and have an intense orange color.

The chromium atoms are in oxidation state +6 in both, and the chromate and dichromate ions are fairly strong oxidizing agents.

Chromium in the +6 (or VI) oxidation state is often referred to as hexavalent chromium.

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The percent composition by mass of some compounds is 32.01% C, 4.03% H, and 63.96% O, with a total molecular mass of 150 amu. The empirical formula of the compound is CH2O8, and the molecular formula is C3H6O24.

The percent composition by mass of some compounds is 32.01% C, 4.03% H, and 63.96% O, with a total molecular mass of 150 amu. This can be used to calculate the empirical formula and the molecular formula of the compound. To calculate the empirical formula, the mass of each element must first be calculated and then divided by the atomic mass of each element.

The mass of Carbon is 32.01% of 150 amu, which is 48.015 amu. The mass of Hydrogen is 4.03% of 150 amu, which is 6.045 amu. The mass of Oxygen is 63.96% of 150 amu, which is 95.945 amu. When divided by atomic mass, the ratio of elements is C:H:O = 1:2:8. This is the empirical formula of the compound.

The empirical formula gives the simplest ratio of the elements present in the compound, but does not necessarily indicate the actual number of atoms of each element present in the compound. To calculate the molecular formula of the compound, the empirical formula must be multiplied by an integer to correct the number of atoms of each element. The empirical formula for this compound is CH2O8. To determine the molecular formula, the empirical formula must be multiplied by a factor of 3. The molecular formula is therefore C3H6O24.

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Based on the Lewis structure, SCl₂ is a polar molecule whereas CBr₄ is a non-polar molecule.

Lewis dot structures, also known as electron dot structures, are pictorial representations that show the interatomic chemical bonds in a molecule. They also depict how many lone pairs are overall in each atom that makes up the molecule. Common names for Lewis dot structures include electron dot structures and Lewis structures. Lewis described an acid as an electron pair acceptor, while a base is an electron pair giver. One dot is included in a Lewis Electron Dot Formula along with the symbol of the element and each valence electron.

Hence, Lewis structure denotes nature of molecules

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I just know that much if my answer is helpful please mark it brainlist

i When sodium carbonate (Na2CO3) is mixed with an aqueous solution of copper(II) sulfate (CuSO4), the student can expect to see several evidence of a chemical reaction:

Formation of a solid precipitate: When these two solutions are mixed, a solid precipitate of copper(II) carbonate (CuCO3) will form. This is a sign that a chemical reaction has occurred.

Change in color: The reaction between sodium carbonate and copper(II) sulfate will also result in a change in color. The solution may turn a blue or green color, indicating the presence of copper(II) ions.

Release of gases: The reaction between sodium carbonate and copper(II) sulfate may also produce gases, such as carbon dioxide (CO2).

ii The balanced chemical equation for the reaction between sodium carbonate and copper(II) sulfate is:

2Na2CO3(aq) + CuSO4(aq) → 2Na2SO4(aq) + CuCO3(s)

iii This is a double displacement reaction, also known as a metathesis reaction. In this type of reaction, the cations (positively charged ions) and anions (negatively charged ions) of the reactant compounds exchange places to form the products. In this case, the sodium ions (Na+) and the copper ions (Cu2+) exchange places to form sodium sulfate (Na2SO4) and copper carbonate (CuCO3).

The reaction mechanism explains the separate phases of a reaction and identifies any intermediates that are produced during one step and used in a different step later in the reaction.

One or maybe more chemicals, commonly referred to as reaction mixture, are converted within one or more chemical molecules, referred to as products, during a chemical reaction. Chemical elements and compounds are both substances.

Rearranging the atoms or molecules of two or more substances when they come into touch with one another, producing the production of one or more new substances. The interaction of two different substances' electrons is what drives chemical reactions.

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Using simple and environmentally friendly synthesis approach, we can produce approximately 120 g of G-dots per 100 kg of food waste.

Because of the abundance of oxygen-containing functional groups on their surface, G-dots are highly soluble in water. Because of similar quantum effects and emission traps on the surfaces, the narrow band of photoluminescence emission (400-470 nm) confirms that the size of the G-dots (∼4 nm) is small. G-dots have excellent photostability; their photoluminescence intensity decreases slowly (∼8%) after 10 days of continuous excitation with a Xe lamp. We performed a cell viability assay to evaluate the effect of cytotoxicity by introducing G-dots into cells such as Chinese hamster ovary cells (CHO-K1), mouse muscle cells, and African green monkey kidney cells (COS-7) for 24 hours.

These G-dots are excellent probes for in vitro bioimaging due to their high photostability and low cytotoxicity. Furthermore, byproducts of G-dot synthesis from large food-waste derived sources aided in the growth and development of seedlings germinated on 3DW-supplemented gauze. G-dots hold great promise in a variety of fields, including biomedical imaging, solution state optoelectronics, and plant seed germination and/or growth, due to the advantages of green synthesis, high aqueous stability, high photostability, and low cytotoxicity.

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The equilibrium constant for three reaction are

What is equilibrium constant?

The relationship between the reactants and products when a chemical reaction reaches equilibrium is revealed by the equilibrium constant of a chemical process, which is typically represented by the letter K.

There are certain rules such as

When we reverse the reaction equilibrium constant becomes inverse and when multiply particular reaction using any number then that number  raised to power of the equilibrium constant.

2HBr (g)  ⇄  H₂ (g) + Br₂ (g)

[tex]K = \frac{[H_{2} ][Br_{2} ]}{[HBr]^{2} } \\\\[/tex]

[tex]\frac{1}{2} H_{2} (g) + \frac{1}{2} Br_{2} (g)[/tex]  ⇄ HBr(g)

[tex]K1 = \frac{[HBr]}{[H_{2} ]^{1/2}[Br_{2} ]^{1/2} }[/tex]

Squaring on both sides,

[tex]K1^{2} = \frac{[HBr]^{2} }{[H_{2} ][Br_{2} ] }[/tex]

Putting value of K in above equation -

K1² = 1/K

K1 = (1/K)^(1/2)

2) H₂ (g) +  Br₂ (g)  ⇄  2HBr (g)

Reverse the main equation

So, K₂ = 1/K

HBr (g)  ⇄  1/2 H₂ (g) + 1/2 Br₂ (g)

Multiplying equation by 1/2

So, K raised to the power 1/2,

K₃ = K^(1/2)

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The equilibrium constant for each new reaction in terms of K, will be  K1 = (1/K)^1/2 ; K2 = 1/K ; K3 = K^1/2

Why is the equilibrium constant important?

The amount of reactant to product in a chemical reaction can be compared to derive the equilibrium constant, which is used to predict chemical behavior. Rate of the forward reaction equals Rate of the backward reaction at equilibrium.

For reaction, 2 HBr(g) ⇌ H2(g) + Br2(g)

Equilibrium constant K will be [H2] [ Br2] / [HBr]^2

1) 1/2 H2(g) + 1/2 Br(g) ⇌ HBr(g)

K1 =[HBr] / [H2]^1/2 [ Br2]^1/2

     = (1/K)^1/2

2) H2(g) + Br2(g) ⇌ 2HBr(g)

K2 = [HBr]^2 / [H2] [ Br2]

     = 1/K

3) HBr(g) ⇌ 1/2 H2(g) + 1/2 Br2(g)

K3 =  [H2]^1/2 [ Br2]^1/2 / [HBr]

      =  K^1/2

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The conductivity of copper can be decreased when it takes in oxygen from the air and forms copper oxide on the surface or when oxygen impurities are present in the material. Copper oxide is a poor conductor of electricity compared to pure copper, and the presence of oxygen impurities can disrupt the regular arrangement of copper atoms and hinder the flow of electrons, leading to a decrease in conductivity.

The medicine rocecoxib, often known as viox, comprises an atom of this element double-bonded to two distinct oxygens.

Celecoxib is a nonsteroidal anti-inflammatory medicine (NSAID) used to treat mild to moderate pain and help reduce symptoms of arthritis, such as inflammation, swelling, stiffness, and joint discomfort (e.g., osteoarthritis, rheumatoid arthritis, or juvenile rheumatoid arthritis).

People who use NSAIDs (non-aspirin non-steroidal anti-inflammatory drugs), such as celecoxib, may be more likely to experience a heart attack or stroke than those who do not use these treatments. These occurrences could be fatal and could occur suddenly.

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To solve this, we must know each and every concept related to mechanisms of organic reaction. Therefore, the  arrow that best describes the relationship between the reactants and products is the equilibrium arrow. The correct option is option A.

The technique of just an organic reactions is just the order of the steps in the process, giving information on which bonds are produced and/or disrupted in each step.

Understanding the processes of organic reactions is vital for understanding Organic Chemistry and for being able to harness the reactions to generate useful molecules. The  arrow that best describes the relationship between the reactants and products is the equilibrium arrow.

Therefore, the correct option is option A.

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Because a greater percentage of active sites will be occupied by substrate, competitive inhibition will be reduced.

When the competitive inhibitor attaches to the active site, the substrate is unable to bind there. Although it doesn't prevent substrate binding, the noncompetitive inhibitor attaches to a different spot on the enzyme and alters it in ways that prevent it from efficiently catalyzing the reaction.

When an inhibitor binds to an enzyme's target molecule, also known as the substrate, this process is known as inhibiting the activity of enzyme catalysis. In order to do this, the active site of the substrate's binding is blocked in some way.

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Answer:

3CO(g) + Fe₂O₃(s)

Explanation:

In a chemical equation, the reactants are the substances that undergoes a chemical reaction to form the products. In this case, 3CO(g) and Fe₂O₃(s) react to form 2 {Fe}(s) and 3CO₂(g).

Answer:

Second answer may be 4Al +3O2 gives 2Al2O3

Relation of structure of an enzyme to its reaction specificity :The reaction specificity relates to unique shape of active site to which only a complementary shape can bind.

The relationship between enzyme structure and enzyme specificity is that an enzyme's form, which is a result of its amino acid sequence, determines how specific it is.

An enzyme's three-dimensional structure, which is essential to its normal operation, determines how specific it is. The lock-and-key theory of enzyme activity states that the three-dimensional structure of an enzyme's active site enables the enzyme to bind readily to just certain substrates.

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It is untrue that a bcc structure packs monatomic solids more effectively than just a fcc structure because it uses different unit cells.

The central atom and the eight eighths from of the corners make up the BCC unit cell's final atomic composition, which is two atoms overall. Again, there seem to be eight atoms in the unit cell's corners in the FCC layout, and one atom is positioned in the middle of each face. The neighboring cell and the molecule in the face are connected.

Since the atom in this novel shape is located in the cube's body, it is known as a body-centered cubic structure (see the diagram below). Iron in its phase, chromium, tungsten, tantalum, or molybdenum are a few metals that have this crystalline structure.

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The one that will not show geometric (cis-trans) isomerism is 3-ethyl-3-heptene. Thus, the correct answer to this question is A.

Geometric isomers are molecules that have the same molecular formula and the same bond connectivity but differ in the spatial arrangement of their atoms. Geometric isomers can only occur in molecules with double bonds and will have different physical properties such as boiling point, melting point, and solubility.

The correct answer is 3-ethyl-3-heptene. This molecule does not contain a double bond and therefore cannot have geometric isomers. All the other choices (b, c, and d) contain a double bond and would be expected to exhibit geometric isomerism.

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Answer:

The sign of ΔH is negative and reaction is exothermic so correct option is D.

Explanation:

Chemical reactions are endothermic if the heat of reaction is written on the reactant side of the equation. The heat of the reaction in exothermic reactions is written on the product side. The energy that is either released or absorbed when chemicals are changed in a chemical reaction is known as the heat of reaction. The heat of reaction, also known as reaction enthalpy, is frequently given as either specific enthalpy in kJ/kg or kJ/L or as molar enthalpy in kJ/mol.

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The process's H indication The reaction of NaCl(l) NaCl(s) is positive and endothermic.

The process of melting salt is endothermic.

Gibbs free energy is connected to enthalpy change and entropy change at constant temperature in the following ways:

ΔG= ΔH– TΔS

The given reaction is,

                NaCl (l) → NaCl(g)

Now, we know that, as we move from solid to liquid and liquid to gas, entropy increases.

Thus, in the given reaction, entropy increases.

Also, if ΔG> 0, reaction is never spontaneous, and if ΔG< 0, reaction is spontaneous.

Now, as ΔS is positive, so, ΔG will be negative i.e. exothermic if and only if ΔH is negative.

Therefore, the correct option is negative and the process is exothermic. The reaction is as follows: NaCl(l) NaCl (g)

We now know that entropy rises as a substance changes state from solid to liquid and then from liquid to gas.

Entropy so rises in the process described.

Additionally, a reaction is always spontaneous if G > 0, and never if G 0.

Since S is now positive, G will only be exothermic, or negative, if H is also negative.

As a result, the process is exothermic, and the right answer is negative.

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Any source outside the body that emits ionising radiation, whether it be a beta source, neutron source, or gamma source, might be a risk for external radiation exposure.

The most dangerous outside threat is gamma radiation. "Beta burns" can be brought on by beta particles that partially penetrate skin.

Ionizing radiations have the potential to result in dermatitis, burns, cell damage, cataracts, and alterations in the blood. Any exposed area of the body can become heated by microwaves and radio waves, infrared rays can cause cataracts and skin burns, and UV light can cause skin cancer, conjunctivitis, arc eye, and conjunctivitis.

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Addition of 6M HI will increase the concentration of Hgl4.

The principle of Le Chatelier is as follows: A change in one of the variables that describe an equilibrium system causes a shift in the position of the equilibrium, which cancels out the effect of the change.

In this question,

Addition of 6M HI shifts the equilibrium in forward direction and hence more amount of HgI4^- formed.

This is accordance with Le-Chatelier principle which states that , increasing the concentration of reactants ( gases or aqueous phase only) shifts the equilibrium in forward direction and increase the concentration of products shift the equilibrium in backward direction .

Addition of 6M HI will increase the concentration of Hgl4.

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In the gold unit cell, packing is more effective. The sodium chloride unit cell has a greater packing efficiency. In both lattice structures, packing is equally efficient.

Two unit cells share an atom on a face, therefore only one of these cells is the owner of the entire atom.

An example of cubic close packing is a crystalline structure in which planes of densely packed atoms or ions are arranged in a sequence of three alternating layers with various relative orientations.

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Answer:

Br

Explanation:

The first ionization energy is a measure of the energy required to remove the outermost, or highest energy, electron from an atom or a positive ion. Among the elements Na, P, Ca, and Br, the element with the highest first ionization energy is Br.

The first ionization energy generally increases across a period (row) on the periodic table and decreases down a group (column). This trend is due to the increasing effective nuclear charge (the positive charge felt by an electron) and decreasing electron shielding (the effect of inner electrons on the energy of outer electrons) as one moves from left to right across a period.

In the case of Na, P, Ca, and Br, all four elements are in the same period, so they experience similar effective nuclear charge. However, Br has a higher atomic number than the other three elements, which means it has more protons in its nucleus and a stronger positive charge. This leads to a higher first ionization energy for Br compared to Na, P, and Ca.

Overall, the element with the highest first ionization energy among Na, P, Ca, and Br is Br.

The equilibrium concentration of reactants and products are i.e.

[H2]=0.049,[I2]= 0.049,[HI]=0.36.

What is equilibrium concentration?

When the products and reactants remain constant over time, a chemical is said to be at equilibrium concentration. In other words, the rate of forward reaction in a chemical reaction must equal the rate of backward reaction in order for there to be chemical equilibrium, also known as equilibrium concentration.

For detailed calculation please refer attached file.

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Dissolve 60g of potassium bromide in 340g of water to produce 15% (mass/mass) aqueous solution of potassium bromide.

Here we have to prepare a total of 400 g of solution. Aqueous solution means the solvent we use here is water.

So to prepare 400 g of 15% aqueous solution of potassium bromide, we need to find out how many grams of potassium bromide need to be dissolved in water and how many grams of water must be used.

Here the weight percent is given, that is 15%

       15/100 = weight of potassium bromide/ 400 g

       0 .15      = weight of potassium bromide / 400

      weight of potassium bromide needed = 0.15 × 400

                                                                       =  60 g

So, we calculated the required amount of potassium bromide as 60 grams. The total weight of the solution to be made is 400 grams.

So amount of water required = 400 - 60

                                                =  340 g

So we need to mix 60 grams of potassium bromide in 340 grams of water to get a 15% (mass/mass) aqueous solution.

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