HELP ME OUT NO SCAM OR ELSE!!!! I ONLY GOT 1 MIN!!!! 50 BRAINLY PTS

Answer:

11.2

Step-by-step explanation:

y=-2x

Step-by-step explanation:

it can't be y=2x and y=-½ because it passes by the opposite side of the given graph

Answer:

$5.24 to nearest cent.

Step-by-step explanation:

Price of 2.2 pounds

= 2.38 * 2.2

= $5.236

triangle on right is the same as the triangle on the left

use pythagorean theorem

hypotenuse will give to the sides of the rectangle

a^2 + b^2 = hypotenuse squared

10.4^2 = 108.16

15.3^2 = 234.09

342.25 = hypotenuse squared

take the square root in both sides

hypotenuse = the square root of 342.25 =

18.5

add up the areas of the 2 triangles and rectangle

triangle area is 1/2 times 10.4 times 15.3 =

79.56

2 triangles areas are 159.12

rectangle area is 18.5 × 7 = 129.5

159.12 + 129.5 = 288.62

answer 1 = 288.62

second question:

to get 1 side take the

square root of 702.25 which is

26.5

to get the perimeter

multiply 26.5 by 4 which is

106

answer 2 is choice B 106

Answer:

Step-by-step explanation:

Answer:

A) D) F)

Step-by-step explanation:

A) Since the graph is 10x10, and there are 10 seasons, it makes sense for A) to be an option

D) There is a total of 50 values that will be on the verticle axis, which seems like a fair number when the highest value is 37

F) (Season 8, 30 average points per game)

The height of the kite above the ground to the nearest tenth of a foot is 84.1 ft

The situation forms a right angle triangle.

Therefore, the length of the string is the hypotenuse of the triangle formed.

Hence, using trigonometric ratios,

sin 35 = opposite / hypotenuse

sin 35 = h / 140

cross multiply

h = 140 sin 35

h = 140 × 0.57357643635

h = 80.3007010891

Height of the kite above the ground = 80.3007010891 + 3.75 = 84.0507010891

Height of the kite above the ground = 84.1 ft

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Answer:

the area of ∆ABC = 9

Step-by-step explanation:

[tex]CA=\sqrt{\left( -1-2\right)^{2} +\left( 2-5\right)^{2} } = \sqrt{18} =3\sqrt{2}[/tex]

[tex]CB=\sqrt{\left( 5-2\right)^{2} +\left( 2-5\right)^{2} } = \sqrt{18} =3\sqrt{2}[/tex]

Since CA = CB  then  A(-1,2), B (5,2) and C (2,5) are the vertices of an isosceles triangle.

Area calculation:

Let The point H be the midpoint of side AB

[tex]x_{H}=\frac{-1+5}{2} =2\\y_{H}=\frac{2+2}{2} =2[/tex]

Then

H(2 , 2)

therefore,

[tex]CH=\sqrt{\left( 2-2{}\right)^{2} +\left( 2-5\right)^{2} } =3[/tex]

Finally,

[tex]\text{the area of triangle ABC} =\frac{\text{CH} \times \text{AB} }{2} =\frac{3\times 6}{2} =9[/tex]

Answer: The date tree is 3 times as tall as the lemon tree

Step-by-step explanation:

There are two trees.

Date tree = unknown height

Lemon tree = 8 feet

Equation

? = 3 x 8

We can assume that the 8 in the equation is the height of the lemon tree since it was already given. The equation's purpose is to find the height of the date tree resulting in 3 times 8 which is 24.

If we compare their heights, we can say that the date tree is 3 times taller than the lemon tree since 24 is 3 times greater than 8.

Answer:

The area of a rectangle is 5/4

Step-by-step explanation:

==========================================================

Explanation:

We have five slots which we can label A,B,C,D,E

We start at 8 and count down by 1 each time until all slots are accounted for. Then multiply out those items: 8*7*6*5*4 = 6720

--------------

Another approach is to use the nPr permutation formula.

Plug in n = 8 and r = 5.

[tex]n P r = \frac{n!}{ (n-r)! }\\\\8 P 5 = \frac{8!}{ (8-5)! }\\\\8 P 5 = \frac{8!}{ 3! }\\\\8 P 5 = \frac{8*7*6*5*4*3!}{ 3! }\\\\8 P 5 = 8*7*6*5*4\\\\8 P 5 = 6720\\\\[/tex]

In the second to last line, the "3!" factorial terms cancel out.

We have the string 8*7*6*5*4 show up again to help reinforce the previous section.

Answer:

No

Step-by-step explanation:

15^2+15^2=450 not 900=3^2

Hope this helps! ;-)

Step-by-step explanation:

Equation to find the sum of the first n terms :

[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] x (2[tex]a_{1}[/tex] + (n - 1)d)

- where n is the first n terms

- where [tex]a_{1}[/tex] is the first term in the sequence

- where d is the difference (To find the difference: [tex]a_{1}[/tex] - [tex]a_{2}[/tex])

How to find n for the given sum :

1. Using the previous equation, plug in all the numbers that you know

2. PEMDAS then combine all like terms

3. Distribute what's on the outside to the inside of the parenthesis

4. Move  [tex]S_{n}[/tex] to the other side to make a quadratic equation

5. Solve the quadratic, then use the positive number and round that number (term of numbers that isn't whole isn't possible ig??)

Question 1:

Sum of first 10 terms : [tex]S_{10}[/tex] = [tex]\frac{10}{2}[/tex] ( 2 x 2 + (10 - 1)6)

 [tex]S_{10}[/tex] = [tex]\frac{10}{2}[/tex] (4 + (9)6) = (4 + 54) = 58

 [tex]S_{10}[/tex] = [tex]\frac{10}{2}[/tex] x 58

Answer : 290

Find n for the given sum : 1704 =  [tex]\frac{n}{2}[/tex] x (2 x 2 + (n - 1)6)

distribute 6 into (n-1)

1704 =  [tex]\frac{n}{2}[/tex] x ( 4 + 6n - 6)

combine like terms

1704 =  [tex]\frac{n}{2}[/tex] x ( -2 + 6n )

Distribute  [tex]\frac{n}{2}[/tex] to ( -2 + 6n )

1704 = [tex]\frac{-2n}{2}[/tex] - [tex]\frac{6n^{2} }{2}[/tex]

Simplify fractions and move 1704 to the other side

-3[tex]n^{2}[/tex] - n + 1704 = 0

Use a quadratic calculator to find the answer and use the answer with the whole number

Answer : -24

Question 2:

(i'm just gonna show you the answers for the rest of them-)

Sum of the first 14 terms: 490

Find n for the given sum: 33.65 (I'm gonna round it to 34)

Question 3:

Sum of the first 21 terms: 483

Find n for the given sum: 11.48 (rounded: 11)

Question 4:

Sum of the first 32 terms: -1328

Find n for the given sum: -9.34 (rounded -9)

really hope this helps in any way :D

Answer: 5 hours

Step-by-step explanation:

If 10% of 140 is 14. And if 14 mg of caffeine is leaving per hour then it would take 10 hours to completely leave from ones body, but for half of it to leave it would take 5.

Answer:

A

Step-by-step explanation:

using the rule of logarithms

[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]

[tex]log_{8}[/tex] (x + 9) + 3 = 3 ( subtract 3 from both sides )

[tex]log_{8}[/tex] (x + 9) = 0 , then

x + 9 = [tex]8^{0}[/tex] = 1 ( subtract 9 from both sides )

x = - 8

Answer:

A

Step-by-step explanation:

to find the y- intercept let x = 0 in the equation and solve for y

y = 5(0)² - 17(0) - 12 = 5(0) - 0 - 12 = 0 - 12 = - 12

then the y- intercept is (0, - 12 )

Answer:

[tex]\huge\boxed{\sf (0,-12)}[/tex]

Step-by-step explanation:

[tex]y=5x^2-17x-12[/tex]

y-intercept is the point where x = 0

Put x = 0 in the above equation.

[tex]y=5(0)^2-17(0)-12\\\\y = 0-0-12\\\\y=-12[/tex]

So, y = -12, when x = 0.

Ordered pair = (x,y) = (0,-12)

[tex]\rule[225]{225}{2}[/tex]

Answer:

3/10 of the circumference

Step-by-step explanation:

Take the fraction between the central angle and the total degree measure of the circle, which is 2π.

Step-by-step explanation:

it depends if you use degrees or radians as angle measure.

let's assume degrees.

arcsine is the inverse function of sine.

so, when sin(x) = 1/2, arcsin(1/2) = x

when now x = 2×arcsin(1/2), we get

x = 2×30 = 60°

The distance between Reeta and the school when the cyclists arrive the home for this case is found to be 2 km

You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically. For example, if it is asked to increase some items by 4, then you can add 4 in that item to increase it by 4. If something is, for example, doubled, then you can multiply that thing by 2 and so on methods can be used to convert descriptions to mathematical expressions.

How to find the speed of an object?

If the object is going linearly, and at a constant speed, then the speed of that object is given by the distance it travelled to the time it took to travel that distance.

If the object travelled D distance in T units of time, then that object's speed is

[tex]Speed = \dfrac{D}{T}[/tex]

Given that:

Suppose at time 0 hours, all three people departed from school (on that Monday).

After 't' hours, suppose the cycle gets punctured.

Then, as the cycle was going by 20 km/hour speed, so in 't' hours, it must have covered d kilometres (suppose),

then we get:

[tex]S =\dfrac{D}{T}[/tex]

[tex]20=\dfrac{d}{t}[/tex]

d = 20t

This distance is measured from school. But we know that this distance is 4 km, so we get:

20t = 4

t  =  1 / 4

The remaining 1 km (as the home is 5 km away from school and 4 km is already travelled) is walked by Cyclists. And walking speed is 5 km/hour, so let they take T hours to travel that 1 km walking, then we get:

5 =  1 / T

t = 0.2 hours

So, the total time cyclists took to reach home from school is: 0.2+0.2=0.4 hours

Reeta is walking that whole 5 km.

The time the cyclist reached home, Reeta had walked for 0.4 hours as they had started at the same time, and it took cyclists 0.4 hours to reach home.

Thus, we have:

Time is taken 0.4 hours, speed of Reeta = walking speed= 5 km/hour, then we get:

D = S x T

D = 5 x 0.4 = 2 km

So Reeta was 2 km away from school when cyclists reached home on that Monday.

Thus, the distance between Reeta and the school when the cyclists arrive at the home for this case is found to be 2 km

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Answer:

60

Step-by-step explanation:

1. Calculate area of front surface:

Area of rectangle + Area of smaller rectangle

6*3 + 2*1 = 20

2. then multiply the area by the depth (3)

20 * 3 = 60 cm^3

Answer:

volume = l×b×h = 1.6 × 1.6 × 1.6 = 4.096cm³

The 16% of these students are taller than 66.7 inches and 285 students are between 61.6 and 68.4 inches tall.

It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.

We have:

Mean of 65 inches and a standard deviation of 1.7.

From the graph:

P(X> 66.7) = (13.5 + 2.35 + 0.15)%

P(X> 66.7) = 16%

P(61.6 < X < 68.4) = (13.5 +34 + 34 + 13.5)%  = 95%

= (300×95)/100

= 285 students

Thus, the 16% of these students are taller than 66.7 inches and 285 students are between 61.6 and 68.4 inches tall.

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The Answer is: A. 52/3

The expressions that are differences of perfect cubes from the options given are:

c. 216a⁶ - 27y³

d. 8a¹⁵ - 27

A perfect cube can be described as a number that is gotten when an integer is multiplied by itself three times.

216a⁶ - 27y³ is a difference of perfect cubes because: (6a²)³ - (3y)³.

So also is the expression, 8a¹⁵ - 27.

The difference of perfect cubes are:

c. 216a⁶ - 27y³

d. 8a¹⁵ - 27

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Answer:

C 216a6 - 27y3

D 216a6 - 27y3

Step-by-step explanation:

I took the test on edge. :)

Answer:

103.4 mi to nearest hundredth.

Step-by-step explanation:

This is an application of the Tangent/secant of a Circle theorem.

If h is the distance to the horizon:

h^2 = 2.7 * (3959 + 2.7)

h^2 = 10696.59

h = 103.424 miles.

Answer:

43÷100*2100=903

Step-by-step explanation:

43 devide by 100 because it is a percentage, we always devide percentages by 100. It gives an answer of 0,43.

0,43 multiply by 2100 because we need a cost.