help me with this pls

Answer:

I graphed it on desmos:

Answer:

11 + 13i

Step-by-step explanation:

A must know is that

[tex] \sqrt{i} = - 1[/tex]

Complex numbers

1st: foil the equations

[tex] - 3(1 - 2i) + 7i(1 - 2i)[/tex]

[tex] - 3 + 6i + 7i- 14 {i}^{2} [/tex]

2nd Combine like terms and substitute

[tex]i ^{2} for \: - 1[/tex]

[tex] - 3 + 14 + 13i[/tex]

[tex]11 + 13i[/tex]

Answer:

cos(x-[tex]\frac{pi}{4}[/tex])-2

Step-by-step explanation:

The function is cos(x).

The horizontal shift is caused by (x- pi/4) so it would go to the right a distance of pi/4. If it was positive the entire thing would go left (x + pi/4).

The vertical shift is caused by the negative 2. Unlike horizontal shifts, negative moves it down and positive moves it up.

The x-axis is in radians. Desmos has option to change it to radian.

Answer:

x = 29

Step-by-step explanation:

Take the smallest integer as x. The next one as (x+1) and the last one as (x+2)

x + (x+1) + (x+2) = 90

x + x + x + 3 = 90

3x = 87

x = 29

Hence, x = 29

Hope this helps out. Feel free to mark me as brainliest! :)

[tex]v = \frac{2}{3} \pi {r}^{3} [/tex]

[tex]v = \frac{2}{3} \times \pi \times {1.5}^{3} [/tex]

[tex]v = 7.07 \: {cm}^{3} [/tex]

[tex]v = \pi {r}^{2} h[/tex]

[tex]v = \pi \times {1.5}^{2} \times 4[/tex]

[tex]v = 28.27 \: {cm}^{3} [/tex]

[tex]v = 7.07 + 28.27[/tex]

[tex]v = 35.34 \: {cm}^{3} [/tex]

Hence, the volume of the given compound shape is 35.34 cubic centimeters.

v of hemisphere:

2/3 pi r^3

v of cylinder:

pi r^2 h

total:

add both the value

apply the formula and try

This is a matched pairs design because both types of tread were randomly assigned to each vehicle.

The term matched pairs design has to do with the situation in which participants are randomly assigned to an experiment or a control group. For each participant assigned to an experimental group, another is assigned to the control group.

Thus, this is a matched pairs design because both types of tread were randomly assigned to each vehicle.

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[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond[/tex]      

      ➪  What is the quotient of 7 and the difference of a number and 8?

[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond[/tex]

         ➪ First, the word "quotient" indicates that we divide.

   ✳︎ Here, we are asked to divide 7 by the difference of a number and 8.

➪ The word "difference" indicates that we subtract.

        ✳︎ Here, we are asked to subtract  a number minus 8.

Let the number be x.

Since the difference of x and 8 means we subtract x minus 8, this expression looks as follows:-

         [tex]\texttt{x-8}[/tex]

  ◈     Now, we are also asked to find the quotient of 7 and the difference of a number and 8, which equals [tex]\bold{x-8}[/tex].

As I said earlier, the "quotient" means we divide, so we divide 7 by [tex]\bold{x-8}[/tex].

So we conclude that the expression is:-

7÷(x-8)

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Answer:

domain: all real numbers (-∞,∞)

range: y ≤ 64

Step-by-step explanation:

since the domain is arn,

and range is the coordinates

coordniate (top or bottom-most point)

downward facing so the top

(2, 64)

since it is downward facing we use ≤ instead of ≥

y value is 64 (just as x is 2)

your answer is y ≤ 64

hope this helps:)

Answer:

[tex]D=[x E R | {x = \infty} ][/tex]

[tex]R = [yER| y\leq 64][/tex]

Step-by-step explanation:

1) Identify whether the [tex]x[/tex] and [tex]y[/tex] values are continuous

2) Since [tex]x[/tex] will continue below the [tex]x[/tex]-axis, it will approach infinity.

   Therefore [tex]D=[x E R | {x = \infty} ][/tex]

3) Since [tex]y[/tex] ONLY continues below 64, [tex]R = [yER| y\leq 64][/tex]

This is a 3-D container and the dimensional factor is F=3.  The volume increases by a factor of 33 = 27.

The answer is 4608 x 27 / 123 = 72

Answer:

-22, -28, -32, -43, 13

Step-by-step explanation:

If it is after the digit 0 it will be less than any number above itself.

Answer:

I don't know it is actually pretty hard! But is this part of the rsm mcp contest

Step-by-step explanation:

The sum of digits of the products is given by S = 176

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

The number 22 multiplied by a 22-digit number that contains only "2"s would result in a number that consists of a string of "4"s.

This is because 2 multiplied by 2 results in 4. Since all the digits in the 22-digit number are "2"s, each digit would multiply by 2 and result in "4".

Therefore, the product of 22 multiplied by a 22-digit number that contains only "2"s would be a 44-digit number consisting of "4"s.

The sum of the digits of a 44-digit number consisting of only "4"s can be calculated by multiplying the digit "4" by the total number of digits, which in this case is 44.

Sum of digits = 4 × 44 = 176

Hence , the sum of the digits of the product would be 176

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Answer:

(0, 2)

Step-by-step explanation:

it right I got 100% on my quiz

And… here are others that are right in the quiz

Identify coordinate point B.

(1, 5)

Identify coordinate point D.

(7, 3)

Identify coordinate point C.

(6, 7)

Hope it helps! :)

The product of the given expression is [tex]\frac{x(x-1)(x-4)}{2(x+4)}[/tex] OR [tex]\frac{x(x^{2} -5x+4)}{2x+8}[/tex] OR [tex]\frac{x^{3} -5x^{2} +4x}{2x+8}[/tex]

From the question, we are to determine the product of the given expressions

The given expressions are

[tex]\frac{x^{2} - 16}{2x+8}\times \frac{x^{3}-2x^{2} +x}{x^{2} +3x-4}[/tex]

[tex]\frac{(x+4)(x-4)}{2(x+4)}\times \frac{(x^{2} -x)(x-1)}{(x-1)(x+4)}[/tex]

[tex]\frac{(x-4)}{2}\times \frac{(x^{2} -x)}{(x+4)}[/tex]
[tex]\frac{(x-4)}{2}\times \frac{x(x-1)}{(x+4)}[/tex]

[tex]\frac{x(x-1)(x-4)}{2(x+4)}[/tex]

OR

[tex]\frac{x(x^{2} -5x+4)}{2x+8}[/tex]

OR
[tex]\frac{x^{3} -5x^{2} +4x}{2x+8}[/tex]

Hence, the product of the given expression is [tex]\frac{x(x-1)(x-4)}{2(x+4)}[/tex] OR [tex]\frac{x(x^{2} -5x+4)}{2x+8}[/tex] OR [tex]\frac{x^{3} -5x^{2} +4x}{2x+8}[/tex]

Learn more on Simplifying fractions here: https://brainly.com/question/27038950

Here is the complete and correct question:

What is the product? StartFraction x squared minus 16 Over 2 x + 8 EndFraction times StartFraction x cubed minus 2 x squared + x Over x squared + 3 x minus 4 EndFraction

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Answer:

A. StartFraction x (x minus 4) (x minus 1) Over 2 (x + 4) EndFraction

Step-by-step explanation:

correct on edge :)

Answer:

h = 20.5 yards

Step-by-step explanation:

Volume of Rectangular Pyramid: lwh/3

492 = (18) * (4) (h) /3

Multiply 3 on both sides

1476 = (18) (4) (h)

1476 = 72h

Flip the equation.

72h = 1476

h = 41/2 or 20.5 yards

See attached for a sketch of some of the cross sections.

Each cross section has area equal to the square of the side length, which in turn is the vertical distance between the curve y = √(x + 1) and the x-axis (i.e. the distance between them that is parallel to the y-axis). This distance will be √(x + 1).

If the thickness of each cross section is ∆x, then the volume of each cross section is

∆V = (√(x + 1))² ∆x = (x + 1) ∆x

As we let ∆x approach 0 and take infinitely many such cross sections, the total volume of the solid is given by the definite integral,

[tex]\displaystyle \int_{-1}^1 (x+1) \, dx = \left(\frac{x^2}2 + x\right) \bigg|_{-1}^1 = \boxed{2} ~~~~ (B)[/tex]

Answer:

i would say satisfied because you broke even. Because then you still work the same as you did, because before that you were breaking even every month. So you are not getting paid any extra

Step-by-step explanation:

The equation of the circle is given as (x-h)² + (y-k)² = r². Then the value of y will be ± √5/3.

A circle can be characterized by its center's location and its radius's length.

Let the center of the considered circle be at (h, k) coordinate.

Let the radius of the circle be 'r' units.

Then, the equation of that circle would be:

(x-h)² + (y-k)² = r²

The equation of the circle has the center at the origin and the radius is one unit. Then we have

x² + y² = 1

The point P = (-2/3, y) lies on the unit circle. Then the value of y will be

(-2/3)² + y² = 1

y² = 1 - 4/9

y² = 5/9

y = ± √5 / 9

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Answer:

the top right (2) answer is probably what you'll want to go for, if this is incorrect then you have my deepest apologies

Step-by-step explanation:

Answer:

100°

Step-by-step explanation:

The triangle is a shape with 3 sides and angles. The value of z from the given figure to the nearest tenth is 3.2

The triangle is a shape with 3 sides and angles

From the given triangle, we will use the expression below to determine the value of z

2.6/sin51= z/sin76

simplify

z = 2.6sin76/sin51
z = 2.5227/0.7771

z = 3.246

Hence the value of z from the given figure to the nearest tenth is 3.2

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Answer:

1. [tex]\normalsize \boxed{\textsf{$4\sqrt{2}\cdot\sqrt{2}$}} \implies \boxed{8}[/tex]

2. [tex]\normalsize \boxed{\textsf{$3\sqrt{7}-2\sqrt{7}$}} \implies \normalsize \boxed{\textsf{$\sqrt{7}$}}[/tex]

3. [tex]\normalsize \boxed{\textsf{$\dfrac{\sqrt{7}}{2\sqrt{7}}$}} \implies \normalsize \boxed{\textsf{$\dfrac{1}{2}$}}[/tex]

4. [tex]\normalsize \boxed{\textsf{$2\sqrt{5}\cdot 2\sqrt{5}$}} \implies \boxed{20}[/tex]

Step-by-step explanation:

The Radical Rules by Lial et al. (2017) state that:

Product rule: [tex]\large \textsf{$\sqrt[n]{a}\cdot\sqrt[n]{b}=\sqrt[n]{ab}$}[/tex]

Quotient rule: [tex]\large \textsf{$\sqrt[n]{\dfrac{a}{b}}=\dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}$}\ \ \textsf{$(b \neq 0)$}[/tex]

1.

[tex]\implies \normalsize \textsf{$4\sqrt{2}\cdot\sqrt{2}$}\\\\\normalsize \implies \textsf{$4\sqrt{2\cdot2}$}\\\\ \implies \normalsize \textsf{$4\sqrt{4}$}\\\\ \implies\normalsize \textsf{$4\cdot 2 = 8$}[/tex]

[tex]\normalsize \boxed{\textsf{$4\sqrt{2}\cdot\sqrt{2}$}} \implies \boxed{8}[/tex]

2.

[tex]\implies \normalsize \textsf{$3\sqrt{7}-2\sqrt{7}$}\\\\ \implies\normalsize \textsf{$(3-2)\sqrt{7}$}\\\\ \implies\normalsize \textsf{$1\sqrt{7}$}\\\\ \implies\normalsize \textsf{$\sqrt{7}$}[/tex]

[tex]\normalsize \boxed{\textsf{$3\sqrt{7}-2\sqrt{7}$}} \implies \normalsize \boxed{\textsf{$\sqrt{7}$}}[/tex]

3.

[tex]\implies \normalsize \textsf{$\dfrac{\sqrt{7}}{2\sqrt{7}}$}\\\\\\ \implies\normalsize \textsf{$\dfrac{1\sqrt{7}}{2\sqrt{7}}$}\\\\\\ \implies\normalsize \textsf{$\dfrac{1}{2}$}\\\\[/tex]

[tex]\normalsize \boxed{\textsf{$\dfrac{\sqrt{7}}{2\sqrt{7}}$}} \implies \normalsize \boxed{\textsf{$\dfrac{1}{2}$}}[/tex]

4.

[tex]\implies \normalsize \textsf{$2\sqrt{5}\cdot 2\sqrt{5}$}\\\\ \implies\normalsize \textsf{$2\cdot2\sqrt{5\cdot5}$}\\\\ \implies \normalsize \textsf{$4\sqrt{25}$}\\\\ \implies \normalsize \textsf{$4\cdot5=20$}\\\\[/tex]

[tex]\normalsize \boxed{\textsf{$2\sqrt{5}\cdot 2\sqrt{5}$}} \implies \boxed{20}[/tex]

Reference:

Lial, M., Hornsby, J., Schneider, D., & Daniels, C. (2017). College Algebra and Trigonometry, Global Edition (6th ed., p. 94).

Answer:18

Step-by-step explanation:

n+r=9

n×r=27

r²=9

n²=36

n+n=12

r+n=9

r+r=6

Answer:

1/8

Step-by-step explanation:

Probability denotes the possibility of something happening. It is a field of mathematics that studies the probability of a random event occurring. From 0 to 1.

the value is expressed.

When a coin is tossed, the chance of it landing on heads is 1/2, and vice versa.

So, we divide 1/2 by the number of times it lands on heads to get 1/4. However, when the second one landed on tails, we must multiply it by 1/2 again, making 1/4 x 1/2 = 1/8.

hope this helps:)

Answer:

you how are doing please study and work hard

Step-by-step explanation:

I don't know what the 3rd fruit is. let's call it an apple.

so,

1 apple + 3 cherries = 3 bananas

1 apple = 3 bananas - 3 cherries

1 banana + 2 cherries = 1 apple = 3 bananas - 3 cherries

5 cherries = 2 bananas

1 apple + 1 banana = (1 banana + 2 cherries) + 1 banana =

= 2 bananas + 2 cherries =

= 5 cherries + 2 cherries =

= 7 cherries

the numbers did not help, as they were wrong.

e.g. if you assume the apple = 5, a cherry = 1 and a banana = 2, you would get 8 = 6 on the first scale.

if you change the apple to a 3, that would make the first scale true (6 = 6), but the second scale wrong (4 = 3).

funny enough, the other answer got 7 nevertheless (but the wrong way - actually 2 mistakes balanced each other out).

it is 7 cherries, though !

the actual numbers would be e.g.

a cherry = 1

then

1 banana = 5/2 = 2.5

1 apple = 3×5/2 - 3 = 15/2 - 6/2 = 9/2 = 4.5

to get whole numbers, we could multiply all by 2 :

cherry = 2

banana = 5

apple = 9

and then the first balance :

9 + 3×2 = 3×5

9 + 6 = 15

15 = 15 correct

the second balance

5 + 2×2 = 9

9 = 9 correct.

Nickel - 5 cents

Dime - 10 cents

Quarter - 25 cents

Judy put in: 50 + 25 = 75 cents

The machine gave back: 10 + 10 + 5 = 25

Subtract the two numbers to find the difference (what the fruit juice cost): 75 - 25 = 50 cents

Answer:

Nickel - 5 cents

Dime - 10 cents

Quarter - 25 cents

Judy put in: 50 + 25 = 75 cents

The machine gave back: 10 + 10 + 5 = 25

Subtract the two numbers to find the difference (what the fruit juice cost): 75 - 25 = 50 cents

Step-by-step explanation:

Answer: [tex]\frac{7}{16}[/tex]

Step-by-step explanation: Distance to school = [tex]\frac{7}{10}[/tex] mile

Distance covered = [tex]\frac{5}{8}[/tex] of [tex]\frac{7}{10}[/tex]

                      = [tex]\frac{5}{8}[/tex] x [tex]\frac{7}{10}[/tex]

                       = [tex]\frac{35}{80}[/tex]

                      = [tex]\frac{7}{16}[/tex]

Answer: C

Step-by-step explanation: