Answer:
The higher the amplitude, the higher the energy.
PLEASEEE HELP HELP PLEASE
A 0.450 kg baseball comes off a bat and goes straight up. At a height of 10.0 m, the baseball has a speed of 24.5m/s. Determine its mechanical energy at this height. Show your work
What is the baseball's mechanical energy when it is at a height of 9.0m? Explain your answer.
The mechanical energy of the baseball when it is at a height of 9.0m is 39.7 N.
What is the mechanical energy of the baseball bat?The mechanical energy of the bat is in the form of potential energy.
Potential energy = mass * acceleration due to gravity * heightAt a height of 9.0m, the potential energy of the ball = 0.45 * 9.81 *
Potential energy = 39.7 N
In conclusion, the mechanical energy of the baseball bat is the potential energy at that height.
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A step-up transformer has a primary coil with 100 loops and a secondary coil with 1,500 loops. If the primary coil is supplied with a household current of 120 V and 15 A, (a) what voltage is produced in the secondary circuit? (b) What current flows in the secondary circuit?
(a) The voltage that is produced in the secondary circuit is 1,800 V.
(b) The current that flows in the secondary circuit is 1 A.
Voltage in the secondary coilNp/Ns = Vp/Vs
where;
Np is number of turns in primary coilNs is number of turns in secondary coilVp is voltage in primary coilVs is voltage in secondary coil100/1500 = 120/Vs
Vs = (120 x 1500)/100
Vs = 1,800 V
Current in the secondary coilIs/Ip = Vp/Vs
where;
Is is secondary currentIp is primary currentIs = (IpVp)/Vs
Is = (15 x 120)/1800
Is = 1 A
Thus, the voltage that is produced in the secondary circuit is 1,800 V.
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The farther a star is away from Earth, the more it is
Answer:
• black hole - one of the most dense objects in the universe
• red giant - a very large star
• white dwarf - an old, very dense hot star that is cooling
• nebula - a mass of gas and dust
An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape. What is the acceleration due to gravity of the moon?
Answer:
1/6 m/s^2 ( about 1/6th gravity of Earth ( 9.81 m/s^2)
Explanation:
Displacement = yo + vo t - 1/2 a t^2
- 3.2 = 0 + 0 - 1/2 a(2.0)^2
- 3.2 = -2a
a = 3.2 / 2 = 1.6 m/s^2
An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape. Then the acceleration due to gravity of the moon is 1.6 m/s².
What is gravity ?Gravity, which derives from the Latin word gravitas, which means "weight", is a basic interaction in physics that causes all objects with mass or energy to attract one another. The electromagnetic force, the weak interaction, and the strong interaction are all significantly stronger than gravity, which is by far the weakest of the four fundamental interactions. As a result, it has no appreciable impact on subatomic particle level phenomena. However, at the macroscopic level, gravity is the most important interaction between objects and governs the motion of planets, stars, galaxies, and even light.
Sublunar tides in the oceans are created by the Moon's gravity, much as gravity on Earth imparts weight to physical things (the analogous antipodal tide is generated by inertia).
according to kinematics,
S = ut + 1/2 at²
initial velocity is zero
S = 1/2 at²
putting all the values,
3.2 = 1/2a2²
6.4/4 = a
a = 1.6 m/s²
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The water is flowing through the horizontal constricted pipe. The pressure at one end is 4500Pa, speed is 3m/s and area of cross-section is A, Calculate the speed and pressure at another end where the area of cross-section is A/3.
The speed and pressure at another end will be 9 m/sec and -31500 pascals.
What is gauge pressure?The difference between absolute pressure and atmospheric pressure is known as gauge pressure. Relative pressure is another name for gauge pressure.
Given data in problem is;
For horizontal pipe, Z₁=Z₂
Pressure at end 1, P₁ = 4500Pa
Speed at end 1, V₁ = 3 m/sec
Speed at end 2, V₂ = ? m/sec
Area of cross-section at end 1,A₁ =A
Area of cross-section at end 1,A₂ = A/3
From the continuity equation;
A₁V₁=A₂V₂
A× 3 = (A/3)×V₂
V₂ = 9 m/sec
From Bernoulli's equation;
[tex]\rm \frac{P_1}{\rho g} + \frac{v_1^2}{2g} +Z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} +Z_2 \\\\ \frac{P_1-P_2}{\rho g } = \frac{v_2^2-v_1^2}{2g} \\\\ \frac{P_1-P_2}{\rho} = \frac{v_2^2-v_1^2}{2} \\\\ \frac{4500-P_2}{1000} = \frac{9^2-3^2}{2} \\\\ 4500 -P_2 = 36000 \\\\ P_2 = - \ 31,500 \ pa[/tex]
Hence the speed and pressure at another end will be 9 m/sec and -31500 pascals.
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After washing lettuce, you can dry the water from it using a salad spinner. You put the lettuce in the bowl, and then crank the handle, spinning and drying the lettuce.
From the frame of reference of the lettuce in the spinning strainer, what causes the water on the lettuce to come off the lettuce and go to the walls of the bowl?
The centripetal force
The force of gravity
Newton's first law of motion
The centrifugal force
Centripetal force causes the water on the lettuce to come off the lettuce and go to the walls of the bowl.
What is centripetal force?Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation. This force can move the body in the circular direction.
So we can conclude that Centripetal force causes the water on the lettuce to come off the lettuce and go to the walls of the bowl.
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The force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is the centrifugal force.
What is the centrifugal force?The centrifugal force is the force that force that tends to throw an object out of the circular path. It is the opposite of the centripetal force which tends to keep the object in the circular path.
Hence. the force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is the centrifugal force.
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The stool is 120 cm tall. How tall is it in inches? Note: there are 2.54 cm in 1 inch
Answer:
47.24 in
Explanation:
120 / 2.54 = 47.24
A motor hoists a mass m = 60 kg crate at a constant velocity to a height of h = 5 m in 2 s. If the indicated power of the motor is 3.2 kW, determine the motor's efficiency.
Problem 3: A block of mass m= 15.5 kg rests on an inclined plane with a coefficient of
static friction of us = 0.11 between the block and the plane. The inclined plane is L = 6.8 m long and
it has a height of h = 3.05 m at its tallest point.
A. What angle in degrees does the plane make with respect to the horizontal? B. What is the magnitude of the normal force in newtons that acts on the block? C. What is the component of the force of gravity along the plane, fgx in newtons? D. Write an expression in terms of degrees, the mass, the coefficient of the static friction, and the gravitational constant, for the magnitude of the force due to static friction, just before the block begins to slide.
(a) The angle the plane makes with respect to the horizontal is 27⁰.
(b) The magnitude of the normal force acting on the block is 135.3 N.
(c) The component of the force of gravity along the plane, fgx is 68.96 N.
(d) The expression for the net force on the block is mgsinθ - μmgcosθ = 0.
Angle of the plane with respect to the horizontalsin θ = h/L
where;
θ is the angle of inclinationh is height of the inclineL is length of the planesin θ = 3.05/6.8
sin θ = 0.4485
θ = arc tan(0.4485)
θ = 26.7⁰
θ ≈ 27⁰
Normal force on the blockFₙ = mgcosθ
Fₙ = (15.5)(9.8)cos(27)
Fₙ = 135.3 N
Parallel component of the force on the planeFx = mgsinθ
Fx = (15.5)(9.8) sin(27)
Fx = 68.96 N
Net force on the block∑F = 0
Fx - Ff = 0
mgsinθ - μmgcosθ = 0
Thus, we can conclude the following;
the angle the plane makes with respect to the horizontal is 27⁰, the magnitude of the normal force acting on the block is 135.3 N,the component of the force of gravity along the plane, fgx is 68.96 N, and the expression for the net force on the block is mgsinθ - μmgcosθ = 0.Learn more about static friction here: https://brainly.com/question/13680415
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A sphere of radius r has surface area
A = 4r2and volume V = (4/3r^3) The radius of sphere 2 is triple the radius of sphere 1.
(a)
What is the ratio of the areas, A2/A1?
(b)
What is the ratio of the volumes, V2/V1?
Answer:
A2/A1 = 9
V2/V1 = 27
Explanation:
Area of Sphere 1; A1 = 4πr²
Volume of Sphere 1; V1 = (4/3)πr³
Area of Sphere 2; A2 = 4π(3r)² = 9*4πr²
Volume of Sphere 2; V2 = (4/3)π(3r)³ = 27*(4/3)πr³
Thus;
A2/A1 = 9*4πr²/4πr² = 9
V2/V1 = [27*(4/3)πr³]/[(4/3)πr³] = 27
A vector of magnitube 5 units is inclined at an angle 37° to the x-axis and another vector of magnitube 10 units is inclined at 53° to the x-axis. What is the magnitude of the sumbof the vector components ( i ) along the x-axis ( ii ) along the y-axis? ( sin 37° = cos 53° = 0.6 / sin 53 = cos 37° = 0.8 )
Answer:
See below
Explanation:
x axis components
5 cos 37 + 10 cos 53 = 5(.8) + 10(.6) = 1.0 units x-axis
y axis components
5 sin 37 + 10 sin 53 = 5(.6) + 10 (.8) = 1.1 units y- axis
The correct answer for the magnitude of the sum of vector is (i) along x-axis is [tex](\sqrt{10})^2[/tex] and (ii) along y-axis is [tex](\sqrt{11})^2[/tex] .
Given:
Vector A magnitude: 5 units,
angle of inclination with x-axis = 37°.
Vector B magnitude: 10 units.
angle of inclination with x-axis = 53°.
Sum of vectors along x-axis:
AB = [tex]\sqrt{5cos37^o +10cos53^o }[/tex]
= [tex]\sqrt{(5*(0.8))^2+(10*(0.6))^2}[/tex]
[tex]= (\sqrt{10})^2[/tex]
Along y-axis:
AB =[tex]\sqrt{5sin37^o +10cos53^o }[/tex]
[tex]\sqrt{5(0.6) +10(0.8) }\\\\= (\sqrt{11})^2[/tex]
Magnitude along x-axis and along y-axis is [tex]10[/tex] and [tex]11[/tex] respectively.
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Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts a force of 75.0 N, the second a force of 96.0 N, friction is 12.0 N, and the mass of the third child plus wagon is 27.0 kg.
(a) What is the system of interest if the acceleration of the child in the wagon is to be calculated? (Select all that apply.)
the wagon
the child in the wagon
the children outside the wagon
(b) Draw a free body diagram, including the weight and all other forces acting on the system. (Do this on paper. Your instructor may ask you to turn in this diagram.)
(c) Calculate the acceleration.
m/s2
(d) What would the acceleration be if friction is 21.0 N?
(a) The system of interest if the acceleration of the child in the wagon is to be calculated are the wagon and the children outside the wagon.
(b) The acceleration of the child-wagon system is 0.33 m/s².
(c) Acceleration of the child-wagon system is zero when the frictional force is 21 N.
Net force on the third child
Apply Newton's second law of motion;
∑F = ma
where;
∑F is net forcem is mass of the third childa is acceleration of the third child∑F = 96 N - 75 N - 12 N = 9 N
Thus, the system of interest if the acceleration of the child in the wagon is to be calculated are;
the wagon the children outside the wagonFree body diagram→ → Ф ←
1st child friction wagon 2nd child
Acceleration of the child and wagon systema = ∑F/m
a = 9 N / 27 kg
a = 0.33 m/s²
When the frictional force is 21 N∑F = 96 N - 75 N - 21 N = 0 N
a = ∑F/m
a = 0/27 kg
a = 0 m/s²
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An extended body (not shown in the figure) has its center of mass at the origin of the reference frame. In the case below give the direction for the torque τ with respect to the center of mass of the body due to force F acting on the body at a location indicated by the vector r.
Options are:
-Y
x
Z
-Z
+ X axis.
The equation for torque is:
[tex]\tau = r \times F[/tex]
Torque is the CROSS-PRODUCT of 'r' and 'F'.
We can use the right-hand rule to determine the direction of torque.
Looking at the diagram, with an open hand, point your fingers towards the top of the picture (Along the +Z axis in the direction of the 'r' vector.)
Then, curl your fingers in the direction of the force vector, (along the -Y axis).
Your thumb will stick out in the direction of the torque, or the +X axis.
You can also just eliminate any options that involve axes that have already been used for 'r' and 'F'. In this case, there are components in the Z and Y axis, so this leaves the 'X' axis to be considered.
A truck is carrying a refrigerator as shown in the figure. The height of the refrigerator is 158.0 cm, the width is 60.0 cm. The center of gravity of the refrigerator is 67.0 cm above the midpoint of the base.
What is the maximum acceleration the truck can have so that the refrigerator doesn't tip over? (The static friction between the truck and the refrigerator is very large.)
The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².
What will be the maximum acceleration of the truck to avoid tipping over?The maximum acceleration is obtained by taking clockwise moments about the tipping point of rotation.
Clockwise moment = Anticlockwise moment
Ft * 1.58 m = F * 0.67 m
where
Ft is tipping force = mass * acceleration, aF is weight = mass * acceleration due to gravity, gm * a * 1.58 = m * 9.81 * 0.67
a = 4.15 m/s²
The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².
In conclusion, the acceleration of the truck is found by taking moments about the tipping point.
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A ball slows down as it rolls up a hill. What is the value of the change in its kinetic energy, ΔEk?
Positive
Zero
Negative
For a ball that slows down as it rolls up a hill the value of the change in its kinetic energy, ΔEk is: Negative
Meaning of Kinetic energyKinetic energy can be defined as the ability assumed by an object in motion.
Kinetic energy is also said to be a form of mechanical energy that is possessed by an object to be in motion.
Normally kinetic energy is believed to be positive by when it begins to slow down a negative effect is experienced
In conclusion, For a ball that starts rolling down a ramp the value of the change in its kinetic energy, ΔEk is: Positive
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The atomic mass of nitrogen is 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00. What is the molar mass of ammonium sulphate [(NH4)2SO4]?
A.
63.09 g
B.
84.17 g
C.
114.12 g
D.
118.16 g
E.
132.17 g
Reset Next
The molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g (option E). Details about molar mass can be found below.
How to calculate molar mass?The molar mass of a substance can be calculated by adding the atomic masses of the elements in the compound.
According to this question, the atomic mass of nitrogen is given as 14.01, hydrogen is 1.01, sulfur is 32.07, and oxygen is 16.00.
The molar mass of ammonium sulphate is as follows:
[(NH4)2SO4] = [14.01 + 1(4)]2 + 32.07 + 16.00(4)
= 36.02 + 32.07 + 64
= 132.09
Therefore, the molar mass of ammonium sulphate [(NH4)2SO4] is 132.17 g.
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Hello!
I have an equation where I can't really find To (Initial temperature). The equation is from the formula Newton's law of cooling. To is the initial temperature of the object and ln is the natural log. The -0.00124 is the constant k multiplied by the time.
I just need to find the initial temp.
Answer:
[tex]T_0=80695.17162...[/tex]
Explanation:
Given equation:
[tex]\ln \left(\dfrac{T_0-100}{T_0}\right)=-0.00124[/tex]
To solve the given equation:
[tex]\textsf{Apply log rules}: \quad e^{\ln (x)}=x[/tex]
[tex]\implies \dfrac{T_0-100}{T_0}=e^{-0.00124}[/tex]
Multiply both sides by T₀:
[tex]\implies T_0-100=T_0e^{-0.00124}[/tex]
Add 100 to both sides:
[tex]\implies T_0=T_0e^{-0.00124}+100[/tex]
Subtract [tex]T_0e^{-0.00124}[/tex] from both sides:
[tex]\implies T_0-T_0e^{-0.00124}=100[/tex]
Factor out the common term T₀:
[tex]\implies T_0(1-e^{-0.00124})=100[/tex]
Divide both sides by [tex](1-e^{-0.00124})[/tex]
[tex]\implies T_0=\dfrac{100}{1-e^{-0.00124}}[/tex]
Carry out the calculation:
[tex]\implies T_0=\dfrac{100}{1-0.99876...}[/tex]
[tex]\implies T_0=\dfrac{100}{0.001239231...}[/tex]
[tex]\implies T_0=80695.17162...[/tex]
anyone solve this for mw urgently please.
Decrease.
What is the weight on the equator than at the Poles?Yes, You weigh less on the equator than at the North or South Pole, but the difference is small.
Note that your body itself does not change.
Rather it is the force of gravity and other forces that change as you approach the poles. These forces change right back when you return to your original latitude.
In short, a trip to the equator is not a viable long-term weight-loss program.
Your weight is the combination of all the large-scale, long-term forces on your body. While the earth's gravity is by far the strongest large-scale force, it is not the only one.
We experience as "something pulling you down" is actually the total of all the forces and not just gravity.
The four dominant large-scale, long-term forces are:
The earth's gravity
The sun's gravity
The moon's gravity
The earth's centrifugal force
Hence, the weight of a body at the equator will be less than at the Poles.
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Pls help !!
What must be the same for two resistors that are connected in parallel?
OA. The resistance of each
OB. The voltage drop across each
OC. The power used by each
OD. The current in each
Answer
its c
Explanation:
When resistors are connected in parallel combination the voltage drop across each resistor is same. However , the total current gets branched into different amount .
Question :
— What must be the same for two resistors that are connected in parallel ?
AnswEr :
When the two resistors are connected in parallel therefore , the Voltage drop across each resistors will be same .Option B seems to be correct answer .
A vector A⃗ has a magnitude of 40.0 m and points in a direction 20.0∘ below the positive x axis. A second vector, B⃗, has a magnitude of 75.0 m and points in a direction 50.0 above the positive x axis. Sketch the vectors A⃗ , B⃗ , and C⃗ =A⃗ +B⃗, and using the component method of vector addition, find the magnitude of the vector C⃗ .
The magnitude of the vector C is 96.32m
How to solve for the magnitude of vector c
Ax = AcosθA
= 40 cOS 20
= 37.59
Ay = AsinθA
-40sin20
= -13.68
Bx = B cos θ B
= 75Cos50
= 48.21
By = BsinθB
= 75sin50
= 57.45
Cx = AX + Bx
= 37.59 + 48.21
= 85.8
Cy = Ay + By
= -13.65 + 57.45
= 43.77
The magnitude is solved by
|c| = [tex]\sqrt{Cx^{2}+Cy^{2} }[/tex]
= √85.8² + 43.77²
= 96.32m
The magnitude of the vector c is 96.32m
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Why was the APA not implemented early on for research on humans and these ethics of research in place?
APA not implemented early on for research on humans and these ethics of research in place because there was no stable and widely accepted system of research.
What is APA?
This is referred to a writing style used by American Psychological Association in reasearches etc.
There was no stable method of writing which was the reason why it wasn't used early for researches.
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how mesuremerment of gravity using simple pendulum
Answer:
See below
Explanation:
Set up your pendulum
measure its length and time the period ( you could time 100 of them and divide the time result by 100 to get the period, T)
then use
T = 2 pi sqrt (L/g) T = period L = length g = gravity
Complete the sentence to describe how light behaves as it relates to its nature (waves or particles). light travels as and interacts with matter as .
Light behaves as it relates to its nature (waves or particles). light travels as and interacts with matter as wave particles.
What is light?Electromagnetic radiation that is within the region of the electromagnetic spectrum that the human eye can see is referred to as light or visible light.
The main characteristics of light include intensity, polarization, frequency or wavelength spectrum, and propagation direction. One of the fundamental constants of nature is its speed in a vacuum, which is 299 792 458 meters per second (m/s).
Light can be categorized according to two theories: the first categorizes light as particles, and the second categorizes light as waves.
The main difference between the wave and particle natures of light is that the former asserts that light can act as an electromagnetic wave while the latter asserts that light is made up of tiny particles known as photons.
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Answer: 1.waves 2.particles
Explanation: just did it!<3
What is my speed for this?
A treasure chest full of silver and gold coins is being lifted from a pirate ship to the shore using two ropes as shown in the figure. The mass of the treasure chest is 75.6 kg.
If the tension in rope A is 7.42x10^2 N and the tension rope B carries is 7.52x10^2 N, what is the tension in rope C?
The tension in rope C is determined as 122.23 N.
Tension in rope CThe tension in rope C is calculated as follows;
B² = A² + C²
C² = B² - A²
C² = (752²) - (742²)
C² = 14,940
C = √14,940
C = 122.23 N
Thus, the tension in rope C is determined as 122.23 N.
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A cube, whose mass is 0.660 kg, is attached to a spring with a force constant of 106 N/m. The cube rests upon a frictionless, horizontal surface (shown in the figure below).
The cube is pulled to the right a distance A = 0.140 m from its equilibrium position (the vertical dashed line) and held motionless. The cube is then released from rest.
(a) At the instant of release, what is the magnitude of the spring force (in N) acting upon the cube?
________N
(b) At that very instant, what is the magnitude of the cube's acceleration (in m/s2)?
_____ m/s2
(c)
In what direction does the acceleration vector point at the instant of release?
- The direction is not defined (i.e., the acceleration is zero).
-Away from the equilibrium position (i.e., to the right in the figure).
- Toward the equilibrium position (i.e., to the left in the figure).
- You cannot tell without more information.
***Please refer to attached photo
Answer:
F = - F x force acting on cube
F = -106 N/n * .14 m = -14.8 N direction opposite to force
a = F / m = -14.8 N / .66 kg = -22.5 m/s^2 acceleration of cube
direction is towards equilibrium point (opposite F)
Select the correct answer. Which segment of this graph shows a decreasing velocity? Graph representing Time in seconds on the x-axis and position in miles on the y-axis. The line starts at point A (0, 20), and passes points B (20, 20), C (40, 40), D (60, 60), E (80, 60), and F (100, 80) A. A to B B. B to C C. C to D D. D to E E. E to F
The portion that shows a decreasing velocity is D to E.
What is a position - time graph?The position time graph is used to describe the motion of a body. We know that the slope of a velocity time graph is the velocity of the graph.
If we look at the graph as shown in the image attached to the answer, we can see that the portion that shows a decreasing velocity is D to E.
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Answer:
D - E
Explanation:
hope this help
Karen Horney, a prominent neo-Freudian, believed that Freud's theory Select one: A. discounted the importance of dreams. B. disputed that women never experience a phallic stage of development. C. discounted strong unconscious, aggressive desires. D. showed a masculine bias.
Karen Horney, a prominent neo-Freudian, believed that Freud's theory showed a masculine bias (Option D).
What is Freud's theory?Freud's theory, also called the psychoanalytic theory, is a model used in physiology to understand human behavior.
Freud's theory is based on the assumption that human behaviors are mainly controlled by the libido (unconscious) of people.
In conclusion, Karen Horney believed that Freud's theory showed a masculine bias (Option D).
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Using appropriate technology, you determine that Earth's magnetic field at your location has a magnitude of 5.88 10-5 T and is directed north at an angle of 56° below the horizontal. You charge a metallic projectile and fire it north with a speed of 663 m/s and at an angle of 14° above the horizontal. Determine the sign (+ or −) and charge of the projectile, if the magnetic force on the projectile is 3.22 10-10 N, directed due west.
C
The sign (+ or −) and charge of the projectile, if the magnetic force on the projectile is 3.22 10-10 N, directed due west is mathematically given as
q=+1.11524613*10^{−4}C
What is the sign (+ or −) and charge?Generally, the equation for Force is mathematically given as
[tex]F=Bqvsin\theta[/tex]
Therefore
[tex]3.22 10^{-10}= 5.88 10^{-5 } *633*sin 56*q\\\\q=\frac{3.22 10^{-10}}{5.88 10^{-5 } *633*sin 56}[/tex]
q=+1.11524613*10^{−4}C
In conclusion, the sign (+ or −) and charge
q=+1.11524613*10^{−4}C
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An ideal gas in an isentropic process has an initial pressure of 200 kPa and relative pressure is 3.482; the final pressure is now 320 kPa, find the relative pressure at this state. round to the nearest 3 decimal places
The relative pressure at this state is determined as 0.455.
Initial pressure of the ideal gasThe pressure of the ideal gas given rise to the relative pressure is calculated as follows;
R.P = P2/P1
P2 = P1(R.P)
P2 = 200 kPa x (3.482)
P2 = 696.4 kPa
New relative pressureR.P = (P3)/(P2)
R.P = (320)/(696.4)
R.P = 0.455
Thus, the relative pressure at this state is determined as 0.455.
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