When a constant force is applied, an increase in the mass of an object decreases its acceleration and vice versa.
What is the relationship between the force, mass, and acceleration of an object?The mass of an object is the quantity of matter present in the object.
Force is a push or pull agent that causes a change in the motion or state of rest of an object.
Acceleration of an object is the change in velocity with time of the object.
The relationship between the force, mass, and acceleration of an object is given below:
Force = mass * accelerationMass = Force / accelerationAcceleration = Force / massFrom the above formulas, it can be seen that mass and acceleration have an inverse relationship such that as one increases, the other decreases, and vice versa.
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Bus A and Bus B leave school on a field trip when a stopwatch reads zero. Bus A travels at a constant 50 km/h, and Bus B travels at a constant 75 km/h. How far are the two buses from school when the stopwatch reads 1.5 h? a. Bus A is 76.5 km from school, Bus B is 51.5 km from school c. Bus A is 75 km from school, Bus B is 112.5 km from school b. Bus A is 112.5 km from school, Bus B is 75 km from school d. Bus A is 51.5 km from school, Bus B is 76.5 km from school
Answer:bus
Explanation:
1. A man pulls a crate with a rope. The crate slides along the floor in the horizontal direction (x direction). The man exerts a force of 50 N on the rope, and the rope is at an angle . Describe how the force components change as the angle increases from 0° to 90° and use your graph to explain your answer. Give a detailed explanation of the forces at . Show a sample calculation at one angle for both components.
The variation of the components of the force with the angle of inclination of the direction of the applied force, as shown in the graph indicates that the Fₓ has a maximum, while [tex]F_y[/tex] has a minimum value given by Fₓ = 50 N × cos(0°) = 50 N, and [tex]F_y[/tex] = 50 N × sin(0°) at θ = 0°, while at 45°, Fₓ = [tex]F_y[/tex], with [tex]F_y[/tex] having a maximum value of 50 N, and Fₓ = 0 at 90°.
What is a component of a force?The component of a force are the mutually perpendicular forces to which a force acting at an angle, relative the coordinate axis can be resolved into.
The component of the force applied by the man to the force required to move the box in the horizontal direction, Fₓ, increases as the angle approaches zero, and decreases as the angle approaches, 90°, given that the horizontal component of the force is found from the equation, [tex]F_x = F \times cos(\theta)[/tex], where, [tex]\theta[/tex] is the angle the line of action of the force makes with the horizontal, and F, is the force the man applies' such that we have at θ = 0°, Fₓ = 50 N × cos(0°) = 50 N
When the angle is θ = 45°, Fₓ = 50 N × cos(45°) = 25·√2 N
When the angle θ = 90°, Fₓ = 50 N × cos(90°) = 0
The vertical component of the force applied [tex]F_y[/tex], however, increases as the angle made by the line of force with the horizontal, increases to 90°, as shown in the graph, and decreases to 0 as the inclination angle of the force decreases, such that the have:
When the angle made with the horizontal, θ = 0°, [tex]F_y[/tex] = 50 N × sin(0°) = 0
When the angle made with the horizontal, θ = 45°, [tex]F_y[/tex] = 50 N × sin(45°) = 25·√2 N
At θ = 90°, [tex]F_y[/tex] = 50 N × sin(90°) = 50 N
The graph of both components starts at 50 N and 0 N when θ = 0°, and both intersect when θ = 45°, while the values of the horizontal and vertical component changes, such that at 90°, the vertical force component is the largest.
Please see the attached graph.
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Guitars have strings of different linear mass density. If the lowest density string and the highest density string are under the same tension, which string would support waves with the higher wave speed?.
In order to accommodate the increased wave speed, guitars have linear strings with variable linear mass densities, a linear density string and a higher density string under the same tension.
There is a formula for speed velocity. is determined by multiplying the mass of the strength by the square of the attention attention force. As a result, this demonstrates that the investment's velocity accelerated toward the square of the linear identity.
What then is becoming increasingly identity? No. They never fell short to cut. In order to answer the issue, the lesser density string will have a higher velocity if it is under the same strain as the advertising industry.
Lower your pace for the higher density strength and the wave speed.
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a 1.0 kg is dropped from a height of 6.0m. at what height is the rock's kinetic energy twice its potential energy?
Answer:
2.0m
Explanation:
heat is added to a 3.0 kg piece of ice at a rate of how long will it take for the ice at to melt? (for water and heat is added to a 3.0 kg piece of ice at a rate of how long will it take for the ice at to melt? (for water and 1,000 s 640,000 s 1.6 s 0.0 s
It will take 1.6s for the ice to melt.
First we have to write the expression for the heat balance equation for the system
Q supply = Qgain/
t= mLf/t
Here, m is the ice,
Lf is the latent heat of fusion
and t is the time taken to melt the ice.
Now we have to substitute the required value in the above expression to determine the value of time.
636 kJ/s = (3 kg)(334 kJ/kg) / tt =1.575 s
What is latent heat?
The heat or energy that is absorbed or released during a substance's phase shift is known as latent heat. It could go from a solid to a liquid or from a liquid to a gas, or vice versa. Enthalpy, a characteristic of heat, is connected to latent heat.
Therefore, the closest option is 1.6s
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You have someone in front of you that you are pulling hair samples from pre-emptively—not because you need them right now but just in case they might be relevant later. What is most likely true about the person in front of you?
The most likely true about the person in front of you is any of the above could be true and is denoted as option D.
What is a Sample?This is referred to as the matter or substance which is obtained so as to aid investigation processes and examples include hair, blood etc. It is useful as it helps to solve a crime and ensures that the culprit is punished.
Taking hair samples from pre-emptively could be because of any of the reasons listed such as being a suspect or a witness to a crime thereby making option D as the correct choice.
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The options are:
They are a suspect in a police interrogation.They are a witness of a crime.They are dead.Any of the above could be true.a 30.0 kg child starting from rest slides down a water slide with a vertical height of 10.0m. what is the child's speed (a) halfway down the slides vertical distance and (b) three-fourths of the way down?
a)Child's speed halfway down the slide is 9.89m/s.
b)Child's speed three fourth of the way down is 12.12 m/s.
Potential energy that a massive object has in relation to another massive object due to gravity is called gravitational potential energy. Potential energy associated with the gravitational field is converted to kinetic energy when the objects falls towards each other.
As we know that, ΔPE=KE
mgΔh=mv²/2
Now, v=sqrt(2gΔh)
Halfway down the slide, Δh=5 m
gravity = 9.8 m/s²
v=sqrt(2gΔh)
v= √2* 9.8 * 5
= √98
= 9.89 m/s
For the three fourth of the way down, Δh=7.5 m.
v= √2* 9.8 * 7.5
= 12.12 m/s
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Hello, I am currently stuck on this question and I am very confused as to how to solve it, may I have some help?
Recall, Newton's gravitational law states that any particle of matter in the universe attracts any other particle with a force varying directly as the product of their masses and inversely as the square of the distance between them. It is expressed as
F = Gm1m2/r^2
where
F is the force in Newton
G is gravitational constant = 6.673 x 10^-11 Nm^2/kg^2
m1 and m2 are the masses in kg
r is the distance in meters
From the information given,
r = 1.5
acceleration = 2cm^2/s
Recall, 100 cm = 1m
2 cm = 2/100 = 0.02m
Thus,
acceleration = 0.02m/s^2
Since the masses are identical, then m1 = m2
Each of them is accelerating at 0.02m/s^2
Recall,
Force = mass x acceleration
Force = m1 x 0.02 = 0.02m1 N
By substituting the given values into the formula, we have
0.02m1 = (6.673 x 10^-11 x m1 x m1)/1.5^2
m1 on the left cancels out one m1 on the right. It becomes
0.02 = (6.673 x 10^-11 x m1)/1.5^2
By crossmultiplying,
0.02 x 1.5^2 = 6.673 x 10^-11 x m1
0.045 = 6.673 x 10^-11 x m1
m1 = 0.045/6.673 x 10^-11
m1 = 6.74 x 10^8 kg
The mass of each ball is 6.74 x 10^8 kg
Which theoretical physicist, cosmologist, and author said, "however difficult life may seem, there is always something you can do and succeed at"?.
Professor Hawking .
Professor Stephen Hawking said that "however difficult life may seem, there is always something you can do and succeed at".
Who is Stephen Hawking?Stephen Hawking was widely regarded as one of the greatest theoretical physicists of all time. His work on the origins and structure of the universe, from the Big Bang to black holes, revolutionized the field, and his best-selling books drew readers who did not have Hawking's scientific background."It is possible." These were the final words of physicist Stephen Hawking's message, which was sent to a black hole after his death in 2018. The European Space Agency shared Hawking's narration in a soul-shaking video today to commemorate the 50th anniversary of Earth Day.To learn more about Stephen Hawking refer to :
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a 20. g particle is moving to the left at 30. m/s. how much net work must be done on the particle to cause it to move to the right at 30. m/s?
The net work done will be zero on moving the ball to the right.
The net work done is equal to the change in kinetic energy. The initial velocity is - 30 m/s and the final velocity is + 30 m/s. Also, the formula for kinetic energy is: K.E. = 1/2m([tex] { v_{f} }^{2} [/tex]
- [tex] { v_{i} }^{2} [/tex]
Keep the values in formula to find the kinetic energy
K.E. = 1/2×20×(30² - (-30)²)
Taking square on Right Hand Side of the equation
K.E. = 10×(900 - 900)
Performing subtraction on Right Hand Side of the equation
K.E. = 0
Thus, the net work done will be zero. The work done on stopping the particle and then moving it to different direction will be equal. Thus, we get the value zero.
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Estamos bajando dos cajas de madera con frutos menores (una encima de la otra) por una rampa con una inclinación de 30 grados con la horizontal. La caja inferior tiene una masa de 80kg y su coeficiente de fricción con el suelo es de 0.3, y la caja superior tiene una masa de 30kg con un coeficiente de fricción con la caja inferior de 0.8. Calcula la fuerza que tenemos que ejercer para que ambas cajas bajen con velocidad constante de 0.5m/s.
La situación planteada se muestra a continuación:
(El diagrama mostrado es para la caja inferior). A continuación mostramos el diagrama para la caja superior:
Si consideramos el sistema de dos cajas como uno solo tenemos el siguiente sistemas de ecuaciones:
[tex]\begin{gathered} F+F_f-W_x=0 \\ N-W_y=0 \end{gathered}[/tex]De donde:
[tex]\begin{gathered} F=W_x-F_f \\ F=W_x-\mu N \\ F=W_x-\mu W_y \\ F=(80)(9.81)\sin 30-(0.3)(80)(9.81)\cos 30 \\ F=188.5 \end{gathered}[/tex]Ahora debemos determinar si la caja de arriba no se resbala al aplicar esta fuerza, para esto debemos recordar que la fricción es máxima con el coeficiente de fricción estático.
Entonces tenemos que la fricción es máxima para el bloque de arriba cuando:
[tex]F_f=(0.8)(30)(9.81)\cos 30=203.89[/tex]Dado que la fuerza que debemos aplicar no es mayor a la fricción máxima concluimos que ambas cajas bajaran al mismo tiempo. Por lo tanto la fuerza que debemos aplicar es de 188.5 N.
Amber walked to the swimming pool, stopping to talk to Maria on her way there.
Amber walked at a constant speed of 100 m/min for the first four minutes; then she
visited with Maria for three minutes; then walked for two more minutes at a constant
speed of 75 m/min. In words, describe how a distance-versus-time graph of Amber's
progress would look.
Answer:
Amber use 25m for looking
Answer:
25 min's, that's what Amber used
A car coasts into a hill at 16.0 m/s. It slows down with a uniform acceleration of -1.0 m/S/S.
What is the displacement after 5.0s?
What is the displacement after 10.0s?
In the given question, a car coasts into a hill at 16.0 m/s and it slows down with a uniform acceleration of -1.0 m/S/S.
to find,
the displacement after 5.0s, s=60m
the displacement after 10.0s, s=80m
according to the equation of motion,
s=ut+1/2at^2
a) t=5second, u=16m/s
s=ut+1/2at^2
s= 16*5 + 1/2 (-1.6) 5^2
s=80-20
s=60m
b)t= 10second , u=16m/s
s=ut+1/2at^2
displacement s=16*10 + 1/2 (-1.6)*10^2
displacement s=80m
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a 50.0-kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 n. for the first 11.0 m the floor is frictionless, and for the next 10.0 m the coefficient of friction is 0.20. part a what is the final speed of the crate after being pulled these 21.0 m?
The final speed of the crate after being pulled these 21.0 m is 12.34 m/sec.
What is speed?Speed is defined as the SI unit of speed is m/s and is calculated as the product of distance to time.
Mass = 50 kg
Horizontal force = 225 N
Coefficient of friction = 0.20
ΔK1 = F x D1
ΔK1 = 225 x 11
ΔK1 = 2475 J
ΔK2 = F X D2 - umgD2
ΔK2 = 225 x 10 - 0.20 x 50 x 9.8 x 10
ΔK2 = 2250 - 980
ΔK2 = 1270 J
Therefore ,
ΔK = ΔK1 + ΔK2
ΔK = 2475 + 1270
ΔK = 3745 J
As per kinetic equation
KE = 1/2 mv²
3745 = 1/2 x 50 x v²
v² = 149.8
v = 12.34 m/sec
Thus, the final speed of the crate after being pulled these 21.0 m is 12.34 m/sec.
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What is the resultant of two displacement vectors having the same direction?1) The resultant is the sum of the two displacements having the same direction as the original vectors.2) The resultant is the difference of the two displacements having the same direction as the original vectors.3) The resultant is the sum of the two displacements having the direction opposite to the direction of the original vectors.4) The resultant is the sum of the two displacements having the direction perpendicular to the direction of the original vectors.
When two vectors have the same direction, they can be added and the direction of the resultant is the same as the direction of the vectors. Additionally, the magnitude of the resultant is simply the sum of the corresponding magnitudes of the vectors.
Therefore, the answer is:
1) The resultant is the sum of the two displacements having the same direction as the original vectors.
The intensity of an electromagnetic wave is related to which property of the wave squared?.
The intensity of an electromagnetic wave is related to the amplitude squared.
Electromagnetic wave:
Electromagnetic radiation consists of waves of the electromagnetic field, which propagate through space and carry electromagnetic radiant energy.
The intensity of electromagnetic waves:
The intensity of an electromagnetic wave is defined as the energy crossing per second per unit area held perpendicular to the direction of propagation of electromagnetic waves.
The formula for the intensity of electromagnetic waves:
I = η ε Ε² / 2
E = amplitude
Therefore we get that the intensity of an electromagnetic wave is related to the amplitude squared.
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What is the independent variable of Measuring physical properties: the Tiny World
The independent variables of measuring physical properties are given below -
What is physical properties?
A physical properties in any property that is measurable, whose value describe a state of physical system.
The changes in the physical properties of a system can be used to describe its changes between the momentary that state of
physical properties are often referred to as observables.
They are not modal properties.
Any variable that can be attributed a value without attributes a value to any to any other variables is called independent variables.
It is a variable that stands alone and isn't changed by other variables you are trying to measure.
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How will a strong material differ from a weaker material?
The greatest stress that a material can withstand before failing is referred to as its strength. Its stiffness describes how much it will flex or bend when pulled. High strength is frequently found in materials with high stiffness. The greatest stress that a material can withstand before failing is referred to as its strength.
Stress is the force applied to a material's unit area. Strain is the term for a body's reaction to stress. The body can distort under stress. Stress units can be used to quantify the amount of force that a material has experienced.Materials science is the study of the characteristics of solid materials and how a material's structure and composition affect those characteristics.Strain is calculated by dividing the amount of deformation the body experiences in the direction of the applied force by the body's starting dimensions.To know more about stress
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63-kg rock-climber is being pulled up the last 5.9 s of her climb by a rope. Her speed increases from 0 m/s to 2.9 m/s as she is being pulled upward. How much tension force is she applying to the rope?
The tension force applied to the rope when a rock-climber is being pulled up with an increase in speed of 0 to 2.9 m/s in 5.9 s is 30.97 N.
What is tension force?Tension force is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.
To calculate the tension force she applied to the rope, we use the formula below.
Formula:
F = m(v-u)/t.......... Equation 1Where:
F = Tension force applied to the the ropem = mass of the rock climberv = Final velocityu = Initial velocityt = time.From the question,
Given:
m = 63 kgv = 2.9 m/su = 0 m/st = 5.9 sSubstitute these values into equation 1
F = 63(2.9-0)/5.9F = 30.97 NHence, the tension force applied to the rope is 30.97 N.
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A ball is released from rest and falls 125 meters in 5 seconds. What was the magnitude of its acceleration?
The magnitude of the acceleration of the ball is 10 m/s².
What is acceleration of an object?
The acceleration of an object is the change in the velocity of the object with time.
The acceleration of the object is calculated using the following kinematic equation as shown below,
h = vt + ¹/₂at²
where;
h is the height of the objecta is the acceleration of the objectt is the time of motionv is the initial velocity of the ball = 0Substitute the given parameters and solve for the acceleration of the ball.
125 = 0 + ¹/₂a(5)²
2(125) = 25a
250 = 25a
a = 250/25
a = 10 m/s²
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light travels through water with a speed of 2.25x10⁸ m/s. What is refractive index?
The refractive index of water is 1.3
Find the refractive index of water.
Lightspeed in water [tex]V_water}[/tex]= 2.25*10^8 m/s
We know that,
Speed of light in vaccum [tex]V_{vaccum}[/tex]=3*10^8 m/s
µ=[tex]\frac{C}{V_{m} }[/tex]
where,
µ= refractive index
C= speed of light in air/vaccum
[tex]V_{m}[/tex]=speed of light in any medium
µ=[tex]\frac{3*10^8 m/s}{2.25*10^8 m/s}[/tex]
µ=1.3
Hence, the refractive index of water is 1.3
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In which type of circuit must the current always be the same through each
resistor?
A: Series Circuit
B: Parallel Circuit
C: Both
Answer:
Since there is only one path for electron flow in a series circuit, the current is the same magnitude at any point in the circuit
Explanation:
The answer is A. Series Circuit
three uncharged capacitors with equal capacitances are combined in parallel. the combination is connected to a 6.99 v battery, which charges the capac
..............................
The capacitance of each capacitor is 2.1 ×[tex]10^{-5}[/tex]F.
Let
Equivalent capacitance of the circuit = [tex]C_{eq}[/tex]
[tex]C_{eq}[/tex] =Q/V
where Q is the charge and V is the potential difference.
Q = [tex]3.5[/tex]×[tex]10^{-4[/tex]
V = 5.55 V
Putting the values
[tex]C_{eq}[/tex] = [tex]3.5[/tex]×[tex]10^{-4[/tex]/5.5V
[tex]C_{eq}[/tex] = [tex]6.4[/tex]×[tex]10^{-5}[/tex]F
The circuit consists of 3 capacitors in parallel, each one having the same capacitance C.
To find C:
C = [tex]C_{eq}[/tex]/3
C = 2.1 ×[tex]10^{-5}[/tex]F
The capacitance of each capacitor is 2.1 ×[tex]10^{-5}[/tex]F.
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The full Question is :
Three uncharged capacitors with equal capacitances are combined in parallel. the combination is connected to a 5.55-v battery, which charges the capacitors. the charging process involves 3.45 Ã 10-4 c of charge moving through the battery. find the capacitance of each capacitor.
Imagine that you could increase the gravitational force on Earth to 200% its current force. What would life be like?
Be sure to answer these questions in your response:
• How would your weight change?
• What challenges would this increase cause?
• What benefits would this increase bring about?
• Would you choose to keep the gravity increase? Why or why not?
(100 POINTSS, ASAP PLS!)
Answer:
You weight would be doubled because gravitational force is doubled
2. Challenges:
a. Everyone’s body would have to adjust to the new weight and learn to walk again
b. Earth would be closer to the sun, so everything would be hotter on Earth
c. Flying airplanes and driving cars might no longer work at all (talk about how difficult this would make traveling)
3. Benefits:
a. Time would go by much slower so technically everyone would live longer
b. Balloons wouldn’t fly off anymore
4. You have to decide for yourself if you’d like it better or worse
Explanation:
In the district soccer championship finals, elizabeth kicks a 0.57 kg soccer ball with a force of 22.8 n. how much does she accelerate the soccer ball from rest in the process?
acceleration a = F/M therefore acceleration the soccer ball from rest in the process is 40 m/s².
Given
mass of soccer ball, M = 0.57 kg
Force F = 22.8 n
acceleration a = F/M
a = 22.8 n/ 0.57 kg
a = 40m/s²
We refer to any process where the velocity changes as acceleration. You can only accelerate by changing your speed, direction, or both as velocity is a function of both speed and direction. When two things are moved against one another, instant friction results. The motion will be opposed by the friction, who will also be working against it. When an item is in motion and its velocity changes, the concept of acceleration takes place. Friction, which opposes motion, always lowers acceleration. An object and a surface come into contact and cause friction. The features of the surface and the item as well as whether or not the object is moving determine its magnitude.
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For the velocity-time graph shown, which statement describes what happens to the velocity between approximately 24 s and 25 s?
A) The lander's velocity increases away from the reference.
B) The lander's velocity decreases toward the reference.
C) The lander's velocity decreases away from the reference.
D) The lander's velocity increases toward the reference.
The velocity–time graph of the Lunar Landing Powered Descent that has a domain of 10 ≤ t ≤ 25, and a range of -2 ≤ v ≤ -40, between the 24th and the 25th seconds gives;
C) The Lander's velocity decreases away from the reference
What is a velocity–time graph?A velocity time graph is a graph that shows the variation of the velocity of an object with time.
The information with regards to the lunar landing powered descent graph are;
Coordinate points on the graph;
(10, -2); At time t = 10 seconds, the average velocity, v = 0
(10.5, -40); The velocity relative to the starting point changed and decreased from 0 m/s to -40 m/s
(15, -5); The velocity increased from -40 m/s to -5 m/s
(22, -3); The velocity increases from -5 m/s to -3 m/s
(24, -2); The velocity increases from -3 m/s to -2 m/s
(25, -15); The velocity decreases from -2 m/s to -15 m/s
Therefore, taking the reference point as the point where the velocity is zero, 0, we have that between approximately 24 seconds and 25 seconds, the Lander's velocity decreases away from the reference.
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The input force of 11 N acting on the effort arm of a lever moves 0.4 m, which lifts a 40 N weight resting on the resistance arm a distance of 0.1 m.What is the efficiency of the machine
ANSWER:
90.9%
STEP-BY-STEP EXPLANATION:
Given:
Input force = 11 N
Distance 1 = 0.4 m
Weight = 40 N
Distance 2 = 0.1 m
We calculate the work in each case to then calculate the efficiency of the machine, just like this:
[tex]\begin{gathered} W_1=11\cdot0.4=4.4\text{ J} \\ W_2=40\cdot0.1=4\text{ J} \\ \text{ Therefore:} \\ e=\frac{W_2}{W_1}\cdot100 \\ e=\frac{4}{4.4}\cdot100 \\ e=90.9\% \end{gathered}[/tex]The efficiency of the machine is 90.9%
A stone propelled from a catapult with a speed of 50m|s attains a height of 100m. Calculate:
a) the time taken
(b) the angle of projectile
(c) the range attained
For the projectile motion of the stone a) The time taken T = 9.04s b) the angle of the projectile = 62.31° c) the Range attained R = 209.923m
A stone propelled from a catapult is an example of projectile motion.
Given, the initial velocity of the stone u = 50 m/s; This initial velocity with which the stone is thrown has two components 1) vertical [tex]u_{y}[/tex] = u sinθ along the Y axis and 2) horizontal [tex]u_{x}[/tex]=u cosθ along the X axis
where θ is the angle of projection
maximum vertical displacement or height attained by stone = H
(Use sign convention +ve for upwards and -ve for downwards)
a) equation for the maximum vertical height reached by a body during projectile motion [tex]H=\frac{u^{2} sin^{2}\theta }{2g}[/tex] (1)
equation for the time of flight of projectile motion [tex]T=\frac{2usin\theta}{g}[/tex] (2)
Given H = displacement in the y direction = height attained = 100m
u = initial velocity = 50m/s ; acceleration due to gravity g =9.8 m/[tex]s^{2}[/tex]
using equation (1)
[tex]100=\frac{50^{2}sin^{2}\theta }{2*9.8}[/tex]
⇒[tex]sin^{2} \theta= \frac{100*2*9.8}{50^{2} }[/tex]
⇒sinθ[tex]=\sqrt{\frac{10*2*9.8}{50^{2} } }[/tex]
⇒sinθ = 0.885437
⇒θ = [tex]sin^{-1} (0.885437)[/tex]
⇒θ = 62.31°
Hence from equation (2) time of flight
[tex]T=\frac{2*50*sin\theta}{9.8}[/tex]
⇒[tex]T=\frac{2*50*0.885437}{9.8}[/tex]
⇒T = 9.04 s
Time is taken T =9.04s
b) Angle of projectile θ = 62.31°
c) The range attained [tex]R=\frac{u^{2}sin2\theta }{g}[/tex]
⇒[tex]R = \frac{50^{2}sin(2*62.31)}{9.8}[/tex]
⇒R = [tex]\frac{50^{2}*0.8229}{9.8}[/tex]
⇒R= 209.923m
horizontal range attained R= 209.923m
Components of a projectile motion:
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Consider two pieces of the same metal at the same temperature, but one piece is a higher mass than the other. Which piece of metal has more thermal energy?.
Answer:
The one that has higher mass
a cureent of 0.22A flows through the secondary winding of the transformer. The terminal voltage of the winding is 2400V, and the primary winding is 120V . What is the current in the primary winding?
The current in the primary winding is 4.4 A.
What is primary winding?
A primary winding is the winding of a transformer that is connected to and recive energy from an external source of electron.
The primary winding is the coil that draws power from the source.
Sol- As per the given question -
Current Is=0.22A
Primary winding Vp=120v
Voltage of winding Vs=2400v
Current of primary winding Ip?
Np/Ns=Vp/Vs=Is/Ip
Vp/Vs= Is/Ip
120/2400 =0.22/Ip
Ip= 20×0.22
Ip= 2.2×2
Ip=4.4 A
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