HELP ME PLEASE ECPLAIN WHY

Answer:

Q7) ( 2,-2)

Q8) (- 0.5 , -2)

Step-by-step explanation:

As we have to find the mid-points of the line segments, the line segments will be divided in same ratio i.e. 1:1 (∵ A Mid-point divides a line segment into equal parts )

According to Section formula ,

[tex]( x' , y') = (\frac{mx^2 + nx^1}{m+n} , \frac{my^2+ny^1}{m+n} )[/tex]

where (m,n) are the ratios in which a line segment is divided & ( x¹ , y¹ ) ( x², y²) are the co-ordinates of a line segment.

In Q7 ,

x¹ = 3 , y¹ = -9 , x² = 1 , y² = 5 & m = n = 1

So putting the section formula here gives :-

[tex]( x' , y') = (\frac{1*1 + 1*3}{1+1} , \frac{1*5+1*(-9)}{1+1} ) = ( 2 , -2)[/tex]

In Q8 ,

x¹ = 5 , y¹ = -1 , x² = -6 , y² = -3

So putting the section formula here gives :-

[tex](x' , y') = (\frac{1*(-6) + 1*5}{1+1} , \frac{1*(-3) + 1*(-1)}{1+1}) = ( -0.5 , -2)[/tex]

Step-by-step explanation:

Q3

(a) If 0 < |x − 1| < δ, then |f(x) − 2| < 2

What this means is, how far can x stray from the x=1 line such that f(x) stays within 2 units of the y=2 line (0 < f(x) < 4).

If we move 2 units left of x=1, we get f(x) = 4.

If we move about 3.5 units right of x=1, we get f(x) = 4.

Therefore, δ can't be more than 2.

(b) If 0 < |x| < δ, then |f(x) − 3| < 1

What this means is, how far can x stray from the x=0 line such that f(x) stays within 1 unit of the y=3 line (2 < f(x) < 4).

If we move 1 unit left of x=0, we get f(x) = 4.

If we move 1 unts right of x=0, we get f(x) = 2.

Therefore, δ can't be more than 1.

Since f(x) isn't continuous within this domain, we can't conclude that the limit exists.

Q4

(a) Yes.  If δ = 0.25, then 0.75 < x < 1.25, and f(x) > 200.

(b) No.  f(1) = 300, so even if δ = 0, f(x) will be less than 400.

(c) Yes.  If δ ≈ 0.1, then 0.9 < x < 1, and f(x) > 450.

Answer:

20a + 25b - 15

Step-by-step explanation:

Answer:

 I think is:    

5 ( 4a + 5b - 3 )

= 5 × 4a + 5 × 5b - 5 × 3

= 20a + 25b - 13

Answer:

3 and 6       5and 4

Step-by-step explanation:

Answer:

Step-by-step explanation:

x = 4

3x^2

3(4)^2

3(16)= 48

Answer: 8, 24, and 24 is greater

Step-by-step explanation:

(-4)(-2) = 8

(-8)(-3) = 24

8 < 24

Answer:

-24x²

Step-by-step explanation:

remove the parentheses, multiply the numbers, apply exponent rule and add the numbers

Answer:

x= 3

Step-by-step explanation:

mark me brainliest :)

Answer: C. x = 3

Hope this helps!

Answer:

Step-by-step explanation:

Answer:

true

Step-by-step explanation:

The given statement AB+BC=AC, then AB=BC​ is false for the line segment.

A line section that can connect two places is referred to as a segment.

In other words, a line segment is just part of a big line that is straight and going unlimited in both directions.

The line is here! It extends endlessly in both directions and has no beginning or conclusion.

If AC is the line segment and B is in between AC  somewhere then the given statement AB+BC=AC, then AB=BC​ is not necessarily true.

As the two diagrams below;

Diagram 01) →

Here B is the midpoint of  AC so AB = BC

Diagram 02) →

Here B is not the midpoint of AC so AB ≠ BC

Hence "The given statement AB+BC=AC, then AB=BC​ is false for the line segment".

For more about line segment,

https://brainly.com/question/25727583

#SPJ2

Answer:

Step-by-step explanation:

This is an arithmetic sequence, in which a set number is added to the previous term to get the next term. The number added is figured out by subtracting the 1st term from the 2nd term and the 2nd term from the 3rd term.

Now that we know the number is 3, we can complete the sequence:

4, 7, 10, 13, 16, 19, 22

We will add all the terms up to get 91.

Answer:

6.5

Step-by-step explanation:

|-6.5| = 6.5

Answer:

6.5

Step-by-step explanation:

Answer:

[tex]8\frac{-2x}{-2}=\frac{0}{-2}[/tex]

Step-by-step explanation:

[tex]\left(2a^3b^4c^0\right)^3[/tex]

Cube each portion:

[tex]2^3\left(a^3\right)^3\left(b^4\right)^3\left(c^0\right)^3[/tex]

[tex]8\left(a^3\right)^3\left(b^4\right)^3\left(c^0\right)^3[/tex]

[tex]8a^9\left(b^4\right)^3\left(c^0\right)^3[/tex]

[tex]8a^9b^{12}\left(c^0\right)^3[/tex]

[tex]8a^9b^{12}\times1[/tex]

[tex]8a^9b^{12}[/tex]

Answer:

100

Step-by-step explanation:

cause they its 100

Answer:

14 feet

Step-by-step explanation:

Use the square area formula, A = s², where s is the side length

Plug in the area and solve for s:

A = s²

200 = s²

14 = s

So, each side of the patio is 14 feet

Answer: The answer is D 2,6000.00

Answer:

D

Step-by-step explanation:

Answer:

8.33333333333%

Step-by-step explanation:

50/6

Answer:

12%

Step-by-step explanation:

Answer:

10.8

Step-by-step explanation:

6% of 180 is 10.8

Answer:

2.48 × 10 -6

Step-by-step explanation:

i don't know how to put it, but the negative next to the 6 is small, and high up, and so is the 6

Answer:

x=7

Step-by-step explanation:

because u add the like terms so

3x+2x

which would be

5× so now its

5x+5=12+4x

-4. -4

x+5=12

-5. -5

x=7

Answer:

3

Step-by-step explanation:

By order of PEMDAS, perform math within parentheses first.

[tex](28 - 19) \div 3[/tex]

Continue with PEMDAS

[tex](9) \div 3[/tex]

Now, simply divide

[tex]9 \div 3 = 3[/tex]

Answer:

Substitute (x+4)2−16 ( x + 4 ) 2 - 16 for x2+8x x 2 + 8 x in the equation x2+y2+8x−6y=24 x 2 + y 2 + 8 x - 6 y = 24 . (x+4)2−16+y2−6y=24 ( x + 4 ) 2 - 16 + y 2 ...

Step-by-step explanation:

Answer:

your answer would be C

Step-by-step explanation:

Step-by-step explanation:

He grew 65cm a year??? Omg

I think it is

65cm x 4(years)= 260cm

150.25 + 260= 410.25cm

So, when he was 15 years old he was 410.25cm tall

Answer:

Distance=Speed×Time

When speed is 40 kmph

Distance traveled by car =40×9

=360 km

When speed is 60 kmph

Time taken to complete the journey =

60

360

=6 hours

Answer:

2/3

Step-by-step explanation:

0.6 repeating as a fraction is 2/3

Answer:

The answer is 2/3 or

Step-by-step explanation:

[tex]\frac{2}{3}[/tex]

h=A 6/b or 6 divided b = h