How can you find directions using satellite orbiting?

Answers

Answer 1

Answer:

Satellites may move north to south, or south to north, or west to east, but never from east to west. When satellites are launched, they always head eastward to take advantage of the Earth's rotation, going more than 1,000 miles per hour near the equator. This saves a lot of fuel.


Related Questions

Mr Jones launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, what direction and value is his acceleration air resistance is negligible.

A. 9.8 m/s/s west
b. 9.8m/s/s east
C. 9.8m/s's down
d 9.8m/s/s south​

Answers

Answer:

9.8m/s^2 down  (option C)

Explanation:

The only acceleration acting on this motion case in the acceleration due to gravity: 9.8 m/s^2 in the downwards direction.

What is gravitonal force

Answers

Answer:

its something that hold the air for forceing liy by the exgen

Explanation:

Robin would like to shoot an orange in a tree with his bow and arrow. The orange is hanging yf=5.00 myf=5.00 m above the ground. On his first try, Robin looses the arrow at v0=35.0 m/sv0=35.0 m/s at an angle of θ=30.0°θ=30.0° above the horizontal. The arrow has an initial height of y0=1.50 m,y0=1.50 m, and its tip is x=60.0 mx=60.0 m away from the target orange. Treating the arrow as a point projectile and neglecting air resistance, what is the height of the arrow once it has reached the horizontal position xx of the orange? Use g=9.81 m/s2g=9.81 m/s2 for the acceleration due to gravity.

Answers

Answer:

h' = 55.3 m

Explanation:

First, we analyze the horizontal motion of the projectile, to find the time taken by the arrow to reach the orange. Since, air friction is negligible, therefore, the motion shall be uniform:

s = vt

where,

s = horizontal distance between arrow and orange = 60 m

v = initial horizontal speed of the arrow = v₀ Cos θ

θ = launch angle = 30°

v₀ = launch speed = 35 m/s

Therefore,

60 m = (35 m/s)Cos 30° t

t = 60 m/30.31 m/s

t = 1.98 s

Now, we analyze the vertical motion to find the height if arrow at this time. Using second equation of motion:

h = Vi t + (1/2)gt²

where,

Vi = Vertical Component of initial Velocity = v₀ Sin θ = (35 m/s)Sin 30°

Vi = 17.5 m/s

Therefore,

h = (17.5 m/s)(1.98 s) + (1/2)(9.81 m/s²)(1.98 s)²

h = 34.6 m + 19.2 m

h = 53.8 m

since, the arrow initially had a height of y = 1.5 m. Therefore, its final height will be:

h' = h + y

h' = 53.8 m + 1.5 m

h' = 55.3 m

How are graphs used to represent and analyze acceleration? please help!

Answers

Graphs are used to show how fast it goes and how long it takes

Why are the coral reefs suffering? (site 2) explain

Answers

Answer:

bcuz ov yo fat mamma

Explanation:

Answer:

Water pollution

Explanation:

Mr Johnson launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, how much time does it take before the arrow hits the ground below (step 1 of a quesiton will need this answer for a future question)
a 2 seconds
b. 1 second
c.4 seconds
d 19.6​

Answers

Answer:c

Explanation:

1. It plays a vital role for self- expression and has been part of rituals
and religious gatherings.
B. Dance
A. Aerobic activity
C. Fitness D. Zumba​

Answers

Answer:

b.dance

Explanation:

don't know the explanation

I need emergency help we only have 3 minutes left

Answers

Answer:

Option A

Explanation:

Ast the force is equal and the diayance is equal the beam is also balanced

A force of 20 N to the south is applied to each object below. Which object will undergo the greatest change in momentum?

Answers

Answer:

Hello there! The answer your would be looking for is:

A 33 kg object that is moving north at 10 m/s

Momentum can be defined as the product of mass and velocity. Thus momentum is directly proportional to both velocity and momentum. Thus, the object with greater mass as well as velocity has greater momentum. Therefore, option C is correct.

What is force?

Force can be described as an external agent acting on a body, to change its state of rest or motion. There are several kinds of forces such as magnetic force, frictional force, nuclear force, etc.

In physics, force can be described as the product of the mass and acceleration of the body. Greater mass results in greater force required to be exerted on the object to make it move or stop.

Therefore, when mass or velocity or both increases, the momentum of the object increases as well. Therefore, the larger object moving faster gain greater momentum.

Therefore, when the same force is exerted on the object then, the 41 kg object that is moving north at 12 m/s will undergo the greatest change in momentum.

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Your question was incomplete but most probably the complete question was,

A force of 20 N to the south is applied to each object below. Which object will undergo the greatest change in momentum?

A. A 33 kg object that is moving north at 12 m/s

B. A 41 kg object that is moving north at 10 m/s

C. A 41 kg object that is moving north at 12 m/s

D. A 33 kg object that is moving north at 10 m/s

which refers to information gathered by the systematic study of nature?

prediction
communication of facts
scientific knowledge
hypothesis

Answers

Answer:

it is scientific knowledge

Explanation:

got i right on edge

The scientific knowledge refers to information gathered by the systematic study of nature.

What is scientific knowledge?

A generalized corpus of laws and ideas developed employing the scientific method to describe an interesting occurrence or behavior is referred to as scientific knowledge.

What is systematic study?

Science would be the systematic study of the composition and dynamics of the physical as well as the natural world via experimentation and observation.

the systematic study of natural circumstances and phenomena. empirical proof. the term for the facts and figures that support an explanation in science.

Therefore, the correct answer will be option (C)

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What is Newton's universal law of gravitation

Answers

Answer:

an object that is in motion wont go out of motion until there is another force pushing on it

Which statement best describes energy and matter in a closed system? (2 po
O Energy and matter flow into and out of the system.
Energy can flow into and out of the system but matter cannot.
Energy and matter are contained within a closed system.
O There is no energy in a closed system; there is matter.

Answers

Answer:

Energy can flow into and out of the system but matter cannot.

Explanation:

In a closed system, energy can flow in and out of the system but matter cannot.

A closed system prevents double way flow of matter. A closed system conserves matter.

For an isolated system, energy and matter cannot flow out of the system.

For open systems, energy and matter can flow out of the system.

Such systems are used for certain thermodynamics experiment.

An object accelerates 12.0 m/s2 when a force of 6.0 newtons is applied to it. What is the mass of the object?

Answers

Answer:

0.5 kg

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{6}{12} = \frac{1}{2} \\ [/tex]

We have the final answer as

0.5 kg

Hope this helps you

A T-shirt cannon mounted at the top of an arena needs to fire a t-shirt into the first row, a horizontal distance of 39 meters away. If the cannon launches t-shirts at 12 m/s, how high is the cannon mounted?
A.) 8.9 m
B.) 3.3 m
C.) 53.4 m
D.) 16.2 m

Answers

B.)3.3 would be the answer

A 4.00-kg particle moves along the x axis. Its position varies with time according to x= 5t +1 2.0t^3, where x is in meters and t is in seconds. Find:

a. the kinetic energy of the particle at any time t.
b. the acceleration of the particle and the force acting on it at time t.
c. the power being delivered to the particle at time t.
d. the work done on the particle in the interval t = 0 to t =5

Answers

Answer:

a) The kinetic energy of the particle at any time t is [tex]K = 50+120\cdot t^{2}+72\cdot t^{4}[/tex].

b) The acceleration of the particle at time t is [tex]a= 12\cdot t[/tex]. The force acting on the particle at time t is [tex]F = 48\cdot t[/tex].

c) The power being delivered to the particle at time t is [tex]\dot W = 240\cdot t +288\cdot t^{3}[/tex].

d) The work done on the particle in the interval t = 0 to t = 5 is 48000 joules.

Explanation:

a) The kinetic energy of the particle is entirely translational, whose formula is:

[tex]K = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (1)

Where:

[tex]K[/tex] - Translational kinetic energy, measured in joules.

[tex]m[/tex] - Mass of the particle, measured in kilograms.

[tex]v[/tex] - Velocity of the particle, measured in meters per second.

The velocity of the particle is the rate of change of the position of the particle in time, that is:

[tex]v = 5+6\cdot t^{2}[/tex] (2)

Where [tex]t[/tex] is the time, measured in seconds.

By substituting on (1), we have the following expression: ([tex]m = 4\,kg[/tex])

[tex]K = 2\cdot (5+6\cdot t^{2})^{2}[/tex]

[tex]K = 2\cdot (25+60\cdot t^{2} +36\cdot t^{4})[/tex]

[tex]K = 50+120\cdot t^{2}+72\cdot t^{4}[/tex]

The kinetic energy of the particle at any time t is [tex]K = 50+120\cdot t^{2}+72\cdot t^{4}[/tex].

b) The acceleration of the particle is the rate of change of the velocity of the particle in time, that is:

[tex]a= 12\cdot t[/tex] (3)

Where [tex]a[/tex] is the acceleration of the particle, measured in meters per square second.

The acceleration of the particle at time t is [tex]a= 12\cdot t[/tex].

The force is obtained by multiplying (3) by the mass of the particle. That is to say: ([tex]m = 4\,kg[/tex])

[tex]F = m\cdot a[/tex] (4)

[tex]F = 48\cdot t[/tex]

The force acting on the particle at time t is [tex]F = 48\cdot t[/tex].

c) According to the Work-Energy Theorem, the change in kinetic energy of the particle equals the change in the net work done on the particle. In this case, the power is equal to the rate of change in kinetic energy.

[tex]\dot W = \dot K[/tex] (5)

[tex]\dot W = \frac{d}{dt}(50+120\cdot t^{2}+72\cdot t^{4})[/tex]

[tex]\dot W = 240\cdot t +288\cdot t^{3}[/tex]

The power being delivered to the particle at time t is [tex]\dot W = 240\cdot t +288\cdot t^{3}[/tex].

d) The work done on the particle ([tex]W[/tex]), measured in joules, is equal to the change of the kinetic energy of the particle:

[tex]W = K(5)-K(0)[/tex] (6)

[tex]W = [50+120\cdot (5)^{2}+72\cdot (5)^{4}]-[50+120\cdot (0)^{2}+72\cdot (0)^{4}][/tex]

[tex]W = 48000\,J[/tex]

The work done on the particle in the interval t = 0 to t = 5 is 48000 joules.

What is the acceleration of gravity, in m/s2, on the surface (or outer limit) of Venus? The mass of Venus is 4.87 1024 kg and its radius is 6.05 106 m.

Answers

Answer:

8.9 m/[tex]s^{2}[/tex]

Explanation:

From Newton's law of universal gravitation,

F = [tex]\frac{GMm}{R^{2} }[/tex] .............. 1

and from Newton's second law of motion,

F = mg ........... 2

Equating the two expression,

mg = [tex]\frac{GMm}{R^{2} }[/tex]

g = [tex]\frac{GM}{R^{2} }[/tex]

Given that: mass of Venus = 4.87 x [tex]10^{24}[/tex] Kg, radius = 6.05 x [tex]10^{6}[/tex] and G = 6.67 x [tex]10^{-11}[/tex] N[tex]m^{2} Kg^{-2}[/tex]

Thus;

g = [tex]\frac{6.67*10^{-11}*4.87*10^{24} }{(6.05*10^{6} )^{2} }[/tex]

  = [tex]\frac{3.24829*10^{14} }{3.66025*10^{13} }[/tex]

 = 8.87450

g = 8.9 m/[tex]s^{2}[/tex]

the acceleration of gravity on the surface of Venus is 8.9 m/[tex]s^{2}[/tex].

Select all correct answers....Covalent compounds​

Answers

I know for sure that the third one is correct

I WILL GIVE BRAILYEST!!! What is the mass of an object moving at a velocity of 5 m/s if the momentum of the object is 50 kg•m/s?
a. 250 kg
c. 10 Kg
b. .002 Kg
d. 45 Kg

Answers

Answer:

a. 250kg I think it's the right answer. hope it helps:)

Answer:

C.10

Explanation:

because when you divide 50 divided by 5 = 10

A radio signal has a frequency of 1.023 x 108 HZ. If the speed of the signal in air is 2.997 x 108m/s, what is the wavelength of the signals? а 7.15 m b 5.23 m C 2.93 m d 0.93 m​

Answers

Answer:

2.93 m  (which agrees with answer "C" on the list)

Explanation:

Recall that the speed of the wave equals the product of the wave's length times its frequency. Therefore, the wavelength is going to be the quotient of the speed of the signal divided its frequency:

Wavelength = 2.997  10^8 / 1.023  10^8 =  2.93 m

how long does the guided discovery stage of the drawing in phase last? in training program

Answers

Answer
2 to 3 weeks
This aspect of the drawing-in phase can last 2 to 3 weeks, or as little as a few workouts, and is designed to a) reverse the effects of disuse, b) get the clients oriented to all available technologies, c) allow the clients to learn what their options are and which exercises they likes best.

Answer:

2 to 3 weeks

Explanation:

which state can you infer that average home prices are the highest? Florida California Texas New York

Answers

Answer:

California

Explanation:

just took the test

The state you can infer where average home prices are the highest is California. Option B. This is further explained below.

What is an average home price?

Generally, an average home price refers to a cumulative average to the house or home pricing in a state.

In conclusion, California has the highest average home prices highest in America.

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Mr Jones launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, how far south does the arrow travel. (Step 2, you need the previous questions answer to answer correctly

a. 118.4 m south
b 1936 m south
C 2 m south
d 640 m south​

Answers

Answer:c

Explanation:its the answer because its the answer

A 1150 kg car is on a 8.70° hill.
Using X-Y axes tilted down the
plane, what is the y-component
of the weight?

Answers

Answer:

Explanation:

y-component = - mgcos(8.7)

= - (1150)(9.81)cos(8.7)

= - 11151.69378

= - 11151.69 N

The weight of the y-component is 11140.33N.

How to find the weight of the y-component?

To find the weight of the y-component:

Given,

Car weight = 1150 kg

Anfle = 8.70 degree

weight = mg = 1150 * 9.8

= 11270 N

Y-component =  mg cos∅

= 11270 * cos(8.70)

= 11140.33N

The aspect that pushes proper or left is referred to as the x-factor, and the element that pushes up or down is known as the y-component.

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The chart shows Daniela’s run through her race.

A graph with horizontal axis time (seconds) and vertical axis position in (meters). The line runs straight from 0 seconds 5 meters to 10 seconds 30 meters.
What is her velocity?

1.5 m/s
2 m/s
2.5 m/s
5 m/s

Answers

Answer:

Explanation:

velocity is the rate of change of displacement with respect to time.

Velocity = displacement/time

If a  line runs straight from 0 seconds 5 meters to 10 seconds 30 meters.

The velocity will be expressed as;

v = d2-d2/t2-t1

v = 30-5/10-0

v = 25/10

v = 2.5m/s

Hence her velocity is 2.5m/s

Daniela's velocity is 2.5 m/s.

Velocity is the ratio of displacement to time taken. It is given by:

Velocity = displacement / time

The velocity of Daniela can be gotten by calculating the slope of the graph. Considering the points (0, 5) and (4, 15).

[tex]Velocity(slope)=\frac{15-5}{4-0}=2.5\ m/s[/tex]

Therefore Daniela's velocity is 2.5 m/s.

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why is it more painful to walk on gravel with your shoes off then on (3 marks please)

Answers

Answer:

Because shoes protect our feet from some of the most harmful platforms

Gravel has some small pebbles on it sometimes (or other sharp objects)

Gravel is pretty hard.

An object moves at constant speed in a circle. Which of the following is true:

A. A net force in the direction of motion acts on the object.
B. A net force pointing away from the center of the circle acts on the object.
C. A net force pointing towards the center of the circle acts on the object.
D. The net force acting on the object is zero.

Answers

The answer to your question is B

Experiment: Gravity

Potential Energy = Force x Distance

To show you how this works, study the following example.

If the washers had a mass of 2 grams, and since the force due to gravity in the metric system is 9.8 m/sec2, the weight would be:

W = mass (kg) x gravity

W = 0.002 kg x 9.8 = 0.0196 Newton's. The Newton (N) is the measure of force (or weight here) in the metric system.

The next phase of the computation is to determine the difference in potential energy between where the washers originally started from and the energy of the new position. If the washers were originally 1 meter from the floor or desktop, and the magnet raised them 1 centimeter, the difference in distance raised will be 1 cm, or 0.01 m. Therefore, the potential energy change will be:

Force x Distance = Potential Energy

(0.0196 N) x (0.01 m) = 0.000196 Nm (or Joules)

The magnet is changing the potential energy of the washers by 0.000196 J, or in scientific notation:
1.96 x 10-4 J.

Answers

Answer: the washer would slow down depending on how strong the magnet is even though the gravitational pull is the same. the change would be .6

Explanation: i don't really get it

If a ball rolls down an incline with a starting velocity of 0m/s and a final velocity of 6m/s
and it takes a total of 1.4 seconds, calculate its acceleration.

Answers

Answer:

If a ball rolls down an incline with a starting velocity of 0m/s and a final velocity of 6m/s

and it takes a total of 1.4 seconds, calculate its acceleration.

Answer:

Acceleration is 4.28 m/s²

Explanation:

Acceleration is change of speed in time. To solve this, we will assume that the acceleration is constant, meaning that every second the velocity increases for the same constant value.

a = ∆v/t

∆v is the difference between two measured velocities:

a = (v2 - v1) / t

v1 = 0m/s

v2 = 6m/s

t = 1.4 s

Now, we only plug in the given values:

a = (6 - 0) / 1.4

a = 6 m/s / 1.4 s

a = 4.28 m/s²

A potter's wheel is a uniform disk of mass of 10.0 kg and radius 20.0 cm. A 2.0-kg lump of clay, roughly cylindrical with radius 3.0 cm, is placed at the center of the wheel. The wheel initially rotates at 30.0 rev/min. The clay then flattens into a disk of radius 8.0 cm. What is the final angular speed of the wheel?

a. 29.6 rev/min
b. 29.2 rev/min
c. 30.8 rev/min
d. 30.4 rev/min
e. 30.0 rev/min

Answers

Answer:

b. 29.2 rev/min

Explanation:

Assuming no external torques acting during the process, total angular momentum must be conserved, as follows:

       [tex]L_{0} = L_{f} (1)[/tex]

The initial angular momentum L₀, can be expressed as follows:

        [tex]L_{0} = I_{0} * \omega_{0} (2)[/tex]

        where I₀ = initial moment of inertia = moment of inertia of the disk +

        moment of inertia of the cylinder and ω₀ = initial angular velocity  =

       30.0 rev/min.

Replacing by the values, we get:[tex]I_{0} = \frac{1}{2} * m_{d} *r_{d} ^{2} + \frac{1}{2}* m_{c} *r_{c} ^{2} = 0.2 kg*m2 +9e-4 kg*m2 = 0.2009 kg*m2 (3)[/tex]⇒ L₀ = I₀* ω₀ = 0.2009 kg*m² * 30.0 rev/min = 6.027 kg*m²*rev/minThe final angular momentum can be written as follows:

       [tex]L_{f} = I_{f} * \omega_{f} (4)[/tex]

       where If = final moment of inertia = moment of the inertia of the solid

      disk + moment of  inertia of the clay flattened on a disk, and ωf = final

      angular velocity.

Replacing by the values, we get:

   [tex]I_{f} = \frac{1}{2} * m_{d} *r_{d} ^{2} + \frac{1}{2}* m_{fd} *r_{fd} ^{2} = 0.2 kg*m2 +6.4e-3 kg*m2 = 0.2064 kg*m2 (5)[/tex]

       ⇒ Lo =Lf = If*ωf

Replacing (2) in (1), and solving for ωf, we get:

        [tex]\omega_{f} = \frac{L_{o}}{I_{f} } = \frac{6.027kg*m2*rev/min}{0.2064kg*m2} = 29.2 rev/min (6)[/tex]

The rate of change of angular displacement is defined as angular speed. The final angular speed of the wheel will be 29.2 rev/min.

What is angular speed?

The rate of change of angular displacement is defined as angular speed.  is stated as follows:

ω = θ t

Where,

θ is the angle of rotation,

t is the time

ω is the angular speed

The given data in the problem is

m is the mass of wheel = 10.0 kg

r₁ is the radius of disk = 20.0 cm=0.2

M is the mass of clay= 2.0 kg

R is the radius of cylinder =  3.0cm

[tex]\rm \omega_i[/tex] is the initial rotational speed =30.0 rev/min

r₂ is the final radius of disk=  8.0 cm.

[tex]\rm \omega_f[/tex] is the initial rotational speed=?

When the external torques act on the body is zero the total angular momentum must be conserved, as follows:

Initial momentum = Final momentum

[tex]\rm L_0=L_f[/tex]

The value of the initial angular momentum L₀ is found by

I₀ = initial moment of inertia = moment of inertia of the disk +moment of inertia of the cylinder

[tex]\rm I_0= \frac{1}{2}m_dr_d^2+ \frac{1}{2}m_cr_c^2\\\\ \rm I_0= \frac{1}{2}\times 10\times (0.2)^2+ \frac{1}{2}\times m_2(0.03)^2[/tex]

[tex]\rm L_0 = I_0\times \omega_0\\\\ L_0 = 2009\times 30\\\\ \rm L_0 =6.027 \;kgm^2rev/min[/tex]

The value of the final angular momentum [tex]I_f[/tex] is found by

[tex]\rm I_f= \frac{1}{2}m_dr_d^2+ \frac{1}{2}m_fr_fd^2\\\\ \rm I_0= 0.2064 m_2[/tex]

[tex]\rm I_f[/tex] is the final moment of inertia = moment of the inertia of the solid disk + moment of inertia of the clay flattened on a disk.

[tex]L_0 =L_f = I_f \times \omega_f[/tex]

[tex]\rm \omega_f=\frac{L_0}{I_f} \\\\ \rm \omega_f=\frac{6.027 m_2}{0.2064 m_2} \\\\ \rm \omega_f= 29.2\; rev/min[/tex]

Hence the final angular speed of the wheel will be 29.2 rev/min.

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9. What distance is a book from the floor if the book contains 196 Joules of potential energy and has a mass of 5 kg?​

Answers

Answer:

the book is 4 meters from the floor

Explanation:

Use the formula for potential energy:

U = m g h

196 J = 5kg 9.8m/s^2 h

h = 196 / (5*9.8 ) m

h = 4 m

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