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Answer:

V = 603.19 unit^3

or

V = 192π unit^3

Step-by-step explanation:

V = πr^2 *h

V = π(8)^2 *3

V = 603.19 unit^3

or

V = 192π unit^3

Answer:

603.186^3

Step-by-step explanation:

v =  πR2 · h

π8^2 x 3

= 603.186^3

Answer:

48°

Step-by-step explanation:

We solve the above question using circle theorem.

Finding x

The formula is given as

x = 1/2 (150° - 54°)

x = 1/2 (96)°

x = 48°

Answer:

5

Step-by-step explanation:

Answer:

5 centimeters

Step-by-step explanation:

You have to look at where it says 2 inches, and follow the line up to where the red stops and see how many centimeters it crosses

Answer:

radius=6

Step-by-step explanation:

The conic section has focus ( - 1, -3), directrix 2 = 3, then it is a parabola.

For a parabola, the focus and directrix play important roles in determining its shape. The distance between a point on the parabola and the focus is equal to the perpendicular distance between that point and the directrix.

Let's calculate the distances and verify if they are equal:

Distance between the point (2, -7) and the focus (-1, -3):

d₁ = √[(2 - (-1))² + (-7 - (-3))²] = √[9 + 16] = √25 = 5

Distance between the point (2, -7) and the directrix 2 = 3:

d₂ = |y - directrix| = |(-7) - 3| = |-10| = 10

Since d₁ ≠ d₂, we can conclude that the conic section cannot be an ellipse.

In an ellipse, the sum of the distances from any point on the ellipse to the two foci is constant. However, in this case, the distances are not equal.

Similarly, for a hyperbola, the difference between the distances from any point on the hyperbola to the two foci is constant. Since the distances are not equal in this case, we can also rule out a hyperbola.

Therefore, based on the given information, the conic section is a parabola.

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Answer: 22.44

Step-by-step explanation:

Base × Height /2 → (3 × 2.24)/2

3.36 · 4 = 13.44

13.44 + 3²

22.44

Answer:

is D

Step-by-step explanation:

because it just makes more sense and my teacher told me the answer

MJH = 120

Let TJH = x

You’re told MJT is 4 times TJH

So you have 4x + x = 120

Simplify: 5x = 120

Divide both sides by 5:

X = 24

TJH = x = 24 degrees.

JT is a bisector so both TJH and TJA are the same. So TJA is also 24 degrees

So MJA = 120 - 24 - 24 = 72

MJA = 72 degrees

Answer

34MJT

Step-by-step explanation:

did it on edge

Answer:

No

Step-by-step explanation:

a^2 + b^2 = c^2

Since 78 is the largest it will be c.

26^2 + 76^2 = 78^2

676 + 5776 = 6084

6452 does NOT = 6084

Since c^2 is larger it is an obtuse triangle.

Answer: Height of tree = 26 ft

Make a triangle ABC with 40 degrees angle. The shadow is the base of the triangle equals 31 feet.

Base = AC = 31

Perpendicular = CB = ?

Hypotenuse = AB

Using trigonometric equation

tan 40 (deg) = CB / AC

CB = Tan 40 x AC

CB = 0.83909 x 31

CB = 26.011

Thus the height of the tree = 26 ft

Answer: Graph A

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Correct on khan

Answer:

4) -3

Step-by-step explanation:

The minimum y value of this absolute value function is -3

Answer:

a = 18.8

Step-by-step explanation:

With it being a right angle, you can use the pythagorean theorem equation.

[tex]a^{2} + b^{2} =c^{2} \\a^{2} + 18^{2} =26^{2} \\a^{2} +324 = 676\\a^{2} = 676 - 324 \\a^{2} = 352\\a = \sqrt{352} \\a = 18.76 = 18.8[/tex]

The (s - 1)2F(s - 1) - (s - 1) option matches the given function (option B).

Let's go through the options one by one to determine the correct answer.

Option A: s-F(s) - s

This option doesn't match the given function.

Option B: (s - 1)2F(s - 1) - (s - 1)

This option matches the given function.

Option C: (s2 - 1)F(s) - s + 1

This option doesn't match the given function.

Option D: sF(s - 1) - 5 - 1

This option doesn't match the given function.

Option E: (s - 1)F(s - 1) - s

This option doesn't match the given function.

Based on the given function, the correct answer is Option B: (s - 1)2F(s - 1) - (s - 1).

Regarding the second question, the Existence and Uniqueness Theorem guarantees the existence and uniqueness of a solution passing through a given point (x0, y0) only if the function is continuous and satisfies certain conditions. None of the provided options mention the function's continuity or satisfy the conditions for the Existence and Uniqueness Theorem. Therefore, none of the options can be determined as having a unique solution passing through the point (2, 4).

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The degree of precision of a quadrature formula with an error term of 27" (T) is 2.

To understand why the degree of precision is 2, let's first define what the degree of precision means in the context of quadrature formulas. The degree of precision refers to the highest power of x up to which the formula can integrate exactly. In other words, if a quadrature formula has a degree of precision of 2, it means that the formula can integrate exactly all polynomials of degree 2 or lower.

Now, to determine the degree of precision based on the given error term of 27" (T), we need to consider the approximation error. The error term T represents the maximum absolute difference between the exact integral and the approximate integral obtained using the quadrature formula.

In this case, the error term is given as 27" (T). The presence of the quotation mark (") indicates that the error term is measured in arc seconds. This suggests that the error is related to numerical integration over angles or circular arcs.

Since the error term is specified as 27" (T), we can conclude that the error is proportional to the square of the step size used in the quadrature formula. Therefore, the error term is of the order h^2, where h represents the step size.

Since the error term is of order h^2, it implies that the degree of precision is 2. This means that the quadrature formula can provide an exact result for polynomials of degree 2 or lower.

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Let θ be an angle in quadrant iii such that = cosθ − 45, the exact values of csc θ and tan θ are 5/3 and -3/4 respectively.

As an angle θ is in quadrant III, and cosθ = -4/5

To identify the exact value of cscθ and tanθ, we will first calculate the value of sinθ by using the Pythagorean identity

sin²θ + cos²θ = 1

⇒ sin²θ + (-4/5)² = 1

⇒ sin²θ = 1 - (-4/5)² = 1 - 16/25 = 9/25

⇒ sinθ = √(9/25) = 3/5

Now, we can calculate the value of cscθ as

cscθ = 1/sinθ = 1/(3/5) = 5/3

Next, we can estimate the value of tanθ by using the identity

tanθ = sinθ/cosθ= (3/5) / (-4/5) = -3/4

Therefore, the exact values of cscθ and tanθ are

cscθ = 5/3 and tanθ = -3/4.

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We get two solutions where x = 22 and y = 20 and x = 42 and

y = 0 with the objective function value being 420.

Here we are given the objective function to be

z=10x+10y

The constraints given are

6x + 6y ≥ 102

14x − 11y ≥ 88

x + y ≤ 42

Now if we plot the points in a graph we will now have to shade the easible region.

Clearly for the constraint 6x + 6y ≥ 102,

the shaded region would be away from the origin.

similarly for the constraint 14x − 11y ≥ 88,

the shaded region will be away from the origin.

and for the last constraint, x + y ≤ 42

this will be similar to the objective function and the shaded region will be towards the origin.

Hence we obtain the blue shaded feasible region.

Marking the corner points as A, B, C and D we get

point           coordinates               objective function value

   A                    (11,6)                             110 + 60 = 170

   B                    (17,0)                             170 + 0 = 170

   C                    (22,20)                          220 + 200 = 420

   D                    (42,0)                             420 + 0 = 420

Hence we get two solutions where x = 22 and y = 20 and x = 42 and

y = 0 with the objective function value being 420.

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I think the anwser is c -2 and 9

Answer:

One example of this can be:

P(x) = (3/2)*(x - 4)*(x - 5)*(x - 5)*(x - 6)

Step-by-step explanation:

A quartic equation is a polynomial of degree 4.

Now, remember that for a polynomial of degree n, with leading coefficient A and zeros {x₁, x₂, ..., xₙ}

The polinomial can be written as:

p(x) = A*(x - x₁)*(x - x₂)*...*(x - xₙ)

In this case we know that we have the zeros 4, 5 and 6.

Notice that this is a polynomial of degree 4 but we have 3 zeros, so one of them may be a double one, i will assume that is the 5.

And we have a leading coefficient that we do not know, let's call it A

Then we can write our polynomial as:

P(x) = A*(x - 4)*(x - 5)*(x - 5)*(x - 6)

Now we know that the polynomial passes through the point (7, 18), then:

P(7) = 18 = A*(7 - 4)*(7 - 5)*(7 - 5)*(7 - 6)

With this equation, we can find the value of A.

18 = A*(7 - 4)*(7 - 5)*(7 - 5)*(7 - 6)

18 = A*12

18/12 = A

(3/2) = A

Then our equation can be:

P(x) = (3/2)*(x - 4)*(x - 5)*(x - 5)*(x - 6)

Answer:

c or d sorry if I'm wrong

Step-by-step explanation:

I think it's your d because of the shortest answers and they're the only two that makes sense

Answer:

Step-by-step explanation:

-6*p ---> -6*5=-30

23 - 25<---5*5

p is 5

-30 - (-2)=-28

Answer: The answer is 3

Step-by-step explanation:

Hope this helps you! Have a good day! :)

Answer:

not telling u, imbecil

Step-by-step explanation:

hahhahahahah

Answer:

Slope of line is 0 and intercept is 7 Step-by-step explanation:

Answer : The probability of the given event occurring would be 0.75 or 75%.

Explanation :The given problem states that you ordered eighteen burritos, with nine having hot peppers and nine not having hot peppers. However, the restaurant forgot your order. We are supposed to find the probability of the event happening.

Let the probability of getting a burrito with hot peppers be P(h) and the probability of getting a burrito without hot peppers be P(n).

The total number of burritos ordered is 18.

Thus, P(h) + P(n) = 18. We can assume that all burritos are the same.

Thus, P(h) = 9/18 = 0.5 and P(n) = 9/18 = 0.5.

Therefore, the probability of getting an order that is incorrect would be: 1 - (0.5 * 0.5) = 1 - 0.25 = 0.75 or 75%. Therefore, the probability of the given event occurring would be 0.75 or 75%.

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Answer:

I don't think it is correct.

Step-by-step explanation:

Square root just means half of a number. If you square this number, it just goes back to it's original form, just without the square root sign. But however, You must square the 10 at the end of the equation as well. This solution is not correct.

Answer:

∠ N = 31°

Step-by-step explanation:

The inscribed angle KLN is half the measure of its intercepted arc KL, so

∠ N = [tex]\frac{1}{2}[/tex] × 62° = 31°

Answer:

B:y=|x+2| -3

The graph shows the points throughout the equation