help me on this asap​

Answer:

8:9

Step-by-step explanation: Add 88+11 to get his weight before=99 Pounds. Then you put together the ratio. 88:99.

The GCF for those numbers would be 11, so divide them both by 11, to get a final answer of 8:9

The metaphor and its purpose from the excerpt from "On Beholding the Mountain" is "The heart's flame illustrates the intensity of the writer's emotion".

A metaphor is a figure of speech which is used to compare two things without using "like" or "as", by making the object of the metaphor take on the characteristic of the other thing.

It is also the use of a word or phrase to refer to something that it is not, invoking a direct similarity between the word or phrase used and the thing described but without the words like or as, which would imply a simile.

Therefore, the correct answer is option D; The heart's flame illustrates the intensity of the writer's emotion.

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126 Grams Per Box

Step-by-step explanation:

15 grams of fiber / 5 ounces = 3 grams

3g X 7oz = 21g

21g X 6b = 126g

G - Grams

Oz - Ounces

B - Bars

Answer:

31°

Step-by-step explanation:

As the opposing side and adjacent side of the angle x are given, we need to take the tan ratio of the angle.

=============================================================

Solving :

⇒ tan x° = 9/15

⇒ tan x° = 3/5

⇒ x = tan⁻¹ (0.6)

⇒ x = 31°

The size of the unknown angle "x"

We'll have to check which is the appropriate one from SOHCAHTOA.

In this question we'll have to use tan because opposite and adjacent is given.

[tex]\large\boxed{Formula: tan(A)= \frac{opp}{adj}}[/tex]

Substitute according to the formula.

[tex]tan \: x= \frac{9}{15}[/tex]

We'll have to use tan inverse.

[tex]x={tan}^{-1}(\frac{9}{15})[/tex]

[tex]x=30.96375653[/tex]

[tex]\large\boxed{x=31° }[/tex]

Hence, the size of the unknown angle "x" is 31°

Answer:

ok so i think its a becuase thats wgat i got

Step-by-step explanation:

Answer: [tex]125^{\circ}[/tex]

Step-by-step explanation:

Angles that form a straight angle are supplementary, so:

[tex]m\angle 1+m\angle 2=180^{\circ}\\ \\ 55^{\circ}+m\angle 2=180^{\circ}\\ \\ m\angle 2=\boxed{125^{\circ}}[/tex]

x/7 >= -6

x×1/7 >= -6

x>= -6 ÷ 1/7

x>= -6× 7/1

x>= -6×7/1

x>= -42

Answer:

D. 2x-30

Step-by-step explanation:

7x-5(x+6)

7x-5x-30

2x-30

Answer:

5

Step-by-step explanation:

Spanish: 46

Chinese: 51

Both languages: 46 - 41 = 5

Hope this helps

Answer:

-11 < x < 7

Step-by-step explanation:

x² + 4x < 77

Subtract 77 from both sides

   x² + 4x - 77 < 0

To find the zero points (Roots),

Make x² + 4x - 77 = 0

Now find the factors

         x² + 11x - 7x - 77 = 0

     x(x + 11) - 7(x + 11)   = 0

               (x +11) (x - 7)  = 0

x + 11 = 0            or (x -7) = 0

     x = -11           or        x = 7

So, the solutions of  the inequality is between (-11) and 7

   -11 < x < 7

Answer:

x < –11 or x > 7 is the correct answer!!

Step-by-step explanation:

The answer above this was just slightly wrong. I took the exam and put my answer as option b and got it correct. Here is how I solved it correctly!

To solve the inequality x^2 + 4x > 77, we can factor the quadratic expression as (x - 7)(x + 11) > 0

To determine the solution, we consider the signs of each factor:

(x - 7) > 0 and (x + 11) > 0

This means x is greater than 7 or x is less than -11.

So, the simplified solution to the inequality x^2 + 4x > 77 is:

x < -11 or x > 7

Answer:

  C, A, E, B, D

Step-by-step explanation:

The conversion relations between rectangular and polar coordinates can be used to find the polar coordinate equivalents. Those relations are ...

__

Using the expression for x, this is ...

  r·cos(θ) = 2

  r = 2/cos(θ) . . . . divide by cos(θ)

  r = 2·sec(θ) . . . . use the trig identity

__

From above, this becomes ...

  r² = 36

  r = 6 . . . . . . take the square root

__

From above, this becomes ...

  r² = 2·r·sin(θ)

  r = 2·sin(θ) . . . . . . divide by r

__

Using the above relations, this is ...

  r·cos(θ) = √3·r·sin(θ)

  1/√3 = sin(θ)/cos(θ) . . . . . . divide by √3·r·cos(θ)

  tan(θ) = 1/√3   ⇒   θ = arctan(1/√3)

  θ = π/6

__

From above, this is ...

  r·cos(θ) = r·sin(θ)

  1 = sin(θ)/cos(θ) = tan(θ) . . . . divide by r·cos(θ)

  θ = arctan(1)

  θ = π/4

_____

Additional comment

An equation of the form y = kx defines a line through the origin and through opposite quadrants of the Cartesian plane. Above, we found the equivalent polar equation to be θ = arctan(k). Using the principal branch of the arctangent function, this is the equation of a ray.

However, the tangent function is periodic with period π, so θ = arctan(k)+π is also an equivalent to the rectangular equation. It is the opposite ray, so forms the complete line when joined with the first ray.

The correct answer for the polar coordinates will be C, A, E, B, D

The polar coordinate system is a two-dimensional coordinate system in which a distance from a reference point and an angle from a reference direction identify each point on a plane. The pole is the reference point, and the polar axis is the ray from the pole in the reference direction.

The conversion relations between rectangular and polar coordinates can be used to find the polar coordinate equivalents. Those relations are ...

x = r·cos(θ)

y = r·sin(θ)

x² +y² = r²

x = 2

Using the expression for x, this is ...

r·cos(θ) = 2

r = 2/cos(θ) . . . . divide by cos(θ)

r = 2·sec(θ) . . . . use the trig identity

x²+y²=36

From above, this becomes ...

r² = 36

r = 6 . . . . . . take the square root

x²+y²=2y

From above, this becomes ...

r² = 2·r·sin(θ)

r = 2·sin(θ) . . . . . . divide by r

x=√3y

Using the above relations, this is ...

r·cos(θ) = √3·r·sin(θ)

1/√3 = sin(θ)/cos(θ) . . . . . . divide by √3·r·cos(θ)

tan(θ) = 1/√3   ⇒   θ = arctan(1/√3)

θ = π/6

x=y

From above, this is ...

r·cos(θ) = r·sin(θ)

1 = sin(θ)/cos(θ) = tan(θ) . . . . divide by r·cos(θ)

θ = arctan(1)

θ = π/4

However, the tangent function is periodic with period π, so θ = arctan(k)+π is also equivalent to the rectangular equation. It is the opposite ray, so forms the complete line when joined with the first ray.

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Answer:

93 boxes will be needed.

Step-by-step explanation:

Divide 1570 ÷ 17

This gives the answer 92.35

So 92 boxes won't be enough. 0.35 of a box itsn't helpful in the real world. So you need 93 boxes.

Answer:

i believe the answer is A

Step-by-step explanation:

Step-by-step explanation:

it is not important that the triangle is right-angled.

but the distance between each pair of points is calculated via Pythagoras

c² = a² + b²

with c being the Hypotenuse (baseline opposite of the 90° angle) = distance between the end points, and a and b are the legs (= the x and y coordinate differences of the 2 end points) of the virtual right-angled triangles between each pair of points.

so,

AB² = (6 - -3)² + (-4 - -4)² = 9² + 0² = 81

AB = 9 ft

BC² = (6 - 6)² + (8 - -4)² = 0² + 12² = 144

BC = 12 ft

and now for AC, which is because of the special case of how the main triangle is placed and oriented, the same calculation as with Pythagoras for the main right-angled triangle. but I keep showing you the point distance calculation, because this is what you will need in the future for more general triangle or other shapes calculations :

AC² = (6 - -3)² + (8 - - 4)² = 9² + 12² = 81 + 144 = 225

AC = 15 ft

so, Nasir will need

9 + 12 + 15 = 36 ft

of fencing.

Answer:

10 and 4; and -8 and -5.

Answer:

i = right angle

ii = obtuse angle

iii = straight angle

iv = obtuse angle

v = acute angle

Step-by-step explanation:

an acute angle is an angle less than 90 degrees

an obtuse angle is an angle more than 90 degrees

a right angle is an angle equivalent to 90 degrees (looks like two straight lines perpendicular)

a straight angle is an angle equivalent to 180 degrees (looks like a straight line)

a reflex angle is an angle greater than 180 degrees

so, ...

i = right angle

ii = obtuse angle

iii = straight angle

iv = obtuse angle

v = acute angle

Answer:

This is the i-ready test, you have to try your best because if someone were to give you the answer, that will be cheating. The test provides teachers with a complete picture of student performance relating to their grade level and national norms. So, just try your best so you can get the lessons that are right for you.

(Im just saying but you don't have to listen to me ^^)

Answer: y = 3/5x + 13/5

Step-by-step explanation:

To solve this you would have to use slope-point form Y − y1 = m(x − x1)

In this case, you would plugin your x and y values from your 1 point. It would look something like this. y - 2 = m(x + 1). But now the issue is we don't know our slope, To find out a slope you would use 2 - y1/x2 -x1 which would be 3/5 so, in the end, the equation would look like y - 2 = 3/5 (x + 1). Now solve for Y and your answer would be y = 3/5x + 13/5

The legs of the triangle are 6.91 feet, 7.9 feet, and 10.5 feet.

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

The ratio of the one leg of the right triangle to the other leg of the right triangle must be 8:7.

Let x be one leg and y be another leg. Then we have

x/y = 8/7

   y = 7x/8

Then the greatest length of one leg of the right triangle given the other leg of the right triangle is 10.5 feet will be

 10.5² = x² + (7x/8)²

110.25 = x² + 49x²/64

110.25 = 113x²/64

      x² = 62.44

        x = 7.902

        x ≅ 7.9 feet

Then the other leg will be

y = 7.9 x 7 / 8

y = 6.91

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[tex]\text{The base and height have to be factors of 60, since}\\\\~~~~~~~~\text{Area}= \dfrac{1}{2} \times \text{Base} \times \text{Height}\\\\\implies 30 = \dfrac 12 \times \text{Base} \times \text{Height}\\\\\implies \text{Base} \times \text{Height}= 60[/tex]

[tex]\textbf{Example 1:}\\\\\text{Height} = 6~ cm \\\\\text{Base} = 10~ cm\\\\\text{Area} = \dfrac 12 \times 6 \times 10 = 30~ cm^2\\\\\textbf{Example 2:}\\\\\text{Height} = 5~ cm\\\\\text{Base} = 12~ cm\\\\\text{Area} = \dfrac 12 \times 12 \times 5 = 30~ cm^2\\\\\textbf{Example 3:}\\\\\text{Height} =4~ cm\\\\\text{Base} = ~15 ~cm\\\\\text{Area} = \dfrac 12 \times 15 \times 4 = 30~ cm^2[/tex]

Let's see

Base be B

Height be H

So

The ppossible values are

Answer:

help me to find Xian pleaseee:( i miss him so much:(

sorry for answering Non sense po i hope u understand me ty po!

Answer:

P = 20

Step-by-step explanation:

Hello!

We can solve this by substituting -4 for t.

Remember that any negative number squared is the absolute value of that number squared.

The final evaluation is 20.

Hey there!

Solve for f :

f = 27.9 ✅

> Given expression :

[tex] \displaystyle \frac{f}{9} = 3.1 \\ \\ [/tex]

> Multiply both sides by 9 :

[tex] \displaystyle \frac{f}{9} \times \red{9} = 3.1 \times \red{9} \\ \\ \Longrightarrow \boxed{ \green{f = 27.9}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

Therefore, our answer is f = 27.9

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Answer:

the center is (5,-1) and the radius is 3

Step-by-step explanation:

The graph which shows the function h(x) according to the task content is; Choice B.

It follows from the task content that the function h(x) = f(x)/4.

On this note, it follows that the values of h(x) in each case is one-fourth of the value of f(x).

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Answer:

-3k^3+8k

Step-by-step explanation:

-2k^3-k^3+8k

Combine like terms

-3k^3+8k

Answer: Standard Form: [tex]-3k^3+8k[/tex]

Step-by-step explanation:

[tex]-k*(3k^2-8)=-3k^3+8k[/tex]

Step 1:

[tex]((0 - 2k^3) - k^3) + 8k[/tex]

Pull out like factors, Pulling out like terms:  [tex]8k - 3k^3 = -k[/tex] • [tex](3k^2 - 8)[/tex]

Factoring: [tex]3k^2 - 8[/tex]

Final result:

[tex]-3k^3+8k[/tex]

Answer:

23

Step-by-step explanation:

Given Shane hits 5 HRs out of 100 At-bats,

[tex]\frac{x}{460} = \frac{5}{100} \\\frac{x}{460} (460) = \frac{5}{100} (460)\\x = 23[/tex]

Answer:

[tex] \frac{4}{9} [/tex]

Step-by-step explanation:

[tex]( \frac{16 {}^{ \frac{1}{2} } }{81 { }^{ \frac{1}{2} } }) \\ ( \frac{ {4}^{2 \times \frac{1}{2} } }{9^{2 \times \frac{1}{2} } }) \\ ( \frac{4^{1} }{9 ^{1} } ) \\ \frac{4}{9} [/tex]

[tex]: \: \implies \: \sf{ \bigg( \dfrac{4 {}^{2} }{9 {}^{2} } \bigg) } {}^{ \frac{1}{2} } \\ \\ : \: \implies \: \sf{ \bigg( \dfrac{4 {}^{ \: 2 \times \frac{1}{2} } }{9 {}^{ \: 2 \times \frac{1}{2} } } \bigg) } \\ \\ : \: \implies \: \sf{ \bigg( \dfrac{4 {}^{ \: \cancel2 \times \frac{1}{ \cancel2} } }{9 {}^{ \: \cancel2 \times \frac{1}{ \cancel2} } } \bigg) } \\ \\ : \: \implies \: \sf{ \bigg( \dfrac{4 {}^{ \: 1 }}{9 {}^{ \: 1 } } \bigg) } \\ \\ : \: \implies \: \red{\bf{ \bigg( \dfrac{4 }{9 } \bigg) } }[/tex]

The scale factor of the dilation is 0.5

From the figure, we have the following lengths:

AB = 2

AB' = 1

The scale factor of dilation is then calculated as:

Scale factor = AB'/AB

This gives

Scale factor = 1/2

Evaluate

Scale factor = 0.5

Hence, the scale factor of the dilation is 0.5

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