how to find acceleration with mass and force calculator

Answers

Answer 1
Force = Mass X Acceleration
Mass= Force divided Acceleration Acceleration = Force divided mass
How To Find Acceleration With Mass And Force Calculator
Answer 2

Use the equation a = F/m, where an is the acceleration, F is the force being applied, and m is the mass of the object, to calculate acceleration using mass and force. Calculating the acceleration is as simple as dividing the force by the mass.

What is Newton's second law of motion?

Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the force applied on it, and inversely proportional to its mass. The mathematical representation of this law is:

F = ma

where F is the force applied on an object, m is the mass of the object, and a is its acceleration. This law implies that the greater the force applied on an object, the greater its acceleration will be, and that the acceleration of an object will decrease as its mass increases, given a constant force.

This law helps to explain the behavior of objects under the influence of external forces. It is used in many areas of science and engineering, including mechanics, physics, and aerospace. Understanding the relationship between force, mass, and acceleration is fundamental to the study of mechanics and the design of machines and structures.

Here in the Question,

To find acceleration using mass and force, you can use the following steps:

1. Determine the force acting on the object. This can be done using a force meter, a scale, or by calculating the force using the formula F = ma, where F is the force in newtons (N), m is the mass of the object in kilograms (kg), and a is the acceleration in meters per second squared (m/s²).

2. Measure the mass of the object in kilograms. This can be done using a  scale.

3. Use the formula a = F/m to calculate the acceleration of the object. Rearrange the formula to solve for a: a = F/m.

5. Plug in the values for force and mass and solve for acceleration. For example, if the force acting on an object is 20 N and the mass of the object is 5 kg, the acceleration can be calculated as follows:

a = F/m

a = 20 N / 5 kg

a = 4 m/s²

So, the acceleration of the object is 4 meters per second squared.

It's important to note that the units of force and mass should be in the correct SI units (newtons and kilograms, respectively) to ensure the correct unit for acceleration (meters per second squared).

Therefore, To find acceleration using mass and force, use the formula a = F/m, where a is the acceleration, F is the force applied, and m is the mass of the object. Simply divide the force by the mass to calculate the acceleration.

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Related Questions

A cat that has a mass of 6 kg climbs to the top of a tree that is 20 m high. How much potential energy does the cat have at the top of the tree?

Have a great day!

Answers

Answer:

1176.798 J

Explanation:

[] Use the following equation:

U = mgh

m - mass

g - gravitational field

h - height

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

What is the net force on a car with a mass of 1000 kg if its
acceleration is 35 m/s^2?

Answers

Answer:

3000N

Explanation:

divided to get answer

the force needed to accelerate the 1000kg car by 3m/s2 is 3000N

Which electromagnetic wave has a lowest frequency?
Group of answer choices

A) x-rays

B) ultraviolet light

C) microwaves

D) infrared light

E) visible light

Answers

I think that the answer would be A

Answer:

E.visible lights

Explanation:

llll

hope its attachments

find u + (3v - w)
u =-4i-8j
v= -11i -3j
w=5i+7j

Answers

Answer:

gunrun

Explanation:

If a rock weighing 3.5 newtons is resting on cliff's ledge 12 meters from the canyon floor, what is its potential energy?

Group of answer choices

87 joules

4.5 joules

42 joules

142 joules

Answers

Answer:

42 Joules

Explanation:

Potential energy

= weight × height

= (3.5)(12)

= 42 joules

A billiard ball with a speed of 5 m/s strikes another stationary billiard ball in a perfectly elastic collision.

After the collision, the first ball has a speed of 4.35 m/s and is traveling at an angle of 30° below its original line of motion.

Find the speed and angle of the second ball, with respect to the initial line of motion, after the collision.

Answers

Assuming both billiard balls have the same mass, conservation of momentum says

[tex]m\vec v_1 + m\vec v_2 = m{\vec v_1}\,' + m{\vec v_2}\,'[/tex]

where m = mass of both billiard balls, and v₁ and v₂ = their initial velocities, and v₁' and v₂' = their final velocities. The masses are the same so the exact value of m is irrelevant. The first ball has initial speed 5 m/s and the second is at rest, so

[tex]\left(5 \dfrac{\rm m}{\rm s}\right) \, \vec\imath = {\vec v_1}\,' + {\vec v_2}\,'[/tex]

After the collision, the first ball has speed 4.35 m/s and is moving at angle of 30° below the original path, so

[tex]{\vec v_1}\,' = \left(4.35\dfrac{\rm m}{\rm s}\right)\left(\cos(30^\circ) \, \vec\imath + \sin(30^\circ) \, \vec\jmath\right) \approx \left(3.77 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(-2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]

Then the second ball has final velocity vector

[tex]{\vec v_2}\,' \approx \left(1.23 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]

so it moves with speed

[tex]\left\|{\vec v_2}\,'\right\| \approx \sqrt{\left(1.23\dfrac{\rm m}{\rm s}\right)^2 + \left(2.18\dfrac{\rm m}{\rm s}\right)^2} \approx \boxed{2.50 \dfrac{\rm m}{\rm s}}[/tex]

at an angle of

[tex]\theta \approx \tan^{-1}\left(\dfrac{2.18}{1.23}\right) \approx \boxed{60.5^\circ}[/tex]

or about 60.5° above the original line of motion.

What is the half-life of an isotope if after 30 days you have 31.25 g remaining from a 250 g beginning sample size?

Answers

The half-life of the given isotope will be 10 days, if after 30 days only 31.25 grams are remaining from a sample of 250 grams of the sample size taken in the beginning.

What is Half-life of an element?

The Half-life is the time which is required for a quantity to reduce the content to half of the amount present as its initial value. The term is used in nuclear physics to describe how quickly an unstable atom undergo radioactive decay or how long does stable atoms survive. The term is also used generally to characterize any type of exponential decay.

The half-life of the isotope can be calculated by the formula:

FR = 0.5n

FR = Fraction Remaining = 31.25 g / 250.0 g = 0.1250

n = number of half lives elapsed = ?

0.125 = 0.5n

log 0.125 = n log 0.5

-0.9031 = -0.3010 n

n = 3.000 half lives have elapsed

3 half lives = 30 days

1 half live = 10 days

Therefore, the half-life of the isotope will be 10 days.

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ignoring air resistance, an object falling toward the surface of the earth has a velocity that is

Answers

your answer would be 9.18 m/s^2

A geothermal plant has been built in a location. Which of these is the most likely benefit of the geothermal plant in this location?

A. Decrease in geothermal fuels consumption
B. Improvement to hot springs and geysers
C. Long-term cost savings for energy users
D. Increase in emission of greenhouse gases

Answers

Answer:

C

Explanation:

A and B are not true and D is a disadvantage

Answer:

C.  Long-term cost savings for energy users.

Explanation:

C is correct because the first option is a drawback that is unlikely.  B is a good answer but not the best.  It's a likely benefit, but C is a more likely benefit.  D is a drawback.  C is correct.  I also got this right on my quiz.

Hope this helps!

Can someone help me with this physics question? I don't know which answer is correct.

Answers

3. Distance is a quantity that is always a vector.

B.

What is the momentum of a 5 kg object that has a velocity of 1. 2 m/s? 3. 8 kg • m/s 4. 2 kg • m/s 6. 0 kg • m/s 6. 2 kg • m/s.

Answers

Answer:

6 kg.m/s

Explanation:

Momentum is the product of mass and velocity. So,

p = mv

Here,

p denotes momentum [?]m denotes mass [5kg]v denotes velocity [1.2 m/s]

→ p = 5 kg × 1.2 m/s

→ p = (5 × 1.2) kg.m/s

→ p = (5 × 12/10) kg.m/s

→ p = 12/2 kg.m/s

p = 6 kg.m/s

Therefore, momentum of the object is 6 kg.m/s.

The momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.

MOMENTUM:

Momentum of a substance is the product of its mass and velocity. That is;

Momentum (p) = mass (m) × velocity (v)

According to this question, an object has a mass of 5kg and velocity of 1.2m/s. The momentum is calculated thus:

Momentum = 5kg × 1.2m/s

Momentum = 6kgm/s.

Therefore, the momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.

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The slope of position-time graph represents

Answers

Answer:

The speed.

Explanation:

The slope of a line is that line's rate of change.  If a car is travelling at 20 km/hr and we plot distance vs time graph, the slope of that line will be 20.

in any chemical reaction or physical change the mass of the product is ___ The mass of the reactant
a. The relationship cannot be determined by the amount of information given
b. equal to or the same
c. twice is greater than
d. twice as less than

Answers

Answer: b. equal to or the same

In Law of Conservation of mass,  the mass of the product equals the mass of the reactant. A reactant is the chemical reaction of two or more elements to make a new substance, and a product is the substance that is formed as the result of a chemical reaction.

pls mark brainliest! i really need one :(

is atom on the offficial repository of ubuntu ?

Answers

Answer:

Atom, the cross-platform, open source code editor developed by Github, has become quite popular thanks to its plug-ins and embedded Git Control. ... There are, however, official Atom repositories for some Linux distributions, like Ubuntu, Debian, Fedora, Red Hat, CentOS, and open.


What happens to the gravity force if the mass of the planet is increased?

Answers

Answer:

The more mass an object has, the greater its gravitational field and gravity force will be.

Explanation:

gravity force = mass × gravitational field strength (g)

The more mass, the more g-force.

If the energy in a mechanical wave increases or decreases, what is also going to increase or decrease? A wavelength B amplitude с frequency d refraction​

Answers

Answer:

i think wave lengh not 100% sure tho

If the energy of the mechanical wave will increase or decrease, then the wavelength will also change accordingly. Hence, option A is correct.

What is Wavelength?

The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is more frequently described in nanometers (nm), which are units of 10⁻⁹ m, or angstroms, which are units of 10⁻¹⁰ m, for infrared (IR), visible light (UV), and gamma radiation.

Frequency, which is defined as the number of wave cycles per second, and wavelength have an inverse relationship. The wavelength of a signal decreases with increasing frequency, or we can say that wavelength and refractive index are inversely proportional to each other.

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What event will produce the greatest increase in the gravitational force between the two masses?

Question 5 options:

Doubling the distance between the masses


Reducing the small mass by half


Doubling the large mass


Reducing the distance between the masses by half

Answers

Answer:

Doubling the large mass

Explanation:

By doubling the mass you will get more gravational force

A 50 kg pitcher throws a baseball with a mass of 0. 15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is no net force on the system, what is the velocity of the pitcher? â’0. 1 m/s â’0. 2 m/s â’0. 7 m/s â’1. 4 m/s.

Answers

The velocity of the pitcher at the given mass is 0.1 m/s.

The given parameters:

Mass of the pitcher, m₁ = 50 kgMass of the baseball, m₂ = 0.15 kgVelocity of the ball, u₂ = 35 m/s

Let the velocity of the pitcher = u₁

Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;

m₁u₁ = m₂u₂

[tex]u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{0.15 \times 35}{50} \\\\u_1 = 0.105 \ m/s\\\\u_1 \approx 0.1 \ m/s[/tex]

Thus, the velocity of the pitcher at the given mass is 0.1 m/s.

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3. A(n)______ is someone who travels to new places or does new things. A. explorer B. thrill C. expedition D. research

Answers

Answer:

explorer

Explanation:

Answer:

a) EXPLORER

Explanation:

An explorer is someone who travels to new places or does new things.

45. 3. (III) A 7.26 kg bowling ball hangs from the end of a 2.5 m rope. The ball is pulled back until the rope makes an angle of 45 with the vertical. a. What is the increase in the ball’s potential energy when it is lifted? b. If the ball is released from rest and swings downward like a pendulum, how much kinetic energy will the ball have at the bottom of its swing? c. How fast will the ball be moving at the bottom of its swing?

Answers

Explanation:

For the first question look at the picture. It should be pretty clear. Remember that cos45° = sqrt2 / 2.

2) We calculate it thanks to the conservation of mechanical energy:

Em1 = Em2

U1 + K1 = U2 + K2

K1 = 0J

U2 = 0j

U1 = K2

3) mgh = 1/2mv^2

v = sqrt(2gh)

If a car can go from 0 to 60 km/h in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50 km/h?

Answers

Answer:

This question assumes that the car accelerates at the same rate as when it went from 0 to 60km/h

24.29m/s or 87.4km/h

Explanation:

Let's find the acceleration of the car:

let vi=0, vf=60km/h (16.67m/s), Δt = 8.0s

a = (vf-vi)/Δt

a = (16.67m/s-0)/8.0

a = 2.08m/s^2

Now we can use this acceleration to find vf in the second part:

50km/h is 13.89m/s

a = (vf-vi)Δt

vf = aΔt + vi

vf = 2.08m/s^2*5.0+13.89m/s

vf = 24.29m/s (87.4km/h)

Depth perception is also known as ___________ vision.

Answers

Answer:

depth from optical expansion

Explanation:

please help me with this​

Answers

Answer:

>400N is needed to balance that lever

One ball of mass 0.600kg travelling 9.00m/s to the right collides head on elastically with a second ball of mass 0.300kg travelling 8.00m/s to the left.what are their velocities after collisions?

Answers

Let m₁ and v₁ denote the mass and initial velocity of the first ball, and m₂ and v₂ the same quantities for the second ball. Momentum is conserved throughout the collision, so

m₁ v₁ + m₂ v₂ = m₁ v₁' + m₂ v₂'

where v₁' and v₂' are the balls' respective velocities after the collision.

Kinetic energy is also conserved, so

1/2 m₁ v₁² + 1/2 m₂ v₂² = 1/2 m₁ (v₁')² + 1/2 m₂ (v₂')²

or

m₁ v₁² + m₂ v₂² = m₁ (v₁')² + m₂ (v₂')²

From the momentum equation, we have

(0.600 kg) (9.00 m/s) + (0.300 kg) (-8.00 m/s) = (0.600 kg) v₁' + (0.300 kg) v₂'

which simplifies to

10.0 m/s = 2 v₁' + v₂'

so that

v₂' = 10.0 m/s - 2 v₁'

From the energy equation, we have

(0.600 kg) (9.00 m/s)² + (0.300 kg) (-8.00 m/s)² = (0.600 kg) (v₁')² + (0.300 kg) (v₂')²

which simplifies to

67.8 J = (0.600 kg) (v₁')² + (0.300 kg) (v₂')²

or

226 m²/s² = 2 (v₁')² + (v₂')²

Substituting v₂' yields

226 m²/s² = 2 (v₁')² + (10.0 m/s - 2 v₁')²

which simplifies to

3 (v₁')² - (20.0 m/s) v₁' - 63.0 m²/s² = 0

Solving for v₁' using the quadratic formula gives two solutions,

v₁' ≈ -2.33 m/s   or   v₁' = 9.00 m/s

but the second solution corresponds to the initial conditions, so we omit that one.

Then the second ball has velocity

v₂' = 10.0 m/s - 2 (-2.33 m/s)

v₂' ≈ 14.7 m/s

what led scientists to the discovery of the strong nuclear force?

Answers

Answer:

Explanation:

The concept of a new strong nuclear force was introduced. In 1935, the first theory for this new force was developed by the Japanese physicist Hideki Yukawa, who suggested that the nucleons would exchange particles between each other and this mechanism would create the force.

60W of power is taken by a small electrical heater from a 12V supply Determine the current flowing through the heater​

Answers

Answer:

5 amps

Explanation:

I = P/V

I = current (amps)

P = power (watts)

V = voltage (volts)

I = 60/12

I = 5

what is a joule in physics?​

Answers

Explanation:

Joule is unit of work or energy in the International System of Units (SI)

[tex] \large \mathfrak {Formula}[/tex]

work (joules) = force (newtons) x distance (meters)

[tex] \large\mathfrak{Invented \: by} [/tex]

James Prescott Joule

a 280 nm thin film with index of refraction 1.6 floats on waterwhat is the largest wavelength of reflected light for which constructive interference occur? answer in units of m.

Answers

Answer:

Inside the film the wavelength will be λ/n

For constructive interference to occur the film must be λf/4 thick where λf is the wavelength of the light in the film - there will be a 180 degree phase shift at the water/film interface since the index of refraction of the film is greater than that of water - and the light has to travel λ/2 inside the film for constructive interference to occur

280 nm / 1.6 * 4 = 700 nm is the greatest wavelength allowed

Note that 700 nm is also the upper wavelength of the visible spectrum

what role does gravity have in the motion of planets around the sun?

Answers

Answer:

The gravity helps the planets stay together near the Sun, without it Earth would be floating away with the planet eventually becoming frozen up, thus the role gravity have in the motion of planets around the sun is by keeping them together.

Explanation:

Hope this helps!

29) A cheetah can accelerate from rest to 25
m/s in 6 s. Assuming that the cheetah moves
with constant acceleration, what distance does
it cover in the first 3 s

Answers

Answer:

[tex]\huge\boxed{\sf S = 18.75 \ meters}[/tex]

Explanation:

Given Data:

Initial Velocity = Vi = 0 m/s (rest)

Final Velocity for 6 seconds = Vf = 25 m/s

Time (1) = T1 = 6 seconds

Time (2) = T2 = 3 seconds

Required:

Distance for 3 seconds = S = ?

Solution:

For 6 seconds, the acceleration will be:

[tex]\displaystyle a = \frac{Vf-Vi}{t} \\\\a = \frac{25 - 0}{6} \\\\a = 25 / 6\\\\\boxed{a = 4.167 \ m/s^2}[/tex]

Since, acceleration is constant, it will be the same at 3 seconds as well.

Using second equation of motion to find Distance (S) with time being 3 seconds:

[tex]\displaystyle S= Vit+\frac{1}{2} at^2\\\\S = (0)(3)+ \frac{1}{2} (4.167)(3)^2\\\\S = \frac{1}{2} (4.167)(9)\\\\S = \frac{37.5}{2} \\\\\boxed{S = 18.75 \ meters}\\\\\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807
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