The sum of ten and the quotient of a number 2 and 6.
Answer:
10+(n/2)=6
Step-by-step explanation:
Let the number be n
Quotient of n and 2 is (n/2)
Sum of this and 10 is
10+(n/2)=6
Help me find this asap
Answer:
DQ = [tex]\frac{5}{(2-\sqrt{x})(2-\sqrt{x+h})(\sqrt{x}-\sqrt{x+h})}[/tex]
Step-by-step explanation:
Given function is f(x) = [tex]\frac{5}{2-\sqrt{x}}[/tex]
f(x + h) = [tex]\frac{5}{2-\sqrt{x+h} }[/tex]
Therefore, indicated difference quotient will be,
DQ = [tex]\frac{f(x+h)-f(x)}{h}[/tex]
Now we substitute the values in the difference quotient,
DQ = [tex]\frac{\frac{5}{2-\sqrt{x+h} }-\frac{5}{2-\sqrt{x}}}{h}[/tex]
= [tex]\frac{5(2-\sqrt{x})-5(2-\sqrt{x+h})}{h(2-\sqrt{x})(2-\sqrt{x+h})}[/tex]
= [tex]\frac{10-5\sqrt{x}-10+5\sqrt{x+h}}{h(2-\sqrt{x})(2-\sqrt{x+h})}[/tex]
= [tex]\frac{-5\sqrt{x}+5\sqrt{x+h}}{h(2-\sqrt{x})(2-\sqrt{x+h})}[/tex]
= [tex]\frac{5(-\sqrt{x}+\sqrt{x+h})}{h(2-\sqrt{x})(2-\sqrt{x+h})}[/tex]
= [tex]\frac{5(-\sqrt{x}+\sqrt{x+h})(\sqrt{x}+\sqrt{x+h})}{h(2-\sqrt{x})(2-\sqrt{x+h})(\sqrt{x}+\sqrt{x+h})}[/tex]
= [tex]\frac{5[(x+h)-x]}{h(2-\sqrt{x})(2-\sqrt{x+h})(\sqrt{x}+\sqrt{x+h})}[/tex]
= [tex]\frac{5h}{h(2-\sqrt{x})(2-\sqrt{x+h})(\sqrt{x}+\sqrt{x+h})}[/tex]
= [tex]\frac{5}{(2-\sqrt{x})(2-\sqrt{x+h})(\sqrt{x}+\sqrt{x+h})}[/tex]
Using the slope formula, find the slope of the line through the given points.
(2,6) and (6,2)
Answer:
m=(y2-y1)/(x2-x1)
=(2-6)/(6-2)
=-4/4
=-1
Step-by-step explanation:
The temperature is _____ °C
Answer:
25 0r 26 F
Step-by-step explanation:
around .5 - 1 C
which of these equations or inequalities below are true 4 - 5< -2
Answer:
4-5<-2 is false it should be 4-5>-2
Step-by-step explanation:
Answer:b
Step-by-step explanation:
The shaded set of numbers shown on the x-axis can be expressed in interval notation as _____
This is basically saying [tex]1 \le x < 4[/tex]
The square bracket says "include this endpoint" while the curved parenthesis means "exclude this endpoint". We can tell what is included/excluded based on how the endpoint is drawn.
Open circle = exclude endpoint
Closed/filled in circle = include endpoint
Your teacher has also drawn a square bracket at the left endpoint, and a curved parenthesis at the right endpoint. This style of drawing the endpoints helps set up [1, 4). Though sometimes you might see the use of open/closed circles instead for the endpoints. I'm referring to the number line portion.
We want to express the shaded set of numbers on the x-axis with interval notation.
The interval notation is:
[1, 4)
Let's start by analyzing the graph.
We have two ends, one at x = 1, with a colored dot, which means that that value belongs to the set.
We have the other end at x = 4, with a white dot, which means that the value does not belong to the set.
Then the interval notation is:
[1, 4)
Where [] are used for colored dots.
() are used for white dots.
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SOLVING EQUATIONS
1) Solve 3x - 5 = -26
SOLVING QUADRATIC EQUATIONS
Answer:
x = -7
Step-by-step explanation:
This isn't a quadratic.
Step 1: Write out equation
3x - 5 = -26
Step 2: Add 5 to both sides
3x = -21
Step 3: Divide both sides by 3
x = -7
Step-by-step explanation:
[tex]\sf \bf We \: have,[/tex]
[tex]\sf 3x - 5 = -26[/tex]
[tex]\sf : \implies \bf 3x - 5 \green{+5}= -26\green{+5}[/tex]
[tex]\sf : \implies \bf 3x =-21[/tex]
[tex]\sf : \implies \bf 3x× \green{\dfrac{1}{3}}=-21× \green{\dfrac{1}{3}}[/tex]
[tex]\sf : \implies \bf \underline{\boxed{\sf \bf x = -7}}[/tex]
Write down an expression for the nth term of the following sequence 7,16,25,34,43
Answer:
So in this sequence, we are adding by 9 in each term
So our pattern is: 7 , 7 +9 , 7 + 2(9) , 7 + 3(9) .....
hence, we can write it as: 7 + [tex]9^{n-1}[/tex] where n is the number of the term you want
The distance from the green point on the parabola to the parabola's focus is
11. What is the distance from the green point to the directrix?
Focus
11
Directrix
O A. 11
B. 9.5
C. 5.5
Answer:
11
Step-by-step explanation:
sawarasenaaa kimi wa-
Which planet is an inner planet, and which one is an outer planet? Explain your answer.
The correct answers are Planet A 16 hours - Inner planet and planet B 1,408 hours - Outer planet.
What is a planet?Large, circular celestial objects that are neither stars nor their remnants are known as planets. The inner planets are the ones that are much closer to the sun, thus they have much smaller orbits around it and it takes them much less time to circle around it. Also, these planets are much smaller, which enables them to spin around their axis much quicker too, so one day passes much quicker.
The outer planets are the total opposite. They are much further from the sun, so for them to be able to make a single circle around the sun it takes much more time, and also because they are much bigger, it takes them much more time to spin around their own axis, thus making one day much longer than the days of the inner planets.
The complete question is given below as:-
Which planet is an inner planet, and which one is an outer planet? Explain your answer. Planet A 16 hours planet B 1,408 hours
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What is 10x-2(x+6)=52 ?
Answer:x=8
Step-by-step explanation:Reorder the terms:
10x + -2(6 + x) = 52
10x + (6 * -2 + x * -2) = 52
10x + (-12 + -2x) = 52
Reorder the terms:
-12 + 10x + -2x = 52
Combine like terms: 10x + -2x = 8x
-12 + 8x = 52
Solving
-12 + 8x = 52
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '12' to each side of the equation.
-12 + 12 + 8x = 52 + 12
Combine like terms: -12 + 12 = 0
0 + 8x = 52 + 12
8x = 52 + 12
Combine like terms: 52 + 12 = 64
8x = 64
Divide each side by '8'.
x = 8
Simplifying
x = 8
Answer:
x=5
Step-by-step explanation:
The mean absolute deviation is best described as:
The value obtained when averaging the distances between each data point in the data set and the mean.
The value obtained when you add all the values in the data set and divide by the number of values.
The difference between the means of two similar data sets.
An approximation of the center of a data set.
Answer: It’s the second one
Step-by-step explanation:
If you continue the pattern below so that you write all of the numbers in the pattern less than 500, how many even numbers will you write? 4, 9, 14, 19, 24, 29...
Answer:
I think it would be 50 even numbers
Find the counterexample to show that the statement is incorrect. The difference of any two counting numbers will be a counting number Choose the correct answer below. A. 3-5= -2, which is not a counting number. B. 7-4 = 3, which is not a counting number. C. 10-2 = 8, which is counting number D. There is no counterexample. The statement is correct.
Answer:
A. 3-5= -2, which is not a counting number.
Step-by-step explanation:
Counting numbers are non negative numbers greater than 1 up to infinity. Counting numbers are also called natural numbers, and they do not include the negative numbers.
The statement states that "The difference of any two counting numbers will be a counting number"
From option A we can disprove that, since we can see that not all the difference between two counting numbers gives a counting number.
3 is a counting number
5 is a counting number
The difference between 3 and 5 gives -3, which is not a counting number.
This is a counterexample to the statement above.
100 POINTS I NEED HELP ASAP
If h(x) = |2x-4| , find (h-7)
Answer:
The answer is 18.
Step-by-step explanation:
You just need to plug in -7 to the equation 2x-4. You get -18, but absolute value is always positive, so its 18.
The answer is 18.
Sorry no explanation im soooo sorry
Write 18% as a fraction
Hi there!
~
[tex]18[/tex]% [tex]= \frac{9}{50}[/tex]
Answer9/50:
Step-by-step explanation:
18/100
18÷2
100÷2
9/50
Evaluate 10bc-b+c, when b = 3 and c= 2.
I need help ASAP!!!!!!!
Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)
Answer:
The standard equation of the sphere is [tex](x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53[/tex]
Step-by-step explanation:
From the question, the end point are (3,-2,4) and (7,12,4)
Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.
The midpoint can be calculated thus
Midpoint = [tex](\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})[/tex]
Let the first endpoint be represented as [tex](x_{1}, y_{1}, z_{1})[/tex] and the second endpoint be [tex](x_{2}, y_{2}, z_{2})[/tex].
Hence,
Midpoint = [tex](\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2} }{2})[/tex]
Midpoint = [tex](\frac{3 + 7 }{2}, \frac{-2+12 }{2}, \frac{4 + 4 }{2})[/tex]
Midpoint = [tex](\frac{10 }{2}, \frac{10}{2}, \frac{8 }{2})\\[/tex]
Midpoint = [tex](5, 5, 4)[/tex]
This is the center of the sphere.
Now, we will determine the distance (diameter) of the sphere
The distance is given by
[tex]d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2} }[/tex]
[tex]d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}[/tex]
[tex]d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}[/tex]
[tex]d = \sqrt{16 +196 + 0[/tex]
[tex]d =\sqrt{212}[/tex]
[tex]d = 2\sqrt{53}[/tex]
This is the diameter
To find the radius, r
From [tex]Radius = \frac{Diameter}{2}[/tex]
[tex]Radius = \frac{2\sqrt{53} }{2}[/tex]
∴ [tex]Radius = \sqrt{53}[/tex]
r = [tex]\sqrt{53}[/tex]
Now, we can write the standard equation of the sphere since we know the center and the radius
Center of the sphere is [tex](5, 5, 4)[/tex]
Radius of the sphere is [tex]\sqrt{53}[/tex]
The equation of a sphere of radius r and center [tex](h,k,l)[/tex] is given by
[tex](x-h)^{2} + (y-k)^{2} + (z-l)^{2} = r^{2}[/tex]
Hence, the equation of the sphere of radius [tex]\sqrt{53}[/tex] and center [tex](5, 5, 4)[/tex] is
[tex](x-5)^{2} + (y-5)^{2} + (z-4)^{2} = \sqrt{(53} )^{2}[/tex]
[tex](x-5)^{2} + (y-5)^{2} + (z-4)^{2} = 53[/tex]
This is the standard equation of the sphere
Simplify the ratio 45 to 75
The GCF of 45 and 75 is 15.
So, divide both numbers by 15.
45/15 = 3
7515 = 5
Therefore, the simplified version of the ratio is 3 to 5
Best of Luck!
Find a vector equation for the line through the point P = (4, 2, 4) and parallel to the vector v = < -2, -5, -3 > . Assume r(0) = 4i + 2j + 4k and that v is the direction vector of the line. R(t) = Rewrite this in terms of the corresponding parametric equations for the line. x = ______y = ______z = ______
Answer:
The parametric equations are
x = - 2 t + 4 , y = - 5 t + 2 , z = - 3 t + 4
Step-by-step explanation:
Step(i):-
Given point P = ( 4,2,4)
Given vector is -2 i - 5 j - 3 k
The vector equation of a line through the point a⁻ and parallel to b⁻ is
r⁻ = a⁻ + t b⁻
Given r⁻ = 4 i + 2 j + 4 k
r⁻ = 4 i + 2 j + 4 k + t (-2 i - 5 j - 3 k)
Step(ii):-
The Cartesian form
[tex]\frac{x-a_{1} }{b_{1} } = \frac{y-a_{2} }{b_{2} } = \frac{z-a_{3} }{b_{3} } = t[/tex]
[tex]\frac{x-4 }{-2 } = \frac{y-2 }{-5 } = \frac{z-4 }{-3 } = t[/tex]
[tex]\frac{x-4 }{-2 } = t[/tex]
⇒ x - 4 = -2 t
⇒ x = - 2 t + 4
[tex]\frac{y-2 }{-5 } = t[/tex]
⇒ y - 2 = - 5 t
⇒ y = - 5 t + 2
[tex]\frac{z-4 }{-3 } = t[/tex]
z - 4 = -3 t
z = - 3 t + 4
Conclusion:-
The parametric equations are
x = - 2 t + 4 , y = - 5 t + 2 , z = - 3 t + 4
An oil tanker can be emptied by the main pump in 4 hours. An auxiliary pump can empty the tanker in 11 hours. If the main pump is started at 7 PM, when should the auxiliary pump be started so that the tanker is emptied by 10 PM?
Answer:
The pump should be added by 8PM
Step-by-step explanation:
An oil tanker can be emptied by the main pump in 4 hours.
An auxiliary pump can empty the tanker in 11 hours.
the main pump is started at 7 PM,and we have 10 PM - 7PM = 3 hours to empty the tank.
So we have to look for the combined rate of the both pumps .
Let's say the volume= x
Rate of first pump= x/4
Rate of second pump= x/11
The rate will be added together
Combined rate= x/11 + x/4
Combined rate= 15x/44
But they have three hours to complete their pump
15x/44 = 3
X=1.0227
The pump should be added by 8PM
2.64 gallons = how many liters
Answer:
9.9924 liters
Step-by-step explanation:
there are 3.785 liters in one gallon
multiply 3.785 liters times 2.64
that comes out to 9.9924 liters
rochelle needs to pick a frame that measures 7 6/11 inches on each side ?
no the frame will not fit
7 6/11 =7.545454
7.545454 is larger than 7.5
1 point
#11: At MVP Fitness, the enrollment fee is $95 and it costs $40 per month.
At the Body Factory, the enrollment fee is only $25, but it costs $50 per
month. Write and solve an equation to find the number of months at which
the total cost charged by the two companies would be the same.
Your answer
1) 6,875 28
In the problem above,
(estimate: 6,875 28 as 6,000 + 30 = 200).
After the first digit is placed in the hundreds place in the quotient and students have
divided, multiplied, subtracted, and compared, the student should bring down the 7.
Now, estimate 1270 28 and perform a second division (repeat).
1,270 28 is estimated as 1,200 + 30 = 40.
Students then divide, multiply, subtract, and compare the remainder to the divisor,
making sure it is smaller.
Finally, perform 115 -28, by estimating, dividing, multiplying, subtracting, and
comparing
After writing the remainder in the quotient, the division is complete.
What is the Quotient? Answer:
Answer:
?
Step-by-step explanation:
Solve the following inequality
-x<-7
Answer:
The answer could be any number above -7.
So, it could be...
(-8)
(-9)
(-10)
etc.
Step-by-step explanation:
The bigger the negative number, the lower the value.
Angie and Kenny play online video games. Angie buys 1 software and of game play. Kenny 2 buys software and 6 months of game play. Each software package costs $50. If their total cost is $295, what is the cost of one month of game play?
Answer:$12
Step-by-step explanation:
Answer:
months of game play (m) =$11
Step-by-step explanation:
The temperature in Fahrenheit, x, is converted into the temperature in Celsius with the formula [tex]c(x)=\frac{5}{9}(x-32)[/tex]. What transformations are used in transforming the parent graph y = x, to obtain the graph of [tex]c(x)=\frac{5}{9}(x-32)[/tex]
horizontal translation
vertical compression
reflection in the x-axis
vertical translation
reflection in the y-axis
The temperature in Fahrenheit, x, is converted into the temperature in Celsius with the formula . What transformations are used in transforming the parent graph y = x, to obtain the graph of blank. The answers would be:
horizontal translationvertical compressionTo obtain the graph of c(x) = (5/9){ x - 32 } we need as horizontal transformation. The correct option is A.
What is a function?A function is defined as the expression that set up the relationship between the dependent variable and independent variable. A function in mathematics from a set X to a set Y allocates exactly one element of Y to each element of X. The sets X and Y are collectively referred to as the function's domain and codomain, respectively.
Given function of temperature is c(x) = (5/9){ x - 32}. The two graphs are plotted on the x-y plane. It is observed that y = x is transformed to the horizontal direction.
The graph of the two functions y = x and c(x) = (5/9){ x - 32 } is attached with the answer below.
Therefore, to obtain the graph of c(x) = (5/9){ x - 32 } we need as horizontal transformation. The correct option is A.
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What is the first step to evaluate 28-64\div828−64÷828, minus, 64, divided by, 8?
Answer:
64 Divided by 8
Step-by-step explanation:
show that n(n+1)(n+2) is divisible by 6
Solution
(
Proof by induction
Base case:
n=1: 1*2*3=6 is obviously divisible by six.
Assumption: For every n>1 n(n+1)(n+2) is divisible by 6.
For n+1:
(n+1)(n+2)(n+3)=
(n(n+1)(n+2)+3(n+1)(n+2))
We have assumed that n(n+1)(n+2) is divisble by 6.
We now only need to prove that 3(n+1)(n+2) is divisible by 6.
If 3(n+1)(n+2) is divisible by 6, then (n+1)(n+2) must be divisible by 2.
The "cool" part about this proof.
Since n is a natural number greater than 1 we can say the following:
If n is an odd number, then n+1 is even, then n+1 is divisible by 2 thus (n+1)(n+2) is divisible by 2,so we have proved what we wanted.
If n is an even number" then n+2 is even, then n+1 is divisible by 2 thus (n+1)(n+2) is divisible by 2,so we have proved what we wanted.
Therefore by using the method of mathematical induction we proved that for every natural number n, n(n+1)(n+2) is divisible by 6. QED.