How is gravity involved in the formation of stars?

Answer:

it would depend on which element u would be considering

Explanation:

as helium , oxygen , carbon ,sodium and other would be easier while plutonium , americium and other very radioactive elements would be harder

Answer:

~ 20 half lives

Explanation:

(1/2) ^n   = 1/1,000,000     n = number of half-lives

                                        LOG both sides to get

n LOG 1/2 = -6

n = -6/(LOG (1/2)) = 19.931    or approx  20 half lives

Answer:

Approximately [tex]111\; {\rm \Omega}[/tex].

Explanation:

It is given that [tex]R_{1} = 200\; {\Omega}[/tex] and [tex]R_{2} = 250\; {\Omega}[/tex] are connected in a circuit in parallel.

Assume that this circuit is powered with a direct current power supply of voltage [tex]V[/tex].

Since [tex]R_{1}[/tex] and [tex]R_{2}[/tex] are connected in parallel, the voltage across the two resistors would both be [tex]V[/tex]. Thus, the current going through the two resistors would be [tex](V / R_{1})[/tex] and [tex](V / R_{2})[/tex], respectively.

Also because the two resistors are connected in parallel, the total current in this circuit would be the sum of the current in each resistor: [tex]I = (V / R_{1}) + (V / R_{2})[/tex].

In other words, if the voltage across this circuit is [tex]V[/tex], the total current in this circuit would be [tex]I = (V / R_{1}) + (V / R_{2})[/tex]. The (equivalent) resistance [tex]R[/tex] of this circuit would be:

[tex]\begin{aligned} R &= \frac{V}{I} \\ &= \frac{V}{(V / R_{1}) + (V / R_{2})} \\ &= \frac{1}{(1/R_{1}) + (1 / R_{2})}\end{aligned}[/tex].

Given that [tex]R_{1} = 200\; {\Omega}[/tex] and [tex]R_{2} = 250\; {\Omega}[/tex]:

[tex]\begin{aligned} R &= \frac{1}{(1/R_{1}) + (1 / R_{2})} \\ &= \frac{1}{(1/(200\: {\rm \Omega})) + (1/(250\; {\rm \Omega}))} \\ &\approx 111\; {\rm \Omega}\end{aligned}[/tex].

Answer:

power= work done/ time

power=mgh/time

mass(m) =50kg

acelleration due to gravity (g)= 10g/m^2

height(h) =20.0m

time = 1min

Explanation:

power =50×10×20 /1

power = 10,000watts

power =10 ×10^3kw

p =10 Kilowatt's

From the calculations, the value of the acceleration due to gravity is 0.38 m/s^2.

The weight of an object is obtained as the product of the mass of the body and the acceleration due to gravity.

Thus;

When;

mass = 120 kg

weight =  46 N

acceleration due to gravity = 46 N/120 kg

=0.38 m/s^2

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The speed of the cart after 3 seconds of Low fan speed is equal to 54 cm/s.

Mathematically, speed can be calculated by using this formula;

Speed = distance/time

At Low fan speed after 3 seconds, the distance covered is 162 cm:

Speed = 162/3

Speed = 54 cm/s.

At Medium fan speed after 5 seconds, the distance covered is 600 cm:

Speed = 600/5

Speed = 120 cm/s.

At High fan speed after 2 seconds, the distance covered is 128 cm:

Speed = 128/2

Speed = 64 cm/s.

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The speed of the cart after 3 seconds of Low fan speed is 55 cm/s.

The speed of the cart after 5 seconds of Medium fan speed is 120 cm/s.

The speed of the cart after 2 seconds of High fan speed is 63 cm/s.

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its si unit is m/sec.

The graph in the attachment may be used to estimate the cart speed for various fan speeds.

Blue letters indicate the low fan speed. When the line drawn from x hits the blue line, the elapsed time is indicated on the x-axis cart speed after three seconds.

This is equivalent to 55 cm/s.Yellow markings indicate the medium fan speed. After 5 seconds, the line drawn from the point marked 5 on the x-axis crosses the yellow line, marking the time that has passed.

The intersection of the yellow line with the line drawn from the point marked 5 on the x-axis indicates the cart speed five seconds later. The y-axis measurement is roughly 120 cm/s.

Green markings indicate the high fan speed. On the x-axis is the elapsed time. Cart speed at the place where the green line and the line drawn from the x-point axis 2 connect. The y-axis reading is roughly 63 cm/s.

Hence, after the specified seconds, the cart's estimated speeds at low, medium, and high speeds are 55 cm/s, 120 cm/s, and 63 cm/s, respectively.

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Answer:

6 amps

Explanation:by Kirchhoff's loop rule the current at any point in the loop must be equal or charge would be building up. The current at the ammeter is equally to the total current through the sun of the paths in parallel which it is in series with

Answer:

It allows you to walk faster.

Explanation:  

It is the same force that allows you to accelerate forward when you run. Your planted foot can grip the ground and push backward, which causes the ground to push forward on your foot. We call this grip type of friction, where the surfaces are prevented from slipping across each other, a static frictional force.

By using Displacement method we can find volume of irregular object like marble.

In displacement method,  

First , we measuring the volume of water displaced by an object which tell us the volume of the object.

Secondly We can use the physical balance to determine its mass.

Lastly , calculate the density by dividing the mass by the volume.

Procedure to find the Volume of irregular object i.e. marble

step 1 - Fill the graduated cylinder about half full and measure the initial volume of water.

step 2 - Drop the marble in the graduated cylinder.

step 3 -Now measure the final level of water.

Step 4 - Subtract both the values.

Here , comes the Volume of Irregular Object.

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Answer:

24 mph

Explanation:

Speed = Distance / Time

Speed = 20 ÷ 5/6

Speed = 24 mph

NOTE: 5/6 is a fraction in this case and is equivalent to 50/60 and 60 minutes = 1 hour of course.

Hope this helped!

Answer:

[tex]\textsf {speed = 24 mph}[/tex]

Explanation:

[tex]\textsf {Formula used :}\\\implies \textsf {speed = distance/time}[/tex]

[tex]\mathsf {Given :}[/tex]

[tex]\implies \textsf {distance = 20 miles}[/tex]

[tex]\implies \textsf {time = 50 minutes = 5/6 hour}[/tex]

[tex]\textsf {Solving :}[/tex]

[tex]\implies \mathsf {speed = 20 \div 5/6 }[/tex]

[tex]\implies \mathsf {speed = 20 \times 6/5}[/tex]

[tex]\implies \mathsf {speed = 4 \times 6}[/tex]

[tex]\implies \textsf {speed = 24 mph}[/tex]

Answer:

Using two to three sentences, summarize what you investigated and observed in this lab. I investigated that Most of my planets and moons had the element carbon in them. I observed that Different elements absorb different wavelengths of light.

Astronomers use a wide variety of technology to explore space and the electromagnetic spectrum; why do you believe it is essential to use many types of equipment when studying space?

It is essential to use a number of telescopes sensitive to different parts of the electromagnetic spectrum to study objects in space. Even though all light is fundamentally the same thing, the way that astronomers observe light depends on the portion of the spectrum they wish to study. Tools are useful, such as detectors that help see the different wavelengths of light. Not all light can get through the Earth's atmosphere, so for some wavelengths we have to use telescopes aboard satellites.

If carbon was the most common element found in the moons and planets, what element is missing that would make them similar to Earth?  Explain why. (Hint: Think about the carbon cycle.)

The missing element that would make moons and other planets similar to earth is oxygen. The two make carbon dioxide.

We know that the electromagnetic spectrum uses wavelengths and frequencies to determine a lot about outer space. How does it help us find out the make-up of stars?  

electromagnetic radiation Explanation, astronomers observe the wavelengths by putting telescopes on mountain tops and take results of what they are seeing

Why might it be useful to determine the elements that a planet or moon is made up of?

It might be useful so we can make new discoveries of life or even plants on other planets and moons. And discover maybe even more moons one other planets.

Hope this helps!!!!

Explanation:

The correct order of processes leading up to the formation of a main sequence star is : ( C ) Gases condense to form a nebula, gravity causes the nebula to collapse and spin, a protostar forms, and nuclear fusion occurs.

A main sequence star is a group of stars which forms a band of stellar types usually 90 percent when plotted on a graph ( spectrum vs luminosity) it also represents the life stages of a regular star in the galaxy.

In conclusion the correct order of the main sequence star is; Gases condense to form a nebula, gravity causes the nebula to collapse and spin, a protostar forms, and nuclear fusion occurs.

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Gravity causes a black dwarf to get dense enough for fusion to happen.

Gravity compresses the core of a protostar which leads to the increase in temperature. When the temperature is high enough that the star starts fusing hydrogen into helium. This fusion reaction is responsible for the formation of new stars.

So we can conclude that Gravity causes a black dwarf to get dense enough for fusion to happen.

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Answer:

proton in a material all spin in the opposite direction

Answer:

The kinetic energy is proportional to the square of the speed, so doubling the speed increases the kinetic energy by a factor of 4.

The density of the metal sphere is 2 times the density of the liquid as proved.

The net upward force acting on the sphere as it is dropped into the liquid is calculated as follows;

F =  σVg - ρVg

ma =  σVg - ρVg  

where;

σV(a) =  σVg  - ρVg

σ(a) = σg  - ρg

σ(g/2) = σg -  ρg  

g(σ/2) = g(σ -  ρ)

σ/2 = σ -  ρ

σ/2 - σ = -  ρ

-σ/2 = -  ρ

σ = 2ρ

Thus, the density of the metal sphere is 2 times the density of the liquid as proved.

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The words best describe the archer's results are  The correct option is A.

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Precision is about comparing the values to each other then find them near to each other.

Given is an archer's targets on the target board.

Accuracy compares the experimental value to the theoretical value (desired target)

So, when all the values are close to each other but not nearest to the theoretical value, then it is said to be precise but not accurate.

Thus, the correct option is A.

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Answer:

Electron groups could be considered as  Lone pair electrons and bonded pairs of electrons.

Answer: Option D & B

Explanation:

The two or more electrons can be bonded by single bond, double bond, covalent bond of electrons can simply be lone pair of electrons. Unshared pair of electrons are generally termed as lone pair of electrons in an atom which are generally present in the outermost shell of atoms. Hence electron groups can be determined by bonded pairs and lone pairs of electrons.

I got this from another brainly user

The current density of the copper wire is determined as (7.059 x 10⁸ A/m²)/L

The current density of the copper wire is calculated as follows;

J =1/ρ(E) = 1/ρ(V/L)

where;

J =1/ρ(E) = 1/ρ(V/L)

J = (1/1.7 x 10⁻⁸) x (12)/L

J = (7.059 x 10⁸ A/m²)/L

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If the density of the baseball is within the acceptable density range of 0.70 g/cm³ and 0.80 g/cm³, then your response would be Yes and vice-versa.

Density can be defined as a ratio of mass to the volume of an object such as a baseball. Mathematically, the density of a baseball can be calculated by using this formula:

Density = Mass/Volume

Since the necessary parameters weren't provided in the question, I would give an insight on how to answer the question. You should substitute the mass and volume of the given baseball into the above formula and then solve.

Furthermore, if the density of the baseball is within the acceptable density range of 0.70 g/cm³ and 0.80 g/cm³, then your response would be Yes. However, if the density of the baseball is above or below the acceptable density range, then your response would be No.

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Los Angeles lies on the Pacific plate, San Francisco lies on the North American plate, and the meeting point of the two cities is mathematically given as

T = 120 x 105 years

Generally, the equation for Distance is mathematically given as

D = Rate x Time

Therefore

T = D/R

T = (600 x 105) / 5

T = 120 x 105 years

In conclusion, the meeting point of the two plates will be

T = 120 x 105 years

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The main issue that is being discussed in the manuscript is the development of science.

Capitalism impacts on science because extremely narrow and specialized bodies of knowledge creating problems for scientists to bring revolution. The dominant ideas in the society can also limit the development of science.

So we can conclude that the main issue that is being discussed in the manuscript is the development of science.

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KE

For nitrogen n=5

So

Answer:

1.21 or 1.2 acceleration

Explanation:

i think it is 50.0/41.0

which would equal 1.21(depending on if you round it)

Explanation:

Snell's Law of refraction:

Refraction of light obeys the following its two laws which's snell's law.

[tex] \rm \cfrac{sin \: i}{sin \: r } = \mu[/tex]

This is known as the refractive index of the second medium with respect to the first medium. Mu is given as:

[tex] \rm\mu = \cfrac{Speed \; of \; light \; in\; the\; first \; medium}{Speed \; of \; light \; in\; the\; second \; medium}[/tex]

Let's take an example.

If a ray light travels from air to water,then mu = sin i/sin r is the refractive index of water with air.

[tex]\rm \cfrac{sin \: i}{sin \: r } = \mu[/tex]

Ex.1:Ray light from air to water

[tex] \rm \mu \: = \cfrac{3 \times {10}^{8} \: m \: s {}^{1} }{2.25 \times 10 {}^{8} \: m \: s {}^{ - 1} } = \cfrac{4}{3} = \boxed{ 1.33}[/tex]

Ex.2: Ray light from Air to glass:

[tex] \rm \mu \: = \cfrac{3 \times {10}^{8} m \: s {}^{ - 1} }{2 \times {10}^{8 \: } m \: s {}^{ - 1} } = \cfrac{3}{2} = \boxed {1.5}[/tex]

[tex] \rule{225pt}{2pt}[/tex]

Strong nuclear and weak nuclear forces act only over short range distances.

Forces are agents which bring about a change in the state or motion of an object.

Forces can be described as pull or push agents.

Forces can either be contact or non-contact forces.

Some non-contact forces are gravitational forces and nuclear forces.

Nuclear forces act only over short range distances. Example are the strong and weak nuclear forces.

Therefore, strong nuclear and weak nuclear forces act only over short range distances.

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Answer:

Because the angle of the sun moves/rotates in the summer, the sun's rays move their angle and impact the earth.

Answer:

1,86

Explanation:

V=V0+a x t

8 m/s=0 m/s + a x 4,3 s

8m/s=a x 4,3 s

a= 8m/s / 4,3 s

a=1,86

V=Last speed

V0=Initial speed

a=acceleration

t=time