Speed=
[tex]33m {s}^{ -1} [/tex]
Distance=
[tex]163m[/tex]
speed= distance/time
So,
Time= distance/speed
Time= 163/33
=[tex]\huge\underline\mathtt\colorbox{cyan}{4.9393s}[/tex]
how can you reduce the percentage uncertainty in measurements that you make?
Answer:
For example, one method for estimating the length of time it takes something to occur is to time it once using a stopwatch. You can reduce the uncertainty in this estimate by repeating the measurement and taking the average.
There are a lot of way to reduce the uncertainty however with real life sciences like quantum mechanics it will reveal more about the world and life if we have better measuring tools. Being precise is essential to understanding many parts of life.
Hope this helped! Have a great day!!!
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Answer:C
Explanation:
For parallel connection
1/R=1/R1+1/R2+1/R31/R=1/12+1/6+1/41/R=1+2+3/121/R=1/2R=2ohmFor series connection
Net resistance
R=2+3=5ohmHow to do this question plz answer
Explanation:
(i)An analog signal has some feature that is a continuous function of the program material being transmitted. It may take on any of a range of values.
In radio, amplitude, frequency, or phase are features of the radio signal commonly modulated when transmitting an analog signal.
__
(ii)A digital signal has some feature that is a discrete function of the program material being transmitted. It may take on any of a specific set of values.
A digital radio signal typically uses some combination of amplitude, frequency, and phase to represent a discrete state being transmitted. Only specific values of these are used by the transmitter.
(The receiver generally has to deal with corruption of the signal by the transmission channel, so the received set of values may not correlate well with those intended at the transmitter. This is why error-correcting codes are often used with digital signal transmission.)
_____
Additional comment
Analog radio signals are generally transmitted using a carrier wave at a specific frequency (or in some specific frequency range, in the case of frequency modulation). Processing techniques may be used at the transmitter to limit the bandwidth used in the transmission. One commonly-used technique is to limit the transmitted spectrum to one side of the carrier wave frequency. (This is called "single side-band" radio.)
Digital signals offer the opportunity to transmit different bits of the information at different frequencies. Sometimes, "frequency hopping" is used, so that the transmitted carrier wave jumps around from one frequency to another in a predetermined pattern. The effect of this is to spread out the spectrum of the transmitted signal so that average power in any frequency band is significantly reduced. In fact, it may be indistinguishable from background noise, except by a receiver that tunes to the carrier wave in the predetermined frequency pattern.
explain how siphon works with atmospheric pressure?
Answer:
A siphon is a tube that allows liquid to travel upward, above the surface of the origin reservoir, then downwards to a lower level without using a pump. When a certain amount of water moves over the bend in the siphon, gravity pulls it down on the longer leg lowers the atmospheric pressure in the bend of the siphon.
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Explanation:
Which force is making a difference in the weight of each person?
A
applied
B
gravitational
C
normal
D
tension
The force is different because of the amount of weight applied so the answer is A
The force that makes a difference in the weight of each person is Gravitational. Correct option is B.
Gravitational force is a fundamental force of nature that exists between any two objects with mass. It's the force that keeps us and everything else on Earth anchored to its surface. This force is proportional to the mass of the objects involved and inversely proportional to the square of the distance between them.
For example, if you were standing on a bathroom scale, the reading on the scale represents the force of the Earth's gravity acting on your body, which is why it's often referred to as your "weight." The actual mass of an object remains constant regardless of its location, but its weight can vary depending on the strength of the gravitational field at different locations (e.g., the weight on the Moon would be less than on Earth due to the Moon's weaker gravitational pull).
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Why can’t you compress gas but you cannot compress a liquid
On a beautiful spring day, Juan is playing a round of golf. He hits the golf ball with an initial velocity of 44.9 m/s at an angle of 28 degrees. If it hits the ground 6s later, how far does it travel? Answer: ____m
Answer:
140m 13 degree
Explanation:
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Answer:
i dont understand sorry
How does the law of conservation of mass apply to this reaction: Mg + HCI + H2 MgClz?
O The equation needs to be balanced. There are fewer hydrogen atoms in the equation than magnesium or chlorine.
© Only the hydrogen needs to be balanced. There are equal numbers of magnesium and chiorine.
Hydrogen and chlorine need to be balanced. There is an equal amount of magnesium on each side
©
The
law of conservation of nÖss has already been
the equation.
applied. There is an equal number of each element on both sides of
A student drops a ball off the top of building and records that the ball takes 2.55s to reach the ground. Determine all unknowns and answer the following questions. Neglect drag.
The unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.
The given parameter;
time of motion of the ball, t = 2.55 sThe equations that model the motion of the ball is given as follows;
[tex]h = v_0_y + \frac{1}{2} gt^2[/tex]
[tex]v_f = v_0_y + gt[/tex]
All the unknown variables in the equations include;
[tex]v_0_y[/tex] is the initial vertical velocity of the ball, = 0g is the acceleration due to gravity = 9.8 m/s²h is the vertical distance traveled by the ball = ?[tex]v_f[/tex] is the final velocity of the ball = ?The vertical distance traveled by the ball is calculated as follows;
[tex]h = \frac{1}{2} gt^2\\\\h = 0.5 \times 9.8 \times 2.55^2\\\\h = 31.86 \ m[/tex]
The final velocity of the ball is calculated as follows;
[tex]v_f = 0 + 9.8(2.55)\\\\v_f = 25 \ m/s[/tex]
Thus, the unknown variables in the model equation for ball's motion include vertical distance traveled by the ball which is 31.86 m and the final velocity of the ball which is 25 m/s.
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A ship left the dock and travelled north at 50km/hr for 2 hours then it turned west at 60km/hr for 3 hours. What is the net resultant displacement vector R
Answer:
resultant displacement = 20√1o6 km = 205912.6 m in the direction of western north.
Explanation:
assume that the ship started moving from A to B (north at 50km/hr for 2 hours) so the covered distance will be: 50*2 = 100 km
then it moves from B to C so the covered distance will be: 3*60 = 180 km
using Pythagoras, we get the resultant displacement = 20√1o6 km = 205912.6 m in the direction of western north.
Please help me with these answers
Answer:
question 1 is centripetal acceleration question 2 is 4
Explanation:
centripetal acceleration basically is acceleration that only changes velocity but not speed, while for question 2, you divide 10 by 2.5
5.) How could we have improved this activity to be more precise?
ball on ramp
Explanation:
I don't understand this question
could you please explain
Explanation:
Well ball on ramp .Which factors are affected?
Centre of massAcceleration due to gravity Mass of ball .Force appliedSo if we put the ball right above the centre of mass it can be best stabled
Sarah decelerates from 30 to 10m/s over a distance of 5m. What is her acceleration?
Helppppppp pleaseeee
Answer: (Sorry, but I don't know how to calculate mass)
1. 15 N
2. 0.4921 [tex]\frac{ft}{s^2}[/tex] (feet per second squared)
4. 150 N
5. 8.202 feet per second squared
I NEED A SCIENCE EXPERT TO GIVE ME THE RIGHT ANSWER TO THESE ASAP NO LINKS !!!
Answer:
1 st question: Control variable
2nd question: random variable
3rd question: if the two objects are dropped from the same height they will hit the ground at the same time
Answer:
it IS the control variable
Explanation:
A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal
We have that for the Question "A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that the minimum force that must be applied on the book is
F=44N
From the question we are told
A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied on the book, perpendicular to the wall, to prevent the book from slipping down the wal
Generally the equation for the Force is mathematically given as
[tex]F=\frac{mg}{\mu}\\\\F=\frac{2*9.8}{0.45}\\\\[/tex]
F=44N
Therefore
the minimum force that must be applied on the book is
F=44N
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Problem 4:
A body fell vertically from the top of a tower. It covered 123.1 m in the final two seconds
before hitting the ground. Determine the height of the tower rounding your answer to the
nearest two decimal places. Let the acceleration due to gravity g=9.8 m/s2.
Answer:
v2^2 - v1^2 = 2 g s fundamental formula
v2 = v1 + 2 g = v1 + 19.8 increase in velocity in 2 sec
v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76
v1 = (2412.76 - 392) / 39.6 = 51.03
v2 = 51.03 + 19.6 = 70.63
T = 70.63 / .8 = 7.207 sec time to fall height of tower
S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m
(Note v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m
2385 / (2 * 9.8) = 122 m (close to 123.1 as was given
what is the use of telescope
Answer:
The use of a telescope is to see distant objects
Explanation:
For example: you can look through a telescope to see constellations and stars. Hope this helps <3
As shown above an adhesive has been applied to contacting faces of two blocks so that the blocks interact with an adhesive force that has a magnitude, Fadhesion A tension, T, is exerted by a wire attached to the upper blocks causing the blocks to remain at rest The two blocks have weights, Wbottom and Wtop. Which of the following must be true? (1 point) ♡ O Wtop=T OT = Wtop - Fadhesion O Wbottom Fadhesion O T = Wbottom + Wtop + Fadhesion
The magnitude of the adhesive force allows the top block to remain
attached to the bottom when the blocks and the wire are balanced.
The option that must be true is; [tex]\mathbf{W_{bottom} = F_{adhesion}}[/tex]
Reason:
The tension exerted by the wire attached to the top block = T
Magnitude of the adhesive = [tex]F_{adhesion}[/tex]
Weight of the top block = [tex]W_{top}[/tex]
Weight of the bottom block = [tex]W_{bottom}[/tex]
Given that with the exertion of the tension, the two blocks remain at rest, we have;
T = [tex]W_{top}[/tex] + [tex]W_{bottom}[/tex]The adhesive causes the bottom block to remain attached to the top block, we have;
Therefore, the magnitude of the adhesive force adds the bottom weight, to the top, weight, which gives;
The magnitude of the adhesive force = The weight of the bottom block
Therefore;
[tex]W_{bottom}[/tex] = [tex]F_{adhesion}[/tex]Learn more here:
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Answer:
Wbottom=Fadhersion it was right on y test
Explanation:
what are the properties of gravitational force
Explanation:
It obeys the inverse square law.
It is always attractive in nature.
It is a long range force. ...
The graviton is the field particle of gravitational force.
Answer:
Gravitational force−Properties:
(1) It is a universal attractive force. It is directly proportional to the product of the masses of the two bodies.
(2) It obey inverse square law.
(3) It is the weakest force known in nature.
How could you set up the Strong and Weak magnets to show Barry that strong magnets and weak magnets can BOTH repel and attract object's?
Answer:
To show that magnets repel, you must place the strong and weak magnets to another magnet with their poles being both south or both north facing eachother.
To show they attract, place opposite poles near eachother.
A piece of wood has a mass of 8g and a volume of 10cm³ work out the density of the wood
Answer:
0.8 g/cm³Explanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\[/tex]
From the question
mass = 8 g
volume = 10 cm³
We have
[tex]density = \frac{8}{10} = \frac{4}{5} = 0.8 \\ [/tex]
We have the final answer as
0.8 g/cm³Hope this helps you
An object is moving initially with a velocity of 5.6 m/s. After 3.1 s the object's velocity is -2.7 m/s. What is the object's average acceleration during this time
Answer:
-2.68m/s²
Explanation:
To find acceleration use the formula:
acceleration = change in velocity ÷ time
change in velocity = -2.7 - 5.6 = -8.3m/s (final velocity - initial velocity)time = 3.1sSubstitute in the values:
acceleration = -8.3 ÷ 3.1
acceleration = -2.67741.. ≈ -2.68m/s²
Hope this helps!
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one or two sentences state whether you would expect the conditions to be a greater hazard for diversity dive down where is the return to the surface and explain your production in terms of gases define prescient
Answer:
Solubility in gasses and liquids increase as pressure increases. This is due to colligative properties. The nitrogen gas levels would increase the farther the diver dives due to the increase of pressure causing the solubility of the nitrogen to increase, thus increasing the amount of it as you go deeper in the ocean.
Explanation:
As they plummet down, the driver would be in more risk. The solubility of gases and liquids increases as pressure increases. This is due to the existence of colligative properties. The nitrogen gas levels grow when the diver descends further into the water due to increased pressure, which causes the nitrogen's solubility to rise, increasing the amount of nitrogen present.
the total amount of power that a star radiates is called its
what type of wavelengths do ultraviolet rays have?
According to who.int,
"The UV region covers the wavelength range 100-400 nm and is divided into three bands: UVA (315-400 nm) UVB (280-315 nm) UVC (100-280 nm).Mar 9, 2016"
in short 100-400nm
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How many moles of glucose, C6_H12_O6, are in 300 g of glucose? Show your work.
Which of the following is an example of a buoyant force acting on an object?
A. The object remains still despite an applied force.
B. The object travels with straight-line horizontal acceleration.
C. The object floats on top of a fluid.
D. The object travels in uniform circular motion.
Answer:
option c theobject floats on top of a fluidDemarcus launches a small weight into the air. The weight takes 6.4 seconds to reach the ground again. At what time did the weight have a vertical velocity of 0 meters per second?