How far does the runner travel in 10 s going a velocity of 4m/s

[tex]\huge{\color{red}{\fbox{\textsf{\textbf{Answer}}}}} [/tex]

94.6J

Explanation:

Force (F) = 22N

mass (m) = 12kg

distance (S) = 4.3m

While

[tex] \sf Work \: done = Force \times distance[/tex]

This means

W = FS

while mass has no role in equation

Now substituting the required values

[tex] \sf W = 4.3 \times 22 \\ \\ \sf W = 94.6J[/tex]

Answer:

Let M1 = 8 kg and M2 = 34 kg

F = M a = (M1 + M2) a

F = M2 g     the net force accelerating the system

M2 g = (M1 + M2) a

a = M2 / (M1 + M2) g = 34 / (42) g = .81 g = 7.9 m/s^2

Answer:

In a simplest terms,

temperature is how hot or cold an object is, while heat is the energy that flows from a hotter object to cooler one

Solved your another question same like this with scaling to Cm this time we go with metre(m)

Scale factor

Mercury

Ven us

Earth

Mars

Jupiter

Saturn

Uranus

Neptune

The roller coaster experiences no friction, the speed of the roller

coaster at point F is mathematically given as

v=  65.72 m/s

Generally, the equation for the Mechanical enegy is is mathematically given as

ME = mgh + 1/2mv^2

Therefore

ME= 80*9.8*200 + 1/2*80*20^2

ME= 172800 J

In conclusion, the speed of the roller coaster at point F is

ME=1/2*m*V^2

172800 = 1/2*80*V^2

v=  65.72 m/s

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Answer:

613.5 pm

Explanation:

We know that de Broglie wavelength of an electron :

λ = 1.227 / √E nm

λ = 1.227 / √400 nm

λ = 1.227 / 20 nm

λ = 0.6135 nm

λ = 0.6135 x 10⁻⁹ m

λ = 613.5 x 10⁻¹² m

λ = 613.5 pm

Wavelength of election having kinetic energy of 400 ev.

Answer:

A. External

Explanation:

External stimulus includes touch/pain, vision, smell, taste, and sound.

Answer: Limestone Caves

Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.

Answer:

0.5

Explanation:

I think it is this beacause if u have the answer you have that

Answer:

Explanation:
Answer: B mechanical waves.

Waves that do require a medium are called mechanical waves.

Answer:

2

Explanation:

there are two lonely pairs

2 hydrogens

Explanation:

oxygen has 3 lone pairs of electrons which do not take part in the bonding leaving two electrons in the outermost shell to be part of it, hydrogen has only one electron in it's outermost shell it needs one electron to be stable so two atoms of hydrogen bonds with one oxygen atom to to share there electrons to be stable.

The rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.

The rate of conduction of core/blubber interface is calculated as follows;

[tex]\frac{Q}{t} = \frac{kA\Delta T}{d}[/tex]

where;

[tex]\frac{Q}{t} = \frac{kA\Delta T}{d} = \frac{kA}{d} (\Delta Ta \ +\Delta Tb)\\\\\frac{Q}{t} = \frac{kA}{d} ((T_1- T_2 \ +\ T_2-T_3)\\\\\frac{Q}{t} = \frac{0.25 \times 22}{0.04} ( 35 - 29 \ + \ 29 - 12)\\\\\frac{Q}{t} = 137.5( 6 + 17)\\\\\frac{Q}{t} = 3,162.5 \ W[/tex]

Thus, the rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.

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The average speed is 18.73 km/hour.It is found as the ratio of the total distance and the total time taken.

The total distance traveled by an object divided by the total time taken is the average speed.

The average speed of an object indicates the pace at which it will traverse a distance. The metric unit of speed is the meter per second.

The given data in the problem is;

Distance (d₁) = 18 Kilometers

Time (t₁) =  2.5 hours

Distance (d₂) = 150 Km

Time (t₂)= 4 hours

Distance (d₃) =10 Km

Time (t₃)=3 hours.

The average speed is found as;

[tex]\rm v_{avg}= \frac{Total \ distance }{Total \ time } \\\\ V_{avg}=\frac{18+150+10}{2.5+4+3} \\\\ v_{avg}= 18.73 \ km/hours[/tex]

Hence, the average speed is 18.73 km/hour.

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Answer:

thermometer A

Explanation:

The range of a thermometer is the difference between the minimum and maximum temperatures that the thermometer can read.

             ∴ Range of thermometer A = 110° - (-10)° = 120°

                Range of thermometer B = 50° - (-10)° = 60°

∴ Range of thermometer A is greatest.

Hope this helps!

The de-Broglie wavelength of a person jogging at the rate of 2.70m/s is 3.5 x 10⁻³² m.

De-Broglie wavelength is the ratio of Planck's constant  h to the momentum of the electron p.

Momentum p = mass m x velocity v

Given is the mass of a person = 70kg, the speed of person 2.70m/s, Planck's constant h= 6.63 x 10⁻³⁴J.s

De- Broglie wavelength λ= h/mv

λ = 6.63 x 10⁻³⁴/ ( 70 x 2.70)

λ = 3.5 x 10⁻³² m

Thus the wavelength is 3.5 x 10⁻³² m.

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Answer:

True

Explanation:

If there isnt any waste it would reduce the quantity however the waste that is present needs to be dealt with so......

Answer:

C) Cardiovascular, muscular strength/power, muscular endurance

Explanation:

I did take the quiz

Answer:

C) Cardiovascular, muscular strength/power, muscular endurance

Explanation:

The kind of atoms or molecules are present and their relative abundance can be determined by observing wavelengths.

Wavelength is the distance between adjacent crest or trough of the wave.

The light travels in the form of wave and particle. It behaves like both. Light ray consist energy of the photons. The kind of atoms or molecules present behave like particle and they have particular wavelength.

Thus, by observing wavelength , we can determine the kind of atoms or  molecules are present and their relative abundance.

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Explanation:

Standard one kilogram is the mass of a platinium- iridium cylinder having equal diameter at the height kept at 0⁰C at the International bureau of Weights and Measures, held in paris in France. The accurate copies of atandard one kilogram are prepared to Measures mass in different countries.....

[tex]....[/tex]

It is defined as the mass of a particular international prototype made of platinum-iridium and kept at the International Bureau of Weights and Measures. It was originally defined as the mass of one liter (10-3 cubic meter) of pure water. At the Earth's surface, a mass of 1 kg weighs approximately 2.20 pounds (lb).

Answer:

The Earth's revolution not only affects but actually causes the temperature conditions that give us spring, summer, fall and winter seasons. Which season it is depends on whether you live in the Northern or Southern Hemisphere because the Earth's axis tilts toward one of the two as it moves around the sun.

Answer:

the first one, The object moving through air

Answer:

real depth / apparent depth = R.I.

Real depth = 1.5 x 1 = 1.5 m

Answer:

Answer C. But don't be surprised if it isn't.

Explanation:

You can't use D. Trees can be replenished. Maybe not as well as God planted them in the first place, but we can replenish them.

A is incorrect. when burned, trees will produce CO2. In fact, trees produce more CO2 when burned that do fossil fuels do

Fossil fuels don't grow. Their rate of discovery might, but they themselves don't grow. Not B

C is your only choice. The problem is that it is not entirely true. We can replenish trees. Whether enough trees can be used as a clean fuel and be replaced in amounts we are used is the question.

We need voltage first

Apply oHMS law

Answer:

c. I = 1.73A

Explanation:

The formula for power :

The formula for potential difference :

Calculating P by inputting the formula of V :

Solving using the given values :

Consider,

[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =m\langle v(t)\rangle=m\int_{-\infty}^{\infty}x\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial t}\Psi (x,t)+\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial t}\bigg\}dx}[/tex]

Multiply both sides by ih and simplification will yield

[tex]{:\implies \quad \displaystyle \sf ih\langle p\rangle =m\int_{-\infty}^{\infty}x\bigg[\Psi (x,t)\bigg\{\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi^{*}(x,t)}{\partial x^2}-V(x)\Psi^{*}(x,t)\bigg\}+\Psi^{*}(x,t)\bigg\{V(x)\Psi (x,t)-\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}\bigg\}\bigg]dx}[/tex]

Some simplification, Then Integrate by parts and then knowing the fact that the wave function vanishes for [tex]{\bf x\to \pm \infty}[/tex] will yield:

[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =\dfrac{ih}{2}\int_{-\infty}^{\infty}\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial x}\Psi (x,t)-\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}\bigg\}dx}[/tex]

Integrating by parts and knowing the same fact by some simplification will yield:

[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =-ih\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}dx}[/tex]

The momentum is thus contained within the wave function, so we can then deduce that:

[tex]{:\implies \quad \sf p\rightarrow -ih\dfrac{\partial}{\partial x}}[/tex]

[tex]{:\implies \quad \sf p^{n}\rightarrow \bigg(-ih\dfrac{\partial}{\partial x}\bigg)^{n}}[/tex]

[tex]{:\implies \therefore \quad \displaystyle \sf \langle p^{2}\rangle =-h^{2}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]

Now the kinetic energy

[tex]{:\implies \quad \displaystyle \sf \langle K\rangle =\dfrac{\langle p^{2}\rangle}{2m}=\dfrac{-h^2}{2m}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]

The classical formula for the total energy

[tex]{:\implies \quad \sf \dfrac{p^2}{2m}+V(x)=E}[/tex]

Multiplying this equation by [tex]{\sf \Psi (x,t)=\psi (x)exp\bigg(\dfrac{-iEt}{h}\bigg)}[/tex] and use the above equations and simplify it we will be having

[tex]{:\implies \quad \boxed{\bf{\dfrac{-h^2}{2m}\dfrac{d^{2}\psi (x)}{dx^{2}}+V(x)\psi (x)=E\psi (x)}}}[/tex]

This is the Famous Time-Independent Schrödinger wave equation

Note:- If I write all the explanation then the Answer box willn't allow me to submit the answer