Answer:
0.7 is the right
Explanation:
You have to make 500 mL of a 1.50 M BaCl2. You have 2.0 M barium chloride solution available. Determine how to make the needed dilution
Answer:
There are needed 375mL of the 2.0M BaCl₂ solution completing to 500mL with water.
Explanation:
We can find with the volume and concentration of the barium chloride the moles of BaCl₂ required. With the moles and the concentration of our stock solution we can know the volume of the 2.0M BaCl₂ solution required as follows:
Moles required:
0.500L * (1.50mol / L) = 0.750 moles BaCl₂
Volume stock solution:
0.750 moles BaCl₂ * (1L / 2.0mol) = 0.375L
There are needed 375mL of the 2.0M BaCl₂ solution completing to 500mL with water.Please help I need answer soon.
A volcanic mountain made up of volcanic ash, cinders, and bombs is called a ___________________.
Answer:
Cinder cone
Explanation:
Which of the following equilibria could be used to support the claim that the addition of a small amount of NaOH to the buffer will result in only a very small change in pH? (see image)
I think First statement that is Option A, because, it has total equilibrium on both side, which will never result in increase of any pH level higher or lower than the state, hence
Option A.) is correct
Which of the following statements IS true regarding nucleophilic acyl substitution? Aldehydes and ketones go through acyl elimination, not substitution. The alcohol is reformed in the second step. The mechanism proceeds through a carbocation intermediate. The leaving group ability of the heteroatom group determines the reactivity towards nucleophilic acyl substitution.
The true statement is, the leaving group ability of the heteroatom group determines the reactivity towards nucleophilic acyl substitution.
What is Nucleophilic acyl substitution?Nucleophilic acyl substitution describes a class of substitution reactions involving nucleophiles and acyl compounds.
Also, nucleophilic acyl substitution is a type of substitution reaction involving an acyl group and a nucleophile.
Thus, the statement that is true regarding nucleophilic acyl substitution is, the leaving group ability of the heteroatom group determines the reactivity towards nucleophilic acyl substitution.
Thus, in nucleophilic acyl substitution, a nucleophile displaces the leaving group, resulting in a carbonyl compound.
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What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?
Answer:
[tex]\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}[/tex]
Explanation:
Molarity is found by dividing the moles of solute by liters of solution.
[tex]molarity = \frac {moles}{liters}[/tex]
We are given grams of a compound and milliliters of solution, so we must make 2 conversions.
1. Gram to Moles
We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.
C: 12.011 g/mol H: 1.008 g/mol O: 15.999 g/molNext, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.
6(12.011)+12(1.008)+6(15.999)=180.156 g/mol
Use this number as a ratio.
[tex]\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}[/tex]
Multiply by the given number of grams.
[tex]78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}[/tex]
Flip the fraction and divide.
[tex]78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}[/tex]
[tex]\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6[/tex]
2. Milliliters to Liters
There are 1000 milliliters in 1 liter.
[tex]\frac {1 \ L }{ 1000 \ mL}[/tex]
Multiply by 2500 mL.
[tex]2500 \ mL* \frac {1 \ L }{ 1000 \ mL}[/tex]
[tex]2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L[/tex]
3. Calculate Molarity
Finally, divide the moles by the liters.
[tex]molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}[/tex]
[tex]molarity = 0.173183241191 \ mol \ C_6H_12O_6/L[/tex]
The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.
[tex]molarity \approx 0.17 \ mol \ C_6H_12O_6 /L[/tex]
1 mole per liter is also equal to 1 M.
[tex]molarity = 0.17 \ M \ C_6H_12O_6[/tex]
Match the different methods used for calculating revenue and profit to the formulas used for calculating them. total revenue average revenue marginal revenue gross profit net profit
Answer:
See explanation below
Explanation:
1) Total Revenue:
Total revenue refers to the total amount of income that is generated when a company sells or offers their service.
It is usually calculated as the product of the product or services sold by the quantity.
It is calculated by ;
TR = Q * P
Where TR = Total Revenue
Q = Quantity
P = Price
2.) Average Revenue:
Average revenue is the revenue gotten by a company per unit of output sold. It is calculated by:
AR = TR / Q
Where AR = Average Revenue
TR = Total Revenue
Q. = Quantity
3.) Marginal Revenue:
This is the net revenue that is generated by selling an additional unit of commodity; which is the change in total revealer unit. It is calculated by:
MR = change in Total Revenue / change in Quantity
Where MR = Marginal Revenue
4.) Gross Profit:
Gross profit is the amount of revenue left after factoring out the cost of production and sales and servicing.
It is calculated by subtracting revenue from the cost of goods sold -
Gross Profit = Revenue - Cost of goods sold
Net Profit:
Net profit is the amount of money a company has left after subtracting all interests, tax expenses and cost.
It is calculated by;
Net Profit = Gross Profit - Expenses
Reactants of a combustion reaction include
select all that apply
Fuel
Oxygen
Water
Carbon Dioxide
Answer: fuel and oxygen are reactants.
Explanation:
Answer:
fuel and oxygen
Explanation:
I take test
If 4.1 g of 3H2 (g) + N2 (g) → 2NH3 (g) is actually produced, what is the percent yield?
So like, here's the equation:
3H2 (g) + N2 (g) → 2NH3 (g)
And the question is, "If 4.1 g of ammonia is actually produced, what is the percent yield?"
Could you please help? I've been stuck for two days and I have no one to ask. Thanks!!
Answer:
Explanation:
The first thing that you need to do here is to calculate the theoretical yield of the reaction, i.e. what you get if the reaction has a
100
%
yield.
The balanced chemical equation
N
2
(
g
)
+
3
H
2
(
g
)
→
2
NH
3
(
g
)
tells you that every
1
mole of nitrogen gas that takes part in the reaction will consume
3
moles of hydrogen gas and produce
1
mole of ammonia.
In your case, you know that
1
mole of nitrogen gas reacts with
1
mole of hydrogen gas. Since you don't have enough hydrogen gas to ensure that all the moles of nitrogen gas can react
what you need
3 moles H
2
>
what you have
1 mole H
2
you can say that hydrogen gas will act as a limiting reagent, i.e. it will be completely consumed before all the moles of nitrogen gas will get the chance to take part in the reaction.
So, the reaction will consume
1
mole of hydrogen gas and produce
1
mole H
2
⋅
2 moles NH
3
3
moles H
2
=
0.667 moles NH
3
at
100
%
yield. This represents the reaction's theoretical yield.
Now, you know that the reaction produced
0.50
moles of ammonia. This represents the reaction's actual yield.
In order to find the percent yield, you need to figure out how many moles of ammonia are actually produced for every
100
moles of ammonia that could theoretically be produced.
You know that
0.667
moles will produce
0.50
moles, so you can say that
100
moles NH
3
.
in theory
⋅
0.50 moles NH
3
.
actual
0.667
moles NH
3
.
in theory
=
75 moles NH
3
.
actual
Therefore, you can say that the reaction has a percent yield equal to
% yield = 75%
−−−−−−−−−−−−−
Consider if the reaction is conducted with 3 moles of hydrogen and 2 moles of nitrogen as it in the balanced reaction, and if only 4.1 g of ammonia is produced, then the percent yield will be 12%.
What is percent yield?The ratio of the actual yield to the theoretical yield multiplied by 100 is the percent yield. No simple reactions can achieve a 100 % yield.
As per the given reaction, 3 moles of hydrogen reacts with 2 moles of nitrogen and produce 2 moles of ammonia. Molar mass of ammonia is 17 g/mol. Thus, 2 moles are 34 g/mol.
Assume that if the theoretical yield is 34 g, then the percent yield for actual yield of 4.1 g is,
4.1 /34 ×100 = 12.1 %.
Now lets assume that only one mole of hydrogen is reacted here, number of moles of ammonia produced by one mole of hydrogen is :
= 1 mole × 2 mol / 3 moles
= 0.66 moles.
0.66 moles = 0.66 × 17 g/mol = 11.22 g.
For a theoretical yield of 11.22 g, the percent yield will be
= 4.1 /11.22
= 36.6 %.
Therefore, by assuming if 3 moles of hydrogen are reacted then percent yield will be 12% for 4.1 g of actual yield and 36 % if only one mole of hydrogen is reacted.
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if this atom has one additional neutron but the other subatomic particles remained the same as shwon, this slightly different atoms would be called
If this atom has one additional neutron but the other subatomic particles remained the same as shown, this slightly different atom would be called an isotope.
What is an isotope?An isotope is a variant of an atom that has a different number of neutrons. Because isotopes of the same element have the same number of protons in the nucleus, they all have the same atomic number. However, they can differ in mass number, and therefore in atomic mass. In a neutral atom, the number of protons in the nucleus equals the number of electrons that orbit the nucleus, giving the atom a net electrical charge of zero.
However, the number of neutrons in the nucleus can differ, implying that isotopes of the same element may have different atomic masses.
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why is solubility of sucrose (sugar), histidine (an amino acid), gelatin (a protein), and vegetable oil (fat) biologically relevant?
The solubility of compounds such as sucrose, histidine, gelatin, and vegetable oil is biologically relevant due to various reasons. Solubility affects nutrient absorption, cellular processes, transport and distribution of molecules, structural and functional roles of biomolecules, and biological interactions.
What is solubilitySolubility facilitates the digestion and absorption of nutrients, enables cellular reactions and enzymatic processes, influences nutrient transport and distribution within organisms, contributes to the structural and functional properties of biomolecules, and impacts molecular interactions within biological systems. Understanding the solubility of these compounds enhances our understanding of biological mechanisms and aids in the development of therapeutic and nutritional approaches.
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Balance C12H22011 → C + H2
Answer:
What is this?
Explanation:
What two properties of sound remain the same when sound quality differs? Check all that apply.
Answer: I don’t know sorry
Explanation:
if 15.70g of ticl4 reacts in excess oxygen to form 10.40g cl2 what is the percent yield of the reaction
The percent yield of the reaction is approximately 88.71%.
To calculate the percent yield of the reaction, we need to compare the actual yield (the amount of Cl₂ formed) to the theoretical yield (the amount of Cl₂ that would be formed if the reaction proceeded with complete conversion of TiCl₄).
First, we need to determine the molar masses of TiCl₄ and Cl₂. The molar mass of TiCl₄ is calculated as follows:
Ti: 1 atom x 47.87 g/mol = 47.87 g/mol
Cl: 4 atoms x 35.45 g/mol = 141.80 g/mol
Total molar mass of TiCl₄ = 47.87 g/mol + 141.80 g/mol = 189.67 g/mol
Next, we can calculate the number of moles of TiCl₄ and Cl₂ based on the given masses:
Moles of TiCl₄ = 15.70 g / 189.67 g/mol ≈ 0.08274 mol
Moles of Cl₂ = 10.40 g / 70.90 g/mol ≈ 0.14676 mol
From the balanced chemical equation for the reaction:
TiCl₄ + 2O₂ → TiO₂ + 2Cl₂
We can see that the stoichiometric ratio between TiCl₄ and Cl₂ is 1:2. Therefore, according to the balanced equation, the theoretical yield of Cl₂ would be:
Theoretical yield of Cl₂
= 2 (moles of TiCl₄)
= 2 (0.08274 mol)
= 0.16548 mol
Percent yield = (actual yield / theoretical yield) 100
= (0.14676 mol / 0.16548 mol) 100 ≈ 88.71%
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Which type of radioactive decay results in no change in mass number and atomic number for the starling nucleus? A) beta B) alpha C) electron capture D) gamma E) positron emission
The type of radioactive decay that results in no change in mass number and atomic number for the starting nucleus is gamma decay. The correct answer is option D.
Gamma decay is a type of radioactive decay that involves the emission of gamma rays from an atomic nucleus. Gamma rays are high-energy photons that are emitted when the nucleus undergoes a transition from a higher energy state to a lower energy state. Gamma decay does not result in a change in the atomic number or mass number of the nucleus, as no particles are emitted from the nucleus. Instead, the nucleus simply releases energy in the form of a gamma ray. Therefore, option D) Gamma is the correct answer.
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A mass of 80 grams of Bromine would be
calculate+the+milligrams+of+cl+(35.453+g/mol)+in+a+3.49+g+sample+of+cleaning+solution+containing+21.5+wt%+naocl+(74.44+g/mol).+naocl+is+the+only+source+of+cl+in+this+solution.
There are 356.2 mg of Cl in a 3.49 g sample of cleaning solution containing 21.5 wt% NaOCl (74.44 g/mol).
To calculate the milligrams of Cl (35.453 g/mol) in a 3.49 g sample of cleaning solution containing 21.5 wt% NaOCl (74.44 g/mol), first calculate the weight of NaOCl in the sample:3.49 g x 0.215 = 0.75 g NaOCl
Next, calculate the number of moles of NaOCl in the sample:0.75 g NaOCl ÷ 74.44 g/mol = 0.01006 mol NaOClSince NaOCl is the only source of Cl in the solution, this also represents the number of moles of Cl in the sample.
Finally, convert the number of moles of Cl to milligrams:0.01006 mol x 35.453 g/mol x 1000 mg/g = 356.2 mg Cl.
We have to calculate the milligrams of Cl in a cleaning solution sample.
The sample contains NaOCl, so we will first calculate the number of moles of NaOCl in the sample. This will also give us the number of moles of Cl in the sample because NaOCl is the only source of Cl in the solution.
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Hydrogen peroxide is a powerful oxidizing agent that is used in concentrated solution in rocket fuels and dilute solution as a hair bleach.
A 30% by mass of H2O2 solution has a density of 1.11g/ml. Calculate it's morality, mole fraction of H2O2, and molarity.
The molarity of the 30% by mass hydrogen peroxide solution is 9.78 M, the mole fraction of H2O2 is 1.0, and the molar concentration is also 9.78 M.
To calculate the molarity, mole fraction, and molar concentration (molarity) of a 30% by mass hydrogen peroxide (H2O2) solution with a density of 1.11 g/ml, we need to follow these steps:
Step 1: Calculate the molarity (M):
The molarity is defined as the number of moles of solute per liter of solution. We need the molar mass of hydrogen peroxide to calculate the number of moles.
The molar mass of H2O2 = 2(1.01 g/mol) + 2(16.00 g/mol) = 34.02 g/mol
The mass of H2O2 in 100 g of the solution (30% by mass) = 30 g
Number of moles of H2O2 = mass / molar mass = 30 g / 34.02 g/mol = 0.882 mol
The volume of the solution can be calculated using the density:
Volume of solution = mass of solution / density = 100 g / 1.11 g/ml = 90.09 ml = 0.09009 L
Molarity (M) = moles / volume = 0.882 mol / 0.09009 L = 9.78 M
Step 2: Calculate the mole fraction (χ) of H2O2:
The mole fraction is the ratio of the moles of H2O2 to the total moles of all components in the solution.
Mole fraction (χ) = moles of H2O2 / total moles
Total moles = moles of H2O2 = 0.882 mol
Mole fraction (χ) = 0.882 mol / 0.882 mol = 1.0
Step 3: Calculate the molar concentration (molarity):
Molar concentration (molarity) is the number of moles of solute per liter of solution.
Molarity (M) = moles of H2O2 / volume of solution = 0.882 mol / 0.09009 L = 9.78 M
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um can someone help balance this...id.k how
CH4 + 2 O2 = CO2 + 2 H2O
i believe it's this :p
Molecular crystals are held together by the intermolecular forces of dispersion and dipole-dipole forces and by hydrogen bonding. True or False
Molecular crystals are held together by the intermolecular forces of dispersion and dipole-dipole forces and by hydrogen bonding. The statement is True.
Molecular crystals are held together by the intermolecular forces of dispersion, dipole-dipole forces, and hydrogen bonding.
Dispersion forces are the weakest intermolecular forces and are present in all molecules. They are caused by the temporary uneven distribution of electrons in a molecule, which creates a temporary dipole.
The temporary dipole in one molecule can induce a dipole in another molecule, resulting in a weak attractive force.
Dipole-dipole forces are stronger than dispersion forces and are present in molecules that have a permanent dipole. The positive end of one dipole is attracted to the negative end of another dipole, resulting in a stronger attractive force.
Hydrogen bonding is the strongest intermolecular force and is present in molecules that contain a hydrogen atom bonded to a highly electronegative atom, such as oxygen, nitrogen, or fluorine.
The hydrogen atom is partially positive, while the electronegative atom is partially negative. This creates a strong attractive force between the hydrogen atom of one molecule and the electronegative atom of another molecule.
The type of intermolecular force that is most important in holding a molecular crystal together depends on the structure of the molecules in the crystal.
For example, a crystal of water is held together by hydrogen bonding, while a crystal of methane is held together by dispersion forces.
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in the self splicing of group 1 introns, the first transesterification reaction is initiated by:
In the self-splicing of group 1 introns, the first transesterification reaction is initiated by the nucleophilic attack of the 3' hydroxyl group of the guanosine nucleotide within the intron on the 5' splice site.
This nucleophilic attack forms a 3' - 5' phosphodiester bond and releases the 5' exon. This process is facilitated by the catalytic properties of the intron RNA itself, without the involvement of any protein factors.
The self-splicing of group 1 introns involves two transesterification reactions that lead to the removal of the intron and the joining of the flanking exons.
The first transesterification reaction is the key step that initiates the splicing process. It is the attack of the guanosine nucleotide on the 5' splice site that triggers the subsequent splicing reactions.
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3. What is the density of a 100 grams (g) box that displaces 20 mL of water?
Answer: the density is 997 kg
Explanation:
Question 1 (1 point) How many stars are in our solar system? A. About 20.000 B. About 300,000 C. One D. About 5,000
Answer:
C. one star
Explanation:
Of course our solar system has one unique star which is the sun while others have atleast two which are called binary solar
Which of the following is the strongest acid? Select one: a. CH3CH2OH b. CH3OCH3 c. CH3COOH d. CH3NHCH3 e. CH3CH=CH2
Out of the given options, CH3COOH is the strongest acid.
The strength of an acid is determined by its ability to donate protons. The more the acid donates protons, the stronger it is.Acid strength increases with decreasing pKa value. The pKa value of CH3COOH is 4.76. The lower the pKa value, the stronger the acid. CH3OCH3 is a weakly acidic compound with a pKa value of 15.5, whereas CH3CH2OH is a slightly acidic compound with a pKa value of 16. CH3NHCH3 is a non-acidic compound because it lacks an acidic hydrogen atom. CH3CH=CH2 is an alkene and is not an acidic compound.To summarize, CH3COOH is the strongest acid among the given options with a pKa value of 4.76.
So, option c is the correct answer.
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In the cytosol of rat hepatocytes, the temperature is 37°C and the mass-action ratio, Q, is [ATP]/[ADP][Pi] = 5.33 x 10M- Calculate the free energy required to synthesize ATP in a rat hepatocyte (AG'º for ATP hydrolysis is -30.5 kJ/mol.)
The free energy required to synthesize ATP in a rat hepatocyte is 24,365.6364 J/mol
To calculate the free energy required to synthesize ATP in a rat hepatocyte, we can use the formula:
ΔG'º = -RTln(Q)
where:
ΔG'º is the standard free energy change,
R is the gas constant (8.314 J/(mol·K)),
T is the temperature in Kelvin,
ln(Q) is the natural logarithm of the mass-action ratio.
Given:
ΔG'º = -30.5 kJ/mol
T = 37°C = 37 + 273.15 = 310.15 K
Q = 5.33 x [tex]10^{(-10)[/tex] M
First, we need to convert ΔG'º from kJ/mol to J/mol:
ΔG'º = -30.5 kJ/mol = -30.5 x [tex]10^3[/tex] J/mol
Next, we can calculate the free energy required to synthesize ATP using the formula:
ΔG = ΔG'º - RTln(Q)
ΔG = [tex](-30.5 * 10^3 J/mol) - (8.314 J/(molK) * 310.15 K) * ln(5.33 x 10^{(-10))[/tex]
≈ -30,500 J/mol - 2576.1911 J × (-21.3364)
≈ -30,500 J/mol + 54,865.6364 J
≈ 24,365.6364 J/mol
Calculating this expression will give us the value of ΔG, which represents the free energy required to synthesize ATP in a rat hepatocyte.
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Is Chlorine and Sodium an Ionic or Covalent bond?
Answer:
It is an Ionic bond
add single electron dots and/or pairs of dots as appropriate to show the lewis symbols of the following neutral atoms.
Hydrogen is the only exception, as it has only one valence electron.
The Lewis symbol for an atom includes its symbol and valence electrons represented as dots. The following are the Lewis symbols for neutral atoms with their electron dots and pairs of dots:- Hydrogen (H): 1 electron; Lewis symbol: H •- Helium (He): 2 electrons; Lewis symbol: He ••- Carbon (C): 4 electrons; Lewis symbol: C •• ••- Nitrogen (N): 5 electrons; Lewis symbol: N •• •• •••- Oxygen (O): 6 electrons; Lewis symbol: O •• •• ••••- Fluorine (F): 7 electrons; Lewis symbol: F •• •• ••• •••The number of valence electrons for each atom is determined by the group number on the periodic table. Hydrogen is the only exception, as it has only one valence electron.
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What form of electromagnetic radiation does gamma radiation use?
Answer:
Gamma-rays are a form of electromagnetic radiation, as are radio waves, infrared radiation, ultraviolet radiation, X-rays and microwaves. Gamma-rays can be used to treat cancer, and gamma-ray bursts are studied by astronomers.
Explanation:
Hope this helped Mark BRAINLIEST!!!
Gamma Rays are ionizing Electromagnetic radiation, obtained by the decay of an atomic nucleus. Gamma rays are more penetrating, in matter, and can damage living cells to a great extent. Gamma rays are used in medicine (radiotherapy), industry ( Sterilization and disinfection) and the nuclear industry.
Using data in Appendix E in the textbook,
calculate the standard emf for each of the following reactions:
1.H2(g)+F2(g)→2H+(aq)+2F−(aq).
2.Cu2+(aq)+Ca(s)→Cu(s)+Ca2+(aq).
3.2ClO−3(aq)+10Br−(aq)+12H+(aq)→Cl2(g)+5Br2(l)+6H2O(l).
Answer: The standard emf for each of the following reactions are:
1. 2.87V 2. 3.21V 3. -3.91V.
Explanation: The standard emf of the given reaction is given by the formula:EMF= E°(reduced) - E°(oxidized)
1. H2(g) + F2(g) → 2H+(aq) + 2F-(aq).The balanced equation is:H2(g) + F2(g) → 2H+(aq) + 2F-(aq)The standard reduction potentials are given by:E°(H+(aq)/H2(g)) = 0V and E°(F-(aq)/F2(g)) = +2.87V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 2.87 - 0= 2.87V
2. Cu2+(aq) + Ca(s) → Cu(s) + Ca2+(aq).The balanced equation is:Cu2+(aq) + Ca(s) → Cu(s) + Ca2+(aq)The standard reduction potentials are given by:E°(Cu2+(aq)/Cu(s)) = 0.34V and E°(Ca2+(aq)/Ca(s)) = -2.87V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 0.34 - (-2.87)= 3.21V
3. 2ClO-3(aq) + 10Br-(aq) + 12H+(aq) → Cl2(g) + 5Br2(l) + 6H2O(l)The balanced equation is:2ClO-3(aq) + 10Br-(aq) + 12H+(aq) → Cl2(g) + 5Br2(l) + 6H2O(l)The standard reduction potentials are given by:E°(Cl2(g)/2Cl-(aq)) = +1.36V and E°(Br2(l)/2Br-(aq)) = +1.09V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 1.36 - (5*1.09)= -3.91V.
Hence,The standard emf for each of the following reactions are:1. 2.87V2. 3.21V3. -3.91V.
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Define orbit and orbital motion, and explain why orbital motion occurs.
Answer:
Orbital motion occurs whenever an object is moving forward and at the same time is pulled by gravity toward another object. ... The result is a circular or oval path called an orbit, in which one object keeps moving around the other. Because of the relatively great gravity of the sun, Earth orbits the sun
1. Calculate the number of grams of nickel (II) nitrate hexahydrate required to prepare 25 mL of solution with a concentration of 0.034 M. CHECK WITH YOUR INSTRUCTOR BEFORE PROCEEDING. Write the ionic formula, molar mass and this described calculation in the Data and Observations section of your lab report PRIOR TO LAB - I will check this as part of your prelab..
To calculate the number of grams of nickel (II) nitrate hexahydrate required, we need to use the formula:
moles = concentration (M) x volume (L)
First, let's convert the volume from milliliters (mL) to liters (L):
25 mL = 25/1000 L = 0.025 L
The molar mass of nickel (II) nitrate hexahydrate can be calculated as follows:
Nickel (Ni) atomic mass = 58.69 g/mol
Nitrogen (N) atomic mass = 14.01 g/mol
Oxygen (O) atomic mass = 16.00 g/mol
Molar mass of nickel (II) nitrate = (1 * Ni) + (2 * N) + (6 * O)
= (1 * 58.69) + (2 * 14.01) + (6 * 16.00)
= 58.69 + 28.02 + 96.00
= 182.71 g/mol
Now, we can calculate the number of moles:
moles = 0.034 M x 0.025 L
= 0.00085 moles
Finally, we can calculate the mass of nickel (II) nitrate hexahydrate:
mass = moles x molar mass
= 0.00085 moles x 182.71 g/mol
≈ 0.155 grams
Therefore, approximately 0.155 grams of nickel (II) nitrate hexahydrate are required to prepare a 25 mL solution with a concentration of 0.034 M.
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