HELP TIMED IS THIS RIGHT?

Answer:

Step-by-step explanation:

Given that:

a)

[tex]f(x,y) = e^{3x} + y^3 - 3ye^x \\ \\ \implies \dfrac{\partial f}{\partial x} = 0 = 3e^{3x} -3y e^x = 0 \\ \\ e^{2x}= y \\ \\ \\ \implies \dfrac{\partial f}{\partial y } = 0 = 3y^2 -3e^x = 0 \\ \\ y^2 = e^x[/tex]

[tex]\text{Now; to determine the critical point:}[/tex]- [tex]f_x = 0 ; \ \ \ \ \ f_y =0[/tex]

[tex]\implies e^{2x} = y^4 = y \\ \\ \implies y = 0 \& y =1 \\ \\ since y \ne 0 , \ \ y = 1, \ \ x= 0\\\text{Hence, the only possible critical point= }(0,1)[/tex]

b)

[tex]\delta = f_xx, s = f_{xy}, t = f_{yy} \\ \\ . \ \ \ \ \ \ \ \ D = rt-s^2 \\ \\ i) Suppose D >0 ,\ \ \ r> 0 \ \text{then f is minima} \\ \\ ii) Suppose \ D >0 ,\ \ \ r< 0 \ \text{then f is mixima} \\ \\ iii) \text{Suppose D} < 0 \text{, then f is a saddle point} \\ \\ iv) Suppose \ D = 0 \ \ No \ conclusion[/tex]

[tex]Thus \ at (0,1) \\ \\ \delta = f_{xx} = ge^{3x}\implies \delta (0,1) = 6 \\ \\ S = f_{xy} = -3e^x \\ \\ \implies S_{(0,1)} = -3 \\ \\ t = f_{yy} = 6y \\ \\[/tex]

[tex]\implies t_{0,1} = 6[/tex]

[tex]Now; D = rt - s^2 \\ \\ = (6)(6) -(-3)^2[/tex]

[tex]= 36 - 9 \\ \\ = 27 > 0 \\ \\ r>0[/tex]

[tex]\text{Hence, the critical point} \ (0,1) \ \text{appears to be the local minima}[/tex]

c)

[tex]\text{Suppose we chose x = 0 and y = -3.4} \\ \\ \text{Then, we have:} \\ \\ f(0,-3.4) = 1+ (-3.4)^3 + 3(3.4) \\ \\ = -28.104 < -1[/tex]

[tex]\text{However, if f (0,1) = 1 +1 -3 = -1 \\ \\ f(0,-3.4) = -28.104} < -1} \\ \\ \text{This explains that} -1 \text{is not an absolute minimum value of f(x,y)}[/tex]

Answer:

FNB bank

Step-by-step explanation:

FNB = 18000 * 0.056* 8 = 8064

Nedbank = 18000*0.066* 6 = 7128

Standard = 18000*0.072*5=6480

FNB is the best choice for Steven

Answer:

LN = 4 units

Step-by-step explanation:

Since M is on LN , then

LN = LM + MN , that is

4x = 3 + x ( subtract x from both sides )

3x = 3 ( divide both sides by 3 )

x = 1

Then

LN = 3 + x = 3 + 1 = 4

The required length of the line LN = 4.

Given that,
Point M is on the line segment LN. Given LN=4x, MN= x, and LM=3,  to determine the numerical length of LN.

The line is a curve showing the shortest distance between 2 points.

LN = LM + MN
4x = 3 + x
4x - x = 3
3x = 3
x = 3 / 3
x = 1

Length of LN
LN = 4x
     = 4 * (1)
     = 4

Thus the required length of the line LN = 4.

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Answer:

Hello your question is poorly written attached below is the complete question

answer :  attached below

Step-by-step explanation:

To Prove: Z is located 2/3 of the distance from each vertex of ΔABC to the midpoint of the opposite side. we will apply ; property of bisecting a line , equality theorem , transitive property and similarity theorem

Attached below is the proof

Answer:

Exact form: p= 3/2

Decimal form: p= 1.5

Mixed Number: p=1 [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Answer:

Equate the divisor to 0

2x-1=0

2×=1

×=1/2

Putting onto the polynomial

f(1/2) = (1/2)³-1/2)²+3(1/2)-2

=-5/8

Answer:

1584mm^2

Step-by-step explanation:

20 x20 = 400 and there are 3 of them

400+400+400 = 1200

1/2(16x24 ) =192 and there are 2 of them

192+192 = 384

1200+384

Answer:

1408

Step-by-step explanation:

20·16+24·16+20·16+12·﹣204+2·(20·24)2+2·(20·20)2﹣244+2·(24·20)2﹣204=1408

if i did something wrong please let me know

(i might have done it wrong, please use the answer above which would be 1584mm^2)

Answer:

15 hours

so, 8 x y = 120

Step-by-step explanation:

[tex]8\sqrt{120} =[/tex] 15

Answer:

The numbers are 6 and 2

6 squared = 36

2 squared = 4

So 36-4 = 32

And 36 x 2 = 72 + 4 = 76

Answer:

7/10

Step-by-step explanation:

Use the butterfly method:

3/5 7/10

multiply the denominator and numerator to each other sides:

3 * 10 = 30

5 * 7 = 35

35 > 30

35 belongs to 7/10 so:

7/10 is greater

Answer:

$43.20

Step-by-step explanation:

20% of $50.00 is $10.00. $50 - $10 is $40. 8% of $40 is $3.20. Since this is tax, you must add it. $40+$3.20 = $43.20

Answer:

O

Step-by-step explanation:

Answer256pi

Step-by-step explanation:

Area=pi*r^2

=pi*16^2

256pi

Answer:

12:45

Step-by-step explanation:

Step One: An hour after 11:20 is 12:20, plus 15 minutes is 12: 35.

Step Two: Just add 10 minutes, because it doesn't matter when you add the ten minutes.

Answer:

85.80

Step-by-step explanation:

85.82 is closet to 85.80 snice 2 is a low number

Answer:

24 square kilometers

Step-by-step explanation:

Well, this is a trapezoid. The formula for the area of a trapezoid is 1/2 the height times base one plus base two. In other words, 1/2 h x (base 1 + base 2)

So in this case, the two bases are 4 and 12. So we would add the two bases to get 16. Now, we have to half the height. 3 divided by 1/2 is 1.5. So we then do the last step which is multiplying the height by the two bases. So in other words, 1.5 times 16. And 1.5 times 16 is 24. Therefore, the answer is 24 sqaure kilometers.

Answer:

Step-by-step explanation:

Answer:

697.5 ft squared

Step-by-step explanation:

Divide into top two squares and rectangle on bottom so...

(10×7.5)+(8×7.5)×(12.5×45)=area

75+60+562.5=697.5 ft squared

Answer:

x=5, y=3

Step-by-step explanation:

7x-11=24: 7x=35: x=5

3(5)+9=8x: 24=8x: x=3

Answer:

17.5

Step-by-step explanation:

The area of a triangle is (height*base)divided by two

(the eight is really unnecessary)

so 7=base

8=height

7*5=35

35/2=17.5

Answer:

>

Step-by-step explanation:

Answer:

c for me

Step-by-step explanation:

hope that helps you

Answer:

Step-by-step explanation:

Answer:

214 seconds

Step-by-step explanation:

3 times 60 is 180. 180 plus 34 is 214.

Answer:

4th one its negative,linear association

Step-by-step explanation:

The option that best describes the relationship between the variables on the scatter plot is negative, linear association.

Variables have a negative association when the line of best fit is downward sloping. Variables have a linear association when the line of best fit is a straight line. Variables have a positive association when the line of best fit is upward sloping.

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Answer: -0.03

sqrt ((0.12 (0.88) / 200) + (0.15)(0.85)/200)

Step-by-step explanation:

The mean of the sampling distribution of the difference in sample proportions is -0.03, and the standard deviation is 0.0321.

A standard deviation (σ) is a measure of the distribution of the data in reference to the mean.

The proportion of lockout help requests in the summer population is 12% or 0.12, and the proportion in the winter population is 15% or 0.15. The sample sizes are both 200.

Using these values, we can calculate the mean and standard deviation of the sampling distribution of the difference in sample proportions:

Mean = p₁ - p₂ = 0.12 - 0.15 = -0.03

Standard deviation = √[ (p₁ (1 - p₁) / n₁) + (p₂ (1 - p₂) / n₂) ]

= √[ (0.12 (1 - 0.12) / 200) + (0.15 (1 - 0.15) / 200) ]

= √[ (0.000504) + (0.000525) ]

= √[ 0.001029 ]

= 0.0321

Therefore, the mean of the sampling distribution of the difference in sample proportions is -0.03, and the standard deviation is 0.0321.

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Answer:

No.

Step-by-step explanation:

Well at first glance it might seem so but there are two points particularly that can tell you that these points cannot be within a function.

The points (3,2) and (3,-2) will yield an undefined slope (a straight vertical line). There is no possibility that the other points can be in this line (as their y - values are different) and there is no possibilty that this is a function at all according to the vertical line test (the test is that if you draw a vertical line that there shouldn't be more than one point on it).

Answer:

633.9 in.²

Step-by-step explanation:

Surface Area = Base Area + ½(Perimeter of Base)(slant height)

Base area = s² = 15.75² = 248.0625 in.²

Perimeter = 4(15.75) = 63 in.

Slant height = 12.25 in.

Surface area = 248.0625 + ½(63)(12.25)

= 633.9375 ≈ 633.9 in.² (nearest tenth)

Answer:

[tex]t \approx 2.639[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccc}{} & {USA\ 1} & {Japan\ 2} & {\bar x} & {64.6} & {67.5} &{n} & {30} & {30} & {\sigma} & {4.0} & {4.5} \ \end{array}[/tex]

See attachment for data

Required

Determine the test statistic

The test statistic is calculated using:

[tex]t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}}[/tex]

So, we have:

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{4.0^2}{30} + \frac{4.5^2}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00}{30} + \frac{20.25}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{16.00+20.25}{30}}}[/tex]

[tex]t = \frac{64.6 - 67.5}{\sqrt{\frac{36.25}{30}}}[/tex]

[tex]t = \frac{-2.9}{\sqrt{1.2083}}[/tex]

[tex]t = \frac{-2.9}{1.099}[/tex]

[tex]t \approx -2.639[/tex]

The absolute value is:

[tex]t \approx 2.639[/tex]