How does water temperature affect density?

Answers

Answer 1
it expands, increasing in volume. The warmer the water, the more space it takes up, and the lower its density.

Related Questions

What is an electron cloud 5th grade short answer.

Answers

Answer:

the system of electrons surrounding the nucleus of an atom

2. Michael tells Sara he weighs 104 pounds. Sara says she is 44 kilograms. If there are 2.2
pounds in a kilogram, who is heavier?

Answers

Michael is heavier

Sara weighs= 44kg

Michael= 104 pounds which is equal to 47.174kg

THUS, micheal is heavier

Hope this helped you- have a good day bro cya)

4. Analyze: Drag this tile to the green strip. Turn on Show results.
A. What units are given to the right of the equals sign? _ 11,000
B. Why didn't the units cancel in this case? The tile is not fupped
C. What do you think you could do to make them cancel?

Answers

The answer is going to be A

What is conduction?explain? ​

Answers

Answer:

Thermal conduction is the transfer of internal energy by microscopic collisions of particles and movement of electrons within a body. The colliding particles, which include molecules, atoms and electrons, transfer disorganized microscopic kinetic and potential energy, when joined known as internal energy.

Explanation:

sana makatulong

What happens to the sound an object makes when the speed of vibrations decreases (slow down)?.

Answers

The frequency decreases, and you will hear a lower tone

If a powerful gravitational wave passed through you body, moving from your back to your chest, what would happen to your body

Answers

Answer:

If a powerful gravitational wave passed through you body, moving from your back to your chest, what would happen to your body? Your width and height would both oscillate in such a way that you would get taller as you got narrower and shorter as you got wider.

Explanation:

A chemist is studying an unknown substance and could break the substance into its elemental components only by using chemical means. Based on this observation, how should the unknown substance be classified?
A. impure substance
B. solution
C. mixture
D. pure substance

Answers

The answer is D

I took the quiz lol

The magnitude of vector A is 2.5 m and is directed towards east. The magnitude and direction of A /2 will be​

Answers

The magnitude and direction of half of the given vector A is 1.25 m east.

The given parameters;

magnitude of vector A = 2.5 m east

A vector can be described with both magnitude and direction. The magnitude of the vector is the scalar or numeric representation of the vector.

When the scalar representation has direction, we term the quantity a vector quantity.

The magnitude of half of the given vector is calculated as follows;

[tex]\frac{A}{2} = \frac{2.5 \ m}{2} = 1.25 \ m\ east[/tex]

Thus, the magnitude and direction of half of the given vector A is 1.25 m east.

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something about the earth's surface (land or water) changes

Answers

I would say land changes.

The main goal of every defense is to __________. A. stop the ball B. regain possession of the ball C. protect the goal or basket D. all of the above

Answers

Answer:

D.

Explanation:

I believe it is D. Because in defense you are to stop others from scoring, while trying to score. But also while trying to protect the Goal or basket. I hope this helps you out.

Answer:

d

Explanation:

differential rotation is when a planet's equator and polar regions rotate at different rates. True False

Answers

the answer to that is false

The reading on a metronome indicates the number of oscillations per minute. What are the frequency and period of the metronome's vibration when the metronome is set at 180?​

Answers

Answer:

Period: 1/3= 0.33 seconds.

The frequency and period of the metronome's vibration when the metronome is set at 180 is 3Hz and 0.33 s.

What is the frequency?

Frequency is the number of oscillations per second.

The time period is the reciprocal of the frequency.

Given is the metronome set at 180.

The reading of metronome = frequency in seconds = 180 / 60 = 3 Hz

The time period of the metronome's vibration T = 1/3 = 0.33 seconds.

Thus, the frequency and the time period is 3Hz and 0.33 s.

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What is the anomalous expansivity of water

Answers

Answer:

The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4°C to 0°C, and it becomes less dense. The density becomes less and less as it freezes because molecules of water normally form open crystal structures when in solid form.

A block of mass =4.20 kg slides along a horizontal table with velocity 0=3.50 m/s . At =0 , it hits a spring with spring constant =26.00 N/m and it also begins to experience a friction force. The coefficient of friction is given by =0.250 . How far has the spring compressed by the time the block first momentarily comes to rest? Assume the positive direction is to the right.

Answers

The distance in which the spring is compressed is 1.065 m.

The given parameters;

mass of the block, m = 4.2 kgvelocity of the block, v = 3.5 m/sspring constant, k = 26 N/mcoefficient of friction, μ = 0.25

Apply the principle of conservation of energy to determine the distance in which the spring is compressed.

[tex]K.E = W + U\\\\\frac{1}{2} mv^2 = \mu Fx \ + \ \frac{1}{2} kx^2\\\\\frac{1}{2}(4.2)(3.5)^2 = 0.25(4.2 \times 9.8)(x) \ + \frac{1}{2} (26)(x^2)\\\\25.725 = 10.29x \ + \ 13x^2\\\\13x^2 + 10.29x - 25.725 = 0\\\\[/tex]

solve the quadratic equation using formula method;

a = 13, b = 10.29,  c = -25.725

[tex]x = \frac{-b \ \ +/- \ \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-(10.29) \ \ +/- \ \sqrt{(10.29)^2 \ - \ 4(13\times 25.725)} }{2(13)} \\\\x = 1.065 \ m, \ \ or \ -1.86 \ m[/tex]

choose positive distance, x = 1.065 m.

Thus, the distance in which the spring is compressed is 1.065 m.

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If a train is moving south at 50 m/s and a person is running SOUTH on the train at 5 m/s, what is the velocity of the person as seen by someone not moving (watching the train going by)
A-45 m/s North
B-50 m/s South
C-55 m/s North
D-100 m/s South ​

Answers

The velocity of the person as seen by someone not moving (watching the train going by) will be 55 m/s South. I can therefore conclude that none of the option given is correct.

Given that a train is moving south at 50 m/s and a person is running SOUTH on the train at 5 m/s.

That means the person is running relatively to the velocity of the train. Since the train and the person are moving in the same direction, the relative velocity seen by an observer watching the train going will be the addition of both the train and the person in the direction of the train.

That is,

Relative velocity = 50 + 5

Relative velocity = 55 m/s South.

Therefore, the velocity of the person as seen by someone not moving (watching the train going by) will be 55 m/s South.

I can therefore conclude that none of the option given is correct.

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How much force is required to move a tractor 60m, when using 250J of work?

Answers

Answer:

Work done,W= 250J

Displacement , s = 60

We know that, Work done = Force x displacement

i.e , W = Fxs

250 J = F x 60m

F = 250/60

=4.16 N

Hence , 4.16 N of Force is applied on the body.

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

are hotspots active vocanclos

Answers

Answer:

Yes

Explanation:

Thus, as a plate moves over the location of a plume eruption, it carries successively older volcanoes with it. As hotspot volcanoes are transported by plate motion away from the mantle plume, hotspot volcanism ceases. Eventually the hotspot volcanoes become extinct, gradually subside, and are eroded by wave action.

Have the best day! :D

Answer:

yes

Explanation:

Thus, as a plate moves over the location of a plume eruption, it carries successively older volcanoes with it. As hotspot volcanoes are transported by plate motion away from the mantle plume, hotspot volcanism ceases. Eventually the hotspot volcanoes become extinct, gradually subside, and are eroded by wave action.

hope this helps!

You get in your car after work and turn on the radio. What type of communication does the radio use?.

Answers

Answer:

Radio waves

Explanation:

The radio operates by the principles of radio wave.

Electromagnetic wave is a type of wave which does not require material medium for its propagation. A radio wave is an example of electromagnetic wave.

The radio operates in the principle of electromagnetic wave because it does not require material medium for its propagation and it has one of the longest frequency of electromagnetic spectrum.

Thus, we can conclude that the radio operates by the principles of radio wave.

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If you pass an electric current through an iron nail, you will create an electromagnet. This magnet will pick up small objects, thus demonstrating that electrical energy can be converted into mechanical energy. Is there a way to use this principle to create a motor?

Answers

An iron nail, when it loses its magnetism, often iron behaves as a magnet when electric current flows only through the coil of insulated wire wrapped around it. There is therefore, a way to use this principle to create a motor.

An electromagnet is said to be created if a known current is passed through a coil of wire gathered around an iron nail.

The principle is often used to make an electric motor by creating a  current that is moving coil into a movable core that is attached to a spring.

If a current flows through a wire, electrical energy is said to be converted into different kinds of energy such as  heat in a heating element, etc. The electric current could also be transformed or made to create a mechanical energy, which is what happens in an electric motor.

A motor is simply known as a generator working in reverse. This can be liken to a motor when a wire is put in between the two paper clips that are connected to the battery.

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The wave height is equal to twice the _____.wave period wave height wave amplitude wave velocity wavelength

Answers

The wave height is equal to twice the amplitude of the wave.

The wave height of a wave of given wave with amplitude, period and wavelength is equal to twice the amplitude of the wave.

The amplitude of a wave is the maximum displacement of the wave, starting from the zero position of the wave. The wave height measures twice the maximum displacement of the wave.

Thus, we can conclude that the wave height is equal to twice the amplitude of the wave.

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Using Boyle's law, predict what will happen to a balloon that an ocean diver takes to a pressure of 202 kPa.
NO LINKS YA FILTHY VERMINS

Answers

Answer:

Balloon that an ocean diver takes to a pressure of 202 k Pa will get reduced in size that is the volume of the balloon will get reduced

Explanation:

what is the speed of a geosynchronous satellite orbiting mars?

Answers

Answer:

3.07 kilometres per second

How many molecules of Oxygen gas are there on the reactant side of this equation?
C2H6 + 402 ———-> CO2 + H2O
O2
O3
04
O8

Answers

Answer:

4

Explanation:

It has 8 O atoms and 4 O2(g) molecules

At what tension, in newtons, must the D-string must be stretched in order for it to be properly tuned

Answers

The fundamental frequency, wavelength of the wave, and mass per unit

length of the string, determines the tension in the string.

The tension to which the D-string must be tuned is approximately 19.718 Newtons

Reasons:

From a similar question, we have;

Fundamental frequency, f₁ = 146.8 Hz

Oscillating length on the D-string, λ₁ = 0.61 m

Mass of the string = 1.5 × 10⁻³ kg.

We have;

[tex]\displaystyle f_1 \cdot \lambda _1 =\mathbf{ \sqrt{\frac{T}{m/L} }}[/tex]

Therefore;

[tex]\displaystyle T = \mathbf{\frac{f_1^2 \cdot \lambda _1^2 \cdot m }{L}}[/tex]

Which gives;

[tex]\displaystyle T = \frac{146.8^2 \times 0.61^2 \times 1.5 \times 10^{-3} }{0.61 } \approx \mathbf{19.718}[/tex]

The tension to which the D-string must be tuned, T ≈ 19.718 Newtons

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The parameters given in a similar question obtained online are;

The fundamental frequency of the tone, f₁ = 146.8 Hz

The oscillating length on the D-string, λ₁ = 0.61 m

The mass of the string = 1.5 × 10⁻³ kg.

Physics - Electricity and Magnetism

A ceiling fan operates at three speeds, using 120 V of electricity from the wall. At low speeds, it uses 0.25 A. Calculate the resistance needed to generate that current. Then in 1-2 sentences, describe how the resistance would change at medium and high speeds if larger currents are needed at those speeds. Your answer should include the calculated resistance and a sentence describing your reasoning.

Answers

Answer:

480 Ohms for the calculations

Explanation:

For the calculations:

V = 120 and I = 0.25

V = IR

R = V/I

R = 120/0.25

R = 480 Ohms

For the sentences, I am so sorry, I do not have them yet!

I. The resistance which is needed to generate a current of 0.25 Ampere in the ceiling fan is 480 Ohms.

II. Since current is inversely proportional to the resistance in the electrical circuit, an increase in the current (larger currents) flowing into the electrical circuit of the ceiling fan would cause the resistance to decrease in magnitude at medium and high speeds.

Given the following data:

Voltage = 120 VoltsCurrent = 0.25 Ampere

To calculate the resistance needed to generate that current, we would apply Ohm's law:

Ohm's law states that at constant temperature, the current flowing through an electrical circuit is directly proportional to the voltage (potential difference) applied across the two terminals of the electrical circuit and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

[tex]V=IR[/tex]

Where;

V is the voltage measured in Volts.I is the current measured in Ampere.R is the resistance measured in Ohms.

Making R the subject of formula, we have:

[tex]R =\frac{V}{I}[/tex]

Substituting the given parameters into the formula, we have;

[tex]R=\frac{120}{0.25}[/tex]

Resistance, R = 480 Ohms

Since current is inversely proportional to the resistance in the electrical circuit, an increase in the current (larger currents) flowing into the electrical circuit of the ceiling fan would cause the resistance to decrease in magnitude at medium and high speeds.

In conclusion, the larger the current, the lower the resistance would be at both medium and high speeds.

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What is the orbital period of a spacecraft in a low orbit near the surface of mars? the radius of mars is 3. 4×106m.

Answers

Answer:

if not sure sorry hope someone helps u❤️

A 75.0 kg man pushes on a 500,000 kg wall for 250 s but it does not move.

Answers

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The work done in the given case is 0

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

For calculating the work done by an object we apply the formula, that is ~

[tex]f \times s \times \cos( \theta) [/tex]

where f represents force applied, and s represents displacement.

but here, the displacement is zero since the wall didn't move at all, Therefore If we plug it's value as 0, we get

[tex]f = 0 \times s \times \cos( \theta) [/tex]

hence,

[tex]work \: done = 0[/tex]

Solution:Here, though the man is applying force on the wall, the work done is zero. This is because work is said to be done only when a force acting on a body produces motion in it in the direction of the force applied. Here, the man is trying to push the wall with a great force. He might fell exhausted after some time and say that he has done a lot of work. But in terms of physics, he has done no work because the force applied by the person has not produced any displacement. We know, work done = force × displacement. If displacement is zero, then work done is zero.

So therefore, we can conclude that the man hasn't done any work.

Hope it helps.

Do comment if you have any query.


During a test, a solution placed on a sheet
of metal creates bubbles. This solution is
most likely
A. Acidic
B. Neutral
C. Basic

Answers

Answer:

B. Acidic

Explanation:

Neutral an Basic solutions wouldn't create any reaction

If during a test, a solution placed on a sheet of metal creates bubbles, we can conclude that this solution is most likely Acidic.

Reaction of metals with acid

Acid reacts vigorously with metal, displacing hydrogen gas in the process and this process creates bubbles of gases trying to escape from the solution.

Metals do not react basic and neutral solutions.

If during a test, a solution placed on a sheet of metal creates bubbles, we can conclude that this solution is most likely Acidic.

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When waves are closer together and there are more waves, then the wave has a higher ____________.

Answers

Answer:

When waves are closer together and there are more waves, then the wave has a higher frequency.

Explanation:

Hoped this helped.

Answer:

frequency

Explanation:

What acceleration occurs if the friction force in #4 is now 4N?

Answers

The acceleration of the 20 N force is 6.67 m/s^2. The acceleration of the 4N force is 1.33 m/s^2.

What is force?

We define the force that acts on a body as that which is able to cause an acceleration or that which is able  to change the direction of an object. Recall that from the Newton first law, an object would continue in its state of rest or uniform motion unless the object is acted upon by an external force.

Now the frictional force is the force that tends to resist the motion of two surfaces that are in contact. Owing to the fact that it is a resistive force its direction is always opposite the force that seeks to move the object forward.

Now;

F = ma

a = F/m

a = 20 N/3Kg

a = 6.67 m/s^2

If the force is 4N;

a = F/m

a = 4N/3Kg

a = 1.33 m/s^2

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Missing parts;

How would you calculate the acceleration if you push with a 20 N horizontal force on a 3 kg block on a horizontal friction-free air table? What is the acceleration if the friction force is 4 N?

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