How many moles of ammonia gas are produced in the following reaction if 25 moles of nitrogen gas reacts with hydrogen?



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N2(g) + 3H2(g). → 2NH3(g)

1 mole of nitrogen gas reacts with 3 moles of hydrogen gas to produce 2 moles of ammonia gas



A.

100 moles

B.

25 moles

C.

50 moles

D.

75 moles

Answers

Answer 1

Answer:

I think b

Explanation:

Answer 2

50 moles of ammonia gas are produced in the following reaction if 25 moles of nitrogen gas reacts with hydrogen. Therefore, the correct option is option C.

What is moles?

In the National System of Units, the mole represents the unit of substance amount. However many elementary units of a particular substance are present inside an object as well as sample is determined by the quantity of that material. There are precisely  6.022×10²³ elementary entities in a mole.

An elementary object may include an atom, any molecule, and ion, an ion pair, or perhaps a subatomic particle like an electron depending upon what the substance is. 

N[tex]_2[/tex](g) + 3H[tex]_2[/tex](g). → 2NH[tex]_3[/tex](g)

moles of nitrogen = 25 moles

the  mole ratio between nitrogen and ammonia is 1:2

moles of nitrogen = 25×2=50 moles

Therefore, the correct option is option C.

To know more about moles, here:

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The main purpose of a buffer solution is just to resist the change in pH so that the pH of the solution won't be much affected when we add an acid or base into it. The added acid or base is neutralized.

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The half life of tritium is 12.3 years. How much sample will remain if you start with 425g of tritium that is found after 4 half lives?

Answers

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A door is made of solid iron and this one-meter stick. How many kilojoules would it take to be to burn a hole 15 centimeters in diameter?

Answers

Answer:

The heat required, to burn a hole 15 cm in diameter through the iron door is 34,370.050 kJ

Explanation:

The information given on the door are;

The thickness of the door, t = One-meter

The diameter of the hole to be burnt out, d = 15 cm = 0.15 m

The latent heat of fusion of iron, [tex]H_f[/tex] = 247 kJ/kg

The density of iron, ρ = 7.874 g/cm³ = 7874 kg/m³

The volume of the iron to be melted off, V = π·d²/4 × t

∴ V = (π × 0.15²/4) × 1 ≈ 0.01767145867

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The heat required, to melt the mass of iron at the melting point temperature and burn a hole 15 cm in diameter, ΔH, is given as follows;

ΔH = [tex]H_f[/tex] × m

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The heat required, to burn a hole 15 cm in diameter through the iron door ΔH = 34,370.050 kJ.

HELP ME PLS ASAP ILL GIVE BRAINLY

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Molality = moles of solute
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Other

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Answer:133.4

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m

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Explanation: Explanation:

Molarity is number of moles of solute divided by number of litres of solution.

M

=

n

V

Rearrange for V to give

V

=

n

M

Number of moles of KCl is the mass divided by the molar mass of KCl which is 75.5 g/mol, so (5/75.5) = 0.0667 moles.

Now plug in the numbers:

V

=

n

m

=

0.0667

0.5

=

0.1334

litres

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c

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Answers

Answer:

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Answers

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Answers

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The excersise can help to understant the concept of mole fraction

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brainliest please!

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I hope this helps, have a blessed day.

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