Hello! So I need help with these neutralization reactions and its fill in the blank. The question asks,
Balance the following neutralization reactions:
_______ HBr + _______ KOH _______KBr + _______H2O

_______ HF + _______ Fe(OH)3 _______FeF3 + ______ H2O

______HCl + _______ Ca(OH)2 _______CaCl2 + ______ H2O

The given molecule is best described as an organic compound especially an alkane.

The organic compounds are those chemical compounds which has carbon-carbon or carbon-hydrogen bonds.

Some of the organic compounds are Carbohydrates, lipids, proteins, nucleic acids etc.

Alkanes are organic compounds that has straight chain or linear chain between carbon atoms. That is there will be single bonded carbon atoms in the alkanes. So, these are also called saturated compounds.

The general formula for these compounds is CₙH₂ₙ₊₂.

The general formula for the given molecule is C₇H₁₆.

Therefore, the given molecule is best described as an organic compound or as an alkane.

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The mole ratio between sodium bicarbonate and that of acetic acid is 1:1

A mole ratio can be defined as that ratio in whole numbers between the amounts in moles of any two compounds involved in a balanced chemical reaction.

In conclusion, the mole ratio between sodium bicarbonate and that of acetic acid is 1:1

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According to the research, the correct option is false, the statement related to a chemical reaction is false.

They are reactions involving two or more substances (reactants), which change significantly in the process, and can consume or release energy.

Every chemical reaction subjects matter to a chemical transformation, altering its structure and molecular composition.

Therefore, we can conclude that according to the research, the correct option is false, the statement related to a chemical reaction is false.

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Answer:

K<Mg<P<O

Explanation:

Trend is increasing across period and decreasing down a group

Answer:

k-mg-p-o

Explanation:

thank me later love

[tex]\huge\bold\red{Aɴswᴇʀ}[/tex]

Ethanol is a polar solvent, a flammable liquid made of gasoline and alcohol that fully and immediately combines with water instead of separating, which is the opposite of what a firefighter attempting to knock down a car fire might expect.

Answer:

Ethanol has a high vapor pressure. Therefore, even though you may not be able to see the particles of ethanol in the air, they are there and will readily fuel a combustion reaction if an open flame is nearby

From the reaction, the volume of the oxygen required is 89.6 L.

The term stoichiometry has to do with the process by which the mass of reactants or products in a reaction is obtained from the  balanced reaction equation.

In this case, the balanced reaction is equation is;

CH₄  +  2 O₂    →    CO₂  +  2 H₂O

Number of moles of CO2 = 88.0 g/44 g/mol = 2 moles

2 moles of O2 produced 1 mole of CO2

x moles of O2 produces 2 moles of CO2

X = 4 moles

1 mole of oxygen occupies 22.4 L hence 4 moles of oxygen occupies 4 * 22.4 L = 89.6 L

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Answer:

c

Explanation:

sugar and water are soluble hence can be separated using distillation

So, the total atomic mass is [tex]2(1.00794)+32.06+3(15.9994)=\boxed{82.07408 \text{ g/mol}}[/tex]

The procedure to perform a cell membrane experiment is to:

This refers to the semi-permeable membrane that is around the cytoplasm of a cell.

Hence, we can see that the main purpose of the cell membrane practical experiment is to test the permeability of a membrane and to see the amount of liquid that a membrane can hold.

Please note that your question is incomplete so I gave you a general overview to get a better understanding of the concept.

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Answer:

The principal copper ore mineral is chalcopyrite (CuFeS2), which is commonly smelted to yield a matte containing ~50% copper.

Answer:

chalcopyrite

Explanation:

The principal copper ore mineral is chalcopyrite (CuFeS2),

Half life of the reaction is :-101.9 min

a→b

25% reacted means 75% remains

t=42 min

Rate constant

k=(2.303/t)(log a/a-x)

k=(2.303/42)(log 100/100-25 )

k=(0.054) (log 100/75)

k=(0.054)(0.1249)

k=0.0068per min

half life

t1/2=(0.693/k)

     =(0.693/0.0068)

     =101.9 min

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Answer:

94 g/mole

Explanation:

The following answer assumes M is molar mass (g/mole):

One mole of Cl is 35.45 grams.  Since 1 mole of MCl is 74.5 grams, one mole of M will be (74.5-35.45 = ) 39.05 grams/mole.  This just so happens to be the molar mass of potassium, K.  That would mean the compound could be KCl.

We learn from this that M has a single bond.  The oxide of M must take into account the fact that oxygen makes 2 bonds per atom.  That would mean that M ocxide would have the formula M2O.  There are two M's per O.  

M2O would have a molar mass of (2x39.05) + 16 = 94.1 g/mole

333.3 milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂.

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar Concentration. The S.I unit of Molarity is molar (M) or mol/L.

Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}[/tex]

Now put the values in above formula to find the number of moles of Pb(NO₃)₂

Molarity = [tex]\frac{\text{Moles of}\ Pb(NO_{3})_2}{\text{Volume of solution (in L)}}[/tex]

Moles of Pb(NO₃)₂ = Molarity × Volume

                               = 0.699M × 0.107 L       [1ml = 0.001 L]

                               = 0.074 moles

The given balanced chemical equation is

Pb(NO₃)₂(aq) + 2 KOH(aq) → Pb(OH)₂(s) + 2 KNO₃(aq)

The mole ratio of KOH to Pb(NO₃)₂ is 2:1.

The mole of KOH = 0.074 mol × 2

                             = 0.148 moles

Now put the value in above formula to find the volume of KOH  

Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}[/tex]

Volume of KOH = [tex]\frac{\text{Number of mole of KOH}}{\text{Molarity}}[/tex]

Volume of KOH =  [tex]\frac{0.148\ mol}{0.444\ M}[/tex]

                          = 0.333 L

                          = 333.3 mL     [1L = 1000 mL]

Thus from the above conclusion we can say that 333.3 milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Calculate the number of milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂. The equation for the reaction is:

Pb(NO₃)₂(aq) + 2 KOH(aq) → Pb(OH)₂(s) + 2 KNO₃(aq)

_________ mL KOH.

The equation is given is of combustion of ethanol.

Fuel ethanol (C2H5OH) has high energy carbon-carbon (C-C) and carbon-hydrogen (C-H) bonds that store chemical energy. From the ethanol container, ethanol molecules evaporating, enter the flame's base. A physical action called evaporation converts liquid into gas. Ethanol evaporates with a constant molecular structure.

The molecules of ethanol and oxygen combine inside the flame and undergo a chemical transformation. Let's consider matter, or the atoms. The oxygen (O2) and ethanol (C2H5OH) molecules' atoms reorganise into carbon dioxide (CO2) and water (H2O). There are always the same number of atoms. A chemical equation may be used to demonstrate how the atoms are rearranged.

Energy is released as the atoms in the oxygen and ethanol are rearranged. When the high-energy C-C and C-H bonds in ethanol are swapped out for the low-energy H-O and C=O bonds in carbon dioxide and water, chemical energy is released as heat and light.

The ethanol and oxygen atoms are rearranged into carbon dioxide and water during burning. Water and carbon dioxide escape from the flame's top.

To conclude with we can say that the given reaction of combustion of ethanol. Ethanol with oxygen given carbon dioxide with water on reaction.

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If you started with 2.864 g of sodium bicarbonate and heated it to constant mass, 0.59 gram would be the mass that residue after the reaction.

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

2NaHCO₃  → Na₂CO₃ + CO₂ + H₂O

According to Stoichiometry

= [tex]2.864\ g\ NaHCO_{3} \times \frac{1\ \text{mole}\ Na_2CO_3}{105.9\ g/mol} \times \frac{1\ \text{mole}\ CO_2}{2\ \text{mole}\ NaHCO_3} \times \frac{44\ g \ CO_2}{1\ \text{mole}\ CO_2}[/tex]

= 0.59 g

Thus from the above conclusion we can say that If you started with 2.864 g of sodium bicarbonate and heated it to constant mass, 0.59 gram would be the mass that residue after the reaction.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: If you started with 2.486 g of sodium bicarbonate and heated it to constant mass, what would the mass of the residue be after the reaction? Show your work.

NaHCO₃  → Na₂CO₃ + CO₂ + H₂O  

The theoretical yield of the Hg is 4.02 g.

The theoretical yield is the yield that is obtained from the stoichiometry of the reaction.

The reaction equation is; 2HgO(s) ------> 2Hg(l) + O2(g)

Number of moles of HgO =  4.37 g/217 g/mol = 0.02 moles

Number of moles of Hg = 3.21 g/201 g/mol = 0.012 moles

Now;

Theoretical yield of Hg = 0.02 moles * 201 g/mol = 4.02 g

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581.4g of F2 is needed to generate 7.65 mol of CF4.

The reaction of formation of CF4 is-

   C(S) +2F2(g)  -> CF4  

So according to this equation 2 mol of F2 is needed to form 1 mol of CF4 thus to produce 7.65 mol of CF4 we need 15.3 mol of F2 .

And 1 mol F2= 38g of F2

so 15.3 mol F2 means 581.4 g of F2.

As no of mol = [tex]\frac{given mass}{molar mass}[/tex] . \

What is the formation reaction?

When 1 mol of any substance is produced from its elements in their standard state.

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Rate constant:

The rate constant at 65°C is [tex]k_{2} = 3.069 x 10^{-6}[/tex]

What is the Arrhenius equation?

Sometimes the Arrhenius equation is written as [tex]k = Ae^{-E/RT}[/tex], where k is the rate of the chemical reaction, A is a constant that varies depending on the chemicals involved, E is the activation energy, and R is the universal gas constant, and T is the temperature.

According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.

Calculation:

According to the Arrhenius equation for variable temperature:

[tex]ln(\frac{k2}{k1}) = - \frac{Ea}{R} (\frac{1}{T2} - \frac{1}{T1})[/tex]

The temperatures are given to be computed in kelvins and then both temperature and activation energy will be put in the above equation, we get,

[tex]ln ( \frac{k_{2}}{3.54 x 10^{-5}} ) = -\frac{89000J/mol}{8.314J (mol* K)} ( \frac{1}{338.15K} - \frac{1}{318.15K} \\ln ( \frac{k_{2}}{3.54 x 10^{-5}} ) = 2.1602\\k_{2} = 3.54 x 10^{-5} *exp(2.1602)\\k_{2} = 3.54 x 10^{-5} *8.67\\ k_{2} = 30.69 x 10^{-5}\\k_{2} = 3.069 x 10^{-6}[/tex]

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In the reaction of silver nitrate with copper metal, metallic silver comes out of solution, and the solution turns blue. This as a single replacement reaction.

A single replacement reaction, also known as a single displacement reaction, occurs when one element in a molecule is swapped out for another. The starting materials are always pure elements, such as a pure zinc metal or hydrogen gas, plus an aqueous compound.

A + BC → B + AC

When A is more reactive than B or when the product AC is more stable than BC, single replacement reactions happen. A and B could either be two halogens or two metals (with hydrogen included) (C is a cation). C functions as a spectator ion when BC and AC are in aqueous solutions.

For example, 2HCl(aq)+Zn(s)→ZnCl₂(aq)+H₂(g)

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Answer:

Scientists were slow to let go of the current theories.

Explanation:

this is correct

If an element has an electron configuration that ends in 5d^4, it is found in column 6 of the periodic table.

The energy level refers to the position where an electron is found in the atom. If the electron moves from a higher to a lower energy level, energy is evolved as light.

Now;

v = λf

f = v/λ

f = 3 * 10^8 m/s/6.34 x 10^–7m

f = 4.7 * 10^14 Hz

From E = hc/λ

E = 6.6 * 10^-34 * 3 * 10^8/4.65 x 10^–7m

E = 4.3 * 10^-19 J

From;

λ = h/mv

λ =  6.6 * 10^-34Js/905 kg * 26.8 m/s

λ =  2.27 * 10^-38 m

Given that;

E = hf

E = 6.6 * 10^-34Js * 1175  x 10^3 Hz

E = 7.8 * 10^-28 J

If an element has an electron configuration that ends in 5d^4, it is found in column 6 of the periodic table.

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The shielding effect is more noticeable in metals than non-metals.

The shielding effect is known as a decrease in the effective nuclear charge on the electron cloud as a result of a variation in the attraction forces acting on the atom's electrons.

Metals will have a more pronounced shielding effect as compared to nonmetals during the same time span. The amount of p+ atoms in the nucleus grows as you advance across the periodic table, raising the nuclear charge of the atom. Because the valence e- are drawn more firmly towards the nucleus in nonmetals, the inner core's shielding action is less obvious.

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Correct option:

Number of atoms is given by option is C, i.e. [tex]1.20\times10^{24}\,atoms[/tex].

Calculation of number of atoms:

As, mole tells about the amount of substance.

Chemical units known as moles are employed to calculate the mass or molecular mass of a compound, molecule, or atom. For instance, there is one mole in 12 grams of carbon.

[tex]1 mole= 6.022\times10^{22}\,atoms/molecules/ions[/tex]

Molecular mass of Mg= 24.30 g/mol

Given weight of Mg= 48.60 g

Atoms present in 48.60 g= ?

[tex]6.022\times10^{23}= N_A[/tex](Avogadro's number)

[tex]n=\frac{m}{M}=\frac{Given\,number\,of\,atoms}{N_A}\\\\\frac{m}{M}=\frac{N}{N_A}\\\\\frac{48.60}{24.30}=\frac{N}{6.022\times 10^{23}}\\\\ N= 2\times 6.022\times10^{23}\\N= 12.044\times10^{23}\,atoms[/tex]

[tex]N= 1.2\times10^{24}\,atoms\,of\,Mg[/tex]

So, the correct option is C.

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Answer: C

Explanation: 1.20 x 10^24 atoms

How many liters of oxygen gas were used up?

If 185 g of wax [tex]C_{22}H_{44}[/tex] burns, 13.73 L of oxygen gas is used.

An ideal gas equation is:

The macroscopic characteristics of ideal gases are related to the ideal gas law (PV = nRT). Gas is considered to be perfect if its particles (a) do not interact with one another and (b) occupy no space (have no volume).

First, determine the gas's moles using the gas law.

PV = nRT, where n is the number of moles and R is the gas constant. Next, divide.

To obtain molar mass, multiply the given mass by the number of moles.

Data provided:

P= 101kpa =0.996792 atm

V= ?

R= 0.082057338 L atm K[tex]^{1} mol^{-1}[/tex]

T=25 +273 =298 K

Moles =?

Moles = mass/molar mass = 185g/308.6

Moles =0.56

Putting value in the given equation:

PV/RT =n

0.56 = [tex]\frac{0.996792 atm XV}{0.082057338 L atm K^{1} mol^{-1} X 298}[/tex]

13.73 L =V

13.73 L of oxygen gas was used up if 185 g of [tex]C_{22}H_{44}[/tex] wax burns.

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The atoms present in the elements, compounds and mixtures are represented in the diagrams by spheres.

Elements are pure substances consisting of the same atoms entirely.

Compounds are formed from two or more elements chemically combined together.

Mixtures are two or more substances physically combined together.

The atoms present in the elements, compounds and mixtures are shown in the attached image.

In conclusion, atoms of the same kind are present in elements whereas atoms of different kinds are found in compounds and mixtures.

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The grams of agarose that are weighed out are 6 g.

The concentration of a solution is expressed in a number of ways like molarity, molality, normality. It is also expressed as w/v, w/w, and v/v.

In w/v, the w represents the weight of the solute and v is the volume of the solution.

w/v = Mass of the solute/volume of the solution

Calculations:

It is given that w/v is 1.2%. This means that 1.2 g of agarose is present in 100 mL of the solution or 1.2 g/100 mL.

The weight of agarose present in 500 mL of the solution is calculated as:

Mass of agarose = (1.2 g/100 mL) x 500 mL

= 6 g

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The number of units of NO3 present on the product side is 6.

The given reaction is:

3Cu + 8HNO3 -----> 3Cu(NO3)2 + 2NO + 4H2O

To find:

The number of units of NO3.

Solution:

The given reaction shows that three moles of copper and eight moles of nitric acid react to produce three moles of Cu(NO3)2, two moles of NO and four moles of water.

Each molecule of Cu(NO3)2 contains two units of NO3. As the number of moles of Cu(NO3)2 produced is 3, the total units of NO3 in the product side is 3 x 2 = 6.

Therefore, the correct option is 6.

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Answer: 3. 6

Explanation: to put it simply

Answer:

O2(oxygen)

Explanation:

Reduced means the valence electrons are gained. From this equation we see in CO2, C is 4+ and for each O there's a 2-, however, originally, C and O2 are all 0, it's obvious that O is reduced from 0 to 2-

Answer:

a is my answer

Explanation: