How many moles of AgI will be formed when 75.0 mL of 0.300 M AgNO3 is completely reacted according to the balanced chemical reaction:
2AgNO₃(aq)+ Cal2(aq)-->2Agl(s)+Ca(NO3)2(aq))

How Many Moles Of AgI Will Be Formed When 75.0 ML Of 0.300 M AgNO3 Is Completely Reacted According To

Answers

Answer 1

The number of moles of AgI that will be formed when 75.0 mL of 0.300 M AgNO₃ is completely reacted is 0.0225 moles.

How to calculate number of moles?

The number of moles of a substance can be calculated from a stoichiometric approach.

Stoichiometry is the study and calculation of quantitative (measurable) relationships of the reactants and products in chemical reactions (chemical equations).

According to this question, the following reaction is given: 2AgNO₃(aq) + Cal2(aq)-->2Agl(s) + Ca(NO3)2(aq)

moles of AgNO₃ = 0.075 × 0.3 = 0.0225 moles

If 2 moles of AgNO₃ reacted to produce 2 moles of AgI, then 0.0225 moles of AgI will also be produced.

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Related Questions

I WILL GIVE 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE

Answers

The solution has a molarity of 0.0924 M.

What is molarity, for instance?

The number of moles of solute per litre of solution is known as molarity.. For instance, water is both the solution and the solute when table salt is dissolved in it. Each mole of sodium chloride weighs 58.44 grammes. 58.44 grammes of sodium chloride are dissolved in one litre of water to produce one molar solution, or 1M.

Moles of solute per litre of solution is known as molarity (M).

Given: moles of NH3 = 0.355, volume of solution = 3.84 L

Molarity = 0.355 moles / 3.84 L = 0.0924 M

Therefore, the molarity of the solution is 0.0924 M.

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How many grams are in 1.48x x 10

Answers

The answer is 14.8 grams, which is option (d).

How many grammes of Sodium chloride are there in 7.8 moles?

Therefore keep in mind that we are using molecular masses here. Therefore, 58 0.5 g of sodium chloride and one more will be obtained. Divide the mass of Sodium chloride by its molar mass to determine the number of moles: 0.941 moles are equal to 55 g/58.44 g/mol. 55 g of Sodium chloride is therefore equal to 0.941 moles of Sodium chloride.

How much is 1 gramme?

A unit of mass is a gramme. One kilogramme weighs one thousandth of a gramme. The weight of a cube of pure water that is one centimetre in size and four degrees Celsius was the original definition of a gramme. The gramme has the sign g.

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Question:

How many grams are in 1.48 x10⁷μg?

1.48 x103³

1.48 x10¹³

1.48

14.8

none of the above

A student wants to help preserve coral reefs which field of study would be most useful ?

Answers

For a student wishing to contribute to the preservation of coral reefs, oceanography would be the most beneficial topic of study because it is ocean-focused.

What are coral reefs?

An underwater environment known as a coral reef is characterized by corals that construct reefs. Coral polyp colonies are bound together by calcium carbonate to build reefs. Stony corals, whose polyps gather together, make up the majority of coral reefs.

Coral reefs offer chances for recreation, serve as a barrier against erosion and storm damage, and support local economies. They are also a source of fresh medications and food. More than 500 million people rely on reefs for safety, income, and food.

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Plants go through seasonal changes from summer to fall because temperatures ___________. A: begin to cool daylight hours decrease.
B: begin to cool and daylight hours in increase.
C: warm up in daylight hours decrease.
Or D: warm up, and daylight hours increase.
30 POINTS IF YOU ANSWER THIS QUESTION ALSO, I HAVE 15 MINS
Also, there’s no science so I picked “ chemistry”

Answers

A: begin to cool and daylight hours decrease.

Plants go through seasonal changes from summer to fall because of the changes in temperature and the length of daylight hours. As summer ends and fall begins, temperatures begin to cool down and the days become shorter. This change in temperature and daylight hours triggers physiological changes in plants, such as the slowing down of growth and the production of pigments like anthocyanins, which give leaves their characteristic red and orange colors in the fall. These changes allow the plant to prepare for the colder winter months and conserve energy for the upcoming spring growth season.

Answer:

a. begin to cool and daylight hours decrease

hope this helps ;)

Using the following reaction, determine the theoretical yield of Acetylsalicylic acid if given 2.31 grams of salicylic acid? (reminder, salicylic acid is the limiting reagent)

Answers

3.01 grams are determined to be the acetylsalicylic acid theoretical yield.

Describe the limiting reagent.

The limiting reagent is a substance that prevents a chemical reaction from occurring completely. When a limiting reagent is used in a chemical reaction, the atoms, molecules, or ions of the other reactant that it (the limiting reagent) reacts with will either stay free or unreacted.

Salicylic acid has a molar mass of 138.12 g/mol. As a result, the quantity of salicylic acid we have is:

n = mass/molar mass i.e. 2.31 g/138.12 g/mol

n = 0.0167 mol

Acetylsalicylic acid has a molar mass of 180.16 g/mol. Theoretically, the production of acetylsalicylic acid is therefore:

mass = n x molar mass

mass = 0.0167 mol x 180.16 g/mol = 3.01 g

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use the balance equation for the haber process, repeated below N2(g)+3H2(G)=2NH3(G)
How many moles of ammonia are produced when 5.0 moles of hydrogen reacts with excess nitrogen

Answers

The moles of the ammonia that is produced is 3.33 moles.

What is the number of moles?

Stoichiometry is an important tool in chemical analysis, and it is used in a wide range of industries, including pharmaceuticals, materials science, and environmental science.

The balanced reaction equation in this case can be given as;

[tex]N_{2} (g)+3H_{2} (g)--- > 2NH_{3} (g)[/tex]

If 3 moles of hydrogen produces 2 moles of ammonia

5 moles of hydrogen will produce 5 * 2/3

= 3.33 moles

Thus we have 3.33 moles of ammonia.

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How many moles of HCl are there in 75.0 mL of 0.150 M HCl?

Answers

Explanation:

Each liter of this solution has .15 moles

.075 Liter  will have   .075 liter * .15 mole/liter = .01125 moles

                                                                 (round as needed)

Final answer:

To calculate the moles of HCl in 75.0mL of a 0.150M solution, first, convert the volume to liters (0.075L). Then, multiply the molarity by the volume in liters to get the moles. Therefore, there are 0.01125 moles of HCl in the solution.

Explanation:

To find out how many moles of HCl are there in 75.0 mL of 0.150 M HCl, you need to understand the concept of molarity. Molarity (M) is defined as the number of moles of solute per liter of solution. Since molarity is expressed in moles/L, to calculate moles we use the formula: moles = Molarity x Volume(L).

First, convert 75.0mL to Liters by dividing by 1000 to get 0.075L.

Then multiply this volume by the molarity to calculate the moles:

0.150M x 0.075L = 0.01125 moles of HCl.

So, there are 0.01125 moles of HCl in 75.0 mL of 0.150 M HCl solution.

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How many grams of water would be formed from 96.0 g NH3 in a reaction represented by the balanced equation below. 4 NH3(g) + 3 O₂(g) → 2 N₂(g) + 6 H₂O(l)​

Answers

Answer:

4 NH3(0) + 3 O2(g) → 2 N2(g) + 6H20() ... How many grams of water would be formed from 96.0 g NH3 in a reaction represented by the balanced equation below.

Missing: 6 ‎H₂O( ‎l)​

Explanation:

We wish to determine the mass of Mg required to react completely with 250mL of 1.0 M HCI. HCI reacts with Mg according to the
equation below.

2HCl(aq) + Mg(s) → MgCl₂(aq) + H₂(g)

How many moles of HCI are present in 250. mL of 1.0 M HCl?

Answers

The number of moles of HCl present in 250. mL of 1.0 M HCl is 0.250 moles.

How to calculate number of moles?

The number of moles of a substance can be calculated using the following expression;

Molarity = no of moles ÷ volume

According to this question, we were given 250. mL of 1.0 M HCl. The number of moles can be calculated as follows;

no of moles of HCl = 0.250L × 1.0M

no of moles of HCl = 0.250 moles

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Answer: .25

Explanation:

For a particular reaction at 121.3 °C, Δ=53.29 kJ/mol , and Δ=623.51 J/(mol⋅K) . Calculate ΔG for this reaction at −79.6 °C.

Answers

At -79.6 °C, the standard free energy change for this reaction is -67.24 kJ/mol.

How to determine standard free energy change?

Use the following equation to calculate the standard free energy change at a different temperature:

ΔG = ΔH - TΔS

where ΔH = enthalpy change, ΔS = entropy change, and T = temperature in Kelvin.

Given:

ΔH = 53.29 kJ/mol

ΔS = 623.51 J/(mol⋅K)

T = -79.6 + 273.15 K = 193.55 K

First, convert ΔH from kJ/mol to J/mol:

ΔH = 53.29 × 10³ J/mol

Next, convert ΔS from J/(mol⋅K) to kJ/(mol⋅K):

ΔS = 623.51 J/(mol⋅K) ÷ 1000 = 0.62351 kJ/(mol⋅K)

Plug in the values:

ΔG = (53.29 × 10³ J/mol) - (193.55 K × 0.62351 kJ/(mol⋅K))

ΔG = 53.29 kJ/mol - 120.53 kJ/mol

ΔG = -67.24 kJ/mol

Therefore, the standard free energy change for this reaction at -79.6 °C is -67.24 kJ/mol.

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Why is the sky blue? Explain with good explanation

Answers

The sky appears blue to us because of a phenomenon known as Rayleigh scattering.

Sunlight is made up of many different colors, each with a different wavelength. When sunlight enters Earth's atmosphere, the shorter blue wavelengths are scattered more easily than the longer red wavelengths. This is because the blue light interacts more with the molecules in the air, causing it to be redirected in many different directions.

As a result, when we look up at the sky, we see the blue light being scattered in all directions, giving the sky its blue color. At sunrise and sunset, when the sun is closer to the horizon, the light has to pass through more of the atmosphere, causing more of the blue light to be scattered away and leaving behind the longer red wavelengths, which gives the sky a reddish or orange hue.

1. Using a graduated cylinder, measure out 50 mL water (H2O) and pour it in a 100 mL beaker 2. Using a balance, measure out 5 g of glucose (C6H12O6) 3. Pour the 5 g of glucose into the 50 mL of water 4. Stir the contents of the beaker using a glass rod 5. Using tweezers, count out 15 pieces of iron (Fe) filings 6. Add the iron filings to the beaker 7. Stir the contents of the beaker using a glass rod During which step(s) was the student handling a pure substance? Responses A Steps 1 and 3Steps 1 and 3 B Step 4 onlyStep 4 only C Steps 1, 2, and 5Steps 1, 2, and 5 D Steps 6 and 7Steps 6 and 7

Answers

The step during which the student handling pure substance is : B.) Step 4 only.

During which step was the student handling pure substance?

In step 4, student added 5 grams of glucose to 50 mL of water, which is a pure substance. Glucose is a compound with the chemical formula C₆H₁₂O₆, and it is a pure substance because it consists of only one type of molecule.

In steps 1, 2, and 5, student was handling water, glucose, and iron filings respectively, but these are not pure substances in those steps because they are mixed with other substances or impurities.

In steps 6 and 7, the student added iron filings to beaker and stirred the mixture, but iron filings are not pure substance either because they may contain impurities or other metals in addition to iron.

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Mangrove trees grow in swampy areas and have strong roots that hold the soil in place. How is this helpful for the environment?


a

They absorb water from the soil.


b

They overtake the environment.


c

They provide wood for humans.


d

They protect the land from eroding

Answers

Mangrove trees' robust roots aid in stabilizing the soil and preventing soil erosion. This is especially crucial in swampy coastal locations, where the soil is frequently loose and prone to wind and wave erosion. Mangrove trees work to stabilize the coastline and stop land erosion by securing the soil in place.

Mangrove trees also aid in removing contaminants from the water, enhancing the quality of the water in coastal areas while serving as an essential home for a variety of wildlife species. Mangrove trees contribute significantly to environmental protection and are an essential component of coastal ecosystems.

Mangrove trees are crucial for environmental preservation because they hold the soil in place and stop erosion in marshy coastal areas. They also provide crucial habitats for numerous wildlife species, stabilize the coastline, and stop the land from being lost to erosion while enhancing water quality by filtering pollutants from the ocean.

Mangrove trees are an essential part of coastal ecosystems overall, and preserving them is essential for preserving a healthy and sustainable environment.

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How many grams of oxygen form when each quantity of reactant completely reacts?

2HgO(s)→2Hg(l)+O2(g)

Answers

When 216.59 g of HgO completely reacts, 16.00 g of O2 will be produced.

The oxygen produced

The balanced chemical equation for the reaction:

2HgO(s) → 2Hg(l) + O2(g)

states that 2 moles of HgO will produce 1 mole of O2.

We can use the molar mass of HgO and the mole ratio of HgO to O2 to calculate the mass of O2 produced from a given mass of HgO.

The molar mass of HgO is 216.59 g/mol (200.59 g/mol for Hg + 16.00 g/mol for O).

So, 1 mole of HgO has a mass of 216.59 g.

According to the balanced equation, 2 moles of HgO produce 1 mole of O2.

Therefore, 1 mole of O2 has a mass of 32.00 g.

Using stoichiometry, we can calculate the mass of O2 produced when a certain mass of HgO reacts completely.

For example, if we start with 216.59 g of HgO (1 mole), then the amount of O2 produced will be 0.5 moles (1 mole of O2 for every 2 moles of HgO), which is equivalent to 16.00 g of O2 (0.5 moles of O2 x 32.00 g/mol).

So, when 216.59 g of HgO completely reacts, 16.00 g of O2 will be produced.

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List all possible values of the magnetic quantum number ml for a 1s electron.

Answers

The magnetic quantum number (ml) represents the orientation of the orbital in three-dimensional space the only possible value of the magnetic quantum number ml for a 1s electron is 0.

What is a quantum ?

Quantum is the smallest possible unit of a physical quantity, such as energy or momentum. It is a fundamental concept in quantum mechanics, which is the branch of physics that deals with the behavior of matter and energy at the atomic and subatomic level.

The idea of quantization was first proposed by Max Planck in 1900, when he discovered that energy is emitted and absorbed in discrete units called "quanta" when studying the behavior of light and blackbody radiation. Later, this idea was extended to other physical quantities, such as the momentum and position of particles.

According to quantum mechanics, the behavior of particles and systems cannot be fully described using classical mechanics, which assumes that particles have definite positions and velocities at all times. Instead, the behavior of particles and systems is described using wave functions, which represent the probability of finding a particle at a given position and time.

The principles of quantum mechanics have important applications in many areas of physics, including atomic and molecular physics, condensed matter physics, and particle physics. They are also the basis.

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Faculty of Science
Department of Chemistry
8/2019 SECOND SEMESTER EXAMINATIONS
351 STATISTICAL MECHANICS AND THERMODYNAMICS
INSTRUCTIONS: Answer any FOUR questions.
Pluck's constant, h: 6.26 x 1034 J.S
zmann constant, k: 1.38 x 10 JK
nic mass Unit, amu: 1.661 x 10-kg
Nag
3Higi
C₂ (N₂) = 27.9 +0.00418T JK mol
C₂ (H₂) = 29.6+0.00231T JK 'mol
C₂ (NH) 29.9+0.00261T JK 'mol"¹
Gas constant, R: 8.314 JK mol
Avogadro constant, L: 6.022 x 10 mol
Speed of light, C: 2.998 x 10" ms¹¹
1. (a) Deduce the translational, rotational and vibrational mode of motion for the following
molecules: (i) NHs (ii) CO₂ (iii) CH.
(b) Calculate the enthalpy change at 800 °C for the reaction:
2NH
اله
November, 2019
UNIT: 4
Time allowed: 3hrs
All 92.2 kJ/mol
=
2. (a) Sate the equipartition law of energy.
(b) Apply the classical theory in calculating the expected heat capacity at constant pressure
for H₂ and Cl2 molecule given that the experimental value for H₂ is 28.86 JK 'mol and that
of Cle is 34.51 JK 'mol Explain the variation in these values.
(b) What will be the C₂ for a monoatomic gas?

Answers

(a) (i) NH3: Translational, rotational, and vibrational modes of motion.

(ii) CO2: Translational and vibrational mode of motion.

(iii) CH4: Translational, rotational, and vibrational modes of motion.

What is a Vibrational Mode of Motion?

This simply refers to the oscillatory movement of a physical system around its equilibrium position. This phenomenon is characterized by a complex interplay of forces and energy transfer mechanisms, which can lead to a wide range of intriguing dynamical behaviors.

The part b of the first question, the reaction given is incomplete, and the products are missing. Please provide the complete balanced chemical equation for the reaction so that the enthalpy change can be calculated.


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Amount of CuO formed when 63.5 g of copper is heated strongly in air is:

Answers

Amount of Cuo formed when 63.5g of copper is heated strongly in air is
A:The mass of CuO formed when 63.5g of Copper is heated strongly in air is 79.5g


1.How do we determine the mass of Cuo formed ?

For that we have to write the balenced equation of the reaction and it is given below

2Cu + O2 -----> 2CuO

We have to determine mass of Cuo formed from the reaction

Molar mass of Cu = 63.55 g/mol

Mass of Cu from balenced equation = 2*63.55 = 127.1 g

Molar mass of CuO = 79.55 g/mol

Mass of Cuo from balenced equation = 2*79.55 = 159.1g

From balenced equation 127.1g of Cu reacted to form 159.1 g of CuO

Thus ,63.5 g of Cu will react to form = (63.5*159.1)/127.1 = 79.5 g

Mass of CuO formed is 79.5 g


2.How do you find the mass of a compound produced ?

Multiply atomic weight from periodic table of each element by the number of atoms of that element present in the compound . Add it all together and put units of grams/mole after the number


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A new band sensation is playing a concert and recording it for a live album to be released this summer. Select all the statements that are true for when the recorded sound moves through the speaker.

a. The frequency or amplitude of the waves will not change.

b. The speaker changes the wave from an electromagnetic wave to a mechanical wave.

c. The waves from the speaker are mechanical waves.

d. The frequency or amplitude of the waves could change.

e. The speaker changes the wave from mechanical wave to an electromagnetic wave.

f. The waves from the speaker are electromagnetic waves.

g. The speaker does not change the wave type.

Answers

Answer:

c. The waves from the speaker are mechanical waves.

d. The frequency or amplitude of the waves could change.

g. The speaker does not change the wave type.

These statements are true. The waves that come out of the speaker are mechanical waves, meaning they require a medium to travel through, such as air or water. The frequency and amplitude of the waves could change, depending on the characteristics of the sound being played through the speaker. The speaker does not change the type of wave from mechanical to electromagnetic, or vice versa.

A sealed container holds 12.0 L of gas
at 2.5 atm pressure. A valve is opened
any some gas escapes. What happens
to the pressure in the container?
A. The pressure remains the same.
B. The pressure increases.
C. The pressure decreases.

Answers

A sealed container holds 12.0 L of gas at 2.5 atm pressure. A valve is opened and some gas escapes. The pressure decreases. Option C is correct.

When a valve is opened in a sealed container of gas, some of the gas molecules inside the container escape.

This means that the total number of gas molecules inside the container decreases, which in turn causes the pressure to decrease. This can be explained by the ideal gas law.

If some gas escapes from the sealed container, the number of gas molecules inside the container decreases.

As a result, the pressure inside the container decreases as well.

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A new band sensation is playing a concert and recording it for a live album to be released this summer. Select all the statements that are true for when the audience hears the sound.

a. The frequency or amplitude of the sound waves will not change.


b. Sound waves that the audience hears are electromagnetic waves.


c. Hearing the sound does not change the wave type.


d. The frequency or amplitude of the sound waves could change as the song plays.


e. Hearing the sound waves changes the wave from mechanical wave to an electromagnetic wave.


f. Hearing the sound waves changes the wave from an electromagnetic wave to a mechanical wave.


g. Sound waves that the audience hears are mechanical waves.

Answers

Answer:

a. The frequency or amplitude of the sound waves will not change.

d. The frequency or amplitude of the sound waves could change as the song plays.

g. Sound waves that the audience hears are mechanical waves.

These are the true statements.

others are false.

b. Sound waves that the audience hears are not electromagnetic waves. Sound waves are a type of mechanical wave, which means that they require a medium to travel through, and in this case, the medium is air.

c. Hearing the sound does not change the wave type. The wave type remains a mechanical wave, even after it reaches the audience's ears.

e. and f. are also not true, as the process of hearing sound does not change the wave type from mechanical to electromagnetic or vice versa.

5. It is important to make certain that there is no air bubble in the tip of the burette below the stopcock before the initial reading of the liquid level in the burette is taken. If a 0.5ml air bubble is present in the tip of a burette, what percent error in 5-mL, 20-mL, and 25-mL samples will result if the air bubble is dislodged during the dispensing of the samples? ​

Answers

Answer:

If a 0.5 mL air bubble is present in the tip of a burette, the initial reading will be too high by 0.5 mL. If the air bubble is dislodged during the dispensing of the samples, the final reading will be too low by 0.5 mL. This will result in a systematic error in the volume measurements.

To calculate the percent error in the volume measurements, we can use the formula:

% error = (systematic error / true value) x 100

For a 5-mL sample, the true value is 5 mL. If the air bubble is dislodged, the measured volume will be 4.5 mL, resulting in a systematic error of 0.5 mL. Therefore, the percent error is:

% error = (0.5 / 5) x 100 = 10%

For a 20-mL sample, the true value is 20 mL. If the air bubble is dislodged, the measured volume will be 19.5 mL, resulting in a systematic error of 0.5 mL. Therefore, the percent error is:

% error = (0.5 / 20) x 100 = 2.5%

For a 25-mL sample, the true value is 25 mL. If the air bubble is dislodged, the measured volume will be 24.5 mL, resulting in a systematic error of 0.5 mL. Therefore, the percent error is:

% error = (0.5 / 25) x 100 = 2%

So, the percent error in the volume measurements will be higher for smaller samples, and lower for larger samples.

Final answer:

The percent error for a 5 mL sample is 10%, for a 20 mL sample is 2.5%, and for a 25 mL sample is 2%.

Explanation:

The percent error can be calculated using the formula:

Percent Error = ((Actual Value - Experimental Value) / Actual Value)×100%

In this case, the actual value is the volume of the sample (5 mL, 20 mL, or 25 mL) and the experimental value is the volume obtained if the air bubble is dislodged.

The percent error for a 5 mL sample would be:

Percent Error = ((5 mL - 4.5 mL) / 5 mL ) ×100% = 10%

The percent error for a 20 mL sample would be:

Percent Error =( (20 mL - 19.5 mL) / 20 mL) ×100% = 2.5%

The percent error for a 25 mL sample would be:

Percent Error = ((25 mL - 24.5 mL) / 25 mL) × 100% = 2%

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All of the following are unique properties of water except ____
Water has high specific heat.

Water has high heat of vaporization.

Water expands when it freezes.

Water is a non polar molecule.

Answers

Answer:

Water is a non polar molecule

Explanation:

Water interacts differently with charged and polar substances than with nonpolar substances because of the polarity of its own molecules. Water molecules are polar, with partial positive charges on the hydrogens, a partial negative charge on the oxygen, and a bent overall structure.

Using the Ideal Gas equation, if the number of moles is constant, as pressure and volume increase temperature will __________.

Answers

Explanation:

Ideal gas law

PV = n R T        If P and V increase then T must increase

   ( n  and R   are constant)

What is 99+49x901/1098

Answers

Answer:

139.20856102 this is thee answer

Answer:

139,18

Explanation:

How much of the reagent is left over?

Answers

31.5 g of Sulfuric acid can be produced from the given amounts of Sulfur trioxide and Water.

Why does Sulfur trioxide not dissolve in water but does in Sulfuric acid?

Option 'c' is the right response to this question because sulphur trioxide cannot be directly dissolved in water to create sulphuric acid because doing so produces a thick fog of the acid that is difficult to condense.

Sulfur trioxide + Water → Sulfuric acid

moles of Sulfur trioxide = mass/molar mass = 25.7 g / 80.06 g/mol = 0.321 mol

moles of Water = volume x density/molar mass = 12.7 mL x 1.00 g/mL / 18.02 g/mol = 0.705 mol

The amount of Sulfuric acid that can be produced is equal to the number of moles of Sulfur trioxide, which is 0.321 mol. To convert this to grams, we multiply by the molar mass of Sulfuric acid:

mass of Sulfuric acid = moles of Sulfuric acid x molar mass = 0.321 mol x 98.08 g/mol = 31.5 g

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A new band sensation is playing a concert and recording it for a live album to be released this summer. Select all the statements that are true for band producing sound.

a. The produced sound waves are electromagnetic waves.


b. Producing sound changes the wave from an electromagnetic wave to a mechanical wave.

c. The frequency or amplitude of the sound waves will change if the singer varies their voice.


d. The produced sound waves are mechanical waves.


e. Producing sound changes the wave from mechanical wave to an electromagnetic wave.

f. Producing the sound does not change the wave type.

g. The frequency or amplitude of the sound waves will not change.

Answers

Answer:

c. The frequency or amplitude of the sound waves will change if the singer varies their voice.

d. The produced sound waves are mechanical waves.

f. Producing the sound does not change the wave type.

g. The frequency or amplitude of the sound waves will not change

These statements are true. Sound waves are mechanical waves, meaning they require a medium to travel through, such as air or water. Producing sound involves creating vibrations in the medium, which then propagate as sound waves. The frequency and amplitude of the sound waves will change depending on the characteristics of the source producing the sound. However, producing sound does not change the type of wave from mechanical to electromagnetic, or vice versa

What volume of 17.5 Molar stock solution of acetic acid is required if we prepare 500 milliliters of a 1 Molar acetic acid solution? Show the calculation.

Answers

Answer:  C1V1=C2V2

Explanation: i hope this help im want to help you please

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Methamphetamine is a notorious street drug. One synthesis involves reductive amination of benzyl methyl ketone with methylamine. Indicate the reactions and give the structure of methamphetamine​

Answers

Methamphetamine is an amphetamine that stimulates the central nervous system (CNS).

Methamphetamine works by facilitating the release of catecholamines from brain nerve terminals, including noradrenaline, dopamine, and serotonin, as well as by inhibiting their uptake. As a result, the concentration of these neurotransmitters in the synaptic cleft rises, stimulating postsynaptic receptors more intensely.

The catalytic reduction of 1-phenyl-2-propanone (P-2-P, benzyl methyl ketone, BMK, or phenylacetone) in the presence of ammonia or methylamine is the fundamental reaction in all processes used to create methamphetamine. The Leuckart method (non-metallic reduction) and catalytic metal reduction are currently the most widely used reduction techniques.

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Find ΔE for the change in state of 1.0 mol H2O (l) at 79∘C to H2O(g) at 114 ∘C. The heat capacity of H2O(l) = 75.3 J/molK, the heat capacity of H2O(g) = 25.0 J/molK, and the heat of vaporization of H2O is 40.7×103J/mol at 100 ∘C.

Answers

The energy change for the change in state of 1.0 mol H2O (l) at 79∘C to H2O(g) at 114∘C is 42,643 J/mol.

What are heat capacity and specific heat?

The heat capacity of a thing is the amount of energy needed to raise its temperature by one degree Celsius. The amount of energy needed to increase the temperature of 1 gram of a substance by 1oC is known as a substance's specific heat.

We have to calculate the power needed to warm one mole of liquid water from 79∘C to 100∘C:

q1 = nCΔT

= (1.0 mol)(75.3 J/molK)(100-79 K)

= 1593 J

we have to calculate the energy,

q2 = nΔHvap

= (1.0 mol)(40.7×10^3 J/mol)

= 40,700 J

Now, we have to calculate the energy,

q3 = nCΔT

q3 = (1.0 mol)(25.0 J/molK)(114-100 K)

q3 = 350 J

The total energy change is:

ΔE = q1 + q2 + q3

ΔE = 1593 J + 40,700 J + 350 J

ΔE = 42,643 J/mol

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A new band sensation is playing a concert and recording it for a live album to be released this summer. Create a sequence chain showing the flow of energy changes that occur from the time the sound is created until the audience hears the sound.

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Answer:

Sound is Produced → Speaker → Wave Display → Microphone → Wave Display → Audience Hears Sound

Explanation:

Here is a more detailed explanation of each step in the sequence chain:

Sound is Produced: The sound is initially created by the band on stage. The sound is produced through the vibrations of musical instruments or the vocal cords of the singer.Speaker: The sound waves produced by the band travel through the air as mechanical waves until they reach the speakers on the stage.Wave Display: The sound waves are displayed on a wave display, which is a device that shows the shape, frequency, and amplitude of the waves. This display helps the sound engineers to monitor and adjust the sound to ensure that it is of high quality.Microphone: The sound waves then pass through the microphone, which converts the mechanical waves into electrical signals. These signals are then transmitted to the mixing console.Wave Display: The electrical signals are displayed again on the wave display at the mixing console, allowing the sound engineers to make further adjustments to the sound quality, such as adjusting the levels and frequencies.Audience Hears Sound: Finally, the electrical signals are transmitted to the amplifiers, which amplify the electrical signals and transmit them to the speakers located throughout the venue. The sound waves produced by the speakers propagate through the air and reach the audience, who hears the sound.
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