How much force is needed to accelerate a 65 kg rider AND her 215 kg motor scooter 8 m/s?? (treat
the masses as like terms)

b).  The power depends on the RATE at which work is done.  

Power = (Work or Energy) / (time)

So to calculate it, you have to know how much work is done AND how much time that takes.

In part (a), you calculated the amount of work it takes to lift the car from the ground to Point-A.  But the question doesn't tell us anywhere how much time that takes.  So there's NO WAY to calculate the power needed to do it.

The more power is used, the faster the car is lifted.  The less power is used, the slower the car creeps up the first hill.  If the people in the car have a lot of time to sit and wait, the car can be dragged from the ground up to Point-A with a very very very small power ... you could do it with a hamster on a treadmill.  That would just take a long time, but it could be done if the power is small enough.

Without knowing the time, we can't calculate the power.

...

d).  Kinetic energy = (1/2) · (mass) · (speed squared)

On the way up, the car stops when it reaches point-A.  

On the way down, the car leaves point-A from "rest".

WHILE it's at point-A, it has no speed.  So it has no (zero) kinetic energy.

Answer:

F = -0.5 N

Explanation:

Given that,

Mass of an egg, m = 25 g = 0.025 kg

Initial speed, u = 4 m/s

Final speed, v = 0 (it stops)

Time, t = 0.2 s

We need to find the average force exerted on the egg. The force is given by :

F = ma

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.025\times (0-4)}{0.2}\\\\F=-0.5\ N[/tex]

So, the average force exerted on the egg is (-0.5 N).

Answer:

76.1N

Explanation:

Given parameters:

Mass of the ball  = 7.77kg

Unknow:

Weight of balloon  = ?

Solution:

Weight is the vertical force applied on a body.

  Weight = mass x acceleration due gravity

So;

  Weight  = mass x acceleration due to gravity

So;

 Weight  = 7.77 x 9.8  = 76.1N

Answer:

I think the bucs are gonna win because Tom Brady is on their team and it's rigged

but maybe I'm just thinking negatively lol

Answer:

The order = [tex]\mathbf{\sqrt{\dfrac{h}{2 \pi m}} \sqrt[4]{\dfrac{H}{g}} \sqrt[4]{\dfrac{1}{2}} }}[/tex]

Explanation:

To miss the crack at a given distance is apparently not the same as the uncertainty that occurred in the distance while falling from the tower. However, it is believed that the uncertainties in both cases appear to be the same.

So, let's work it out together

According to Heisenberg's uncertainty principle:

[tex]\Delta s. \Delta p =\dfrac{h}{2} =\dfrac{h}{4 \pi}[/tex]

Also; if we recall from the equation of motion that:

[tex]v = u + at ---(1) \\ \\ v^2 - u^2 = 2as --- (2) \\ \\ s = ut + \dfrac{1}{2}at^2 --- (3)[/tex]

So, if u = 0 and a = g

Then;

[tex]v = gt --- (1) \\ \\ v^2 = 2gs - - - ( 2) \\ \\ s = \dfrac{1}{2}gt^2 --- (3)[/tex]

From (2)

Making (s) the subject, we have:

[tex]s = \dfrac{v^2}{2g}[/tex]

[tex]s = \dfrac{p^2}{2gm^2}[/tex]

By differentiation;

[tex]ds = d (\dfrac{p^2}{2gm^2})[/tex]

[tex]ds = \dfrac{2pdp}{2gm^2}[/tex]

[tex]\Delta \ s = \dfrac{p \Delta p}{gm^2 }[/tex]

where;

[tex]\Delta p = \dfrac{h}{4 \pi \Delta \ s}[/tex] from uncertainty principle

This implies that:

[tex]\Delta s = \dfrac{p(\dfrac{h}{4 \pi \Delta s }) }{gm^2}[/tex]

[tex]\Delta s = p(\dfrac{h}{4 \pi gm^2 }) \times \dfrac{1}{ \Delta s}}[/tex]

[tex](\Delta s)^2 = \dfrac{hmv} {4 \pi gm^2 }[/tex]

here;

v = 2gH

So;

[tex](\Delta s)^2 = \dfrac {h \sqrt{2gH} }{4 \pi gm }[/tex]

[tex]\mathbf{(\Delta s)^2 = \sqrt{\dfrac{h}{2 \pi m}} \sqrt[4]{\dfrac{H}{g}} \sqrt[4]{\dfrac{1}{2}} }[/tex]

Thus, the order = [tex]\mathbf{\sqrt{\dfrac{h}{2 \pi m}} \sqrt[4]{\dfrac{H}{g}} \sqrt[4]{\dfrac{1}{2}} }}[/tex]

Answer:

579600J

Explanation:

Given parameters:

Height of the building  = 828m

Weight of the man  = 700N

Unknown:

Work done by the man  = ?

Solution:

The work done by the man is the same as the potential energy expended.

 Work done:

             Work done  = Weight x height  = 700 x 828

        Work done  = 579600J

Answer:

69.62 minutes

Explanation:

From the information we have here,

1 byte is = 8 bits

So 1 megabyte = 8 megabits

Then

783.216 x 8 megabits = 6265.728 megabits

This player has its reading capacity at 1.5 megabits / second

So 1 minute = 60x1.5

= 90 megabits / min

Then we have the entire reading time of this CD player to be =

6265.728/90

= 69.62 minutes.

This answers the question

Answer:

Ultraviolet radiation

Explanation:

The type of electromagnetic radiation most likely to cause skin cancer as a result of sun exposure overtime is the ultraviolet radiation.

Electromagnetic radiation occurs with a broad spectrum starting from gamma rays to the radio waves.

From one end to the other, their energy decreases as the wavelength increases.

Within this broad spectrum, the ultraviolet rays which are before the visible rays are very energetic and can cause skin cancer.

Answer:

ultraviolet i think sorry if im wrong :/

Explanation:

Answer:

240 meters

Explanation:

The distance traveled by the vehicle can be calculated using the following equation:

[tex] v_{f}^{2} = v_{0}^{2} + 2ax [/tex]   (1)

Where:

x: is the displacement

[tex]v_{f}[/tex]: is the final speed = 0 (reduces its velocity back to zero)                    

[tex]v_{0}[/tex]: is the initial speed = 60 m/s

a: is the acceleration = -7.5 m/s²

By solving equation (1) for x we have:

[tex] x = \frac{v_{f}^{2} - v_{0}^{2}}{2a} = \frac{0 - (60 m/s)^{2}}{2*(-7.5 m/s^{2})} = 240 m [/tex]

Therefore, the vehicle undergoes 240 meters of displacement during the deceleration period.

I hope it helps you!

The question is incomplete, the complete question is;

A student is measuring the mass of 20 paper clips using an electric balance that measures to the thousandths of a gram. The balance displays the following values for the mass of the paper clip: 20.120 g.

Which of the following choices would be acceptable ways to record this mass on a lab report? Select all that apply.

a) 20g

b) 20.1 g

c) 20.12 g

d) 20.120g

e) 20.1200g

Answer:

d) 20.120g

Explanation:

We have been told in the question that the electronic balance measures the mass of the paper clips to thousandths of a gram.

This implies that the value of mass is measured to the third decimal place.

If we look at the options, 20.120 g is the measurement of the mass to thousandths of a gram hence that is the correct answer to the question.

Answer:

the diameter of the second pipe is 2.52 in

Explanation:  

Given the data in the question;

We know that; the rate of flow is the same;

so

Av1 = Av2

v ∝ √h

[tex]\frac{A1}{A2}[/tex] = [tex]\frac{V2}{V1}[/tex]

[tex]\frac{A1}{A2}[/tex]  = √(  [tex]\frac{h2}{h1}[/tex] )

( π/4.D1² / π/4.D2² ) = √(  [tex]\frac{h2}{h1}[/tex] )

( D1² / D2² ) =  √(  [tex]\frac{2h1}{h1}[/tex] ) since second is double of first

so

( D1² / D2² ) =  √(  [tex]\frac{2}{1}[/tex] )  

3² / D2² =  √2

D2²√2  = 9

D2² = 9/√2

D2² = 9 / 1.4142

D2² = 6.364

D2 = √ 6.364

D2 = 2.52 in

Therefore, the diameter of the second pipe is 2.52 in

Answer:

3.33 m

Explanation:

Pressure is the distributed force applied to the surface of an object per unit area. The force is applied perpendicular to the surface of the object. The SI unit of pressure is N/m² or Pa.

Hydrostatic pressure is the pressure that a fluid exerts at a point due to the force of gravity.

The relationship between  pressure on the bottom of the container,  atmospheric pressure and the pressure due to the depth of the fluid is given by:

[tex]P_{bottom}-P_{atm}=P_{depth}\\\\where\ P_{bottom}=pressure\ at\ the \ fluid\ bottom,\ P_{atm}=atmospheric\ pressure\\P_{depth}=pressure\ due\ to\ fluid\ depth=\rho gh. \ Hence:\\\\P_{bottom}-P_{atm}=\rho gh\\\\Given \ that\ P_{bottom}=115\ kPa=115*10^3\ Pa, let\ us\ assume\ P_{atm}=101\ kPa=101*10^3\ Pa,\rho=420\ kg/m^3,g=acceleration\ due\ to \ gravity=10\ m/s^2.\\\\Therefore:\\\\115*10^3-101*10^3=420*10*h\\\\14*10^3=4200h\\\\h=3.33\ m\\\\[/tex]

Answer:

A feedback mechanism is the constant measurement of the distance between the two vehicles and with this the calculation of the speed between them

An anticipated control mechanism is using the vehicle's acceleration and its deceleration to calculate the future speed and their distances,

Explanation:

For this exercise, the feedback and control mechanisms must be directly related to the kinematic relationships,

It is assumed that the vehicle speed (taken from the speedometer) and the braking capacity (given by the brake manufacturer) are known in the form of negative acceleration,

A feedback mechanism is the constant measurement of the distance between the two vehicles and with this the calculation of the speed between them, for which we know the acceleration that exists. This would be a correct mechanism, in general we can adjust to an error between the sedated distance and the real one, so when they have very different give a maximum acceleration and in decreasing it as the differences between the distances decrease.

An anticipated control mechanism is using the vehicle's acceleration and its deceleration to calculate the future speed and their distances, so we would know the amount of acceleration necessary to reach the optimal distance between the two vehicles.

Distance and time I think

Answer:

C) 128 kg*m/s

Explanation:

When you double something you multiply it by 2 most of the time. 64*2=128 or you can add it 64+64=128. Hope this helps.

Answer:

The specific heat of the unknown material is 131.750 joules per kilogram-degree Celsius.

Explanation:

Let suppose that sphere is cooled down at steady state, then we can estimate the rate of heat transfer ([tex]\dot Q[/tex]), measured in watts, that is, joules per second, by the following formula:

[tex]\dot Q = m\cdot c\cdot \frac{T_{f}-T_{o}}{\Delta t}[/tex] (1)

Where:

[tex]m[/tex] - Mass of the sphere, measured in kilograms.

[tex]c[/tex] - Specific heat of the material, measured in joules per kilogram-degree Celsius.

[tex]T_{o}[/tex], [tex]T_{f}[/tex] - Initial and final temperatures of the sphere, measured in degrees Celsius.

[tex]\Delta t[/tex] - Time, measured in seconds.

In addition, we assume that both spheres experiment the same heat transfer rate, then we have the following identity:

[tex]\frac{m_{I}\cdot c_{I}}{\Delta t_{I}} = \frac{m_{X}\cdot c_{X}}{\Delta t_{X}}[/tex] (2)

Where:

[tex]m_{I}[/tex], [tex]m_{X}[/tex] - Masses of the iron and unknown spheres, measured in kilograms.

[tex]\Delta t_{I}[/tex], [tex]\Delta t_{X}[/tex] - Times of the iron and unknown spheres, measured in seconds.

[tex]c_{I}[/tex], [tex]c_{X}[/tex] - Specific heats of the iron and unknown materials, measured in joules per kilogram-degree Celsius.

[tex]c_{X} = \left(\frac{\Delta t_{X}}{\Delta t_{I}}\right)\cdot \left(\frac{m_{I}}{m_{X}} \right) \cdot c_{I}[/tex]

If we know that [tex]\Delta t_{I} = 6.35\,s[/tex], [tex]\Delta t_{X} = 4.59\,s[/tex], [tex]m_{I} = 0.515\,kg[/tex], [tex]m_{X} = 1.263\,kg[/tex] and [tex]c_{I} = 447\,\frac{J}{kg\cdot ^{\circ}C}[/tex], then the specific heat of the unknown material is:

[tex]c_{X} = \left(\frac{4.59\,s}{6.35\,s} \right)\cdot \left(\frac{0.515\,kg}{1.263\,kg} \right)\cdot \left(447\,\frac{J}{kg\cdot ^{\circ}C} \right)[/tex]

[tex]c_{X} = 131.750\,\frac{J}{kg\cdot ^{\circ}C}[/tex]

Then, the specific heat of the unknown material is 131.750 joules per kilogram-degree Celsius.

Answer:

58.8J

Explanation:

Given parameters;

Mass of ball  = 4kg

Height above the floor  = 1.5m

g  = 9.8n/kg

Unknown:

Potential energy  = ?

Solution:

The potential energy of a body is the energy due to the position of the body.

It is mathematically expressed as:

  Potential energy = mass x acceleration due to gravity x height

  Potential energy  = 4 x 9.8 x 1.5  = 58.8J

Answer:

Explanation:

It takes 3.1 s for the boat to travel from its highest point to its lowest, so the period of oscillation

T = 2 x 3.1 = 6.2 s

frequency of wave n = 1 / T = .1613 per sec

Amplitude of oscillation = .55/2 = .275 mm

The fisherman sees that the wave crests are spaced 4.2 mm apart. so wavelength of wave λ = 4.2 mm .

A ) velocity of wave v = n λ

.1613 x 4.2 = .677 mm /s

B ) Amplitude of wave = .275 mm

C ) The vertical distance determines only the amplitude which does not affect the velocity , so velocity will remain unchanged .

D ) Amplitude of wave depends only on the vertical displacement .

The amplitude will become .5 / 2 = .25 mm .

Distance = (speed) x (time)

Car A: Distance = (8 m/s) x (43 s)  =  344 meters

Car B: Distance = (7 m/s) x (50 s)  =  350 meters

350 meters is a longer distance than 344 meters.

Car-B traveled a longer distance than Car-A did.

Answer:

[tex]\boxed {\boxed {\sf Car \ B : 350 \ meters }}[/tex]

Explanation:

Distance is equal to the product of speed and time.

[tex]d=s*t[/tex]

1. Car A

Car A has a speed of 8 meters per second and travels for 43 seconds.

[tex]s= 8 \ m/s \\t= 43 \ s[/tex]

Substitute the values into the formula.

[tex]d= 8 \ m/s *43 \ s[/tex]

Multiply and note that the seconds will cancel out.

[tex]d= 8 \ m*43= 344 \ m[/tex]

2. Car B

Car B has a speed of 7 meters per second and travels for 50 seconds.

[tex]s= 7 \ m/s \\t= 50 \ s[/tex]

Substitute the values in and multiply.

[tex]d= 7 \ m/s * 50 \ s[/tex]

[tex]d= 7 \ m * 50 = 350 \ m[/tex]

350 meters is a longer distance than 344 meters, so Car B traveled the longer distance.

Ans:

C

Explanation:

because it is moving down the stairs

A spring travelling down a flight of stairs has kinetic energy.

Since it is moving, it would be a spring moving down a set of steps. A stretched spring, a compressed spring, and a spring at the top of a set of steps are all in motion.

Kinetic energy is a type of power that a moving object or particle possesses.

An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force. A moving object or particle has kinetic energy, which depends on both its mass and its rate of motion.

Therefore, A spring travelling down a flight of stairs has kinetic energy.

To learn more about Kinetic energy, refer to the link:

https://brainly.com/question/26472013

#SPJ5

Answer:

ummm hehe this is my time to shine

Explanation:

  MERICIA!!!!!!!!!!!!!!!!!!!!!!!

Answer:

My biggest reason is to make it a habit. Even if the ball goes into the endzone it is a live ball and the offensive players must down the ball. Don't leave any room for "I thought he downed it" or "I thought I heard the whistle" just run to the ball always.

If the players slow down and the returner takes it out of the end zone it could be a big return. Players are on a full sprint for 40+ yards sometimes and instead of breaking down, they choose to contine through the goal line to slow down at a decreased rate (possibly limiting a muscle pull injury).

Answer:

[tex]q=7.965*10^-^6C[/tex]

Explanation:

From the question we are told that

Altitude of  [tex]d_1 390m[/tex]

Magnitude[tex]M_1=60.0 N/C[/tex]

Altitude of [tex]d_2=240 m[/tex]

Magnitude is [tex]M_2= 100 N/C[/tex]

Distance of cube [tex]d_c=150 m[/tex]

Generally the flux [tex]\phi[/tex] is mathematical given as

 [tex]\phi=60(150)^2cos180+100(150)^2*cos0[/tex]

 [tex]\phi=-9*10^5[/tex]

Generally Quantity of charge  q is mathematically given as

 [tex]q=\varepsilon _0 *\phi[/tex]

 [tex]q=8.85*10^-^1^2 *9*10^5[/tex]

 [tex]q=7.965*10^-^6C[/tex]

Answer and Explanation: To know how much tape he will need, we have to calculate the perimeter of each parallelogram-shaped stripe.

Perimeter is the sum of all the sides of a figure.

For a parallelogram:

P = 2*length + 2*width

So, we need to determine width and length of the stripe.

Width is 3 inches. Length is the hypotenuse of the right triangle, whose sides are 6 and 18 inches. Then, length is

[tex]h=\sqrt{18^{2}+6^{2}}[/tex]

[tex]h=\sqrt{360}[/tex]

h = 19 in

Perimeter of the first stripe is

P = (2*19) + (2*3)

P = 44 inches

The hazard sign has 3 stripes. So total perimeter is

[tex]P_{t}=[/tex] 44 + 44 + 44

[tex]P_{t}=[/tex] 132 inches

To outline the parallelogram-shaped stripes, Charles need a total of 132 inches of tape. Since one roll has 144 inches, he will have enough tape to finish the job.

Answer:

[tex]m=1.63\times 10^{-27}\ kg[/tex]

Explanation:

The velocity of a particle is 90% of the speed of light.

The wavelength of the particle is [tex]1.5\times 10^{-15}\ m[/tex]

We need to find the mass of the particle.

The formula for the wavelength of a particle is given by :

[tex]\lambda=\dfrac{h}{mv}[/tex]

h is Planck's constant

v is 90% of speed of light

m is mass of the particle

[tex]m=\dfrac{h}{\lambda v}\\\\m=\dfrac{6.63\times 10^{-34}}{1.5\times 10^{-15}\times 0.9\times 3\times 10^8}\\\\m=1.63\times 10^{-27}\ kg[/tex]

So, the mass of the particle is [tex]1.63\times 10^{-27}\ kg[/tex].

Answer:

a)[tex]V=\pi *r^2 * \sqrt{2gd}[/tex]

b)[tex]dh / dt = 0.2658 mm / min[/tex]

Explanation:

From the question we are told that

Diameter of hole [tex]d_h=4mm=>0.004m[/tex]

Depth of hole [tex]D=0mm=>0.001m[/tex]

Diameter of tank [tex]d_t=2mm=>0.002m[/tex]

Generally the equation for pressure is mathematically given as

[tex]Pressure P= \rho*g*d[/tex]

[tex]P= 1/2*\rho *v^2[/tex]

Where

[tex]v = \sqrt {2gd}[/tex]

[tex]V = Area*v[/tex]

[tex]V=\pi *r^2 * \sqrt{2gd}[/tex]

Generally the level at which the water level will initially drop if the water is not replenished is mathematically given by

[tex]dh / dt = (r/R)^2 *sqrt{2gd}\\dh / dt = (2/2000)^2 *sqrt(2*9.81*1) \\dh / dt = 4.429*10^-3 mm/s \\[/tex]

Therefore the level at which the water level will initially drop if the water is not replenished

[tex]dh / dt = 0.2658 mm / min[/tex]

The rate, in mm/min, at which the water level will initially drop will be 1.0625 mm/min.

Given data:

The diameter of hole is, d = 4.0 mm = 0.004 m.

The depth of hole is, h = 1.0 m.

The diameter of tank is, d' = 2.0 m.

The given problem is based on the flow rate, which is defined as the flow of liquid through a given section per unit time.

Let us first obtain the equation of pressure as,

[tex]P=\dfrac{1}{2} \times \rho \times v^{2}[/tex]

Here, v is the velocity of efflux and its value is,

[tex]v=\sqrt{2gh} \\\\v^{2}=2gh[/tex]

And the level at which the water level will initially drop if the water is not replenished is mathematically given by,

[tex]\dfrac{dH}{dt}=(r/R)^{2} \times v[/tex]

Here,

r is the radius of hole.

R is the radius of tank.

Solving as,

[tex]\dfrac{dH}{dt}=((d/2) /(d'/2))^{2} \times \sqrt{2gh} \\\\\dfrac{dH}{dt}=((0.004/2) /(2/2))^{2} \times \sqrt{2 \times 9.8 \times 1}\\\\\dfrac{dH}{dt}=1.77 \times 10^{-5} \;\rm m/s\\\\\dfrac{dH}{dt}=1.77 \times 10^{-5} \times 6 \times 10^{4} \;\rm mm/min\\\\\dfrac{dH}{dt}=1.0625 \;\rm mm/min[/tex]

Thus, we can conclude that the rate, in mm/min, at which the water level will initially drop will be 1.0625 mm/min.

Learn more about the flow rate here:

https://brainly.com/question/11816739

Answer:

I think it is heterogeneous mixture. have a good day

Answer:

heterogeneous mixture

Explanation:

i took the test

Answer:

3kg

Explanation:

Given parameters:

Force  = 9N

Acceleration  = 3m/s²

Unknown:

Mass = ?

Solution:

From Newton's second law of motion:

        Force  = mass x acceleration

So;

             9  = mass x 3

             mass  = 3kg

Answer:

6N

Explanation:

Given parameters:

Mass of object  = 6kg

Initial velocity  = 5m/s

Final velocity  = 25m/s

Time  = 30s

Unknown:

Net force acting on the object  = ?

Solution:

From Newton's second law of motion:

   Force  = mass x acceleration

Acceleration is the rate of change of velocity with time

  Acceleration  = [tex]\frac{Final velocity - Initial velocity }{time}[/tex]  

  Force  = mass x  [tex]\frac{Final velocity - Initial velocity }{time}[/tex]  

So;

 Force  = 6 x [tex]\frac{25 - 5}{30}[/tex]    = 6N

Answer:

Action-at-a-Distance Forces. Frictional Force. Gravitational Force. Tension Force ... The force of gravity on earth is always equal to the weight of the object as ... The friction force is the force exerted by a surface as an object moves across it or ... The force of air resistance is often observed to oppose the motion of an object

Explanation:

Answer:

I believe the answer is gravity.

Explanation:

Because with friction you need to be rubbing multiple object together, in tension two objects must be pulling against each other, and in air resistance the air must be touching the object either pushing or pulling it. While in gravity the mass of an object is pulling another object toward it, the objects don't have to be touching each other making it an at-a-distance force.