Answer:
1.023 × 10²³ atomsExplanation:
The number of atoms in a substance can be found by using the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 0.17 × 6.02 × 10²³
We have the final answer as
1.023 × 10²³ atomsHope this helps you
Name the intermolecular force that corresponds to: an attraction between a partially positive region in one molecule and a partially negative region in another molecule. an attraction between two temporarily polarized molecules. an attraction between a negatively charged particle and a partially positive region in a molecule. an attraction between a partially positive hydrogen atom in a molecule and a partially negative and highly electronegative atom on another molecule.
Answer:
an attraction between a partially positive region in one molecule and a partially negative region in another molecule....dipole-dipole interaction
an attraction between two temporarily polarized molecules...dispersion forces
an attraction between a negatively charged particle and a partially positive region in a molecule....ion dipole interaction
an attraction between a partially positive hydrogen atom in a molecule and a partially negative and highly electronegative atom on another molecule....Hydrogen bonding
Explanation:
Some molecules have permanent dipole. As a result of this, the positive part of one molecule may attract the negative part of the other molecule leading to dipole-dipole interaction.
Dispersion forces occur in all molecules and is as a result of temporary polarization of a molecule due to instantaneous dipole–induced dipole attractions.
If a charged particle is attracted by a dipole in a molecule, we call it ion-dipole interaction.
When hydrogen is bonded to a highly electronegative element, the positive end of the dipole is on hydrogen while the negative end of the dipole is on the electronegative element. Molecular associations often result from this permanent dipole and is called hydrogen bonding, e.g, HF.
A certain molecular compound has a solubility in acetonitrile of at . Calculate the greatest mass of that could be dissolved in of acetonitrile at this temperature. You may assume the volume of the solution doesn't change as the is dissolved. Be sure your answer has the correct unit symbol and number of significant digits.
Answer:
Amount = 2250 g
Explanation:
Note: This question is incomplete and lacks each and every data to solve. However, I have found the similar question on the internet and will be solving this question for you. Cheers!
Data Missing:
Organic Compound O
Solubility = 0.225 g/ml
Temperature = 10°C
Calculate the greatest mass of O that can be dissolved in 10.0 L acetonitrile at 10°C temperature.
Solution:
As we know the volume of the acetonitrile = 10.0 L
but first, we need to convert this into mL
We know that,
1 L contains 1000 mL
So,
10 L will contain = 10 x 1000 mL
10 L = 10000 mL
We, can write, 10000 mL as:
1 x [tex]10^{4}[/tex] mL
Now, the formula to calculate the greatest amount of O that can be dissolved in 1 x [tex]10^{4}[/tex] mL acetonitrile at 10°C temperature is:
Amount = Solubility x volume
Here,
Solubility = 0.225 g/ml
and
Volume = 1 x [tex]10^{4}[/tex] mL
Plugging in the values, we get:
Amount = 0.225 g/ml x 1 x [tex]10^{4}[/tex] mL
Amount = 0.225 x [tex]10^{4}[/tex] g
Amount = 2250 g
The reaction that occurs in a Breathalyzer, a device used to determine the alcohol level in a person's bloodstream, is given below. If the rate of appearance of Cr2(SO4)3 is 1.24 mol/min at a particular moment, what is the rate of disappearance of C2H6O at that moment
Answer:
The rate of disappearance of C₂H₆O = 2.46 mol/min
Explanation:
The equation of the reaction is given below:
2 K₂Cr₂O₇ + 8 H₂SO₄ + 3 C₂H₆O → 2 Cr₂(SO₄)₃ + 2 K₂SO₄ + 11 H₂O
From the equation of the reaction, 3 moles of C₂H₆O is used when 2 moles of Cr₂(SO₄)₃ are produced, therefore, the mole ratio of C₂H₆O to Cr₂(SO₄)₃ is 3:2.
The rate of appearance of Cr₂(SO₄)₃ in that particular moment is given 1.64 mol/min. This would than means that C₂H₆O must be used up at a rate which is approximately equal to their mole ratios. Thus, the rate of of the disappearance of C₂H₆O can be calculated from the mole ratio of Cr₂(SO₄)₃ and C₂H₆O.
Rate of disappearance of C₂H₆O = 1.64 mol/min of Cr₂(SO₄)₃ * 3 moles of C₂H₆O / 2 moles of Cr₂(SO₄)₃
Rate of disappearance of C₂H₆O = 2.46 mol/min of C₂H₆O
Therefore, the rate of disappearance of C₂H₆O = 2.46 mol/min
1 Define Soft water and Hard water.
Answer
software is a set of instruction given to a computer to perform specific function. MS office etc.
the tangible parts of a computer are known as hardware.
Explanation:
software pprforms the function while hardwares are the structural parts of a computer.
A gray element that borders on the zigzag line of the periodic table, is ductile and malleable, but is not a very good conductor of heat or electricity is known as which of the following?
A. metal
B. halogen
C. metalloid
D. nonmetal
A gray element that borders on the zigzag line of the periodic table, is ductile and malleable, but is not a very good conductor of heat or electricity is known as metalloid. The correct option is option C.
What is periodic table?In chemistry, a periodic table is an orderly arrangement of each of the chemical elements along order of atomic number is, the total amount of protons inside the atomic nucleus.
Whenever the chemical elements stand grouped in this manner, there is a recurrent pattern in their characteristics known as the "periodic law," in which elements within a single column (group) exhibit comparable qualities. A gray element that borders on the zigzag line of the periodic table, is ductile and malleable, but is not a very good conductor of heat or electricity is known as metalloid.
Therefore, the correct option is option C.
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What type of rock is limestone? Describe how a limestone rock is likely to change over a long period of time. Pls answer I will mark brainiest.
What type of rock is limestone? Describe how a limestone rock is likely to change over a long period of time. Pls answer I will mark brainiest.
Answer:Sedimentary Rock Limestone being a sedimentary rock would be converted to marble, a metamorphic rock if subjected to metamorphic conditions over an extensive period of time. Over a long period of time, we would take a look at the rock "limestone" through the rock cycle.#CARRYONLEARNING #STUDYWELLWhat is the equation to find volume?
1. mx+b
2. wxh
3. bxh/2
4. LxWxH
Answer:
Option 4
Explanation:
Volume of any substance is the space occupied by it.
For cuboidal objects the volume is equal to the product of length, weight and height.
Hence, mathematically volume can be written as
[tex]V = L * W * H[/tex]
Thus, option 4 is correct
How many molecules are there in 0.75 mol NH3
There are 4.5165 × 10²³ molecules are there in 0.75 mol NH₃.
A molecule is a set of or more atoms held together by means of attractive forces referred to as chemical bonds; depending on the context, the term may additionally or won't encompass ions that satisfy this criterion.
1 mole of NH₃ = 6.022 × 10²³
0.75 mole = 6.022 × 10²³ × 0.75 molecule
= 4.5165 × 10²³ molecules.
A molecule is defined as the smallest unit of a compound that consists of the chemical properties of the compound. Molecules are made of agencies of atoms. Describing the shape of an atom, an atom is also subdivided into smaller devices. Protons, electrons, and neutrons are sub-debris of an atom. The smallest particle of a substance has all of the bodily and chemical homes of that substance. Molecules are made up of 1 or extra atoms.
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In a reaction, there are multiple ways to discuss the amount of compound produced. Identify the definition of each term related to the reaction yield. The comparison of the experimental amount of product to the calculated amount The calculated amount of product under ideal conditions The amount of product experimentally produced
Answer: The comparison of the experimental amount of product to the calculated amount : Percentage yield
The calculated amount of product under ideal conditions : Theoretical yield
The amount of product experimentally produced : Experimental yield or actual yield
Explanation:
Theoretical yield is to determine how much of the product should be formed based on stoichiometry of the given reaction. It is the maximum amount of product that could be formed from the given amounts of reactants.
Experimental yield or actual yield is the amount of product that is actually formed when the reaction is carried out in the laboratory.
Percentage yield is the ratio of the experimental yield to the theoretical yield, expressed as a percentage.
make a poem about compounds
Answer:
A Werewolf___________
Poem with Compound Words
------------------------------------------
whenever there's a full moon,
I cannot overlook,
some alterations in my ways,
and changes in my look.
my werewolf hair grows everywhere,
my werewolf teeth get long,
my eyesight gets much keener and
I'm muscular and strong.
I get to roam around outside,
the moonlight makes me howl,
these otherworldly sound effects
mean I am on the prawl.
I see the moon is round and full,
I'm moonstruck by the sight,
I've made some telltale changes-so, you'd best stay in tonight.
Explanation:
I HOPE IT HELPS YOUR ENGLISH SUBJECT ;) ★
What is wrong with the following electron configuration?
Answer:
a. without completing 2p stuff...electrons cant go to 3s. the correct configuration is
1s2, 2s2, 2p6, 3s1
b. after 4s, 3d comes not 4d. the correct configuration is 1s2, 2s2, 2p6, 3s2, 4s2, 3d6
c. after 4s, it is 3d and then 4p the correct configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6.
Hope it helps you ｡◕‿◕｡
The camel stores the fat tristearin (C57H110O6) in its hump. As well as being a source of energy, the fat is also a source of water because, when it is used, the reaction 2 C57H110O6(g) + 163 O2(g) 114 CO2(g) + 110 H2O(ℓ) takes place. What mass of water is available from 1.6 pound of this fat? Answer in units of g.
Answer:
8.1 × 10² g
Explanation:
Step 1: Write the balanced equation
2 C₅₇H₁₁₀O₆ + 163 O₂ ⇒ 114 CO₂ + 110 H₂O
Step 2: Convert 1.6 lb of C₅₇H₁₁₀O₆ to g
We will use the conversion factor 1 lb = 453.592 g.
1.6 lb × 453.592 g/1 lb = 7.3 × 10² g
Step 3: Calculate the moles corresponding to 7.3 × 10² g of C₅₇H₁₁₀O₆
The molar mass of C₅₇H₁₁₀O₆ is 890.83 g/mol.
7.3 × 10² g × 1 mol/890.83 g = 0.82 mol
Step 4: Calculate the moles of water produced from 0.82 moles of C₅₇H₁₁₀O₆
The molar ratio of C₅₇H₁₁₀O₆ to H₂O is 2:110. The moles of H₂O produced are 110/2 × 0.82 mol = 45 mol
Step 5: Calculate the mass corresponding to 45 moles of H₂O
The molar mass of H₂O is 18.02 g/mol.
45 mol × 18.02 g/mol = 8.1 × 10² g
Write a balanced equation for the reaction of sodium phosphide with potassium chloride.
Answer:
Na3PO4 + KCl = NaCl + K3PO4
Explanation:
You have to know the Chemical Formula for Sodium phosphide, = Na3PO4 and Potassium chloride. which is = KCI
A series of dilute NaCl solutions are prepared starting with an initial stock solution of 0.100 M NaCl. Solution A is prepared by pipeting 10 mL of the stock solution into a 250-mL volumetric flask and diluting to volume. Solution B is prepared by pipeting 25 mL of solution A into a 100-mL volumetric flask and diluting to volume. Solution C is prepared by pipeting 20 mL of solution B into a 500-mL volumetric flask and diluting to volume. What is the molar concentration of NaCl in solutions A, B and C
Answer:
Solution A: 0.00400M
Solution B: 0.00400M
Solution C: 4.00x10⁻⁵M
Explanation:
Solution A is diluting the 0.100M NaCl from 10mL to 250mL. That is:
250mL / 10mL = 25 times.
That means molar concentration of sln A is:
0.100M / 25 = 0.00400M
Solution B is obtained diluting 25mL to 100mL:
100mL / 25mL = 4 times
0.00400M / 4 times = 0.00100M
And solution C is obtained diluting the solution C from 20mL to 500mL:
500mL / 20mL = 25 times
Solution C:
0.00100M / 25 times = 4.00x10⁻⁵M
The formula for serial dilution can be used to obtain the molarity of solution A, B , C.
For solution AM1V1 = M2V2
M2 = 0.100 M × 10 mL/250-mL
M2 = 0.004 M
For solution BM1V1 = M2V2
M2 = 0.004 M × 25 mL/100-mL
M2 = 0.001 M
For solution CM1V1 = M2V2
M2 = 0.001 M × 20 mL/500-mL
M2 = 0.00004 M
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2.Your culture media recipe says you need to add 2.625g of Sodium Bicarbonate per liter of media. You realize you only have a 7.5% solution of Sodium Bicarbonate you can use. What volume of that solution can you add, while making your media, to have the necessary mass of NaHCO3
Answer:
35mL of the 7.5% solution are required to meake the media
Explanation:
To prepare the culture media there are required 2.625g of sodium bicarbonate. We have a 7.5% solution of sodium bicarbonate (That is, 7.5g of sodium bicarbonate in 100mL of solution). Thus, to obtain 2.625g we need:
2.625g Sodium bicarbonate * (100mL / 7.5g) =
35mL of the 7.5% solution are required to meake the mediaWhat produces the magnetic force of an electromagnet?
O magnetic fields passing through the device
O static charged particles on the wire
O movement of charged particles through the wire
O positive and negative charges repelling each other
Answer:
movement of charged particles through the wire .
Explanation:
When electricity is passed through the wire of electromagnet , moving electrons of the wire produces magnetic field . This magnetic field in increased due to high permeability of soft iron of the electromagnet . It is this magnetic field which creates magnetic force .
How many moles are in 25g of NaCI?
Nacl = (. 23+35. 5)
= 58.5g
.
1 mol of Nacl = 58.5g
X mol Of Nacl = 25g
X Mol of Na Cl =25 ÷ 58.5
X mol of Nacl = 0.4 mol
Ivy has a mixture salt and sand . She wants to separate the two substances by pouring the mixture into a jar of water . How could ivy speed up the separation of the two substance? Shake the jar , put the jar into the freezer, add a third substance such as soil to the jar , remove some of the water from the jar before adding the mixture
Answer:
Remove some water from the jar before adding the mixture.
Explanation:
She will speed it up when removing some water it will stay dry and not be sticky to separate the two ingredients
Answer: Remove a bit of water from the jar
Explanation:
A container was found in the home of the victim that contained 120 g of ethylene glycol in 550 g of liquid. How many drinks, each containing 100 g of this liquid, would a 85 kg victim need to consume to reach a toxic level of ethylene glycol
Answer:
0.432 drinks are toxic
Explanation:
The toxic dose of ethylene glycol is 0.1 mL per kg body weight (mL/kg). In grams (Density ethylene glycol = 1.11g/mL):
1.11g/mL * (0.1mL / kg) = 0.111g/kg
If the victim weighs 85kg, its letal dose is:
85kg * (0.111g/kg) = 9.435g of ethylene glycol
Using the concentration of ethylene glycol in the liquid:
9.435g of ethylene glycol * (550g liquid / 120g ethylene glycol) = 43.2g of liquid are toxic.
The drinks are:
43.2g of liquid * (1 drink / 100 g) =
0.432 drinks are toxicWhich MOLECULES do cells need to get in order to function properly?
Answer:
they get animal cells
Explanation:
A chemist prepares a solution of aluminum sulfate by weighing out of aluminum sulfate into a volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's aluminum sulfate solution. Be sure your answer has the correct number of significant digits.
Answer:
25.8 g/dL
Explanation:
A chemist prepares a solution of aluminum sulfate by weighing out 116.0 g of aluminum sulfate into a 450. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in g/dL of the chemist's aluminum sulfate solution. Be sure your answer has the correct number of significant digits.
Step 1: Given data
Mass of aluminum sulfate (m): 116.0 gVolume of the solution (V): 450. mLStep 2: Convert "V" to dL
We will use the following conversion factors.
1 L = 1000 mL1 L = 10 dL450. mL × 1 L/1000 mL × 10 dL/1 L = 4.50 dL
Step 3: Calculate the concentration (C) of aluminum sulfate if g/dL
We will use the following expression.
C = m/V = 116.0 g/4.50 dL = 25.8 g/dL
Which pair of elements would you expect to exhibit the greatest similarity in their physical
and chemical properties?
Select one:
O a. No
O b. Mg, Al
O c. Br, Kr
O d. As, Br
O e. I, AT
Answer:
e. I, At
Explanation:
Hello!
In this case, since the periodic trends of a series of elements belonging to the same group towards physical and chemical properties tend to be the same when closer in period, we notice that Mg and Al, Br and Kr and As and Br are close but in period, not in the same group; therefore e. I, At, iodine and astatine, are going to tend to exhibit the greatest similarity in their physical and chemical properties.
Best regards!
The combustion of gasoline produces carbon dioxide and water. assume gasoline to be pure octane (c8h18) and calculate how many kilograms of carbon dioxide are added to the atmosphere per 3.8 kg of octane burned. ( hint: begin by writing a balanced equation for the combustion reaction.) express your answer using two significant figures.
Answer:
11.73 Kg of CO₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O
Next, we shall determine the mass of C₈H₁₈ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:
Molar mass of C₈H₁₈ = (12×8) + (18×1)
= 96 + 18
= 114 g/mol
Mass of C₈H₁₈ from the balanced equation = 2 × 114 = 228 g
Convert 228 g to kg.
1000 g = 1 Kg
Therefore,
228 g = 228 g × 1 Kg / 1000 g
228 g = 0.228 Kg
Molar mass of CO₂ = 12 + (16×2)
= 12 + 32
= 44 g/mol
Mass of CO₂ from the balanced equation = 16 × 44 = 704 g
Convert 704 g to Kg
1000 g = 1 Kg
Therefore,
704 g = 704 g × 1 Kg / 1000 g
704 g = 0.704 Kg
SUMMARY:
From the balanced equation above,
0.228 Kg of C₈H₁₈ reacted to produce 0.704 Kg of CO₂.
Finally, we shall determine the mass of carbon dioxide, CO₂, that will be produced by the reaction of 3.8 kg of octane, C₈H₁₈. This can be obtained as follow:
From the balanced equation above,
0.228 Kg of C₈H₁₈ reacted to produce 0.704 Kg of CO₂.
Therefore, 3.8 kg of C₈H₁₈ will react to produce = (3.8 × 0.704) / 0.228 = 11.73 Kg of CO₂
Thus, 11.73 Kg of CO₂ is added to the atmosphere per 3.8 kg of C₈H₁₈.
balance the following equation by oxidation reduction method FeSO4
+
KMnO4+ H2SO4 → Fe2 (SO4)3+ k2SO4+MnSO4+H2O
Answer:
[tex]10\, {\rm Fe}\rm SO_4 + 2\, \rm K {Mn} O_4 + 8\, H_2SO_4\\ \to 5\, {Fe} (SO_4)_3 + K_2SO_4 + 2\, {Mn}SO_4 + 8\, H_2O[/tex].
Explanation:
Identify the elements with oxidation state changes:
Oxidation states of iron, [tex]\rm Fe[/tex]:
[tex]+2[/tex] in [tex]\rm FeSO_4[/tex] among the reactants.[tex]+3[/tex] in [tex]\rm Fe_2(SO_4)_3[/tex] among the products.Change to the oxidation state: [tex]+1[/tex] (oxidation) for each [tex]\rm Fe[/tex] atom.Oxidation state of manganese, [tex]\rm Mn[/tex]:
[tex]+7[/tex] in [tex]\rm KMnO_4[/tex] among the reactants.[tex]+2[/tex] in [tex]\rm MnSO_4[/tex] among the products.Change to the oxidation state: [tex](-5)[/tex] (reduction) for each [tex]\rm Mn[/tex] atom.The change in the oxidation state of [tex]\rm Mn[/tex] is five times the opposite of the change to the oxidation state of [tex]\rm Fe[/tex]. If there are one mole of [tex]\rm Mn\![/tex] atoms in each mole of this reaction, there would be five times as many [tex]\rm Fe\![/tex] atoms per mole reaction. In other words:
[tex]\displaystyle 5\, \overset{+2}{\rm Fe}\rm SO_4 + 1\, \rm K \overset{+7}{Mn} O_4 + ?\, H_2SO_4\\ \to \frac{5}{2}\, \overset{+3}{Fe} (SO_4)_3 + ?\, K_2SO_4 + 1\, \overset{+2}{Mn}SO_4 + ?\, H_2O[/tex].
(Notice that each mole of this reaction would include five times as many [tex]\rm Fe[/tex] atoms as [tex]\rm Mn[/tex] atoms.)
Multiply the coefficients by [tex]2[/tex] to eliminate the fraction:
[tex]\displaystyle 10\, {\rm Fe}\rm SO_4 + 2\, \rm K {Mn} O_4 + ?\, H_2SO_4\\ \to 5\, {Fe} (SO_4)_3 + ?\, K_2SO_4 + 2\, {Mn}SO_4 + ?\, H_2O[/tex].
Find the unknown coefficients using the conservation of atoms.
Reactants:
[tex]2[/tex] potassium [tex]\rm K[/tex] atoms in two [tex]\rm K_2SO_4[/tex] formula units.Therefore, among the products:
[tex]2[/tex] potassium [tex]\rm K[/tex] atoms in one [tex]\rm K_2SO_4[/tex] formula unit.[tex]\displaystyle 10\, {\rm Fe}\rm SO_4 + 2\, \rm K {Mn} O_4 + ?\, H_2SO_4\\ \to 5\, {Fe} (SO_4)_3 + {1}\, K_2SO_4 + 2\, {Mn}SO_4 + ?\, H_2O[/tex].
Products:
[tex]5 \times 3 + 2 + 1 = 18[/tex] sulfur [tex]\rm S[/tex] atoms in five [tex]\rm Fe_2(SO_4)_3[/tex] formula units, two [tex]\rm K_2 SO_4[/tex] formula units, and one [tex]\rm MnSO_4[/tex] formula unit.Reactants:
There are already ten [tex]\rm S[/tex] atoms in that ten [tex]\rm Fe(SO_4)_2[/tex] formula units. The other [tex]18 - 10 = 8[/tex] formula units would correspond to eight [tex]\rm H_2SO_4[/tex] molecules among the reactants of this reaction.[tex]\displaystyle 10\, {\rm Fe}\rm SO_4 + 2\, \rm K {Mn} O_4 + 8\, H_2SO_4\\ \to 5\, {Fe} (SO_4)_3 + {1}\, K_2SO_4 + 2\, {Mn}SO_4 + ?\, H_2O[/tex].
Products:
There are [tex]8 \times 2 = 16[/tex] hydrogen [tex]\rm H[/tex] atoms in that eight [tex]\rm H_2SO_4[/tex] molecules.Therefore, among the products:
There would be [tex]16 / 2 = 8[/tex] molecules of [tex]\rm H_2O[/tex], with two [tex]\rm H[/tex] atoms in each [tex]\rm H_2O\![/tex] molecule.[tex]\displaystyle 10\, {\rm Fe}\rm SO_4 + 2\, \rm K {Mn} O_4 + 8\, H_2SO_4\\ \to 5\, {Fe} (SO_4)_3 + {1}\, K_2SO_4 + 2\, {Mn}SO_4 + 8\, H_2O[/tex].
In his experiment, Balmer introduced hydrogen gas in a discharged tube in order to excite electrons on higher energy levels. Then, as the electrons dropped down to lower energy levels, photons were emitted by the atoms. What is the energy of a photon emitted by a electron dropping from level n
Answer:
2.56 eV
Explanation:
Using the formula;
ΔE= -RH(1/n^2final - 1/n^2initial)
RH = -2.18 * 10-18 J
nfinal = 2
ninitial =1
Substituting values;
ΔE= -2.18 * 10-18 J(1/4^2 - 1/2^2)
ΔE= -2.18 * 10-18 J(0.0625 - 0.25)
ΔE= 4.09 * 10^-19 J
To convert to eV
4.09 * 10^-19 J/1.6 * 10^-19
=2.56 eV
ANSWER QUICK !!!
How many grams of hydrogen gas will be produced if you start with 15.0 grams of zinc and an excess amount of HCI?
balanced equation:
Zn + 2HCI = ZnCl2 + H2
Answer:
uhh
ExplanatioUHHHHHHHHHHHHHHHHHHH
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THIS
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4) 568 cm3 of chlorine at 25° C will occupy 400 cm3 at what temperature given a constant pressure?
The final temperature : T₂=209.86 K = -63.1 °C
Further explanationGiven
V₁=568 cm³
T₁=25° C+ 273 = 298 K
V₂=400 cm³
Required
Final temperature(T2)
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
T₂=(V₂.T₁)/V₁
T₂=(400.298)/568
T₂=209.86 K = -63.1 °C
Which option is the basic unit of water, a compound?
A. A water atom
B. A hydrogen atom
C. A hydrogen molecule
D. A water molecule
Answer:
D. A water molecule
Explanation:
HELPPp now plsss I really need help !!!!!
Answer:
The Forces that form each star would be your answer :)
What is the electron configuration of phosphorus
1s², 2s², 2p⁶, 3s², 3p⁵
Further explanationGiven
Phosphorus element
Required
The electron configuration
Solution
The energy level is expressed in the form of electron configurations.
Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d and f.
Charging electrons in the sub shell uses the following sequence:
1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.
Electron configurations are based on the number of electrons in the atomic number.
The atomic number of the phosphorus is 15, so the number of electrons is 15.
The configuration:
1s², 2s², 2p⁶, 3s², 3p⁵