Help help bell help be math ASAP

Answer:

the answer is in the site faith mate is the same question and in that site have the response np

[tex] {32}^{2x} = 16 ^{2x + 8} \\ = > {2}^{5(2x)} = {2}^{4(2x + 8)} \\ = > {2}^{10x} = {2}^{8x + 32} \\ = > 10x = 8x + 32 \\ = > 10x - 8x = 32 \\ = > 2x = 32 \\ = > x = \frac{32}{2} \\ = > x = 16[/tex]

Answer:

x = 16

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

  1.  x^2 +2x -24 = 0

  2.  x^2 -7x +10 = 0

Step-by-step explanation:

If you look at the factored and expanded forms of a quadratic with solutions p and q, you see ...

  (x -p)(x -q) = x^2 -(p+q) +pq

The x-term coefficient is the opposite of the sum of solutions.

The constant is the product of solutions.

This knowledge lets you write down the standard form equation with no particular effort.

1.  x^2 +2x -24 = 0

2.  x^2 -7x +10 = 0

[tex]\displaystyle{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\boxed{\red{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}\:=\:\dfrac{127\:\sqrt{3}}{6}}}}[/tex]

Step-by-step-explanation:

We have given an expression.

We have to simplify the expression.

The given expression is

[tex]\displaystyle{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:4\:\sqrt{16\:\times\:3}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\boxed{\pink{\sf\:\sqrt{a\:\times\:b}\:=\:\sqrt{a}\:\times\:\sqrt{b}\:}}\:\cdots\sf\:a\:,\:b\:\geq\:0}[/tex]

[tex]\displaystyle{\implies\sf\:4\:\sqrt{16}\:\times\:\sqrt{3}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:4\:\times\:4\:\sqrt{3}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\boxed{\blue{\sf\:\sqrt{\dfrac{a}{b}}\:=\:\dfrac{\sqrt{a}}{\sqrt{b}}\:}}\:\cdots\sf\:b\: > \:0}[/tex]

[tex]\displaystyle{\implies\sf\:16\:\sqrt{3}\:-\:\dfrac{5}{2}\:\times\:\dfrac{\sqrt{1}}{\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:16\:\sqrt{3}\:-\:\dfrac{5}{2}\:\times\:\dfrac{1}{\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:\dfrac{16\:\sqrt{3}\:\times\:2\:\sqrt{3}\:-\:5}{2\:\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:\dfrac{16\:\times\:2\:\sqrt{3}\:\times\:\sqrt{3}\:-\:5}{2\:\sqrt{3}}\:+\:6\:\sqrt{3}} \\ \\\displaystyle{\implies\sf\:\dfrac{32\:\times\:3\:-\:5}{2\:\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]

[tex]\displaystyle{\implies\sf\:\dfrac{8\:\times\:4\:\times\:3\:-\:5\:+\:(\:6\:\sqrt{3}\:\times\:2\:\sqrt{3}\:)}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:-\:5\:+\:(\:6\:\times\:2\:\times\:\sqrt{3}\:\times\:\sqrt{3}\:)}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:-\:5\:+\:(\:12\:\times\:3\:)}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:-\:5\:+\:12\:\times\:3}{2\:\sqrt{3}}} \\ \\ \\ \displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:+\:12\:\times\:3\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{12\:(\:8\:+\:3\:)\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{12\:\times\:11\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{132\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{127}{2\:\sqrt{3}}} \\ \\ \\ \displaystyle{\implies\sf\:\dfrac{127}{2\:\sqrt{3}}\:\times\:\dfrac{\sqrt{3}}{\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{127\:\sqrt{3}}{2\:\times\:3}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{127\:\sqrt{3}}{6}} \\ \\ \\ \displaystyle{\therefore\:\underline{\boxed{\red{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}\:=\:\dfrac{127\:\sqrt{3}}{6}}}}}[/tex]

Answer:

f-1(x) = 1/3x would be the answer

Step-by-step explanation:

Answer:

y= 1/3x

Step-by-step explanation:

inverse function perform the opposite.

3/1 becomes 1/3

Answer:

Step-by-step explanation:

2S₅ - S₅ = 2⁵ - 2⁰

        S₅ = 2⁵ - 1

Sₙ = (bᵃ - 1) / (b - 1)

Answer:

Step-by-step explanation:

90+31=121

180-121=59

Answer:

a=59

basic fact:

angles on a straight line add up to 180

Step-by-step explanation:

we can ignore b for a start

31+90+a=180

121+a=180

121+59=180

a=59

Answer:

630

Step-by-step explanation:

the value of 7 in the tenths place is 70

the value of 7 in the hundredths place is 700

compare 700 and 70

So 700-70 = 630

Answer:

2

Step-by-step explanation:

I got it right bro man my guy I got you

Answer:

answer is ‐10

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

8/6 is also 1 1/3.

(assuming she doesn't include herself in the distribution).

Answer:

2.09

Step-by-step explanation:

And set them up as a function. We could set y equals to each side of it. So if we set y equals to the left-hand. Side we get Y is equal to three has to the X power.

Answer:

Plot a graph of the function y = log (x) and move it by 1 unit to the left.

Plot the graph of the function y = x ^ 2, reflect over the x-axis, and move it 10 units up.

The coordinates of the intersection of the graphs are the solution.

Solution: x=3

I think this your answer you did not really say your answer?????

Answer:

The lines would be parallel.

Step-by-step explanation:

lines with the same slope are parallel.

Answer:

30/5=68x6=48 feet

Step-by-step explanation:

divide the demesions

Answer:

f(x)=x(3/2)

f(4)=4*3/2

6

Answer:

log14=1.146

log18=1.255

Step-by-step explanation:

Use log rules to break up the given logs, to be able to use the information give

Using the product rule, log14 = log(7 x 2) = log7 + log2

Substitute .845 + .301 = 1.146

Using the quotient rule, log18 = log(2 x 3 x 3) = log2 + log3 + log 3

Substite .301 + .477 + .477 = 1.255

The equation in slope-intercept form that represents the situation is y = 3x + 12

A linear equation is on the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

Let x be the calf's age in month and y be the weight.

A calf weighs 18 lbs. when it is 2 months old, and after 8 months it weighs 36 lbs. Hence it can be represented by:

(2, 18) and (8, 36). The equation is given by:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-18=\frac{36-18}{8-2}(x-2) \\\\y=3x+12[/tex]

The equation in slope-intercept form that represents the situation is y = 3x + 12

Find out more on linear equation at: brainly.com/question/14323743

Answer:

x=4

Step-by-step explanation:

you take both equations, and make them equal to each other. so....

5x-6=3x+2 subtract 3x from both sides

2x-6=2 then add 6 to the other side.

2x=8 then divide 8 by 2.

X=8

Answer:

just move the decimal to the right two place, for two zeroes. The answer is 1490.

Step-by-step explanation: Just simply multiply 14.9 by 100.

Answer:

1490.Step-by-step explanation:multiply 14.9 by 100

Answer:

-6

Step-by-step explanation:

y = -2 x -3/2 - 9

3 - 9 = -6

Hey there!

y= -2 (-3/2) - 9

-2(-3/2) = [3]

y = 3 - 9

y = -6

Therefore, your answer is: y = -6

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

the bbc lenth is 19 which i like in my mouth an deven my throayt

Answer: 27

Step-by-step explanation: LCM of 3 and 27 is 27.

Answer:

Step-by-step explanation:

[tex]12000(1+\frac{.12}{4})^{4*45}=2454040.31463\\=2454040[/tex]

Children

Friends

Babies

Lunches

Bikes

Answer:

1, 3, 7

Step-by-step explanation:

4t + 6≤10

4t≤4

t≤1

Therefore, t can either be equal to or greater than 1.

__________________________________________________________

Hope this helps!!

If I am wrong, please tell me, I enjoy learning from my mistakes:)

Answer:

7.2 hours

Step-by-step explanation:

24 · 0.3 = 7.2

Answer:

D) [tex]\left[\begin{array}{cc}-1&2&1&9\end{array}\right][/tex]

Step-by-step explanation:

You basically add the corresponding entries for each row and column:

[tex]\left[\begin{array}{cc}1&-4&3&5\end{array}\right]+\left[\begin{array}{cc}-2&6&-2&4\end{array}\right]=\left[\begin{array}{cc}1+(-2)&-4+6&3+(-2)&5+4\end{array}\right]=\left[\begin{array}{cc}-1&2&1&9\end{array}\right][/tex]

Therefore, option D, [tex]\left[\begin{array}{cc}-1&2&1&9\end{array}\right][/tex], is correct.

Answer:

6:4:3

Step-by-step explanation:

Use 7 to simplify