hi besties help me

Answers

Answer 1

Same I also need help ;-;

Answer 2
Same I need help :/.

Related Questions

I need to know what is the find m<ACD​

Answers

Answer:

28

Step-by-step explanation:

if (AB and DC) parallels lines than the equation is alternate interior and therefore congruent to each other

Answer:
28 because they are equall

1/3 points Previous Answers TanApMath7 10.5.004. My Notes + Ask Your Teacher The owner of the Rancho Los Feliz has 3180 yd of fencing to enclose a rectangular piece of grazing land along the straight portion of a river and then subdivide it by means of a fence running parallel to the sides. No fencing is required along the river. (See the figure below.) What are the dimensions of the largest area that can be enclosed? x = X yd y = 1590 yd What is this area? x yd2 Need Help?

Answers

The dimensions of the largest area that can be enclosed is 1590 × 795= 1264050 yd² when no fencing is required along the river.

Given the owner of the Rancho Los Feliz has 3180 yd of fencing to enclose a rectangular piece of grazing land along the straight portion of a river and then subdivide it by means of a fence running parallel to the sides. No fencing is required along the river.

We need to find the dimensions of the largest area that can be enclosed.

Therefore, the length of the land is the perimeter of the rectangle minus the river front.

We have; 2x + 3y = 3180 yd

Also, we can rewrite this equation in terms of x;

2x = 3180 - 3yy = (3180 - 2x) / 3

Substituting y in terms of x in the area equation;

Area A = x y= x(3180 - 2x) / 3

Taking the derivative of the area equation to find the maximum value of A;

A' = 1060 - 2x / 3 When A' = 0, x = 1590 / 2 = 795 yd.

Substitute x = 795 into the equation for y;

2(795) + 3y = 3180y = (3180 - 1590) / 3 = 530 yd

Therefore, the dimensions of the largest area that can be enclosed are; Length = 1590 yd Width = 795 yd

Hence, the area is given by; Area = Length × Width= 1590 × 795= 1264050 yd².

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Please Answer This, the question is on the picture. it needs to be a fraction
will mark brainllest if its right, no links!

Answers

Given adjacent = 14.7
Given degree = 41
Find hypothenuse
Sohcahtoa (use cah to find hypothenuse)

Cosine = adjacent/hypothenuse
Cos(41) = 14.7/h
0.7547095802 = 14.7/h
14.7/0.7547095802 = 19.477691

Round to nearest tenth:

Solution: 19.5

Answer:

x = 19.48 or 19 12/25

Step-by-step explanation:

cos 41° = 14.7/x

x = 19.48 or 19 12/25

The lengths of three line segments are shown above. Which of the following statements is true?

Answers

Where is the three lines segments

i just want to make sure i’m correct so is this correct?

A standard coffee mug has a capacity of 16 fluid ounces. If Annie needs to fill 26 mugs with coffee, how many total quarts of coffee does she need?

so what i did is i multiplied 16 x 26 = 416 then i divided 32 and 416 and got 13 so Annie filled 13 quarts of coffee.

please tell me i’m correct or not.

Answers

Answer:

I think you are I'm not 100%

Answer:

13qt

Step-by-step explanation:

your totally correct.

water from a tap flows into a bath at rate of a 750 ml/s. how long does it take to fill the bath with 180 L of water​

Answers

Answer:

750 equals to 1081 after that divide 1081 by 750 then you will get an answer.

A rectangular prism has a length of 18 meters, a height of 10 meters, and a width of 5
meters. What is its volume, in cubic meters?

Answers

Answer:

900

Step-by-step explanation:

Help me guys. plz no Decimal please. Thank you!

Answers

Answer: 1,145,375cm^3

Step-by-step explanation:

Which describes the difference between the two sequences?
First Sequence: 3, 6, 9, 12, ...
Second Sequence: 3, 12, 48, 192, ...
The first sequence is geometric because there is a common difference of 3. The second sequence is arithmetic
because there is a common ratio of 4.
O The first sequence is arithmetic because there is a common difference of 3. The second sequence is geometric
because there is a common ratio of 4.
The first sequence is arithmetic because there is a common ratio of 3.
The second sequence is geometric because there is a common difference of 4.
O The first sequence is arithmetic because there is a common difference of 4. The second sequence is geometric
because there is a common ratio of 3.

Answers

Answer:

the sequence is geometric sequence with common ratio (-2).

Option : D is correct.

Step-by-step explanation:

In this question table is given as

n          1          2         3           4            5

f(n)     48       -96      192      -385       768

We have to find out if the sequence is arithmetic or geometric.

For Arithmetic sequence :

Difference should be common in each term of fees.

common difference  = f(2) - f(1)

= -96 -48 = -144

similarly  = f(3) - f (2) = 192 + 96 = 288

Here,  ≠  so the sequence is not an arithmetic sequence.

For Geometric sequence :

Ratio  should be common in each term of f(n)

Common ratio  =

Therefore, the sequence is geometric sequence with common ratio (-2).

Option : D is correct.

how many ways are there to choose a president, vice president, and treasurer of a 7- member club, if no person can hold more than one oce?

Answers

There are 210 ways to choose a president, vice president, and treasurer for a 7-member club, with no person holding more than one office. Each position can be filled by a different member, resulting in 210 unique combinations.

To determine the number of ways to choose the three positions, we can use the concept of permutations. The president can be selected from the 7 members in 7 different ways. Once the president is chosen, there are 6 remaining members to choose from for the position of vice president. Therefore, there are 6 choices for the vice president. Finally, the treasurer can be chosen from the remaining 5 members.

To calculate the total number of ways, we multiply the number of choices for each position:

7 * 6 * 5 = 210.

Hence, there are 210 ways to choose a president, vice president, and treasurer from a 7-member club, with the condition that no person can hold more than one office.

In summary, the answer is that there are 210 ways to select the president, vice president, and treasurer for the 7-member club, with each member occupying only one position.

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Ms. Padilla is ordering art supplies for 90 students. She
orders 8 jars of paint for every 5 students and 10 sketch
pads for every 3 students.
Determine whether each statement about Ms. Padilla's order is true or false.
Select True or False for each statement.
Ms. Padilla orders 40 sketch pads.
O True
O False
оо
Ms. Padilla orders 144 jars of paint.
O True
O False
The ratio of sketch pads to jars of paint in Ms. Padilla's order can be written as
25 : 12
O True
O False
The ratio of jars of paint to sketch pads in Ms. Padilla's order can be written as
4:5.
o
O True
O False

Answers

1. True
2. False
3. False
4. True

Answer:

1. False

Sketch pads ordered: 10(90/3) = 10×30 = 300

2. True

Painting jars ordered: 8(90/5) = 8×18 = 144

3. True

(25×12)/(12×12) = 300/144

or

25/12 = 300/144 = 2.083..

4. False

Since the previous statement isn't 5:4 and it's true, then this statement is false.

Determine the number of ways 7 books can be arranged on a shelf if a) there are no restrictions?

Answers

The number of ways seven books can be arranged on a shelf if there are no restrictions is 7! = 5040.Why? As there are no restrictions, any of the seven books can occupy any of the seven places on the shelf. Therefore, there are 7 ways to place the first book. After the first book has been placed, there are 6 ways to place the second book (as one place is now occupied).Then, after the first and second books have been placed, there are 5 ways to place the third book (since two places are now occupied). Similarly, there are 4 ways to place the fourth book after the first four have been placed. There are 3 ways to place the fifth book after the first five have been placed.

There are 2 ways to place the sixth book after the first six have been placed. There is only one way to place the last book after the first six have been placed.

So, using the Multiplication Principle, the number of ways 7 books can be arranged on a shelf is:7 × 6 × 5 × 4 × 3 × 2 × 1 = 5040.

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Classify the following non-identity isometries of R? If the isometry is not unique, justify all possibilities. (a) Let / be an isometry, without fixed points, given by a reflection followed by a glide reflection (b) Let y be an isometry that fixes two points, g(P) = P and 9(Q) = Q.

Answers

(a) The non-identity isometry given by a reflection followed by a glide reflection can be classified as a translation. In Euclidean geometry, any reflection followed by a glide reflection is equivalent to a translation in a specific direction.

(b) The non-identity isometry that fixes two points can be classified as a rotation. In Euclidean geometry, any isometry that fixes two distinct points is a rotation about the midpoint between those two points.

(a) Let's denote the reflection as R and the glide reflection as G. If G is applied after R, we have GR. Since the isometry does not have any fixed points, GR cannot be a reflection or a translation. Therefore, the only possibility left is that GR is a glide reflection. However, in Euclidean geometry, a glide reflection is equivalent to a translation. Hence, the non-identity isometry in this case is a translation.

(b) Since the isometry fixes two points P and Q, let's denote the isometry as F. Fixing two distinct points implies that the isometry must be a rotation about the midpoint between those two points. Therefore, the non-identity isometry in this case is a rotation.

In summary, the non-identity isometry in (a) is a translation, and the non-identity isometry in (b) is a rotation.

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Given that is a random variable having a Poisson distribution, compute the following: (a) P(x = 1) when μ = 3.5 -0 P(x) = (b) P(x ≤ 9)when μ = 6 P(x) = (c) P(x > 2) when μ = 3 P(x) = (d) P(x < 1) when μ = 2.5 P(x) =

Answers

P(x < 1) = 0.082085.

The given parameters are μ and x. The mean and variance of the Poisson distribution are μ and σ^2 = μ.The probability that the random variable X takes on the value x is given by P(x).P(x=1) when μ = 3.5

Here, x = 1 and μ = 3.5Plug in the given values in the Poisson distribution,

P(x = 1) = ((e^-3.5) (3.5^1))/1!P(x = 1) = ((0.0301974) (3.5))/1!P(x = 1) = 0.105691(1)P(x = 1) = 0.105691

Thus, P(x=1) = 0.105691.P(x ≤ 9)when μ = 6. The given parameters are μ and x. The mean and variance of the Poisson distribution are μ and σ^2 = μ.

P(x ≤ 9) when μ = 6. Here, x ≤ 9 and μ = 6

Using the Poisson formula:

P(x ≤ 9) = Σ P(x = i) for i = 0 to 9.P(x ≤ 9) = Σ P(x = i) for i = 0 to 9.P(x ≤ 9) = Σ ((e^-6)(6^i))/i! for i = 0 to 9P(x ≤ 9) = 0.091578So,

P(x ≤ 9) = 0.091578P(x > 2) when μ = 3.The mean and variance of the Poisson distribution are μ and σ^2 = μ.P(x > 2) when μ = 3:Here, x > 2 and μ = 3

Using the Poisson formula:

P(x > 2) = Σ P(x = i) for i = 3 to infinityP(x > 2) = Σ ((e^-3) (3^i))/i! for i = 3 to infinityP(x > 2) = 1 - P(x ≤ 2)P(x > 2) = 1 - ((e^-3)(3^0))/0! + ((e^-3) (3^1))/1! + ((e^-3) (3^2))/2!P(x > 2) = 1 - ((0.04978706836)(1))/1 + ((0.04978706836)(3))/1 + ((0.04978706836)(9))/2P(x > 2) = 1 - (0.04978706836 + 0.1493612051 + 0.2240418077)P(x > 2) = 0.5768099198So, P(x > 2) = 0.5768099198.P(x < 1) when μ = 2.5.

The given parameters are μ and x. The mean and variance of the Poisson distribution are μ and σ^2 = μ.P(x < 1) when μ = 2.5:Here, x < 1 and μ = 2.5

Using the Poisson formula:

P(x < 1) = P(x = 0)P(x < 1) = ((e^-2.5) (2.5^0))/0!P(x < 1) = 0.082085P(x < 1) = 0.082085Thus, P(x < 1) = 0.082085.

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Given that X is a random variable having a Poisson distribution, the probability mass function of X is [tex]P(x)=((e^{-\mu})(\mu^{x}))/x![/tex],

x=0,1,2,…

Here, μ is the mean or the expected value of the distribution.

a) P(x=1) when μ=3.5 is 0.1288 (approx.)

b) P(x≤9) when μ=6 is 0.99988 (approx.)

c) P(x>2) when μ=3 is 0.5766 (approx.)

d) P(x<1) when μ=2.5 is 0.0821 (approx.).

Compute the following:

a) P(x=1) when μ=3.5

Calculate probability for random variable by using the probability mass function of X as follows:

[tex]P(x=1)=((e^{-3.5})(3.5^{1}))/1![/tex]

=0.1288 (approx.)

b) P(x≤9) when μ=6

Calculate, [tex]P(x\leq9)= \sum P(x=k)[/tex] from

k=0 to

[tex]9= \sum ((e^{-6})(6^{k}))/k![/tex] from

k=0 to

9=0.99988 (approx.)

c) P(x>2) when μ=3

We are given μ=3. Then,

P(x>2)= 1- P(x≤2)

= 1- (P(x=0)+P(x=1)+P(x=2))

[tex]= 1- (((e^{-3})(3^{0}))/0!+((e^{-3})(3^{1}))/1!+((e^{-3})(3^{2}))/2!)[/tex]

= 0.5766 (approx.)

d) P(x<1) when μ=2.5

Then, P(x<1)=

P(x=0)

[tex]= ((e^{-2.5})(2.5^0))/0![/tex]

= 0.0821 (approx.)

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Please solve these for me will give you brainiest please!!

Answers

2- y= -5

3-  y= 2x

4- y= -4

5- y= 6x,,, 60

6-   -4,,,,,,,,,   36

Please help now
What is the value of A when we rewrite 3^x as A^5x

Answers

Answer:

A=3^1/5

Step-by-step explanation:

3^x = 3 ^ 1/5*3^5x. Basically you need 3^x to equal A^x. A^x is equal to A^5x in this situration. So, multiply 5x to equal 1x. To make 1x you need to multiply the 5x by 1/5. So, the A value is 3, since the whole number in the 3^x has to be equal to the whole number in A^x. Knowing this, we can tell that A must be equal to 3^1/5.

Answer:

3^1/5

The area of the base is 7 cm. What is the surface area of the pyramid?

Answers

Answer: 34.5

Step-by-step explanation:

(Base · Height) ÷ 2 → (2 · 4.5) ÷ 2 = 5.5

5.5 · 5 = 27.5

27.5 + 7 = 34.5

 
A debt of $25,000 is to be amortized over 17 years at a 7% annual interest rate under monthly compounding. What value of monthly payments will achieve this? Please round your numerical answer to the nearest integer dollar.

Answers

After considering the given data we conclude that value of monthly payments will achieve this is $25,000 over 17 years at a 7% annual interest rate under monthly compounding is $203.

To evaluate the monthly payments that will amortize a debt of $25,000 over 17 years at a 7% annual interest rate under monthly compounding, we could apply the following steps:
Alter the annual interest rate to a monthly interest rate by applying division of 12. The monthly interest rate is 7% / 12 = 0.5833%.
Alter the number of years to the number of months by multiplying by 12. The number of months is 17 × 12 = 204.
Apply the formula for the monthly payment on an amortized loan:
[tex]P = (r * PV) / (1 - (1 + r)^{(-n))}[/tex]
Here,
P = monthly payment,
r = monthly interest rate,
PV = present value of the loan (which is $25,000),
n = total number of payments (which is 204).
Placing in the values, we get:
[tex]P = (0.005833 * 25000) / (1 - (1 + 0.005833)^{(-204))} = $202.91[/tex]
Hence, the monthly payments that will amortize the debt of $25,000 over 17 years at a 7% annual interest rate under monthly compounding is $203 (rounded to the nearest dollar).
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The Fast Repair Shop charges a $25 fee plus $30 an hour for labor. Write the equation for the cost of the repair job, y, if the repair job took x hours.​

Answers

Answer:

y=30x+25

Step-by-step explanation:

y=mx+b (slope-intercept formula)

y= amount of money per hour of labor

m= 30 (amount per hour, slope)

b= 25 (y-intercept, starting rate)

A bus route takes about 45 minutes. One driver's times for 9 runs of the route are shown.
Times to Complete Bus Router (min)
44.6 44.8 45.0 44.7 44.6 44.9 44.8 44.8 45.0
Calculate the mean of the bus times.
The mean time for this driver to complete the route was
minutes.

Answers

You need to add all the numbers(358.4) and then divide by the total amount of numbers not counting 45 twice(8) and the answer is 44.8

why did the german soilders let the prisoners sing while they were marching? PLSSS HELP ILL MARK BRAILIEST. if u give a link i will not so don’t even try :). pls help!!!!

Answers

They had to sing songs of symbolic value.

w
Which value of x would make ASUV 2 ATUN by HI?
S
(4X-1
O 2
03
O 4
05
2x + 9

Answers

Answer:

fourth answer choice) 5

Step-by-step explanation:

2x + 9 = 4x - 1

9 = 2x - 1

10 = 2x

5 = x

x = 5

I would appreciate Brainliest, but no worries.

The value of x that would make ASUV = ATUN by HL is 4, the correct option is C.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

We are given that;

SUV congruent to TUV

Now,

To solve for x in the equation 2x+9=4x+1, we need to isolate x on one side of the equation.

First, we can simplify both sides by subtracting 2x from each side:

2x+9-2x=4x+1-2x

Simplifying this gives us:

9=2x+1

Next, we can subtract 1 from each side:

9-1=2x+1-1

Simplifying this gives us:

8=2x

Finally, we can divide both sides by 2:

8/2=2x/2

Simplifying this gives us:

4=x

Therefore, by the algebra the answer will be x=4.

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Find the quadratic least squares approximation to the function f(x) = = e* on (0,2).

Answers

The quadratic least squares approximation to f(x) = eˣ on the interval [0,2] is g(x) = (e - 1)x + 1.

Let's choose x = 0, x = 1, and x = 2.

The corresponding y-values will be y = f(0) = e⁰ = 1,

y = f(1) = e¹ = e, and

y = f(2) = e².

Now, we can set up a system of equations using the chosen data points and solve for the coefficients a, b, and c:

For x = 0:

a(0)² + b(0) + c = 1

c = 1

For x = 1:

a(1)²+ b(1) + c = e

a + b + c = e

For x = 2:

a(2)² + b(2) + c = e²

4a + 2b + c = e²

Substituting c = 1 from equation 1 into equations 2 and 3, we have:

a + b + 1 = e

4a + 2b + 1 = e²

Now, we can solve this system of equations to find the values of a and b.

Subtracting equation 2 from equation 3, we get:

4a + 2b + 1 - (a + b + 1) = e² - e

3a + b = e² - e

Substituting b = e - a - 1 into equation 2, we have:

a + (e - a - 1) + 1 = e

e - a = e

a = 0

Substituting a = 0 into equation 2, we get:

b + 1 = e

b = e - 1

Therefore, the quadratic least squares approximation is given by:

g(x) = ax² + bx + c

= (0)x² + (e - 1)x + 1

= (e - 1)x + 1

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Astudent was asked to find a 99% confidence interval for the proportion of students who take notes using data from a random sample of size n - 83. Which of the following is a correct interpretation of the interval 0.14 « p<0.342?

Answers

The given confidence interval is 0.14 < p < 0.342, where p represents the proportion of students who take notes. To interpret this interval correctly, we can say:  We are 99% confident that the true proportion of students who take notes lies between 0.14 and 0.342.

In other words, based on the data from the random sample of size 83, we estimate that the proportion of students who take notes falls within this range with a 99% level of confidence. This means that if we were to take multiple random samples of the same size and calculate confidence intervals, approximately 99% of those intervals would contain the true proportion of students who take notes.

Furthermore, the interval does not include the value of 0.5, which represents no preference or a 50% proportion. Since both 0.14 and 0.342 are less than 0.5, we can infer that the data suggests that a substantial proportion of students take notes, but we cannot conclude with certainty whether the majority or minority take notes without further information.

It's important to note that the interpretation assumes the random sampling method was appropriate and the sample is representative of the population of interest.

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Write a polynomial of least degree with roots 2 and – 7

Answers

Answer: x^2+5x-14

Step-by-step explanation:

2 and -7 are the roots of the polynomial then we have to write them as

 x=2 ,x=-7

To convert these as factors, we have to write them as

(  x-2) (x+7)

The product of those factors will give the polynomial. Because we have two factors, we will get a quadratic polynomial.

x^2+7x-2x-14

x^2+5x-14

Number of factors  =  Highest exponent of the polynomial

Answer:

y = x² + 5x - 14

Step-by-step explanation:

Given roots x = a, x = b, then the corresponding factors are

(x - a) and (x - b) and the polynomial is the product of the factors

y = (x - a)(x - b)

Here the roots are x = 2 and x = - 7, then the factors are

(x - 2) and (x - (- 7)) = (x + 7), so

y = (x - 2)(x + 7) ← expand using FOIL

y = x² + 5x - 14

fill in the missing justifications to the proof given: lm = np, lp = mn prove: lmn = npl

Answers

The justification for the proof based on the information will be:

lm = np (Given)

lp = mn (Given)

(1) lmn = lm * n

Justification: Associative property of multiplication

(2) lmn = np * n

Justification: Substitute lm = np

(3) lmn = n * np

Justification: Commutative property of multiplication

(4) lmn = npl

Justification: Substitute lp = mn

Therefore, lmn = npl.

How to explain the information

The associative property of multiplication is one of the fundamental properties of arithmetic. It states that the grouping of factors does not affect the result of multiplication.

In other words, when you multiply three or more numbers, you can change the grouping of the factors without changing the product.

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A set H in R² is displayed on the right. Assume the set includes the bounding lines. Determine whether H is a subspace of R² and justify.

Answers

To determine whether set H is a subspace of R², we need to check if H satisfies the three requirements for a subspace: closure under addition, closure under scalar multiplication, and contains the zero vector.

To determine if set H is a subspace of R², we need to check if it satisfies the three properties of a subspace.

Closure under addition: For any two vectors u and v in H, their sum u + v should also be in H. If the lines forming the boundary of H extend infinitely, then any two vectors u and v in H can be added to form a vector that lies within H. Thus, H is closed under addition.

Closure under scalar multiplication: For any vector u in H and any scalar c, the scalar multiple cu should also be in H. Similarly to the closure under addition, if the lines forming the boundary of H extend infinitely, then any vector u in H can be multiplied by a scalar to obtain a vector that lies within H. Hence, H is closed under scalar multiplication.

Contains the zero vector: The zero vector (0, 0) is part of R² and is also part of H since it lies within the boundary of H.

Since H satisfies all three requirements, it is a subspace of R².

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Function notation ? G (x)=x-3 ; find g(-6) .. how do I answer this?

Answers

Answer:

The value of g(-6) will be "-9".

Step-by-step explanation:

The given function is:

⇒  [tex]g(x)=x-3[/tex]

then,

⇒  [tex]g(-f)=?[/tex]

On putting the value "-6" at the place of "x", then we get

⇒  [tex]g(-6) = (-6)-3[/tex]

⇒            [tex]=-6-3[/tex]

⇒            [tex]=-9[/tex]

Thus the above is the correct solution.

whats 3x+2 x 12.
.
.
.
.
.
music recommendations pls (unknown artist pls not like billie e. or lil nas x/ariana g and megan/cardi b/Justin b) Artist like ALI, Kikou/ mafumafu/set it off/K.flay/twice/ASTRO/taemin. artist like them? like name the artist and some of their songs.

Answers

Answer:

sheck wes, sam hunt, mainiac, petty level , lakeyah , doja cat, sawatiee

Step-by-step explanation:

Answer:

NF: Songs are kinda depressing sometimes but he is a really good rapper. Hear clouds

Kid Laroi: Listen to without you.

iann dior: rapper and really good

Mumford and sons: more of slow music but upbeat at the same time

Tracy chapman: She has really good music. Recommend listening to fast car

those are some of my favs

Step-by-step explanation:

Do there exist subspaces S,T, and U of R3 such that SIT, SIU, and T 1 U? If so, provide an example of such an S, T, and U, and prove that SIT, SIU, and T 10. If not, prove why they do not exist.

Answers

There exist no subspaces S, T, and U of R³ such that SIT, SIU, and T∩U.

In order to answer the given question, we first need to understand the definition of subspaces of a vector space.A subspace of a vector space is a subset that meets three requirements:

i) It includes the zero element of the vector space.

ii) It is closed under addition (if u and v belong to the subspace, then u + v is also in the subspace).

iii) It is closed under scalar multiplication (if u is in the subspace and k is a scalar, then ku is also in the subspace).

there exist no subspaces S, T, and U of R³ such that SIT, SIU, and T∩U.

The reason is simple because if T∩U = Ø, then either SIT or SIU will be the trivial subspace {0}.

However, this contradicts the fact that both SIT and SIU have to contain a non-zero vector as they are subspaces that are generated by S, T, and U.

Therefore, it is proven that there exist no subspaces S, T, and U of R³ such that SIT, SIU, and T∩U.

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