How much force is needed to accelerate a 1.5 kg physics book to an acceleration of 6
m/s^2?

Answers

Answer 1

Answer:

Force = 8.0 k g m / s

Explanation:

Force = mass x acceleration

Mass = 4.0 k g Acceleration = 2.0 m / s 2

Hence,force = ( 4.0 x 2.0 ) k g m / s 2 = 8.0 k g m / s 2


Related Questions

Rust, or iron oxide, ___________.
Group of answer choices

A is the result of rainwater and oxygen combining with iron

B leaves dark streaks across rocks

C is formed by chemical erosion

D All of the above.

Answers

I think it’s D

God bless!! <3

Answer:

D

Explanation:

because all are reffering to the answer you need

Which best explains the surface tension of water? capillary action cohesion adhesion sublimation

Answers

Answer:

Cohesion

Explanation:

Surface tension of water refers to the ability of the surface of water as a liquid to resist an external force. Surface tension of a liquid like water is dependent on the force of attraction that hold its molecules to one another, which is a force called COHESIVE FORCE.

Cohesion is a property of water characterized by the ability of water molecules to be attracted to one another. This cohesive property causes its molecules to be able to resist external forces or in other words is responsible for the SURFACE TENSION. Hence, the stronger the cohesive force between molecules of a liquid, the higher the surface tension.

A box sitting still on the ground by itself has a Normal Force of 700N, what is the mass? (gravity’s acceleration is 9.80 m/s²)

Answers

Answer:  71.43 kilograms

This value is approximate rounded to two decimal places.

=====================================================

Explanation:

The ground is pushing up with a normal force of 700 N. Because the box is sitting still, this means the force of gravity is pulling the box down with a force of 700N to keep things balanced.

If the force of gravity was greater than 700N, then the box would fall through the ground. If the force of gravity was smaller than 700N, then the box would be accelerated upward. Since neither event is happening, the force of gravity must be equal to the normal force.

Now turn to Newton's second law which says

F = ma

where F is the force, m is the mass and 'a' is the acceleration. We're given the acceleration of gravity is roughly 9.80 m/s^2. So a = 9.80

The force we'll plug in is F = 700. The value of m is unknown, but we can solve for it as such

F = ma

700 = m*9.80

700 = 9.08m

9.80m = 700

m = 700/9.80

m = 71.4285714285714

m = 71.43

The mass is roughly 71.43 kilograms.

a jet can travel at 400 minutes per second how far will it travel at this speed in 3 seconds​

Answers

400 * 3 = 1200
A jet can travel 1200 minutes for 3 seconds

Answer:

1200

Explanation:

What is power the quotient of?

A.speed and energy

B.work and time

C.speed and distance

D.work and distance

Answers

Physics

Power quotient of : _____?

Answer :

[tex]p = \frac{w}{t} [/tex]

P is Power (Watt)

W is Work (Joule)

T is Time (second)

So, it means Work and Time is the quotient of Power. (B)

A ball is thrown with initial velocity 20 meter per second by making an angle 30 degree with a horizontal then find time of flight.

Answers

Answer:

[tex]\huge\boxed{\sf T = 2.04\ secs}[/tex]

Explanation:

Given Data:

Initial Velocity = [tex]\sf V_{i}[/tex] = 20 m/s

Angle = [tex]\sf \theta[/tex] = 30°

Acceleration due to gravity = g = 9.8 m/s²

Required:

Time of flight = T = ?

Formula:

[tex]\sf T = \frac{2\ V_{i}\ sin\theta}{g}[/tex]

Solution:

Putting values in the above formula

T = 2(20)sin 30 / 9.8

T = 40 (0.5) / 9.8

T = 20 / 9.8

T = 2.04 secs

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AnonymousHelper1807

Weathered rocks and soil are moved by _____?

A. Weathering
B. erosion
C. cycles
D. deposition ​

Answers

Answer:

The correct answer is B

2. If a car accelerates uniformly at a rate of
4.0 m/s2, how long will it take to reach a speed of 20
m/s, starting from rest?

Answers

Answer:

The car will take 5 seconds

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes uniformly in time.

If the object starts from a speed vo during a time t with an acceleration a, then its final speed is:

[tex]v_f=v_o+at[/tex]

The car is accelerating at a rate of a= 4~m/s^2 and reaches a speed of vf=20 m/s starting from rest (vo=0).

From the equation shown above, we solve for t:

[tex]\displaystyle t=\frac{v_f-v_o}{a}[/tex]

[tex]\displaystyle t=\frac{20-0}{4}[/tex]

[tex]\displaystyle t=\frac{20}{4}[/tex]

t = 5 seconds

The car will take 5 seconds

a student compared two samples of matter. he recorded the results in the chart. Sample A: Appearance: shiny and yellow. Sample B: Appearance: Dull and yellow. Which property do the two samples have in common? A. volume. B. color

Answers

Answer:

The answer are B

Explanation:the two samples haves yellow color :)

Answer:

B or 2

Explanation:

both of the samples contain a yellow color.

A jet is flying from atlanta to gulfport and is cruising at Mach .79 or 844 km/hr. During the last 89 km it reduces its speed for landing at a rate of -2780 km/hr^2. How long will it take for the jet to reach landing speed? What was the landing speed of the jet?

Answers

Answer:

The time it takes for the jet to reach landing speed is approximately 0.136 hours which is approximately 489 seconds

The landing speed is approximately 466.365 km/hr

Explanation:

The given parameters are;

The initial cruising speed of the jet = Mach 0.79 = 844 km/hr

The rate of speed reduction in the last 89 km = -2780 km/hr²

The distance it  takes the jet to reduce its speed for landing = 89 km

Given the above information,  we make use of the following equation of motion;

s = u·t - 1/2·a·t²

v² = u² - 2·a·s

Where;

s = The distance over which the acceleration (deceleration) is applied = 89 km

u = The initial velocity = 844 km/hr

t = The time taken for the accelerating/decelerating motion

v = The final velocity (landing speed)

Substituting the values gives;

v² = 844² - 2·(2780)·89 = 217496

v = √217496 = 466.365 km/hr

v ≈ 466.365 km/hr

Therefore, the landing speed, v  ≈ 466.365 km/hr

The time it takes is given by the equation, v = u - a·t

Therefore;

t = (u - v)/a = (844 - 466.365)/2780 ≈ 0.136 hours

The time it takes for the jet to reach landing speed ≈ 0.136 hours

From, s = u·t - 1/2·a·t², we have

89 = 844·t - 1/2 × 2780 × t²

89 = 844·t - 1390 × t²

1390 × t² - 844·t + 89 = 0

Solving with an online application gives;

t = 211/695 + (√(27187/2))/695 = 0.4715 hours or t = 211/695 - (√(27187/2))/695 = 0.136 hours

We note that the second time is for the time it will take the jet to get back to 89 km after reaching a speed of 0

Therefore, the correct time is t = 0.136 hours

The time it takes for the jet to reach landing speed ≈ 0.136 hours

Does this graph represent an endothermic or an exothermic reaction

Answers

Answer:

the graph represents an endothermic reaction

Explanation:

remember:

endo- inside

exo- out

Here photosynthesis in a nutshell. Can you explain what is happening?

Answers

Answer:

Photosynthesis is the process of using water, carbon dioxide and sunlight to produce sugar. The process of photosynthesis requires specialized cellular structures called chloroplasts to capture energy from the Sun and converted into chemical energy.

Explanation:

Someone is most likely to walk gingerly in order to do which of the following?
A.exercise his legs
B.trace his steps
C.keep from making noise
D.break in his shoes

I NEED HELP ASAP

Answers

Answer:

I think it a

Explanation:

Answer:

c

Explanation:

A truck with an overall mass of 6,500 kg is accelerating at 0.3 m/s2. What force does the engine need to apply in order to do this? (Round to the nearest tenth of a decimal.)

Answers

Answer:

1950 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 6500 × 0.3

We have the final answer as

1950 N

Hope this helps you

what are some examples of focus

Answers

Some examples of focusing is a person studying, even a camera focusing on an object!

What is the mass number of an atom that has 5 protons and 7 neutrons? I give brainliest.

Answers

Answer:

The atomic mass of an atom that has 5 protons and 7 neutrons would be 12.

Explanation:

In all cases, the number of protons added to the number of neutrons equate to the mass of an atom. Electrons do have mass, but it's so miniscule and insignificant that it doesn't contribute to the overall mass of the atom, so there's no need to count them.  

Bonus Information:

DO NOT CONFUSE MASS WITH CHARGE! Protons and neutrons are the only particles that contribute to the mass of an atom. Meanwhile, protons (+) and electrons (-) are the only particles that have a charge. As it says in its name, neutrons are neutral or have no charge.

Remember:

C = p - e

M = p + n

C = atomic charge, M = atomic mass, p =protons, n = neutrons, e = electrons

I hope this helps!

The critical angle of diamond is 24 degrees. What is its refractive index?

Answers

Answer:

2.46

Explanation:

From the question given above, the following data were obtained:

Critical angle (C) = 24 °

Refractive index (n) =?

The refractive index of the diamond can be obtained by using the following formula as illustrated below:

Refractive index (n) = 1 / sine [critical angle (C)]

n = 1/sine C

n = 1 / sine 24 °

n = 1/0.4067

n = 2.46

Thus, the refractive index of the diamond is 2.46

4.5 x 10kg) - (2.3 x 10 kg)

Answers

Answer:

22 kg

Explanation:

I hope this helps!

Answer:

22 kilograms

Hope it helps :) (if it does can i pls have brainliy thing)

Determine the average speed of a runner who runs 15 Km in one hour and 30 minutes

Answers

v=d/t
v=15/90
v=0.16 km/min

Phich instrument can be used to give a direct measurement of the mass of a rock on moon

Answers

Answer:

you can use a balance

Explanation:

when you tend to measure something you are using your brain so why dont you use your brain dimwitt

do heavier objects fall faster than lighter objects?

Answers

Answer:

Heavy objects fall at the same rate (or speed) as light ones. The acceleration due to gravity is about 10 m/s2 everywhere around earth, so all objects experience the same acceleration when they fall.

Explanation:

Very few people have a definite and pure somatotype. True False​

Answers

the answer is true (for 20 characters long)

Answer: True

Explanation: I got it right on my test :)

A hollow ball with a diameter of 3.81 cm has an average density of 0.0842 g/cm3. What force must be applied to hold it stationary while it is completely submerged under water? (Enter the magnitude in N, and select the direction from the options given.)

Answers

Answer:

0.26

Explanation:

Given that :

Diameter of ball = 3.81 cm = 3.81/100 = 0.0381 m

Radius (r) = 0.0381 / 2 = 0.01905 m

Average density of ball (Db) = 0.0842 g/cm³ = (0.0842 / 1000)kg / 10^-6 = 0.0842/ 1000 * 10^6 = 84.2kg/m³

Density of water (Dw) = 1000kg/m³

Volume of hollow ball: (4/3) * pi * r³

V = (4/3) * π * 0.01905^3

V = 0.0000289583 m³

Required force = (Dw * V * g) - (Db * V * g)

= (1000 * 0.0000289583 * 9.8) - (84.2 * 0.0000289583 * 9.8)

= 0.259896109172

= 0.2598 N

To determine the force that must be applied to the hollow ball to hold it stationary while it is completely submerged under water is 0.2243 Newton.

Given the following data:

Diameter of hollow ball = 3.81 cmDensity of hollow ball = 0.0842 [tex]g/cm^3[/tex]

Density of water = 1000 [tex]kg/m^3[/tex]

Conversion:

Diameter of hollow ball = 3.81 centimeters to meters = [tex]\frac{3.81}{100} = 0.0381\;m[/tex]

Density of hollow ball = 0.0842 [tex]g/cm^3[/tex] to [tex]kg/m^3[/tex] = [tex]\frac{0.0842 \times 10^6}{1000} = 84.2 \;kg/m^3[/tex]

To determine the force that must be applied to the hollow ball to hold it stationary while it is completely submerged under water:

First of all, we would calculate the volume of the hollow ball by using the formula:

[tex]Volume = \frac{4}{3} \pi r^3\\\\Volume = \frac{4}{3} \times 3.142 \times 0.01905^3\\\\Volume = 4.19 \times 0.0000069\\\\Volume = 0.000029 \;m^3[/tex]

Next, we would find the force required for water and the hollow ball:

For water:

[tex]F_w = D_wVg\\\\F_w = 1000 \times 0.000029 \times 9.8\\\\F_w = 0.2842\; Newton[/tex]

For hollow ball:

[tex]F_h = D_hVg\\\\F_h = 84.2 \times 0.000029 \times 9.8\\\\F_h = 0.0239\; Newton[/tex]

Now, we can find the force that must be applied to the hollow ball:

[tex]Force = F_w - F_h\\\\Force = 0.2482 - 0.0239[/tex]

Force = 0.2243 Newton

Read more: https://brainly.com/question/18320053

1. What are the characteristics of winds?
2. The wind vane should be located well above the ground. Why?
3. Describe cup anemometers

Answers

Answer:

wind has two important things that is direction and speed.

Distinguish between average speed and average
velocity​

Answers

Answer:

The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time.

How often should muscle strengthening activities be performed?
A-Never
B-Once a week
C-Twice a week
D-At least three times per week

Answers

Answer:

once a week

Explanation:

once a week so answer B

Answer:

B-Once a week

Explanation:

You answer is B-Once a week

A person with a mass of 40 kg is sitting on a box. What is the value of the normal force

Answers

normal force=mass*gravitational force

normal force=40*0

normal force=40

D. 1
1.212.52
-2
12
12

Answers

Answer:

what?

Explanation:

I WILL GIVE BRAIN LIST PLS HELP

Answers

Answer:

C is corret answer okay

Temperatures of gases inside the combustion chamber of a four‑stroke automobile engine can reach up to 1000°C. To remove this enormous amount of heat, the engine utilizes a closed liquid‑cooled system that relies on conduction to transfer heat from the engine block into the liquid and then into the atmosphere by flowing coolant around the outside surface of each cylinder.

Suppose that, in a particular 4‑cylinder engine, each cylinder has a diameter of 8.75 cm, a height of 11.3 cm, and a thickness of 3.14 mm. The temperature on the inside of the cylinders is 195.2°C, and the temperature outside, where the coolant passes, is 130.0°C. The temperature of the incoming liquid (a mixture of water and antifreeze) is maintained at 95.0°C.

What volume flow rate of coolant [tex]\frac{V}{t}[/tex] would be required to cool this engine? Assume that the coolant reaches thermal equilibrium with the outer cylinder walls before exiting the engine. The specific heat of the coolant is 3.75 J/g°C and its density is 1.070×103 kg/m3. The cylinder walls have thermal conductivity of 1.10×102 W/m⋅∘C. Assume that no heat passes through the ends of the cylinders.

Answers

Answer:

thats a lot, which one u want me to do?

Explanation:

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