The direction of the light can be changed by reflection from a reflecting surface and by the refraction of the light through a medium of different refractive index.
What is reflection?
The phenomenon of the light in which the light ray bounces back from the surface on which they fall is called the reflection.
Now when the light ray falls on a surface that is well polished like the mirror, then the light ray changes its direction. So by using the combination of mirrors, the direction of the light ray can be changed.
What is refraction?
Refraction is a phenomenon in which light rays change their path slightly when it is passing through a transparent medium with a different refractive index.
The concave and convex lens uses this property of light. So by using the convex and concave lens, the direction of the light ray can be changed.
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A boy wants to throw a can straight up and then hit it with a second can. He wants the collision to occur 4.0 meters above the throwing point. In addition, he knows that the time he needs between throws is 3.0 seconds. Assuming he throws both cans with the same speed, what must the initial speed be
16.03 m/s is the initial speed of the cans.
Newton’s equations of motion has to be used to solve it;
He wants collision at height (h) = 4.0 m
The acceleration due to gravity as,
g =9.8ms−²
The initial speed of the thrown can is calculated by:
h = vt - ¹/₂gt²
4 = 3t - (0.5)(9.8)(3)²
4 = 3t - 44.1
3t = 48.1
t = 48.1/3
t = 16.03 m/s
Thus, the initial speed of the boy's thrown can is 16.03 m/s.
By measuring the rate at which the velocity varies with regard to the passage of time, one can calculate the acceleration of a body. By calculating the rate at which the displacement varies with regard to the passage of time, the velocity may be calculated. The perpendicular distance between the body's initial and final locations is its displacement. These are all vector quantities, meaning they all have both magnitude and direction.
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For a simple compressible system, the change in the total energy of a system during a process is affected by ______. Multiple choice question. changes in potential and kinetic energies only change in potential energy only change in kinetic energy only changes in potential, kinetic, and internal energies change in internal energy only
For a simple compressible system, the change in the total energy of a system during a process is affected by changes in potential, kinetic, and internal energies.
First law of thermodynamics:The conservation of energy principle sometimes referred to as the first law of thermodynamics, offers a reliable framework for researching the connections between the many types of energy and their interactions. The first law of thermodynamics asserts that energy can only change forms during a process; it cannot be created or destroyed, according to experimental data. As a result, during a procedure, every piece of energy should be taken into account.
The evaluation of the system's energy at the start and end of the process, as well as the difference between them, is necessary to calculate the energy change of a system during a process. That is,
Energy change = Energy at final state - Energy at the initial state
Δ[tex]E_{system}[/tex] = [tex]E_{2} - E_{1}[/tex]
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hello friends,i need ur help on this,topic of Motion in straight line.
hurryy up please.
and keep answering correctly.
Answer:
V = a * t for uniformly accelerated motion starting at zero speed
V = 4 s * 9.8 m/s^2 = 39.2 m/s
S = V0 t + 1/2 a t^2 = 1/2 a t^2
S = 1/2 * 9.8 m/s^2 * 16 s^2 = 78.4 m
Check:
Average speed = 39.2 / 2 = 19.6 m/s
S = 4 * 19.6 = 78.4 m
Point charges q1and q2 of +12nc and -12nc,respectively are placed 10.0cm apart.compute the resultant electric field(magnitude field)
The electric field due to charge q1 and q2 at the middle point of the line joining the charges q1 and q2 is 8.64*10^(4) N/C.
Note: You have not given the point where the resultant magnetic field has to be calculated. Most probably it is asked to find the electric field at the middle point of the line joining the point charges.
Electric field: The electric force exerted on a unit charge is called the electric field. Electric field due to a charge is calculated using the formula,
E=kq/r^2
where k is a constant whose value is 9*10^(9) N m^2/ C^(2), q is the charge and r is the distance from the charge to the point where the electric field has to be calculated. In the given case, the electric field has to be calculated at the middle point of the line joining charges q1 and q2.
Calculation of electric field due to charge q1:
Given that q1=+12 nC or q1=+12*10^(-9) C and the distance of the charge q1 from the center d1=10.0/2 cm or d1=5*10^(-2) m, the magnitude of the electric field E1 due to charge q1 is,
E1=kq1 /d1^(2)
E1=9*10^(9)*12*10^(-9) / (5*10^(-2))^2
E1=4.32*10^(4) N/C
The direction of the electric field E1 at the middle point is towards the negative charge.
Calculation of electric field due to charge q2:
Given that q2=-12 nC or q1=-12*10^(-9) C and the distance of the charge q2 from the center d2=10.0/2 cm or d2=5*10^(-2) m, the magnitude of the electric field E2 due to charge q2 is,
E2=kq2 /d2^(2)
E2=9*10^(9)*12*10^(-9) / (5*10^(-2))^2
E2=4.32*10^(4) N/C
The direction of the electric field E2 at the middle point is towards the negative charge.
Total electric field:
The total electric field is given by the addition of the electric field. The direction of the electric field is the same for both charges, hence total electric field E is,
E=E1+E2
E=4.32*10^(4) +4.32*10^(4)
E=8.64*10^(4) N/C
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In a given lightning flash, the potential difference between a cloud and the ground is 1.5 times 109 V and the quantity of charge transferred is 23.7 C. What is the decrease in energy of the transferred charge
Answer:
The decrease in energy for a lightning flash, with a potential difference between a cloud and the ground, is [tex]1.5 \times 10^{9}\text{ V}[/tex] and the quantity of charge transferred is 23.7 C is [tex]$3.555 \times 10^{10} \text{ J}$[/tex].
Explanation:
In a lightning flash, the potential difference between a cloud and the ground is [tex]1.5 \times 10^{9}\text{ V}[/tex] and the quantity of charge transferred is 23.7 C.
It is required to determine the decrease in energy of the transferred charge.
It is known that the decrease in energy is calculated by multiplying the potential difference by the quantity of charge. Mathematically it is expressed as:
[tex]\Delta U=q \Delta V[/tex]
In this problem, the value of q is 23.7 C and the value of [tex]\Delta V[/tex] is [tex]1.5 \times 10^{9}\text{ V}[/tex].
Therefore the decrease in energy is:
[tex]$$\begin{aligned}\Delta U&=q \Delta V\\&=23.7\times 1.5 \times 10^{9} \text{ J}\\&=3.555\times 10^{10} \text{ J}\end{aligned}$$[/tex]
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A heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h. If the COP of the heat pump is 2.8, determine the power the heat pump draws when running.
The power that heat pump draws when running will be 6.55 kj/kg
A heat pump is a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building (or a portion of a structure).
Given a heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h and if the COP of the heat pump is 2.8
We have to determine the power the heat pump draws when running.
To solve this question we have to assume that the heat pump is at steady state
Let,
Q₁ = 22000 kj/kg
COP = 2.8
Since heat pump used to heat a house runs about one-third of the time.
So,
Q₁ = 3(22000) = 66000 kj/kg
We known the formula for cop of heat pump which is as follow:
COP = Q₁/ω
2.8 = 66000 / ω
ω = 66000 / 2.8
ω = 6.66 kj/kg
Hence the power that heat pump draws when running will be 6.55 kj/kg
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A stack of 1500 bricks covers a ground area of 2.750m by 1.350m.the average mass of bricks is 3.200kg.calculate the total force on the ground
The total force on the ground due to the bricks is 47,040 N.
Total force on the ground
The total force on the ground due to weight of the bricks is calculated as follows;
Fₙ = mg
where;
Fₙ is normal forcem is mass of the brickesg is acceleration due to gravityFₙ = (1500 x 3.2) x 9.8
Fₙ = 47,040 N
Thus, the total force on the ground due to the bricks is 47,040 N.
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A 480 g peregrine falcon reaches a speed of 75 m/s in a vertical dive called a stoop. If we assume that the falcon speeds up under the influence of grav- ity only, what is the minimum height of the dive needed to achieve this speed
The minimum height of the dive needed to achieve the given speed is v = 69 m/s is 242.9 m.
Given information:
The mass of peregrine falcon is, m = 480
The final speed reached by the peregrine falcon in a vertical dive is, v = 69 m/s
It is given that the falcon is diving vertically downward. It can be compared with the same situation as the free-falling object under the effect of gravity only. So, the initial velocity of the falcon will be u = 0 m/s as the motion starts with rest.
The value of the gravitational acceleration of gravity is, g = 9.80 m/s²
Now, using the third equation of motion, the minimum height required for the final speed will be,
v² - u² = 2gh
69² - 0² = 2 × 9.8 × h
h = 242.9m.
Therefore, the minimum height of the dive needed to achieve the given speed is 242.9 m.
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To develop a model of blackbody radiation that correctly modeled the behavior of emission intensity versus wavelength, Planck applied quantization of:\
Max Planck utilized the concept of energy quantization in order to develop a model for blackbody radiation that accurately fit experimental results.
Electromagnetic waves emitted by using a blackbody are referred to as blackbody radiation. A blackbody is bodily found out through a small hole within the wall of a hollow space radiator.
The depth of blackbody radiation depends on the wavelength of the emitted radiation and the temperature T of the blackbody.
When the temperature of a black frame increases, it is discovered that the wavelength similar to most electricity changes from 0.26 μm to 0. Thirteen μm Then the ratio of the emissive power of the body at the respective temperature is.
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An automated machine passes milk through steam at a temperature of 138OC for two seconds and then cools it rapidly. This is an example of ____________________.
Option (c) is correct
This is an example of Ultra-high-temperature pasteurization(UHT).
For ultra-high-temperature (UHT) pasteurization, milk or cream must be heated for one or two seconds to 138–150 °C (280–302 °F).
The most popular application of UHT is in the production of milk, although it is also used in the production of fruit juices, cream, soy milk, yoghurt, wine, soups, honey, and stews.
The normal unrefrigerated shelf life of UHT milk in a sterile container is six to nine months.
UHT milk is aseptically packaged to provide a shelf-stable good. A sterile product is put within a sterile package using aseptic packaging and such processing needs to happen in a sterile setting.
Both pasteurization and sterilization help in the destruction of microbes and enzymes by heating but pasteurization only kills the vegetative stage of the bacteria, which is where the spores survive, whereas sterilization kills all microorganisms and their spores.
Therefore, an automated machine passes milk through steam at a temperature of 138°C for two seconds and then cools it rapidly is an example of Ultra-high-temperature pasteurization.
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An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 230 N. (a) What is the equivalent spring constant of the bow
Answer: An archer pulls her bowstring back 0.400m by exerting a force that increases uniformly from zero to 230N. The equivalent spring constant of the bow will be 575N/m
Explanation: To find the answer, we have to know about the Simple Harmonic Motion.
What is Simple Harmonic Motion?A particle is said to execute simple harmonic motion, if it moves to and fro about mean position under the action of restoring force. The restoring force is directly proportional to its displacement from the mean position and always directed towards the mean position.If x is the displacement from the mean position, and F is the restoring force, then[tex]F[/tex]∝[tex]-x[/tex]
[tex]F=-kx[/tex] where, k is called the spring constant.
How to approach the problem?Given that, an archer pulls her bowstring back 0.400m by exerting a force that increasing from zero to 230N.Here, from the question given, we can write, [tex]x=-0.400m[/tex] and [tex]F=230N[/tex].Thus, our spring constant k will be,[tex]k=-F/x= (230)/ (0.400) =575 N/m.[/tex]
Thus, we can conclude that, the equivalent spring constant of the bow will be 575N/m.
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The pilot of the fighter jet turns by banking the wings such that the lift of the wings has a component in
the direction of the centre of the turn. The pilot wishes to turn the jet in a tight radius of 960.0 m while
maintaining a constant circular speed of 1440 km/h. Determine the angle of bank needed, measured from
the vertical.
The angle of bank needed, measured from the vertical is 86.6⁰.
Banking angle of the circular path
The angle of bank needed, measured from the vertical is calculated as follows;
v = √(rg tanθ)
where;
v is the speed = 1440 km/h = 400 m/sr is radius of the curve = 960 mg is acceleration due to gravityθ is the banking angle400² = (960 x 9.8 x tanθ)
tanθ = 400²(960 x 9.8)
tanθ = 17
θ = arc tan(17)
θ = 86.6⁰
Thus, the angle of bank needed, measured from the vertical is 86.6⁰.
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PLEASE HELP ME I BEGGG
Answer:
,ff
Explanation:
2331552378 added mee
What are the 2 forces acting on a projectile?
A. Gravity and Tension
B. Air Resistance and Tension
C. Gravity and Air Resistance
D. Gravity and Normal Force
Answer:
Gravity and Air resistance.
Explanation:
A projectile is an object that is launched into the air by the application of an external force and they are able to move freely under the influence of gravity and air resistance.
Therefore,
The 2 forces acting on a projectile are:
Gravity and Air resistance.
A spring whose spring constant is 260 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required to compress it another 1 in. The work required to compress it another 1 in is Btu.
The work required to compress it another 1 in Btu is 0.02463 Btu.
Work finished is elaborated in the sort of way that it consists of both forces exerted at the frame and the full displacement of the body. This block is preceded by a steady force F. The reason for this pressure is to transport the frame a sure distance d in an instant course in the direction of the force.
To explicit this idea mathematically, the work W is the same as the pressure f instances the distance d, or W = FD. If the pressure is being exerted at a perspective θ to the displacement, the work finished is W = FD cos θ.
The work is executed whenever a force actions something over a distance. you can calculate the electricity transferred, or work completed, by multiplying the force by way of the space moved inside the course of the force.
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A 1000-kg sports car of mass accelerates from rest to 20 m/s in 6.6 s. What is the frictional force exerted by the road on the car? Group of answer choices 1500 N 1750 N 2750 N 3000 N
The frictional force exerted by the road on the car is 3000N
Given the mass of the car is 1000 kg , the velocity of the car is 20m/s
and the time is 6.6s
We need to find the frictional force exerted by the road on the car
We know that Force = mass * acceleration
Now here Mass is given but acceleration is not given
So, we will find acceleration by using the formula v = u+at
Where u = 0
v = 20m/s
a = ?
t = 6.6
Substitute the values in the formula We get
v = u+at
20 = 0+(a)(6.6)
20/6.6 = a
∴ a = 3.03 m/s^2
Rounding to nearest tenth is 3m/s^2
Hence the acceleration is 3m/s^2
Now substituting the value of acceleration in F = ma
Where m = mass
a = acceleration
F = 1000*3
∴ F = 3000N
Hence the frictional force exerted by the road on the car is 3000 N
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Calculate the magnitude of the electric field inside the solid at a distance of 9.40 cmcm from the center of the cavity.
The magnitude of electric field inside the solid at a distance of 9.50cm from the center of the cavity is 6.5 x 10⁵ N/C.
Volume of shell of chargeV = ⁴/₃π(R³ - r³)
V = ⁴/₃π (0.092³ - 0.0655³)
V = 2.085 x 10⁻³ m³
Total charge of the surfaceQ = Vσ
where;
V is volumeσ is charge densityQ = 2.085 x 10⁻³ m³ x 7.35 x 10⁻⁴ C/m³
Q = 1.53 x 10⁻⁶ C
Electric field due to the shellE = kQ/R²
E₁ = (9 x 10⁹ x 1.53 x 10⁻⁶)/(0.092)²
E₁ = 1.627 x 10⁶ N/C
Electric field due to the charge qE₂ = (9 x 10⁹ x 2.14 x 10⁻⁶)/(0.092)²
E₂ = 2.276 x 10⁶ N/C
Electric field inside the solid at a distance of 9.50cm from the center of the cavity;
E = E₂ - E₁
E = 2.276 x 10⁶ N/C - 1.627 x 10⁶ N/C
E = 6.5 x 10⁵ N/C
Thus, the magnitude of electric field inside the solid at a distance of 9.50cm from the center of the cavity is 6.5 x 10⁵ N/C.
Complete question:
A point charge of -2.14uC is located in the center of a spherical cavity of radius 6.55cm inside an insulating spherical charged solid. The charge density in the solid is 7.35×10−4 C/m^3.
a) Calculate the magnitude of the electric field inside the solid at a distance of 9.20cm from the center of the cavity.
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You have just checked out a Lime bicycle, only to find that one of its tires is flat. Luckily, you have a bicycle pump with you. As you refill the flat tire, you find that it takes a considerable amount of effort to do it. Why
It will take a considerable amount of effort to pump the flat tire because of the bicycle pump has smaller area and it will require more force to push air into the flat tire.
Difference in air pressurePressure is defined as force applied per unit area of the given surface.
Pressure = Force/Area
The pressure of air inside the bicycle pump is smaller compared to the air pressure inside the tire.
Thus, it will take a considerable amount of effort to pump the flat tire because of the bicycle pump has smaller area and it will require more force to push air into the flat tire.
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What is an application of a magnetic effect of an electric current?
And how does the application work due to the magnetic effect of an electric current?
Applications of Magnetic Effect of ELectric Current:
Electrical appliances such as the electric doorbell, electric fan, electric engines work on the principle of electromagnets. They are used in lifting weighty iron gears and iron scrap.
What is magnetic effect of electric current short answer?Magnetic field exercises a force on a current carrying conductor. The force exerted on the current carrying conductor depends upon the demand of current and movement of magnetic field acting on it.
What is an example of magnetic effect?Examples of magnetic force is a compass, a motor, the interests that hold stuff on the refrigerator, train tracks, and new roller coasters. All moving costs give rise to a magnetic field and the charges that move through its regions, share a force.
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What causes earthquakes?
Where do earthquakes begin?
Answer:
An earthquake is caused by a sudden slip on a fault. The tectonic plates are always slowly moving, but they get stuck at their edges due to friction.
Explanation:
Tensions around rocks are increasing, and an earthquake begins at tectonic plates.
The majority of earthquakes begin at or close to tectonic plate borders, where stress and strain gradually build up due to interactions between the plates over time. An earthquake occurs when the amount of accumulated tension surpasses the capacity of the rocks, which causes an abrupt release of energy. When there is an earthquake, seismic waves are released, and we feel and sense shaking as a result.
But even beyond plate borders, within tectonic plates, earthquakes can still happen. These earthquakes, also known as intraplate earthquakes, are frequently connected to old faults or weak spots in the crust of the Earth. Despite being less frequent than those near plate borders, intraplate earthquakes can nevertheless be severe and cause damage in populated regions.
Hence, tensions around rocks are increasing, and an earthquake begins at tectonic plates.
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What do simple machines increase?
O movement
O force
O gravity
O mechanical advantage
Answer:
Mechanical advantage
Explanation:
Machines help us in giving more output than the input incurred so it only increases mechanical advantage, all the other quantities are dependent on the mechanical advantage.
A current of 0.050 amps flows in a circuit element with a resistance of 25 ohms what is the voltage drop across the circuit element. (use ohms law V=IR)
The voltage drop across the circuit, given that 0.05 A flows in the circuit is 1.25 V
Ohm's lawThis law states as follows:
V = IR
Where
V is the potential differenceI is the currentR is the resistorHow to determine the voltageFrom the question given above, the following data were obtained:
Current (I) = 0.05 AResistance (R) =25 ohmsVoltage (V) =?V = IR
V = 0.05 × 25
V = 1.25 V
Therefore, the voltage drop across the circuit is 1.25 V
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What happens when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure
when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure, then The core contracts and becomes black hole.
What is degeneracy pressure:
The degeneracy pressure found in the interior of a white dwarf or neutron star. The degeneracy pressure is greatly needed in the interior of these stars to counteract the pressure due to gravity.Some neutron stars may have a surface layer of highly degenerate matter that is compressed to great density, but still has some protons
Unlike the main body of the neutron star which is Neutronium, matter compressed until it is all neutrons, packed together. Essentially a huge atomic nucleus.
The star cools and all remaining matter is bound by gravitation into a neutron star.
This object is composed primarily of degenerate neutron matter, this star will collapse into a black hole because gravity will overcome the neutron degeneracy pressure.
hence, when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure, The core contracts and becomes a black hole.
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The odometer of a car changes from 1048 km to 1096 km in 40
minutes. Calculate the average velocity.
O 22 m/s
O 14 m/s
20 m/s
O 18 m/s
Answer:
20m/s
Explanation:
it covers 20 metres in a second
Which mechanical component is required in every gas-engine vehicle, but often not needed in an electric vehicle?.
a gearbox bru.
An asteroid on the earth's orbit experiences a free-fall acceleration which is 8.0 times smaller than it would be on the earth. what is the distance between the asteroid and the earth's surface measured in the earth's radii? neglect the gravity of the moon.
The the distance between the asteroid and the earth's surface measured in the earth's radius is 1.82 R
What are the Asteroids:
Asteroids are small, rocky objects that orbit the Sun. They are much smaller than planets.They are found between the orbits of Mars and Jupiter, though some have more eccentric orbits.here,
An asteroid experiences acceleration on earth's orbit which is 8.0 times smaller than it on the earth surface.
Free fall acceleration of Asteroid:
on earth's surface = gon earth's orbit = g' = g / 8so,
g' = GM /(R + x)^2 ------1
g = GM / R^2
g' = 1/8 ( GM / R^2 ) -------1
where G is gravitational constant
M is mass of earth
R is earth's radius
comparing both equations 1 and 2
GM /(R + x)^2 = 1/8 ( GM / R^2 )
8 R^2 = (R + x)^2
2√2 * R = R + x
x = R (2√2 - 1)
x = 1.82*R
hence, The the distance between the asteroid and the earth's surface measured in the earth's radius is 1.82*R
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A 200-N scaffold is held up by a wire at each end. The scaffold is 18 m long. A 650-N box sits 3.0 m from the left end. What is the tension in each wire
The tension on the left wire 642N and the tension on right wire is 208N
Given that the force of scaffold is 200- N and the length of the scaffold is 18m
We need to find the tension in each wire
Tension Force is the force that is transmitted through a cable, rope, wire or string when it is pulled tight by forces acting from opposite ends
Here
∑ [tex]T_b=0[/tex]
∴ [tex]W_B(15m)+W_S(9m)-T_L(18m) = 0[/tex]
∴ [tex]T_L = \frac{W_B(15m)+W_S (9m)}{18m}\\ T_L = \frac{650(15)+200(9)}{18}\\ T_L = 642 N[/tex]
Hence the tension on the left side is 642N
∑[tex]T_a[/tex] = 0
[tex]T_R(18m)-W_B(3m)-W_S(9m)=0[/tex]
∴[tex]T_R =\frac{W_B(3m)+W_S(9m)}{18m}[/tex]
∴[tex]T_R = \frac{650(3)+200(+9)}{18}\\[/tex]
∴[tex]T_R = 208N[/tex]
Hence the tension on the right side is 208N
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A 36,287 kg truck has a momentum of 907,175 kg • meters per second. what is the truck’s velocity? meters per second
The truck's velocity is 25 m/s.
It is given that,
mass, m= 36,287 kg
momentum, p = 907,175 kg-m/s
Using the formula of momentum, we know that
p = mv
Plugging in the values
907,175 kg-m/s = 36,287 kg x v
v = 25 m/s
So, the velocity of the truck is 25 m/s.
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Answer:25
Explanation:your welcome!:)
A boy is leaning into a wall with a horizontal force of 15 N. Which of the following best describes the vector force the wall is applying to the boy?
A
–7.5 N
B
15 N
C
0 N
D
–15 N
The vector force the wall is applying to the boy is -15 N; option D
What is a reaction force?A reaction force is a force which is equal in magnitude but oppositely directed to a force acting in a particular direction.
The reaction force on the boy is equal in magnitude to the weight of the boy but has an opposite direction.
In conclusion, the vector force applied by the wall on the boy is -15 N.
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An object has a mass of 20.41 kg and an acceleration of 8.22 m/s2. What is the force acting on the object?
Answer: 167.7702 N (Newtons)
Explanation: I had this type of work, so I hope I am correct.
Answer:
~ 168 N
Explanation:
F = m a
= 20.41 * 8.22 = 167.7702 N