HELP PLEASE!!!!! I need help

Answer:

Slope: 4

Y-interecept: -2

Step-by-step explanation:

To find the slope, use rise over run. Go up from the y-intercept and over until you hit another exact point.

To find the y-intercept, just find the point that is on the y-axis.

Answer:

4500

Step-by-step explanation:

10000 x .09 x 5

Answer:

yes

Step-by-step explanation:

you can times them all by 3

BRAINLIEST PLEASE

Answer:

7 - 7y = -3y - (-6)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Recursive formula is the formula A(n) = A(n - 1) + d

Based on the explicit formula we have:

The common difference is:

The first term is:

So the recursive formula is:

Answer:

See below

Step-by-step explanation:

If we want to reflect across x-axis, we'll change the y-coordinate of the        co-ordinate to it's opposite (If it's negative, it will become positive and vice versa) while the x-coordinate will remain the same.

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

A. 364 yards

Step-by-step explanation:

The distance between two points  [tex]A(x_1,y_1)\ and\ B(x_2,y_2)[/tex] on the coordinate plane is given as:

[tex]|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

The cone W, X, Y and Z form a rectangle.

The perimeter for the rectangle = 2(length +  breadth)

[tex]Length=|WX|=\sqrt{(-38-(-38))^2+(53-(-53))^2}=106 \\\\Breadth=|XY|=\sqrt{(38-(-38))^2+(53-53)^2}=76[/tex]

Perimeter = 2(length + breadth) = 2(106 + 76) = 364 yards

Answer:

18

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Answer:

Ex 1. y= -5.00x + 18.00   Ex 2. y= 0.50x + -1.00

Step-by-step explanation:

(results are in decimal form, rounded to the nearest 100th)

Answer:

2y = x + 2

Step-by-step explanation:

Looking at the graph, we can see from one point to the next (from right to left), the x-value rises by 2 and the y-value by 1;

From this we can work out the gradient between two points using the formula, i.e. the change/difference in y divided by the change/difference in x:

[tex]m = \frac{dy}{dx} = \frac{1}{2}[/tex]

Joining the points gives a straight line, which means a constant gradient of ¹/₂

Use the line equation formula to get the function:

y - y₁ = m(x - x₁)

m = ¹/₂

x₁ = 0

y₁ = 1

y - 1 = ¹/₂.(x - 0)

y - 1 = ¹/₂.x

2y - 2 = x

2y = x + 2

Answer:

The area is 103.7 cm

Step-by-step explanation:

Multiply the base by the height:

15.25 * 6.8 = 103.7

♥

1 goes on the first on -1 goes on the second

- 1/125 goes on the last one and -125 the third one

Answer: depends on how your class is weighted, and specifically how many points the thing is, and your point score.

Step-by-step explanation:

i guess 60%? it's too vague

Answer: x=16 this is the answer without the 2 in the beginning of the equation with the 2 there's no solution

Step-by-step explanation:

Answer:

19

Step-by-step explanation:

Given = 1 (it is the given equation)

Addition property of equality = 2 (you add 2x to both sides)

Division property of equality = 3 (you divided both sides by 6)

[tex]\underline{\underline{\frak{\qquad Given :\qquad}}} \\ [/tex]

[tex]\underline{\underline{\frak{\qquad To\:Find :\qquad}}} \\ [/tex]

[tex]\underline{\underline{\frak{\qquad Solution :\qquad}}} \\ [/tex]

☯ [tex]\underline{\boldsymbol{According\: to \:the\: Question\:now :}}\\[/tex]

[tex]:\implies \sf Perimeter_{(of \: equilateral \: \Delta)} = 3a \\ \\ \\ [/tex]

[tex]:\implies \sf 99 = 3(3x) \\ \\ \\ [/tex]

[tex]:\implies \sf 99 = 9x\\ \\ \\ [/tex]

[tex]:\implies \sf x = \dfrac{99}{9} \\ \\ \\ [/tex]

[tex]:\implies \sf x = 11 \: cm \\ \\ \\ [/tex]

[tex]\bigstar \: \underline{\textsf{The measure of the sides of the equilateral traingle :}} \\ \\ [/tex]

[tex]\dashrightarrow\:\:\sf Side_{(of \: equilateral \: \Delta)} = 3x \\ \\ \\ [/tex]

[tex]\dashrightarrow\:\:\sf Side_{(of \: equilateral \: \Delta)} = 3(11) \\ \\ \\ [/tex]

[tex]\dashrightarrow\:\: \underline{ \boxed{\sf Side_{(of \: equilateral \: \Delta)} = 33 \: cm}} \\ \\ [/tex]

[tex]\therefore\:\underline{\textsf{The measure of the sides of the traingle is \textbf{33 cm}}}. \\ \\ [/tex]

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━

[tex]\underline{\underline{\frak{\qquad Verification :\qquad}}} \\[/tex]

[tex]\longrightarrow\: \sf 99 = 3(3x) \\ \\ \\ \\ [/tex]

[tex]\longrightarrow\: \sf 99 = 3(3 \times 11) \\ \\ \\ \\ [/tex]

[tex]\longrightarrow\: \sf 99 = 3(33) \\ \\ \\ \\ [/tex]

[tex]\longrightarrow\: \underline{ \boxed{\sf 99 = 99}}\\ \\ \\ \\ [/tex]

[tex]\longrightarrow\: \underline{ \boxed{\sf LHS = RHS}}\\ \\ \\ \\ [/tex]

[tex]\underline{\underline{\frak{\qquad Hence, Verified\qquad}}} \\ \\ [/tex]

══════════════════════════════════════════════════

Answer:

If you always give without thinking of receiving something, you will get more than you need later.

-lorraine9fig

Step-by-step explanation:

Yes. I used my own quote.

"Challenges are what make life interesting and overcoming them is what makes life interesting"

-Joshua J. Marine

"Don’t Let Yesterday Take Up Too Much Of Today."

-Will Rogers

“You Learn More From Failure Than From Success. Don’t Let It Stop You. Failure Builds Character.”

– Unknown

“It’s Not Whether You Get Knocked Down, It’s Whether You Get Up.”

–Vince Lombardi

“Failure Will Never Overtake Me If My Determination To Succeed Is Strong Enough.”

– Og Mandino

“We May Encounter Many Defeats But We Must Not Be Defeated.”

– Maya Angelou

“The Only Limit To Our Realization Of Tomorrow Will Be Our Doubts Of Today.”

– Franklin D. Roosevelt

Answer:

1) a = 1 ; b = 5 ; c = 0

2) a = 1 ; b = 3 ; c = 10

3) a = -5 ; b = -7 ; c = 2

4) a = 1 ; b = 2 ; c = -9

5) a = -7 ; b = 6 ; c = -1

6) a = 4 ; b = -10 ; c = -7

Step-by-step explanation:

a , b & c are just coefficients of the equation

Answer: [tex]x^{2}[/tex] =5x=0  

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

it isn't a straight line, so it is nonlinear

The linear relation is y = 0.049x + 8.606 then the value of y is 83. Then the correct option is H.

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

The linear relation is given as

[tex]\rm y - 63 = \dfrac{63-60}{1106-1045} (x - 1106)\\\\y = 0.049x+8.606[/tex]

For x = 1500, then the value of y will be

[tex]\rm y = 0.049\times 1500+8.606\\\\y = 82.37 \approx 83[/tex]

More about the linear system link is given below.

https://brainly.com/question/20379472

Answer:

SAS or Side-Angle-Side

Step-by-step explanation:

Answer:

d can be right answer....

Answer:

3/2 or 1.5

Step-by-step explanation:

[tex]slope = \frac{4 - 1}{5 - 3} \\ \\ = \frac{3}{2} \\ \\ = 1.5[/tex]

Answer:

2.52

Step-by-step explanation:

35 x 7.2 = 2.52 :D

Answer:

The same as the top also thanks for the points and did you get a warning for your last post

Step-by-step explanation:

Answer:

Let us consider the quadrilateral ABCD shown below. 

Let us consider the quadrilateral ABCD shown below. 



In the above quadrilateral, A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4) are the vertices.

To find area of the quadrilateral ABCD, now we have take the vertices A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4) of the quadrilateral ABCD in order (counter clockwise direction) and write them column-wise as shown below. 



Add the diagonal products x1y2, x2y3, x3y4 and x4y1 are shown in the dark arrows.

(x1y2 + x2y3 + x3y4 + x4y1) -----(1)

Add the diagonal products x2y1, x3y2, x4y3 and x1y4 are shown in the dotted arrows.

(x2y1 + x3y2 + x4y3 + x1y4) -----(2)

Subtract (2) from (1) and multiply the difference by 1/2 to get area of the quadrilateral ABCD.

So, area of the quadrilateral ABCD is

=  (1/2) ⋅ {(x1y2 + x2y3 + x3y4 + x4y1)

- (x2y1 + x3y2 + x4y3 + x1y4)}

Problem :

Find the area of the quadrilateral whose vertices are

(-4, -2), (-3, -5), (3, -2) and (2, 3)

Solution : 

Let A(-4, -2), B(-3, -5), C(3, -2) and (2, 3).

Plot A, B, C and D in a rough diagram and take them in counter-clockwise order.



Then,

(x1, y1)  =  (-4, -2)

(x2, y2)  =  (-3, -5)

(x3, y3)  =  (3, -2)

(x4, y4)  =  (2, 3)

Area of triangle ABC is 

=  (1/2) ⋅ {(x1y2 + x2y3 + x3y4 + x4y1)

- (x2y1 + x3y2 + x4y3 + x1y4)}

=  (1/2) x  {[20 + 6 + 9 - 4] - [6 - 15 - 4 - 12]}

=  (1/2) x  {[31] - [-25]}

=  (1/2) x  {31 + 25}

=  (1/2) x  56

=  28

So, area of the given quadrilateral is 28 square units.

In the above quadrilateral, A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4) are the vertices.

To find area of the quadrilateral ABCD, now we have take the vertices A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4) of the quadrilateral ABCD in order (counter clockwise direction) and write them column-wise as shown below. 



Add the diagonal products x1y2, x2y3, x3y4 and x4y1 are shown in the dark arrows.

(x1y2 + x2y3 + x3y4 + x4y1) -----(1)

Add the diagonal products x2y1, x3y2, x4y3 and x1y4 are shown in the dotted arrows.

(x2y1 + x3y2 + x4y3 + x1y4) -----(2)

Subtract (2) from (1) and multiply the difference by 1/2 to get area of the quadrilateral ABCD.

So, area of the quadrilateral ABCD is

=  (1/2) ⋅ {(x1y2 + x2y3 + x3y4 + x4y1)

- (x2y1 + x3y2 + x4y3 + x1y4)}

Problem :

Find the area of the quadrilateral whose vertices are

(-4, -2), (-3, -5), (3, -2) and (2, 3)

Solution : 

Let A(-4, -2), B(-3, -5), C(3, -2) and (2, 3).

Plot A, B, C and D in a rough diagram and take them in counter-clockwise order.



Then,

(x1, y1)  =  (-4, -2)

(x2, y2)  =  (-3, -5)

(x3, y3)  =  (3, -2)

(x4, y4)  =  (2, 3)

Area of triangle ABC is 

=  (1/2) ⋅ {(x1y2 + x2y3 + x3y4 + x4y1)

- (x2y1 + x3y2 + x4y3 + x1y4)}

=  (1/2) x  {[20 + 6 + 9 - 4] - [6 - 15 - 4 - 12]}

=  (1/2) x  {[31] - [-25]}

=  (1/2) x  {31 + 25}

=  (1/2) x  56

=  28

So, area of the given quadrilateral is 28 square units.

The area of the given quadrilateral with vertices at (1,6),(7,6),(1,12),(7,12) is 28 square units.

Let the quadrilateral be ABCD.

Any closed figure made by 4 line segments joined end to end in series is called a quadrilateral.

We need the area of the quadrilateral whose vertices are;

(-4, -2), (-3, -5), (3, -2) and (2, 3)

Let; A(-4, -2), B(-3, -5), C(3, -2) and (2, 3).

Then, we have;

(x1, y1)  =  (-4, -2)

(x2, y2)  =  (-3, -5)

(x3, y3)  =  (3, -2)

(x4, y4)  =  (2, 3)

Area =  (1/2) ⋅ {(x1y2 + x2y3 + x3y4 + x4y1)

- (x2y1 + x3y2 + x4y3 + x1y4)}

=  (1/2) x  {[20 + 6 + 9 - 4] - [6 - 15 - 4 - 12]}

=  (1/2) x  {[31] - [-25]}

=  (1/2) x  {31 + 25}

=  (1/2) x  56

=  28

So,

The area of the given quadrilateral with vertices at (1,6),(7,6),(1,12),(7,12) is 28 square units.

Learn more about quadrilaterals here:

https://brainly.com/question/1365755

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Answer:

Y=-5x+5

Step-by-step explanation:

you just change it negative and if it was a fraction you'd change the sign the opposite still but.... flip the fraction :))