How do you do letter b?

Answer:42.55

Step-by-step explanation:

Les get the big boi out of the way first. We see that it is 3.5 by 9 and if we multiply we get 31.5. Next left triangle 2 by 2 so four but divided by 2 is 2. God so many  2's. So total is 33.5 so far. Next triangle is 2 by 5 soo  10 divided by 2 is 5. total is 38.5. Last dude in the middle. We know one side is two so we have to subtract here from the triangles which gets u the other side of 2 so 4. Total is 42.5

The Area of the Shape Shown is 42.5 square units.

The area of Rectangle is length times of width.

The area of the rectangle in the given figure is

Area of rectangle=3.5×9

=31.5 square units.

The area of left side triangle is

Area of triangle=1/2×2×2

=2 square units

The area of right side triangle 1/2×5×2

=5 square units

Now the area of square =2²

=4 square units.

Now total area of figure is 31.5+2+5+4 is 42.5 square units.

Hence, the Area of the shape Shown is 42.5 square units.

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Answer:

0 - 1 - 2 + 3 - 4 + 5 - 6 +7 - 8 + 9 = 3

Step-by-step explanation:

Answer: the number of devices expected to fail during the second month is 24

Step-by-step explanation:

Given that

The device has a constant failure rate with MTTF of 2 months.

As the device has constant failure rate so it has exponential failure distribution

f(t) = λe^-λt

Here MTTF = 1/ λ

so  λ = 1/2 Months⁻¹ = 0.5 Months⁻¹ and from the question,  Number of devices = 100

E( 1 < x < 2) = E ( x < 2) - E (x < 1)

so E(x < X) can be calculated with λ  = 0.5 Months⁻¹ will be calculated as the failure function

f(x) = λ exp ( - λ×t) for t > 0

F (x>0) = 1 - exp( - λx)

so E ( 1 < x < 2) = E ( x < 2) - E (x < 1)

E ( x < 2) = 1 - exp(-0.5 × 2) = 0.6321 ; E (x<1) = 1 - exp(-0.5 × 2) = 1 - exp( -0.5) = 0.3934

so E ( 1 < x < 2) = 0.6321 - 0.3934 = 0.2387

so the number of devices expected to fail during the second month is;

100 × 0.2387 = 23.87 ≈ 24

Answer:  [tex]l=\dfrac{P}{2}-b[/tex]

Step-by-step explanation:

P = 2(l + b)

Divide both sides by 2:

[tex]\dfrac{P}{2}=l+b[/tex]

Subtract b from both sides:

[tex]\dfrac{P}{2}-b=l[/tex]

Note: You can also multiply b by  [tex]\frac{2}{2}[/tex] if you want the left side to be one fraction.

[tex]\dfrac{P}{2}-\bigg(\dfrac{2}{2}\bigg)b=l\\\\\\\dfrac{P-2b}{2}=l[/tex]

Answer:

107.33 inches

Step-by-step explanation:

Area of the square more = length ^2

Area of the square mirror = 720 square inches

Area of the square more = length ^2

720 = length^2

Find the square root of both sides

√720 = √lenght^2

Length = √720

Length = 26.83281573 inches

Each length of the wood = 26.83281573 inches

There are 4 equal sides on the square mirror

Total length of the wood = 26.83281573 × 4

= 107.33126292 inches

Length of wood trim is needed to go around the entire mirror to the nearest hundredth = 107.33 inches

(f+g)(x) = f(x) + g(x)

= 4x - 4 + 2[tex]x^{2}[/tex] - 3x

= 2[tex]x^{2}[/tex] + x - 4

Answer:

Step-by-step explanation:

Since x is used a lot as a variable in algebra, I would use another symbol for multiplication. Though if your teacher requires you to use x as a multiplication symbol, then keep it as is. I use the asterisk symbol

Example: 2 times 3 = 2*3

------------------------------------------

For problem 2, you have the parenthesis in the wrong spots. Saying "the sum of four plus five" means we have 4+5 as you'd expect. Then you multiply that group with 2. So you'd really have (4+5)*2

How is this different from 4+5*2 back in problem 1? It comes down to how the order of operations handles things. To evaluate 4+5*2, we multiply first, then add. So we have 4+5*2 = 4+10 = 14

With the other expression, we add first because it is in the parenthesis block. Afterward we multiply the values to get (4+5)*2 = 9*2 = 18

Answer:

-3/2

Step-by-step explanation:

Take two points from the table and use the slope formula

m= (y2-y1)/(x2-x1)

   = ( 19 - 13)/ ( -4 - 0)

   = 6/-4

   = -3/2

Answer:

3 to 12

Step-by-step explanation:

3 months (January, June, July) and 12 monthes

Answer: the answer is 3 to 12

Step-by-step explanation: hope this will help

Both planes have the same normal vector:

[tex]6x-y-z=6\implies\mathbf n=\langle6,-1,-1\rangle[/tex]

The plane we want must contain the point (4, -3, -1), so its equation would be

[tex]\mathbf n\cdot\langle x-4,y+3,z+1\rangle=0[/tex]

[tex]\implies 6(x-4)-(y+3)-(z+1)=0[/tex]

[tex]\implies\boxed{6x-y-z=28}[/tex]

Answer:

9

Step-by-step explanation:

12×9=108 108>105 so it can't be any other number cuz we go too high or too low

Answer:

9

Step-by-step explanation:

Answer:

1/5

Step-by-step explanation:

Answer:

y = (11x + 13)e^(-4x-4)

Step-by-step explanation:

Given y'' + 8y' + 16 = 0

The auxiliary equation to the differential equation is:

m² + 8m + 16 = 0

Factorizing this, we have

(m + 4)² = 0

m = -4 twice

The complimentary solution is

y_c = (C1 + C2x)e^(-4x)

Using the initial conditions

y(-1) = 2

2 = (C1 -C2) e^4

C1 - C2 = 2e^(-4).................................(1)

y'(-1) = 3

y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)

3 = -4(C1 - C2)e^4 + C2e^4

-4C1 + 5C2 = 3e^(-4)..............................(2)

Solving (1) and (2) simultaneously, we have

From (1)

C1 = 2e^(-4) + C2

Using this in (2)

-4[2e^(-4) + C2] + 5C2 = 3e^(-4)

C2 = 11e^(-4)

C1 = 2e^(-4) + 11e^(-4)

= 13e^(-4)

The general solution is now

y = [13e^(-4) + 11xe^(-4)]e^(-4x)

= (11x + 13)e^(-4x-4)

Answer:

[tex]FH=22[/tex]

Step-by-step explanation:

FH is the combined lengths of FG and GH.

In an equation, this is:

[tex]FH=FG+GH[/tex]

We already know that FG is 8 and that GH is 14. Thus:

[tex]FH=8+14[/tex]

Add:

[tex]FH=22[/tex]

So, the length of FH is 22.

And we're done!

Answer:

H  -2 ≤x≤4

Step-by-step explanation:

The domain is the input values or the x values

-2 ≤x≤4

Answer:

H

Step-by-step explanation:

You can see because the answer starts with -2.

Answer:

The measure of the angles:

24°  and   66°

Step-by-step explanation:

Complementary angles sum 90°

then:

(3x + 3) + (10x-4) = 90

3x + 10x + 3 - 4 = 90

13x - 1 = 90

13x = 90+1

13x = 91

x = 91/13

x = 7°

then:

3x+3 = 3*7 + 3 = 21+3 = 24°

10x - 4 = 10*7  - 4 = 70 - 4 = 66°

Check:

66° + 24° = 90°

Answer:

c×3 (2 b^3 - 2 a b + a)

Step-by-step explanation:

Simplify the following:

c (4 b^3 + 3 a) + b (2 c b^2 - 6 a c)

Hint: | Factor common terms out of 2 c b^2 - 6 a c.

Factor 2 c out of 2 c b^2 - 6 a c:

c (4 b^3 + 3 a) + b×2 c (b^2 - 3 a)

Hint: | Pull a common factor out of c (4 b^3 + 3 a) + b×2 c (b^2 - 3 a).

Factor c out of c (4 b^3 + 3 a) + b×2 c (b^2 - 3 a), resulting in c ((4 b^3 + 3 a) + b×2 (b^2 - 3 a)):

c (4 b^3 + 3 a + 2 b (b^2 - 3 a))

Hint: | Distribute 2 b over b^2 - 3 a.

2 b (b^2 - 3 a) = 2 b^3 - 6 a b:

c (4 b^3 + 3 a + 2 b^3 - 6 a b)

Hint: | Group like terms in 4 b^3 + 3 a - 6 a b + 2 b^3.

Grouping like terms, 4 b^3 + 3 a - 6 a b + 2 b^3 = (4 b^3 + 2 b^3) - 6 a b + 3 a:

c (4 b^3 + 2 b^3) - 6 a b + 3 a

Hint: | Add like terms in 4 b^3 + 2 b^3.

4 b^3 + 2 b^3 = 6 b^3:

c (6 b^3 - 6 a b + 3 a)

Hint: | Factor out the greatest common divisor of the coefficients of 6 b^3 - 6 a b + 3 a.

Factor 3 out of 6 b^3 - 6 a b + 3 a:

Answer: c×3 (2 b^3 - 2 a b + a)

The motion of molecules determines temperature. The faster the particles move, the higher the temperature will be.

A cold cup of water will warm up to room temperature because the energy of the air in the room transfers to the cold water to make the water molecules move faster. The energy goes from hot to cold. The energy transfer is due to the molecules colliding into one another.

The hot cup of water cools down because the energy of the water molecules leaks out to the surrounding air to warm up the air around it, which is why you can feel the heat of the steam of water.

As for why you can feel cold things, its because the energy from your hand moves toward the cold object (again energy going from hot to cold), which makes your brain perceive the cold object.

Answer:

764 - 118 = 646

Step-by-step explanation:

Answer:

subtract 118 from 764 and that's the rest of the students

Answer:

1/2 meter long

Step-by-step explanation:

To answer this question use the equation 1 1/3 - 5/6

Next make 1 1/3 an improper fraction

To do this multiply the integer and the denominator and then add all of that plus the numerator

This means that 1 1/3 is 4/3

4/3 - 5/6

Next make the denominators the same

This means finding the LCM which is 6

8/6 - 5/6 = 3/6 (1/2)

Heidis hair is 1/2 meters long

Answer:

A) [tex]\int\frac{2x^2}{3}dx=\frac{2x^3}{9}+C[/tex]

B) [tex]\int(5-x)^{23}dx=-\frac{(5-x)^{24}}{24}+C[/tex]

Step-by-step explanation:

A)

So we have the integral:

[tex]\int\frac{2x^2}{3}dx[/tex]

First, remove the constant multiple:

[tex]=\frac{2}{3}\int x^2\dx[/tex]

Use the power rule, where:

[tex]\int x^ndx=\frac{x^{n+1}}{x+1}[/tex]

Therefore:

[tex]\frac{2}{3}\int x^2\dx\\=\frac{2}{3}(\frac{x^{2+1}}{2+1})[/tex]

Simplify:

[tex]=\frac{2}{3}(\frac{x^{3}}{3})[/tex]

And multiply:

[tex]=\frac{2x^3}{9}[/tex]

And, finally, plus C:

[tex]=\frac{2x^3}{9}+C[/tex]

B)

We have the integral:

[tex]\int(5-x)^{23}dx[/tex]

To solve, we can use u-substitute.

Let u equal 5-x. Then:

[tex]u=5-x\\du=-1dx[/tex]

So:

[tex]\int(5-x)^{23}dx\\=\int-u^{23}du[/tex]

Move the negative outside:

[tex]=-\int u^{23}du[/tex]

Power rule:

[tex]=-(\frac{u^{23+1}}{23+1})[/tex]

Add:

[tex]=-(\frac{u^{24}}{24})[/tex]

Substitute back 5-x:

[tex]=-(\frac{(5-x)^{24}}{24})[/tex]

Constant of integration:

[tex]=-\frac{(5-x)^{24}}{24}+C[/tex]

And we're done!

Answer:

The yellow polygon is the scaled version of the red one (scaled by 3×), so the variable w = 9

Answer:

9

Step-by-step explanation:

The similarity ratio is 4/x = z/9 = 2/6 = 3/w = y/15

2/6 = 3/w cross multiply expressions 2w = 18 and w = 9

Answer:

The standard form would be 6,880,000,000..

Answer:

16

Step-by-step explanation:

Let x be the number of chocolates obtained by each student

Since the number of chocolates obtained by each student = the number of students in the class, then, number of students in the class = x

256/x = x

Multiply both sides by x

256 = x × x ( x squared)

Multipy powers raised on both sides by 1/2

X = 16

Since there is 28 cards, the chance of drawing 1 card will be [tex]\frac{1}{28}[/tex]

Therefore, [tex]P(13)=\frac{1}{28}[/tex].

There are 13 numbers less than 14 and greater than 0.

Therefore [tex]P(>14)=\frac{13}{28}[/tex]

There are 26 numbers that are not 2 or 17.

Therefore [tex]P(\neq 2,17)=\frac{26}{28}=\frac{13}{14}[/tex]

Hope this helps.

頑張って!

Probability of

Option (1). P(13) =[tex]\frac{1}{28}[/tex]

Option (2). P(less than 14) = [tex]\frac{13}{28}[/tex]

Option (3). P(not 2 or 17) =[tex]\frac{13}{14}[/tex]

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur

Given,

Total number of card = 28

Probability = Number of favorable outcome / Number of total outcome

Probability of picking 13 = [tex]\frac{1}{28}[/tex]

Probability of picking a card less then 14 = [tex]\frac{13}{28}[/tex]

Probability of not picking 2 or 17 = [tex]\frac{26}{28}=\frac{13}{14}[/tex]

Hence, the probability of

Option (1). P(13) =[tex]\frac{1}{28}[/tex]

Option (2). P(less than 14) = [tex]\frac{13}{28}[/tex]

Option (3). P(not 2 or 17) =[tex]\frac{13}{14}[/tex]

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Answer:

Absolute value equation is; |x - 25| ≤ 3

Minimum number of bolts is 22 while Maximum number of bolts is 28

Step-by-step explanation:

We are told that;

Each bag should have 25 bolts in it but 22 or 28 is acceptable.

Since 22 or 28 is acceptable, it means the allowable error is ±3.

Thus, if x is the number of bolts in the bag, the absolute value equation would be;

|x - 25| ≤ 3

Minimum number of bolts is 22 while maximum is 28

step 1

(x - 4) • (x + 5) = 0

STEP

:

A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

Solving a Single Variable Equation:

2.2 Solve : x-4 = 0

Add 4 to both sides of the equation :

x = 4

Solving a Single Variable Equation:

2.3 Solve : x+5 = 0

Subtract 5 from both sides of the equation :

x = -5

.

Answer:

A) [tex]\huge\boxed{\sf x^2 + x - 20 = 0}[/tex]

B) [tex]\huge\boxed{\sf x = - 5 \ \ \ \ OR \ \ \ \ x = 4}[/tex]

Step-by-step explanation:

[tex]\sf (x+5)(x-4) = 0[/tex]

[tex]\rule[225]{225}{2}[/tex]

Expanding:

Expanding Brackets

[tex]\sf x^2 -4x+5x-20 = 0[/tex]

Adding / Subtracting Like terms

[tex]\sf x^2 + x - 20 = 0[/tex]

[tex]\rule[225]{225}{2}[/tex]

Solving:

Given the equation:

(x+5)(x-4) = 0

Using zero Method

Either,

x + 5 = 0   OR      x - 4 = 0

x = - 5       OR       x = 4

[tex]\rule[225]{225}{2}[/tex]

We're given that

[tex]f(x)=x^2-2x+6[/tex]

which means

[tex]f(x+h)=(x+h)^2-2(x+h)+6=x^2+2xh+h^2-2x-2h+6[/tex]

When we subtract these, several terms cancel:

[tex](x^2+2xh+h^2-2x-2h+6)-(x^2-2x+6)=2xh+h^2-2h[/tex]

So the difference quotient is

[tex]\dfrac{f(x+h)-f(x)}h=\dfrac{2xh+h^2-2h}h[/tex]

and since h ≠ 0, we can cancel it out to end up with

[tex]\dfrac{f(x+h)-f(x)}h=2x+h-2[/tex]

Now plug in x = 8 (this could have been done at any prior point):

[tex]\dfrac{f(8+h)-f(8)}h=14+h[/tex]