500 people
200 people wearing red shirts
200x15%= 30 people
30 =6% of 500
Bella received 534 texts last year. This was 211 more than her cousin Riley
received. Write an addition equation to find out how many texts Riley received.
Answer:
534 = R + 211
Step-by-step explanation:
So the amount of texts Riley received can be expressed as a variable, and in this case I'll use "R". So we know Bella received 534 texts. and that's 211 MORE than riley. So R+211 should be the as 534. This gives you the equation: 534 = R + 211. and if you want to solve for R, you can subtract 211 from both sides to solve for R
Please answer both
1 and 2
1. 80 sheep when increase in the ratio 5:4 becomes 100 sheep.
2. The perimeter of the shape is : 26cm
What is Perimeter?Perimeter is the outside boundary of a shape.
It is usually calculated by summing up all the length of the sides of that shape.
Analysis:
1. if the sheep is increased in the ratio 5:4
then new number of sheep becomes 5/4 x 80 = 400/4 = 100 sheep
2. The perimeter of the shape is the sum of all the sides of the shape = 7 + 4 + 10 +5 = 26cm
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The original price of a book is x dollars. The book is sold for 10% discount. After that, the increased by 25%
Answer:
assume X dollar is $100
If so then,
$100-10% =$90
Thus,
$90x125%=$112.5
write an equation of the line with the given slope and y-intercept,(4,3) and (0,1)
Answer:
y=1/2x+1
Step-by-step explanation:
First use slope formula.
[tex]\frac{y2-y1}{x2-x1}[/tex]
Plug in the information needed.
[tex]\frac{1-3}{0-4}=\frac{-2}{-4}=\frac{1}{2}[/tex]
The slope is [tex]\frac{1}{2}[/tex].
Now, use point-slope formula.
y-y1=m(x-x1)
Plug in the information needed.
y-3=1/2(x-4)
y-3=1/2x-2
y=1/2x+1
The equation of the line in slope-intercept form is y=1/2x+1.
Hope this helps!
If not, I am sorry.
Consider these functions:
f(x)= 3x - 7
g(x) = + = 1
What is the value of f(g(3))?
OA. -1
О в.
о
OC. 3
OD. 5
The value of the composition of functions f(g(3)) is given by (A) -1.
Here given that the functions are,
f(x) = 3x-7
g(x) = (x+1)/(x-1)
To find the value of g(3) we have to first substitute the value x = 3 in the given function g(x), doing that we get,
g(3) = (3+1)/(3-1) = 4/2 =2
Thus the value of g(3) = 2
Now in order to find the value of composition of functions f(g(3)) we have to substitute the value of x = g(3) = 2 in the given function f(x), doing that we get,
f(g(3)) = f(x = g(3)) = f(x = 2) = f(2) = 3*2-7 = 6-7 = -1
Thus the value of the required composition of functions f(g(3)) is given by -1.
Hence the correct option is given by (A).
The question is incomplete. Find the full content below.
Consider these functions:
f(x) = 3x-7
g(x) = (x+1)/(x-1)
What the value of f(g(3))?
(A) -1
(B) 0
(C) 3
(D) 5
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Complete the proof.
The options are substitution property of equality, multiplication property of equality, distributive property, and definition of property bisector.
The blanks can be filled with definitions of property bisector, Substitution property of equality, and Distributive property, respectively.
What is an angle?When two straight lines or rays intersect at a shared endpoint, an angle is generated. An angle's vertex is the common point of contact. Angle is derived from the Latin word angulus, which means "corner."
The given blanks can be filled as,
The first blank is needed to be filled with the definition of property bisector.The second blank will be filled by the Substitution property of equality.The third blank can be filled with the Distributive property.Hence, the blanks can be filled with definitions of property bisector, Substitution property of equality, and Distributive property, respectively.
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Solve this please.
• Log 2 + log(3/2) + log (4/3) + log (5/4)+ log(6/5) + log (7/6) + log (8/7)
Answer:
[tex]3 \log 2[/tex]
Step-by-step explanation:
Given expression:
[tex]\log 2 + \log \left(\dfrac{3}{2}\right)+\log \left(\dfrac{4}{3}\right)+\log \left(\dfrac{5}{4}\right)+\log \left(\dfrac{6}{5}\right)+\log \left(\dfrac{7}{6}\right)+\log \left(\dfrac{8}{7}\right)[/tex]
[tex]\textsf{Apply the \underline{Log Product Law}}: \quad \log_ax + \log_ay=\log_axy[/tex]
[tex]\implies \log \left(2 \cdot \dfrac{3}{2} \cdot \dfrac{4}{3} \cdot \dfrac{5}{4} \cdot \dfrac{6}{5} \cdot \dfrac{7}{6} \cdot \dfrac{8}{7}\right)[/tex]
Cross out common factors:
[tex]\implies \log \left(\diagup\!\!\!\!2 \cdot \dfrac{\diagup\!\!\!\!3}{\diagup\!\!\!\!2} \cdot \dfrac{\diagup\!\!\!\!4}{\diagup\!\!\!\!3} \cdot \dfrac{\diagup\!\!\!\!5}{\diagup\!\!\!\!4} \cdot \dfrac{\diagup\!\!\!\!6}{\diagup\!\!\!\!5} \cdot \dfrac{\diagup\!\!\!\!7}{\diagup\!\!\!\!6} \cdot \dfrac{8}{\diagup\!\!\!\!7}\right)[/tex]
Therefore:
[tex]\implies \log 8[/tex]
Factor the number: 8 = 2³
[tex]\implies \log 2^3[/tex]
[tex]\textsf{Apply the \underline{Log Power Law}}: \quad \log_ax^n=n\log_ax[/tex]
[tex]\implies 3 \log 2[/tex]
cos theta=8/17. Find tan theta
A. 15/8
B. 15/17
C. 17/15
D. 8/15
Answer:
A) [tex]\frac{15}{8}[/tex]
Step-by-step explanation:
remember Soh Cah Toa!!
[tex]sin=\frac{opposite}{hypotenuse}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent} \\\\cos=\frac{8}{17}\\\\a^2+b^2=c^2\\8^2+b^2=17^2\\64+b^2=289\\b^2=225\\\sqrt{b^2} =\sqrt{225}\\b=15=opposite\\\\tan=\frac{15}{8}[/tex]
Given the following set of data: 3, 4, 5, 6, 8, 9, 9, which measures below have a value of 6? (Check all that apply.)
(1) mode
(2) range
(3) high value
(4) median
Answer:
Range and median
Step-by-step explanation:
Range = 9 - 3 = 6
Median = 6
Mode = 9
GEOMETRY)
Find the area in square miles, of the sector shown below. Round your answer to the nearest whole number. (Enter only a number for your answer.)
(Picture is below) Thank you!
SOLUTION :-
AREA of sector = ( ∆/360° ) × πr²
∆ = given angle , r = radius
hence ,
AREA of sector for given angle
= ( 120°/360° ) × π 12² mi²
= ⅓ × π × 144 = 150.79 mi² = 151 mi² ( rounded off )
________________________________
HOPE IT HELPS
MARK BRAINLIEST!
FOLLOW ME!
Answer:
Sector area = 151 mi²
Step-by-step explanation:
We can use the formula for sector area:
Area = [tex]\frac{\theta}{360} \pi\ r^2[/tex]
where:
θ = central angle (120°),
r = radius of circle (12 mi) .
Substituting these values into the formula:
Area = [tex]\frac{120}{360} \pi\ \times (12)^2[/tex]
⇒ 48 π
⇒ 150.796
≈ 151 mi² (rounded to the nearest whole number)
A book can travel 462 miles on 42 gallons of gasoline how much gasoline will it need to go 275 miles
B)At the end of the summer, Matt had worked a total of 120 hours and earned $125 in tips. Amy had worked a total of 110 hours and earned $230 in tips. If Matt had to buy non-slip shoes for work that were $50, and Amy had to buy clippers for work that were $30, who earned more profit by the end of the summer?
By taking the quotient between the money that they make and the time spent to make that money, see can see that Amy earned more profit.
Who earned more profit by the end?
Here we can define profit as the ratio between the money that they make, and the number of hours that they worked to make that money.
Matt earned $125, and spent $50 on shoes for his work, so he earned $75.
And worked 120 hours for these $75, so his profit per hour is:
M = $75/120 = $0.625
Amy worked for 110 hours, won $230 and spent $30 on clippers, then she won a total fo $200.
Her profit per hour is:
A = $200/110h = $1.82
We can see that Amy earned more profit.
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Can someone help me with this
The measure of angle B = 31 degrees, measure of angle C = 121 degrees, and b = 9. Then a =
nearest tenth.
to the
Answer: 8.2
Step-by-step explanation:
As angles in a triangle add to 180 degrees,
[tex]\angle A=180^{\circ}-121^{\circ}-31^{\circ}=28^{\circ}[/tex]
So, by the Law of Sines,
[tex]\frac{a}{\sin A}=\frac{b}{\sin B}\\\\a=\frac{b \sin A}{\sin B}\\\\a=\frac{9 \sin 28^{\circ}}{\sin 31^{\circ}}\\\\a \approx \boxed{8.2}[/tex]
Giovanna used the calculations below to determine the height of a stack of 7 books that are each 2 and StartFraction 5 over 8 EndFraction inches thick. What was her error?
7 (2 and StartFraction 5 over 8 EndFraction). 7 (2 + StartFraction 5 over 8 EndFraction). 14 + StartFraction 5 over 8 EndFraction. 14 and StartFraction 5 over 8 EndFraction
The error Giovanna made in her calculation is multiplying 7 by 2 and adding with 5/8(step 3)
Fraction
Her calculation:
7 (2 and StartFraction 5 over 8 EndFraction): 7(2 5/8)7 (2 + StartFraction 5 over 8 EndFraction): 7(2 + 5/8)14 + StartFraction 5 over 8 EndFraction: 14 + 5/814 and StartFraction 5 over 8 EndFraction: 14 5/8Her error was multiplying 7 by 2 and adding with 5/8(step 3)
Correct calculation:
7(2 + 5/8)
= 14 + 35/8
= (112+35) /8
= 147/8
= 18 3/8
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The following equations are given:
Equation #1:
Equation #2:
Equation #3:
Equation #4:
a. Is it possible to solve for any of the variables using only Equation #1 and Equation #2? Explain your answer. If possible, solve for the variables using only equations #1 and #2.
b. Is it possible to solve for any of the variables using only Equation #1, Equation #2, and Equation #3? Explain your answer. If possible, solve for the variables using only equations #1, #2, and #3.
c. If you found solutions in part b, do these solutions also hold for Equation #4?
The solution to the variables using equations 1, 2 and 3 is x = 2, y = -1 and z = 3 and the solutions in part b hold for equation 4
Solving the variables using equations 1 and 2There are three variables in the system
To solve the three variables, there must be at least three equations in the system of equations
Hence, the variables cannot be solved because the number of equations is not enough
Solving the variables using equations 1, 2 and 3We have:
3x + z + y = 8
5y - x = -7
3z + 2x - 2y = 15
Make x the subject in (2)
x = 5y + 7
Substitute x = 5y + 7 in (1) and (3)
3(5y + 7) + z + y = 8
15y + 21 + z + y = 8
16y + z = -13
3z + 2(5y + 7) - 2y = 15
3z + 10y + 14 - 2y = 15
3z + 8y = 1
Multiply 16y + z = -13 by 3
48y + 3z = -39
Subtract 3z + 8y = 1 from 48y + 3z = -39
48y - 8y + 3z - 3z = -39 - 1
40y = -40
Divide by 40
y = -1
Substitute y = -1 in x = 5y + 7
x = 5(-1) + 7
x = 2
Make z the subject in 16y + z = -13
z = -13 - 16y
Substitute y = -1
z = -13 - 16(-1)
z = 3
Hence, the solution to the variables using equations 1, 2 and 3 is x = 2, y = -1 and z = 3
Can the solution work for equation 4?We have:
4x + 5y - 2z = -3
Substitute x = 2, y = -1 and z = 3
4(2) + 5(-1) - 2(3) = -3
Evaluate
-3 = -3 --- this is true
Hence, the solutions in part b hold for equation 4
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Missing part of the question
The following equations are given:
Equation #1: 3x + z + y = 8
Equation #2: 5y - x = -7
Equation #3: 3z + 2x - 2y = 15
Equation #4: 4x + 5y - 2z = -3
What statement it’s true
The relationship given in the graph is not function. Option C. is True.
Functions is the relationship between sets of values. e g y=f(x), for every value of x there is its exists in set of y. x is independent variable while Y is dependent variable.
The relationship given in the system is not a function. because the values of y is repeating at certain values of x. And the curve has number of discontinuity.
Thus, from the options given only option c describe the relationship given in the graph is not a function because there more than one value of x corresponding yo y - 2.
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Given u = 3i - 8j and v = -4i + 8j, what is u v?
The sum of the vectors given is -i
Sum of vectorsVectors consists of y and x axis. They are plotted on an xy plane known as the argand diagram.
Given the following vectors
u = 3i - 8j
v = -4i + 8j
Take the sum of the vectors
u + v = (3i - 8j) + (-4i + 8j)
Take the sum to have
u + v = (3i-4i)+(-8j+8j)
u + v = -I
Hence the sum of the vectors given is -i
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Consider the following system of linear inequalities and corresponding graph:
y ≥ 2x - 4
x > -3
y < 5
Which of the following points is a solution to this system of linear inequalities?
a.)
(5,6)
b.)
(-4,5)
c.)
(-3,7)
d.)
(2,0)
7. If 1 || m and n || q, identify any of the following
angles congruent to 6
The angle congruent to ∠6 are ∠8, ∠3, ∠9 and ∠14
How to find congruent angles?When parallel lines are cut by a transversal, angle relationships are formed. They include corresponding , alternate and many more.
L║m
n ║ q
Therefore, the angles congruent to ∠6 by alternate or corresponding relationship are as follows:
∠6≅∠8≅∠3≅∠9≅∠14
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I need help!!!
There are 3 times as many females as males on the maths course at university. What fraction of the course are male?
Give your answer in its simplest form.
The fraction of the course that are male is 1/4
How to determine the fraction?The given parameter is:
Female = 3 * Male
As a fraction, we have:
Female + Male = 1
Substitute Female = 3 * Male in the above equation
3 * Male + Male = 1
This gives
4 * Male = 1
Divide by 4
Male = 1/4
Hence, the fraction of the course that are male is 1/4
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What is the radius of a sector of a circle with the central angle of measure 45 and whose area is 9/8 pi cm^2
A. 9/4
B. 3
C. 8
D 4/3
The radius of the sector of the circle with the given area is: B. 3.
What is the Area of a Sector?Area of sector of a circle = ∅/360 × πr².
Given the following:
Area of sector = 9/8 π cm².
∅ = 45 degrees
Plug in the values into the formula
9/8π = 45/360 × πr²
1.125 = 0.125 × r²
1.125/0.125 = r²
9 = r²
r = 3 cm
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Help please! I'll give brainliest
Answer:
about 18.3 square meters
Step-by-step explanation:
Since the circle has radius 4 meters, the area of the circle is (4^2)π, or 16π square meters, The area of the square is (4√2)^2, or 32 square meters. Subtracting, we have 16π-32, or about 18.3 square meters, for the area of the shaded region.
AREA UNDER A CURVE will mark brainiest
Answer: 3 units²
Step-by-step explanation: The area of a triangle is 1/2 (Bh); 1*1= 1 (1/2)= 1/2 units². For the other shape, I cut it into a square and another triangle. The square area is length times width; 1*1= 1 units². The final triangle is 3*1= 3*1/2= 1.5 units². Lastly you add all the areas together: 1.5+0.5+1= 3 units²
Third
Base
Second
Base
Home Plate
90 ft
First
Base
A baseball field is in the shape of a square. The
distance between each pair of bases along the edge of
the square is 90 feet. What is the distance between
home plate and second base?
451
√2 feet
The distance between the home plate and the second base is 127.3 feet
What is an equation?An equation is an expression that shows the relationship between two or more variables and numbers.
Let x represent the distance between the home plate and the second base. Using Pythagoras theorem:
x² = 90² + 90²
x = 127.3 feet
The distance between the home plate and the second base is 127.3 feet
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The distance between home plate and second base is 2√4050 feet.
In a square, all sides are equal in length.
If the distance between each pair of bases is 90 feet, it means that each side of the square (representing the distance along the edge) is also 90 feet.
Since home plate and second base are opposite corners of the square, they are connected by the diagonal of the square.
In a square, the diagonal forms a right triangle with the sides of the square.
Using the Pythagorean theorem, we can find the length of the diagonal (the distance between home plate and second base):
diagonal² = side² + side²
diagonal² = 90² + 90²
diagonal²= 8100 + 8100
diagonal² = 16200
diagonal =√16200
diagonal = 2√4050 feet.
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IJ=
What is IJ?
Help me please!! Thanks
Answer: 11
Step-by-step explanation:
By the secant-secant theorem,
[tex]5(5+7)=(JK)(15)\\\\60=(JK)(15)\\\\JK=4\\\\\implies IJ=15-4=11[/tex]
I NEED HELP ASAP 15 POINTS!
1) ray
2) line
3) line segment
4) adjacent angles
5) vertical angles
Answer:
1) RAY
2) LINE
3) LINE SEGMENT
4) VERTICAL ANGLES
5) VERTICAL ANGLES
Please help will give Brainly!!!
Using it's concept, the domain of the function in interval notation is given by:
(-4,2).
What is the domain of a function?The domain of a function is the set that contains all possible input values for the function. In a graph, it is the set that contains the values of x.
For this function, x varies between -4 and 2, with an open circle, meaning that -4 and 2 are not part of it, hence the domain is:
(-4,2).
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anybody can help i dont understand U_U
Answer:
A
Step-by-step explanation:
The first picture shows the parent function,
A function assigns a x for only one y.
The inverse is opposite
The inverse assign a y for only one x.
So the answer is the table that swap x and y values.
The coordinates for the parent function are
(0,0)
(2,1)
(4,2)
So the inverse should have
(0,0)
(1,2)
(2,4)
A shows that, so a is the answer
If the numerator and denominator of a fraction are increased and decreased by 1 respectively, then it becomes 12/11 if the numerator and denominator are increased and decreased by 3 respectively then it becomes 14/9 find the fraction.
Answer needed.
Let the numerator be x & denominator be y then,
ATQ,
x+1/y-1=12/11
11x+11=12y-12
11x-12y+11+12=0
11x-12y+23=0....(1)
&
x+3/y-3=14/9
9x+27=14y-42
9x-14y+27+42=0
9x-14y+69=0....(2)
Multiplying eq . 1 by 9 & eq. 2 by 11
We get,
99x-108y+207=0....(3)
99x-154y+759=0....(4)
Subtracting eq. 4 by eq. 3
99x-108y+207=0
99x-154y+759=0
______________
0 + 46y - 552 =0
______________
46y= 552
________
y=552/46
________
y=12
____
putting the value of y in eq. 1,
11x-12y+23=0
11x-12*12+23=0
11x-144+23=0
11x-121=0
11x=121
x=121/11
x=11
So, y = 12 & x = 11 & the fraction is 11/12
ㅤㅤㅤㅤㅤㅤ
ㅤㅤㅤㅤㅤㅤ
-lyricalblues
The area of the given trapezoid is:
10 cm
8 cm
22 cm
O256 cm²
320 cm²
O 128 cm²
13 cm
Answer:
128 cm²Step-by-step explanation:
Area of trapezoid = ½ (a + b) h
½ (22 + 10) 8 =
½ 32 × 8 =
16 × 8 =
128 cm²