Answer:
C
Step-by-step explanation:
Answer:
E
Step-by-step explanation:
E represents the number of moths initially with the darkest wing colour, and the number of these will increase if the moth's predator (hawks) finds it more difficult to locate them, as the moths with the darkest colour wings will be more likely to survive to reproduce so will increase in number (natural selection).
Hope this helps!
help help i need help with my math
Answer:
13
Step-by-step explanation:
Answer:
13
Step-by-step explanation:
48-[(2^2+3)x5]
48-[(4+3)x5]
48-[(7)x5]
48-[35]
13
PLEASE DO WITH STEPS 3, 4 and 5 SOLVE IN RADICAL FORM AND DECIMAL FORM WITH STEPS PLZ WILL MARK AS BRAINLIEST
Answer:
Step-by-step explanation:
3) (21²-6²)½ = 20.1 cm
4) (10²+7²)½ =12.2 cm
5) (6.5²-2.7²)½ = 5.9 cm
Triangle JKL is similar to triangle MNO. Find the measure of side MN. Figures are
not drawn to scale.
L
O
2
J
K
1.4
M
N
0
Answer:
4.2
Step-by-step explanation:
If they're similar, the fraction between their sides need to be equal, so do this:
2/1.4 = 6/MN
6•1.4/2 = MN
MN = 4.2
I NEED HELP FAST WILL GIVE BRAINLIEST #1 AND IF YOU CAN #2
Answer:
Ok
Step-by-step explanation:
So,
What is the first quartile and third quartile of this data set: 34, 34, 36, 39, 50, 41, 45, 47, 40?
Answer:
http://web.mnstate.edu/peil/MDEV102/U4/S36/S363.htmlStep-by-step explanation:
Answer:
First quartile: 35
Third Quartile: 46
Step-by-step explanation:
Maggie has 7 bills, all tens and twenties, that
total $100 in value. Find the number of tens, x, and
the number of twenties, y, that Maggie has.
Answer:
4 tens, 3 twenties
Step-by-step explanation:
4 tens ($40) and 3 ($60) twenties work. I’m sorry I don’t have a formula for it though.
A population of 350 animals has a growth rate of 5% each year. Write an exponential function to model this situation.
Given:
The population of animals = 350
Growth rate = 5% each year.
To find:
The exponential function to model this situation.
Solution:
The general exponential growth model is:
[tex]f(t)=a(1+r)^t[/tex]
Where, a is the initial value, r is the growth rate in decimal and t is the time period.
Substituting [tex]a=350, r=0.05[/tex] in the above formula, we get
[tex]f(t)=350(1+0.05)^t[/tex]
[tex]f(t)=350(1.05)^t[/tex]
Therefore, the required exponential function is [tex]f(t)=350(1.05)^t[/tex], where f(t) is the number of animals after t years.
Alden has two toys. One toy has a mass of 188 grams, and the other has a mass of 127 grams
whats the rest of the question?
Someone help me answer this pls
Answer:
y>-2x-3
Step-by-step explanation:
I think, not sure.
A motorboat travels 9 miles downstream (with the current) in 30 minutes. The return trip upstream (against the current) takes 90 minutes.
Given :
A motorboat travels 9 miles downstream (with the current) in 30 minutes.
The return trip upstream (against the current) takes 90 minutes.
To Find :
The speed of stream and motorboat.
Solution :
Let, speed of stream is u and speed of motorboat is v.
Now, we know distance is same in both case.
Distance( downstream ) = speed × time
[tex]9 = ( v +u ) \times 0.5\\\\v + u = 18[/tex]....1)
Distance( upstream ) = speed × time
[tex]9 = ( v- u ) \times 1.5\\\\v-u = 6[/tex]....2)
Solving equation 1 and 2 , we get :
v = 12 miles/hour and u = 6 miles/hour
Hence, this is the required solution.
Answer:
The speed of the stream is 6 mph, and the speed of the boat is 12 mph.
Step-by-step explanation:
Downstream:
9 miles in 30 minutes (0.5 hour).
9 mi / 0.5 h = 18 mph
Upstream:
9 miles in 90 minutes (1.5 h).
9 mi / 1.5 h = 6 mph
Let s = speed of stream.
The speed of the stream adds to the speed of the boat downstream and is subtracted fromt he speed of the boat upstream.
Let speed of boat be b.
b + s = 18
b - s = 6
Add the equations.
2b = 24
b = 12
b + s = 18
12 + s = 18
s = 6
The speed of the stream is 6 mph, and the speed of the boat is 12 mph.
the volume of a large aquarium is 210 ft. it is 5 ft wide and 6 ft high. what is the length of the aquarium?
Answer:
7
Step-by-step explanation:
210=5×6×x
x is length of aquarium.
210÷(5×6)=7
$/sqrt{9}$
Hello may any of you help me with these two equations I’m having a little hard time thank you =10 points
Answer:
a. 10.08
b. 0.0576
An isosceles triangle has base angles that each measure 42°. Which equation can be used to find z, the measure of the third angle of this isosceles triangle in degrees? \
Answer:
42 + 42 + z = 180
Step-by-step explanation:
Note that:
Base angles in an isosceles triangle are equal in measure.
The sum of angles in a triangle is 180°.
Thus, the equation would be
42 + 42 + z = 180
Find the range of the given data below:
7, 10, 12, 11, 12, 10, 11, 13, 17, 13
Ans: 10
Answer: 10
Step-by-step explanation:
Arranged data
7,10,10,11,11,12,12,13,13,17
Range= Highest value - Lowest Vlue
Highest value=17
Lowest value =7
Range=17-7
Range=10
Answer:
[tex]Answer: 10
Step-by-step explanation:
Arranged data
7,10,10,11,11,12,12,13,13,17
Range= Highest value - Lowest Vlue
Highest value=17
Lowest value =7
Range=17-7
Range=10 [/tex]
hope it is helpful to you
hi! i’ll give brainliest please help
Answer:
third option mechanical weathering
Step-by-step explanation:
in mechanical weathering it breaks the rock into smaller pieces . these smaller pieces are just like the bigger rock , just smaller .
Solve for the value of e.
pls help
Answer:
44
Step-by-step explanation:
the steps are in the pic above
The first number in a pattern is 8. Each following number is found by subtracting 9 from the previous
number
What is the fifth number in the pattern?
Answer:
8,-1,-9,-18,-27,-36
and so on i would think it would be -27
Step-by-step explanation:
Answer:
-28
Step-by-step explanation:
other answer off by one
solve: (x-3)(x+2)=0
answers:
3 and 2
3 and -2
-3 and -2
none of the choices are correct
Answer:
x=3 x=-2
Step-by-step explanation:
(x-3)(x+2)=0
Using the zero product property
x-3 =0 x+2 =0
x=3 x=-2
Answer:
3 and -2
Step-by-step explanation:
x -3 =0
x= 3
x+2 =0
x= -2
simplify
[tex] \sqrt{12} [/tex]
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]\huge\boxed{2\sqrt{3}}[/tex]
»»————- ★ ————-««
Here’s why:
[tex]\boxed{\text{Simplifying the square root of 12}}\\\\\rightarrow\sqrt{12}\\\\\text{4 can be factored out of 12.}\\\\\rightarrow\sqrt{4(3)}\\\\\text{Two '2's can be factored out of 4.}\\\\\rightarrow\sqrt{2*2*3}\\\\\rightarrow\sqrt{2^2(3)}\\\\\text{Pulling out the terms from under the radical...}\\\\\rightarrow\boxed{2\sqrt{3}}[/tex]
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
GIVING BRAINIEST IF CORRECT!!!
Mr. Cohen just got a pool and decided to fill it up using a hose. After a half hour, the pool is filled 1/15 of the way. How much will the pool be filled after 6 hours?
A. 4/5 full
B. 1/30 full
C. 2/5 full
Answer:
C. 2/5 full
Step-by-step explanation:
[tex]\frac{1}{\frac{1}{15} } :\frac{6}{y}[/tex]
y · 1 = 1/15 · 6
y = 0.4
[tex]y=\frac{2}{5}[/tex]
Rosa is a secretary. She works Monday to Friday every week. If she worked a total of 44.5
hours this week, and her regular pay is $11.46 per hour, what is Rosa’s regular pay?
Answer:
$509.97 is Rosa's regular pay
please show your work
Answer:
X is equal to 4
Solve the expression for a=12 , b=6 and c=3
Answer:
48
Step-by-step explanation:
[tex]a = 12, \ b = 6, \ c = 3\\\\b^2 - c^2 + (a+ b+c) = 6^2 - 3^2 + (12 +6+3) = 36-9+21 = 48[/tex]
Answer:
2-12+(++)
b^{2}-1c^{2}+(a+b+c)
b2−1c2+(a+b+c)
Simplify: 1
Eliminate redundant parentheses
2−12+(++)
b^{2}-1c^{2}+(a+b+c)
b2−1c2+(a+b+c)
2−12+++
b^{2}-1c^{2}+a+b+c
b2−1c2+a+b+c
Solution: 2−12+++
b^{2}-1c^{2}+a+b+c
b2−1c2+a+b+c
A triangle PQR is right angled at R, with PQ=80cm and R=60cm. find QR?
pythagorus theorem
Answer:
Solution given:
A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm
and
base[b]PR=60cm.
perpendicular [P]= QR
by using Pythagoras law
h²=p²+b²
80²=QR²+60²
QR²=80²-60²
QR=[tex]\sqrt{2800}[/tex]
QR=20[tex]\sqrt{7}[/tex]=52.9=53cm
QR=53cm.
1/2x9
step by step please
[tex]4.5[/tex] ✅
Step-by-step explanation:
[tex] \frac{1}{2} \times 9 \\ = \frac{1 \times 9}{2} \\ = \frac{9}{2} \\ = 4.5[/tex]
[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]
PLEASE HELP ME AT LEAST ONE OF THESE IF YOU KNOW
Step-by-step explanation:
answer of number 5
length=7cm
breadth=9 cm
height=6 cm
volume=?
we know
v =l×b×h
=7×9×6
=378
so, the volume is 378 cm
Answer:
cone, radius is 3^2 x pi x 7/3 = 65.98
Step-by-step explanation:
Someone please help me out!!
Answer:
4/ 5
cos A = AB/ AC
= 24/ 30
= 4/ 5
that is option A
A ball is launched from a platform. The equation for the ball's height h at time t seconds after launch is h(t)= -16t^2+153.6t +393.12, where h is in feet. What is the initial height of the ball before launch?
Answer:
The initial height of the ball before launch is 393.12 feet.
Step-by-step explanation:
The ball's height ([tex]h[/tex]), in feet, as a function of time ([tex]t[/tex]), in seconds, is represented by [tex]h(t) = -16\cdot t^{2}+153.6\cdot t + 393.12[/tex]. The initial height of the ball before launch is the height of the ball evaluated at [tex]t = 0\,s[/tex]:
[tex]h(0) = -16\cdot (0)^{2}+153.6\cdot (0) + 393.12[/tex]
[tex]h(0) = 393.12\,ft[/tex]
The initial height of the ball before launch is 393.12 feet.
Find the area of the shaded segment VB and length of VB
Answer:
Area of length Vb = 25 square units
Area of segment Vb = 26 square units
Step-by-step explanation:
Area of length Vb = theta/360 * 2πr
Area of length Vb = 120/360 * 2*3.14 * 12
Area of length Vb = 1/3 * 75.36
Area of length Vb = 25 square units
Ares of length Vb is 25.1 sq. units
Area of shaded portion = Area of sector VUB - Area of triangle VUB
Area of sector VUB = theta/360 * πr²
Area of sector VUB = 120/360 * 3.14*144
Area of sector VUB = 1/3 * 452.16
Area of sector VUB =150.72
Area of triangle VUB = r²sintheta
Area of sector VUB = = 12²sin 120
Area of sector VUB = = 144(0.8660)
Area of sector VUB = 124.71
Area of the shaded segment = 150.72 - 124.71
Area of the shaded segment = 26.01
Area of the shaded segment = 26 sq. unitsAnswer:
Area of length Vb = 25 square units
Area of segment Vb = 26 square units
Step-by-step explanation:
Area of length Vb = theta/360 * 2πr
Area of length Vb = 120/360 * 2*3.14 * 12
Area of length Vb = 1/3 * 75.36
Area of length Vb = 25 square units
Ares of length Vb is 25.1 sq. units
Area of shaded portion = Area of sector VUB - Area of triangle VUB
Area of sector VUB = theta/360 * πr²
Area of sector VUB = 120/360 * 3.14*144
Area of sector VUB = 1/3 * 452.16
Area of sector VUB =150.72
Area of triangle VUB = r²sintheta
Area of sector VUB = = 12²sin 120
Area of sector VUB = = 144(0.8660)
Area of sector VUB = 124.71
Area of the shaded segment = 150.72 - 124.71
Area of the shaded segment = 26.01
Area of the shaded segment = 26 sq. units
easy algebra question below first correct answer gets brainliest
Answer:
using pythagoras theorem
h^2=p^2+b^2
h^2=12^2+9^2
h^2=144+81
h^2=225
h=[tex]\sqrt{225}[/tex]
h=15
Step-by-step explanation: