How does increasing the temperature of a liquid below the boiling point affect
the motion of the particles in the liquid?
OA. The particles move faster.
B. The motion of the particles overcomes the forces holding the
particles together.
OC. The motion of the particles strengthens the forces between the
particles.
D. The particles move slower.

Q methane = Q water

Q = mcΔt

mass water = V x ρ = 1 L x 1 kg/L = 1 kg

298 K to 373K = 25 °C to 100 °C

c water = 75.2 J/mol K = 4.2 J / g °C = 4200 J/kg °C

Q water = 1 x 4200 x (100 - 25)

Q water = 315000 J

Q methane = Q water = 315000 J = 315 KJ

n (mol) methane = ΔH/Q = 890.4 / 315 = 2.83

PV = nRT

V = nRT/P

V = 2.83 x 0.082 x 298/1

V = 69.15 L

The correct statement is Isotopes are members of a family of an element that all have the same number of protons but different numbers of neutrons.

In a simple way to explain, Isotopes are species that have the same atomic number and mass number.

In this case, we can say that the correct statement is proton number of isotopes of an element is same.

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The mass of the ethylene glycol used is 14.26 g

The freezing point is the temperature at which a liquid is converted to a solid.

Given that;

ΔT = 0.0°C - ( -4.3°C) = 4.3°C

ΔT = 4.3°C

But we know that

ΔT = k m i

m = ΔT/k i

m = 4.3°C/1.86 °C/m * 1

m = 2.3 m

Now;

Let the mass of  ethylene glycol be m

Molar mass of  ethylene glycol = 62 g/mol

Mass of solvent = 100.0 g or 0.1 Kg

Then;

2.3= m/62/0.1

2.3 = m/62 * 0.1

m = 2.3 * 62 * 0.1

m = 14.26 g

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Taking into account the change of units, 100 meters are 109.361 yards and 328.084 feets.

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.  

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied.

To solve a direct rule of three, the following formula must be followed, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: [tex]x=\frac{cxb}{a}[/tex]

The direct rule of three is the rule applied in this case where there is a change of units.

To perform in this case the conversion of units, you must first know that:

Then, you can apply the following rules of three:

1 meter ⇒ 1.09361 yards

100 meters ⇒ x

So: [tex]x=\frac{100 metersx1.09361 yards}{1 meter}[/tex]

Solving:

x= 109.361 yards

1 meter ⇒ 3.28084 feets

100 meters ⇒ x

So: [tex]x=\frac{100 metersx3.28084 feets}{1 meter}[/tex]

Solving:

x= 328.084 feets

In summary, 100 meters are 109.361 yards and 328.084 feets.

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Incomplete combustion does not form water and carbon dioxide when it burns.

A fuel receives enough oxygen to complete combustion when it burns in a lot of air.

Fuels like gasoline and natural gas contain hydrocarbons. These are only hydrogen and carbon compounds. When they totally burn:

The hydrogen oxidizes to water while the carbon turns into carbon dioxide (remember that water, H2O, is an oxide of hydrogen)

for full combustion:

hydrocarbon + oxygen→Carbon dioxide + water

The following equations describe how propane, which is used in bottled gas, completely burns.

oxygen + propane→carbon dioxide + water

C3H8 + 5O2 → 3CO2 + 4H2O

When there is insufficient air or oxygen present, incomplete combustion ensues. Carbon dioxide is still created, but it is replaced with carbon monoxide and carbon.

For incomplete combustion in general:

Hydrocarbon + Oxygen→ Carbon Monoxide + Carbon+ Water

incomplete propane combustion, which results in the production of carbon rather than carbon monoxide

oxygen + propane→carbon + water

C3H8 + 2O2 → 3C + 4H2O

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If the molecules of air are added continuously to the inflatable bag of the car then the pressure of the molecule will decrease as given by Boyle's law.

Boyle's law is a gas law that establishes the relation between the volume and the pressure of the gas. It states the inverse correlation between the two factors respective to the constant temperature.

Boyle's law is given as:

P₁V₁ = P₂V₂

Where an increase in the volume will decrease the pressure of the gas. So, if the air molecules are added to the bag then the pressure inside will reduce.

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Answer:The first model (full container) represented matter that has a definite shape. The particles were packed tightly and did not have the freedom to rearrange themselves.

Explanation:

We can say that the volume of the object is directly proportional to its mass. As the volume increases the mass of the object increases in direct proportion. The gradient of the graph equals the density of the material.

Taking into account the definition of density, the volume of a full tank car which contains 3.22×10⁴ kg of acetone is 41.02 m³.

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

[tex]density=\frac{mass}{volume}[/tex]

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

In this case, you know that:

Replacing in the definition of density:

[tex]0.785 \frac{g}{cm^{3} }=\frac{32,200,000 g}{volume}[/tex]

Solving:

volume×0.785[tex]\frac{g}{cm^{3} }[/tex]= 32,200,000 g

volume=[tex]\frac{32,200,000 g}{0.785 \frac{g}{cm^{3} }}[/tex]

volume= 41,019,108.28 cm³=  41.01910828 m³≅ 41.02 m³ (being 1 m³ = 1000000 cm³)

In summary, the volume of a full tank car which contains 3.22×10⁴ kg of acetone is 41.02 m³.

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Answer:

false mocktail is liquor yea

Answer: By blowing into the drinking straw to bubble some of their breath in the water, they are adding gas to the water. This will cause the volume of gas to increase.

The students want to increase the volume of gas the pond weed makes in 5 minutes. The students use a drinking straw to bubble some of their breath into the water. The volume of gas the pond weed makes increases because By blowing into the drinking straw to bubble some of their breath in the water, they are adding gas to the water.

This will cause the volume of gas to increase. One way the students could increase the volume of gas the pond weed makes in five minutes is by increasing light intensity. Pond weeds carry out photosynthesis to produce oxygen and light is an essential factor that affects rate of photosynthesis.

If light intensity is increased, more light energy will be available for plant to convert into chemical energy, which can be used in photosynthesis to produce more oxygen. This increases the volume of gas the pond weed makes in given time.

To increase the light intensity, students could move plant closer to a light source or use stronger light source.

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Hello and Good Morning/Afternoon

Let's consider all the choices to determine the attributes of isotopes

        ⇒ isotopes are often found in nature as they are often the atoms

            that form the world around us

        ⇒ isotopes describe a certain type of atom with a certain

             characterist that exists, thus it isn't theoretical

        ⇒ as said before, isotopes are found in nature and form the world

        ⇒Isotopes are a type of atoms thus they are found in nature

Answer: (D)

Hope that helps!

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Answer:

D. found in nature.

Explanation:

Isotope is any of two or more forms of a chemical element, having the same number of protons in the nucleus, or the same atomic number, but having different numbers of neutrons in the nucleus, or different atomic weights. There are 275 isotopes of the the 81 stable elements, in addition to over 800 radioactive isotopes, and every element has known isotopic forms. Isotopes of a single element possess almost identical properties.  An isotope of an element is just a version of that element with a particular number of neutrons. Some numbers are stable, some are not; the ones that aren't shoot particles out at extremely high speeds ("radiation").

Since radioisotopes generally have the same chemistry as their stable counterparts (since neutrons play almost no role in chemistry), they'll get wherever other atoms of that element would get. Iodine, for example, accumulates in your thyroid gland - so do radioactive forms of iodine, which can then cause thyroid cancer by irradiating it from the inside.

Also because they're chemically almost indistinguishable, they're almost impossible to separate out by any normal means. It's like giving someone a giant bin of golf balls, some of which are 1% heavier than the other golf balls but are otherwise exactly the same, and saying "okay, sort these". Except the golf balls are atoms and the bin is the size of a small country.

The mass and volume has direct proportional to each other.

The volume of the object is directly proportional to its mass which means that if the volume increases the mass of the object increases also increase and vice versa. Due to this direct relationship, the line of regression will go straight between X and Y axis.

So we can conclude that mass and volume has direct proportional to each other.

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Bromine has larger ionic radius and atomic radius than fluorine.

Fluorine has larger ionisation energy and electronegativity than bromine.

Halogen are those elements that are found in group 7 of the periodic table.

Fluorine is in period two of the periodic table, meaning that it contains electrons in only the first two energy levels at ground state. It has a higher ionization energy and electronegativity than bromine.

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Indicate whether fluorine or bromine has a larger value for each of the following properties. a. electronegativity b. ionic radius c. atomic radius d. ionization energy

The partial pressure of oxygen, P(O₂) is 198.83 mmHg.

The partial pressure of a gas is the pressure gas will exert in a mixture of gases which do not react chemically together.

The sum of partial pressure of gases at atmospheric pressure = 760 mmHg

P(N₂) +  P(H₂O) + P(CO₂) + P(O₂) + P(other) = 760 mmHg

P(N₂) = 0.72 atm = 547.2 mmHg

P(H₂O) = 7.7 torr = 7.7 mmHg

P(CO₂) = 0.37 mmHg

P(other) = 0.97 kPa = 5.9 mmHg

P(O₂) = 760 - (547.2 + 7.7 + 0.37 + 5.9) = 198.83 mmHg

Therefore, the partial pressure of oxygen, P(O₂) is 198.83 mmHg.

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Answer:

False

Explanation:

There are two types of covalent bonding: polar covalent boding and nonpolar covalent bonding. During polar covalent bonding, the electrons are not shared evenly. This is due to the electronegativity differences between the two atoms. During nonpolar covalent bonding, the electrons are shared evenly.

The enthalpy change of the reaction, ΔH = -311 kJ

Enthalpy change involved in the reaction of 300 g of CO = -10972.5 kJ

The enthalpy change for the reaction is obtained from the summation of the enthalpies of the reactions of the intermediate steps according to Hess's law.

The equation of the reaction is given below:

The enthalpy of the reaction, ΔH = ΔH₁ + 2ΔH₂ + (-ΔH₃)

ΔH = {(-1299) + (2 * -286) + (1560)}Kj

ΔH = -311 kJ

The equation for the methanation reaction is given below:

3 H₂O + CO → CH₄ + H₂O

The enthalpy for the methanation reaction is as follows:

ΔH = 1.5ΔH₁ + 0.5*(-ΔH₂) + ΔH₃ + -ΔH₄

ΔH = (-483.6 * 1.5) + (0.5 * 221.0) + (-802.7) + (393.5)

ΔH = -1024.1 kJ/mol

Molar mass of CO = 28 /mol

Enthalpy change involved in the reaction of 300 g of CO = 300/28 * -1024.1 kJ/mol

Enthalpy change involved in the reaction of 300 g of CO = -10972.5 kJ

In conclusion, the enthalpy changes are calculated from the enthalpy values of the  intermediate reactions.

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In an exothermic reaction, the reactants have more energy than the products.

Given the heat of fusion of water is 6.02 kJ/mol, it takes 12.9 kJ of heat to melt 38.6 g of ice at 0 °C.

Fusion, commonly known as melting, is a physical process in which matter passes from the solid to the liquid state.

We have ice with a mass of 38.6 g at 0 °C. First, we will convert mass to moles using the molar mass of water.

38.6 g × (1 mol/18.02 g) = 2.14 mol

The heat of fusion (ΔH°fus) for water is 6.02 kJ/mol. The heat (Q) required to melt 2.14 moles of ice is:

Q = 6.02 kJ/mol × 2.14 mol = 12.9 kJ

Given the heat of fusion of water is 6.02 kJ/mol, it takes 12.9 kJ of heat to melt 38.6 g of ice at 0 °C.

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50.97 g AgNO₃ is needed to make 500.0 mL of 0.600 mol/L AgNO3(aq)

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Molar mass of AgNO₃ = (107.9 + 14.0 + 16.0×3) g/mol = 169.9 g/mol

Molarity = Moles of solute ÷ Volume of solution in litre

0.600 mol/L = Moles of solute ÷ 0.5 mL

Moles of solute =0.3 mol

Moles =[tex]\frac{mass}{molar \;mass}[/tex]

0.3 mol =  [tex]\frac{mass}{169.9 g/mol}[/tex]

Mass =50.97 g AgNO₃

Hence, 50.97 g AgNO₃ is needed to make 500.0 mL of 0.600 mol/L AgNO3(aq).

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The enthalpy change for the reaction is 1215.75  kJ/mol.

The term enthalpy change is the energy that accompanies a reaction. Now we have the reaction;  4HNO3(g) + 2H2O(g) → 2N2H4(g) + 7O2(g)

ΔHf HNO3(g) = -134.31 kJ/mol

ΔHf  H2O(g)=     -241.83  kJ/mol

ΔHf N2H4(g) =  97.42 kJ/mol

ΔHf O2(g) = 0  kJ/mol

ΔHreaction = [(2 * 97.42) + ( 7 * 0)] -  [ (4 * -134.31 ) + (2 * -241.83 )

= 194.84 - (-537.25 - -483.66)

=1215.75  kJ/mol

The enthalpy change for the reaction is therefore 1215.75  kJ/mol.

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Answer:

two may be the answer (2)

Answer:

1.45 x 10⁻² g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams CH₄ to moles CH₄ (via molar mass), then (2) convert moles CH₄ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). The final answer should have 3 sig figs to reflect the given value (5.30 x 10⁻³ g).

Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)

Molar Mass (CH₄): 16.043 g/mol

Combustion of Methane:

1 CH₄ + 2 O₂ ---> 2 H₂O + 1 CO₂

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

5.30 x 10⁻³ g CH₄          1 mole              1 mole CO₂          44.007 g
---------------------------  x  ----------------  x  ---------------------  x  -----------------  =
                                      16.043 g            1 mole CH₄            1 mole

=  0.0145 g CO₂

=  1.45 x 10⁻² g CO₂

The products that can be formed are hydrogen iodide and phosphoric acid.

They are substances formed from chemical reactions.

The equation of the illustrated reaction together with the products is as follows:

[tex]P + H_2O + I_2 --- > H_3PO_4 + HI[/tex]

The products formed are phosphoric acid ([tex]H_3PO_4[/tex]) and hydrogen iodide ([tex]HI[/tex].

Alternatively, the equation of the reaction can be written as:

[tex]18P + 5I_2 + 32H_2O -- > 10PH_4I + 8H_3PO_4[/tex]

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Answer:

2

Explanation:

final velocity: 20

initial velocity: 0

time taken: 10

acceleration: ?

a=( v-u)÷2

a=(20-0)÷2

a=20÷2

therefore acceleration =2

Distillation is the process which involves the separation of pure water from impure water.

This is a technique which is used to purify through the boiling and cooling processes in the laboratory and typically involves the use of a liebig condenser.

Pure water is usually collected at 100° celsius with the impurities remaining and filtered out during the process. This is therefore the most apporpriate way of separating pure water from impure water.

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Answer:

2.) C₆H₆O₂

Explanation:

(Step 1)

To find the molecular formula of hydroquinone, you need to first determine the molar mass of the empirical formula. The molar mass is a sum of the individual atomic weights of each element multiplied by their quantities (denoted by the subscripts).

Atomic Weights:

Carbon (C): 12.011 g/mol

Hydrogen (H): 1.008 g/mol

Oxygen (O): 15.998 g/mol

Molar Mass (C₃H₃O): 3(12.011 g/mol) + 3(1.008 g/mol) + 15.998 g/mol

Molar Mass (C₃H₃O): 55.055 g/mol

(Step 2)

As you can see, the molar mass of the empirical formula is not the same as the molar mass of the molecular formula. Rather, the empirical molar mass is approximately half of the molecular molar mass. Therefore, to make these masses equal, we need to double the empirical formula. This can be done by multiplying all of the subscripts by 2.

55.055 g/mol x 2 = 110.11 g/mol

110.11 g/mol = 110.108 g/mol

C₃ x 2 = C₆

H₃ x 2 = H₆

O x 2 = O₂

Therefore, the correct molecular formula of hydroquinone is C₆H₆O₂.

mass MgCl₂ = mol x MM MgCl₂ = 0.05 x 95.211 g/mol = 4.76 g

mass Cl in MgCl₂ :

= (2 x AM Cl)/MM MgCl₂ x mass MgCl₂

= (2 x 35.5 g/mol)/95.211 g/mol x 4.76

= 3.55 g

% mass Cl in the mixture :

= (mass Cl / mass mixture) x 100%

=  3.55 / 9.8 x 100%

= 36.22%

The nuclear fission reaction with the formation of the deuterium has the missing part as ⁴₂He.

Nuclear radiation is given as the reaction in which the emission is formed in the form of the nuclear particles that made the change in the nucleus of the atom.

The nuclear radiation that made the release of ₁¹H can be given to fuse the electron with the He and form:

²₁H + ³₂He →⁴₂He + ₁¹H

Thus, the missing part in the nuclear fission reaction is ⁴₂He.

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