how much dose the least expensive 50 present of trail mix cost? what is the least of 4 pounde of trail mix can cost

The box-whisker plot is missing. Check the attachment for the data.

The least expensive 50% of trail mix costs between $1.25 and $2.75 per pound, as these, depict the minimum point and the median (50% of data), of the given box-whisker plot.

The least 4 pounds of trail mix can cost $6.00, at the minimum rate shown in the box-whisker plot by its starting point of $1.25 per pound.

A box-whisker plot is a diagrammatic representation of data. The whiskers start from the minimum data and go up to the maximum. In between the whiskers is a box that starts from the first quartile of the data (below which 25% of the data lies) and goes up to the third quartile (below which 75% of the data lies). In between the box is a line, that indicates the median of the data. The median is the value of the middlemost data.

In the question, we are given a box-whisker plot, showing the different costs of trail mix at different prices per pound.

1. We are asked how much the least expensive 50% of trail mix costs.

We know that 50% of data is depicted at the median which is the line in between the box in a box-whisker plot. So the least expensive 50% is shown before the line.

The minimum point in the data is $1.25 and the median is $2.75.

Hence, the least expensive 50% of trail mix costs between $1.25 and $2.75 per pound, as these depict the minimum point and the median (50% of data), of the given box-whisker plot.

2. We are asked to find the least cost of 4 pounds of the trail mix.

We know that the starting point of the whisker shows the minimum point in the data. Hence, the least cost of the trail mix is $1.25 per pound.

So, the cost of 4 pounds is $1.25 * 4 = $6.00.

Hence, the least 4 pounds of trail mix can cost $6.00, at the minimum rate shown in the box-whisker plot by its starting point of $1.25 per pound.

Learn more about the box-whisker plots at

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Selena and Drake are evaluating the expression (StartFraction r s Superscript negative 2 Baseline Over r squared s Superscript negative 3 Baseline EndFraction) Superscript negative 1, when r = negative 1 and s = negative 2.


Selena’s Work
Drake’s Work

(StartFraction r s Superscript negative 2 Baseline Over r squared s Superscript negative 3 Baseline EndFraction) Superscript negative 1 Baseline = (r Superscript negative 1 Baseline s) Superscript negative 1 Baseline = StartFraction r Over s EndFraction = StartFraction negative 1 Over negative 2 EndFraction = one-half

(StartFraction (negative 1) (negative 2) Superscript negative 2 Baseline Over (negative 1) squared (negative 2) Superscript negative 3 EndFraction) Superscript negative 1 = (StartFraction (negative 1) (negative 2) cubed Over (negative 1) squared (negative 2) squared EndFraction) Superscript negative 1 = (StartFraction negative 8 Over 4 Endfraction) Superscript negative 1 Baseline = StartFraction 4 Over negative 8 EndFraction = negative one-half


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Selena is incorrect because she should have substituted the values for the variables first, and then simplifed.
Selena is correct because she simplified correctly and then evaluated correctly after substituting the values for the variables.
Drake is incorrect because he should have simplified first, before substituting the values for the variables.
Drake is correct because he substituted the values for the variables first, and simplified correctly

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