grrr i don't have much time, help please T^T
will give brainlist and points! I'LL OWE YOU FOREVER​

Grrr I Don't Have Much Time, Help Please T^Twill Give Brainlist And Points! I'LL OWE YOU FOREVER

Answers

Answer 1

Answer:

2. ( b ) zero

3. ( c ) 10 s

4. Uniform then decreasing

Explanation:

2.

Since the motion is uniform, initial and final velocity will be 0, hence acceleration will be zero.

3.

Initial velocity ( u ) = 5 m/s

Final velocity ( v ) = 35 m/s

Acceleration ( a ) 3 m/s^2

To find : Time ( t )

Formula : -

t = v - u / a

 = 35 - 5 / 3

 = 30 / 3

t = 10 s

Answer 2

Answer:

See below ~

Explanation:

Q2

The uniform circular motion in the movement of object in a circular path with fixed and perpendicular on the direction of the motion acceleration.

d

Q3

Substitute the values in : v = u + at35 = 5 + 3t3t = 30t = 10s (c)

Q4

The vertical component for a projectile by acute angle on the horizontal axis changes from decreasing then increasing velocity.

d

Related Questions

Question 1
A bus travels 5 km east. Then it travels 3 km west by the same path and stops.
What is the bus's displacement?
O 10 km
O2 km
O3km
O 8 km

Answers

2 km, you simply subtract 5 from 3 and find the distance between the 2 travels.

An object moves 4 meters north, then 3 meters east. What is the displacement of the object?

Answers

Answer:

5 meters

Explanation:

4  and  3   are legs of a right triangle with the hypotenuse = displacement

Use Pythagorean theorem

4 ^2 + 3^2 = (displacement)^2

displacement = 5 m

The displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.

What is displacement?

Displacement is change in the position of an object. It can be described as the shortest distance between the initial and final position of an object.

The displacement of the object is calculated as follows;

d² = 4² + 3²

d² = 25

d = 5 m

Thus, the displacement of the object that moved 4 meters north, then 3 meters east is 5 meters.

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What is the de Broglie wavelength of a 2.89 x 10-28 kg particle moving
at 3.00 x 108 m/s? (h = 6.626 x 10-34 J-s)

Answers

Explanation:

formula is given by

h/mv

where h is 6.626 × 10 ^-34

and c = 3 × 10^8

m = mass

by plugging in the values in the formula, the de Brogile wavelength is equal to 7.6424 × 10^(-15)

would appreciate a brainliest :)

What type of waves do not require a medium to travel?.

Answers

Answer:

electromagnetic waves

DOES THE SUN CONTAIN NUCLEAR ENERGY?

Answers

Answer: yes

Explanation: it's fueled by nuclear reactions that fuse hydrogen atoms together into helium and other heavier elements, releasing huge amounts of energy in the process.

A plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km/h from the usual speed. Find its usual speed.

Answers

Answer:

Usual speed: [tex]500\; {\rm km \cdot h^{-1}}[/tex].

Explanation:

Let the usual duration of the trip be [tex]t[/tex] hours ([tex]t > 0[/tex].) The actual duration of this trip would be [tex](t - (1/2))[/tex] hours.

The usual speed would be:

[tex]\begin{aligned}\frac{1500}{t}\end{aligned}[/tex].

The actual speed would be:

[tex]\begin{aligned}\frac{1500}{t - (1/2)}\end{aligned}[/tex].

The actual speed is [tex]100\; {\rm km \cdot h^{-1}}[/tex] greater than the usual speed. In other words:

[tex]\begin{aligned}\frac{1500}{t - (1/2)} - \frac{1500}{t} = 100\end{aligned}[/tex].

Simplify this equation and solve for [tex]t[/tex] ([tex]t > 0[/tex]):

[tex]\begin{aligned}\frac{15}{t - (1/2)} - \frac{15}{t} = 1\end{aligned}[/tex].

[tex]\begin{aligned}15\, t - 15\, \left(t - \frac{1}{2}\right) = t^{2} - \frac{1}{2}\, t\end{aligned}[/tex].

[tex]\begin{aligned}t^{2} - \frac{1}{2}\, t - \frac{15}{2} = 0\end{aligned}[/tex].

[tex]2\, t^{2} - t - 15 = 0[/tex].

[tex](2\, t + 5)\, (t - 3) = 0[/tex].

Since [tex]t > 0[/tex], the only possible value for [tex]t[/tex] would be [tex]t = 3[/tex].

Thus, the usual duration of this trip would be [tex]3\; {\rm h}[/tex]. The usual speed of this trip would be:

[tex]\begin{aligned}v &= \frac{s}{t} = \frac{1500\; {\rm km}}{3\; {\rm h}} = 500\; {\rm km \cdot h^{-1}}\end{aligned}[/tex].

Any sound with a frequency that is too low for humans to hear is called:

Answers

Answer:

infrasound

Explanation:

3. The distance from a makeup mirror to C (the radius of curvature) is 70 cm. How far from the mirror
can a person be and still see an upright, magnified image?

Answers

The far point from the mirror can a person be and still see an upright, magnified image is focus i.e. 35cm from mirror.

What is  radius of curvature?

The mirror is made out of a sphere which has its radius called the radius of curvature.

The focal length f is half of the radius of curvature R of the lens.

Given the radius of curvature is 70cm, then focal length will be 70/2 = 35cm.

The makeup mirror is a concave mirror which forms real and upright images. The magnified images are obtained when the object is placed between focus and mirror.

Thus, the far point is focus i.e. 35cm from mirror.

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The coefficient of dynamic friction between the grass and a 200 kg football blocking sled is 0.20. If a football player only pushes horizontally against the sled, how large must the horizontal force be to keep the sled moving at constant velocity

Answers

The horizontal force be to keep the sled moving at constant velocity is 392 N.

Horizontal force applied to the sled

The horizontal force applied to the sled to prevent it from moving is calculated from Newton's second law of motion.

F - Ff = ma

where;

a is acceleration of the sled

at constant velocity, a = 0

F - μmg = m(0)

F - μmg  = 0

F = μmg

F = 0.2 x 200 x 9.8

F = 392 N

Thus, the horizontal force be to keep the sled moving at constant velocity is 392 N.

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A car travels for 2 hours at a speed of 55 km/h. calculate the distance traveled

Answers

This is a uniform rectilinear motion (MRU) exercise.

We get the data:

d = ?, v = 55 km/h, t = 2 hr

To calculate the distance, multiply the speed by the time.

d = v * t

d = 55km/h * 2hr = 110km

The distance traveled is 110 km.

Mr. Ramirez demonstrates that objects can exert forces on each other even when the objects

are not touching. He removes two long pleces of clear plastic tape from a tape dispenser. He

holds a piece of tape in each hand so that they are hanging down. As he moves his hands closer together, the pieces of tape repel each other. His students then plan an investigation to study the forces exerted by the pieces of tape. a. Identify two factors that may affect the forces exerted by the pieces of tape. Explain your

reasoning.




b. Describe how the effect of one of the factors you identified in part (a) could be tested. Be sure to include a description of how the effect would be measured and how the collected data would be analyzed.

Answers

The two factors that may affect the forces exerted by the pieces of tape are  the charge on the tape and distance between them.

The effect of one of the factors could be tested by altering the distance and calculating the forces between them.

What is force?

A force is the push or pull which make a body to move or stop it.

a. When two objects are kept apart. they are always attracted when uncharged kept at any distance.

When the objects are charged, the force will be attractive or repulsive.

The distance between those charged objects increase or decrease in strength depending on the distance between them.

Thus, the two factors that may affect the forces exerted by the pieces of tape are the magnitude of charge on the tape and distance between them.

b. By increasing the distance between the tapes, we can find the strength of forces.

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When a ball rolls along the carpet, it slows down faster than when it is rolled on the floor. What transfer of energy explains this observation?

Answers

Answer:

D.) A carpet transfers more energy to heat than the floor.



The frictional force between carpet and ball is more due to the rough surface of the carpet as compared to the friction between floor and ball, so the ball on the carpet would come to rest first before a ball on the floor.



Explanation:

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what is the wavelength of a 28Hz periodic wave at 10 meters per second?

Answers

AnswerAnswerAnswerAnswerAnswer:0.3571m

Explanation:

Unguarded live parts operating at 30,000 volts located above a working space must be elevated at least _____ above the working space.

Answers

Unguarded live parts operating at 30,000 volts located above a working space must be elevated at least 9.5' above the working space.

What is voltage?

The voltage is the potential difference between the end of the conductor.
The place where electricity supply wires and power stations are present, the lives must protected. They must live far above the working space.

Thus, it must be 9.5' above the working space.

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In a billiards game, one player hits the cue ball towards another ball. The cue ball has a mass of 0.1kg and hits the other ball with a velocity of 2m/s. If the collision is completely elastic and the cue ball travels with a velocity of 0.8m/s after the collision, what is the mass and velocity of the other ball?​

Answers

Answer:

  3/70 kg ≈ 0.04286 kg

  2.8 m/s

Explanation:

In a perfectly elastic collision, the total momentum of the system is constant, and the difference in velocities changes sign.

We assume the other ball is at rest initially, and that the collision is "head-on." That is, final velocities are in the same direction as the initial velocity of the cue ball. We further assume no energy loss, and that the balls do not rotate.

__

initial momentum

Assuming the ball being hit is initially at rest, it contributes no momentum to the system. The total momentum is ...

  (0.1 kg)(2 m/s) = 0.2 kg·m/s

__

initial velocity difference

If the cue ball has velocity v1 and the hit ball has velocity v2, the initial difference of velocities is ...

  v1 -v2 = 2 m/s -0 m/s = 2 m/s

__

final velocity difference

After the collision, we must have ...

  v1 -v2 = -2 m/s . . . . the velocity difference changes sign

  v2 = v1 +2 m/s = 0.8 m/s +2 m/s

  v2 = 2.8 m/s

The velocity of the other ball is 2.8 m/s after the collision.

__

mass of the other ball

The total momentum after the collision is the same as before, so we must have ...

  m1·v1 +m2·v2 = initial momentum

  (0.1 kg)(0.8 m/s) +(m2)(2.8 m/s) = 0.2 kg·m/s

  m2 = (0.2 kg·m/s -0.08 kg·m/s)/(2.8 m/s) = (0.12/2.8) kg = 3/70 kg

The mass of the other ball is 3/70 ≈ 0.04286 kg.

What happens when oxygen comes in contact with NOx and VOCs?
1. They combine to create ozone to replenish the ozone layer.
2. Oxygen neutralizes NOx and VOCs.
3. They combine to form low altitude ozone.
4. They combine to form smog.

Answers

When oxygen comes in contact with NOx and VOCs They combine to create ozone to replenish the ozone layer. Option A is correct.

What is an ozone layer?

The layer form on the stratosphere region of the earth, which absorbs most of the ultraviolet rays.

The ultraviolet rays come from the sun are very harmful, increases global warming when enter inside the ozone layer due to its deplection.

When oxygen comes in contact with NOx and VOCs They combine to create ozone to replenish the ozone layer.

Hence, option A is correct.

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What happens when a sound wave passes by the particles of a medium?

Answers

Answer:

Propagation of Sound Waves:

Sound waves move (propagate) through a medium by means of particle-to-particle interaction. The source disturbs the immediately surrounding particles, causing them to vibrate about their fixed position at the same frequency as the source.

the amount of energy at the end of the system (output) is different from the starting energy (input). How does this not violate (break) the law of the conservation of energy. This question is based on solar and wind energy

Answers

Answer:

Because some of the energy escaped or was used.

Explanation:

50 points physics question (multiple choice) Will give brainliest!

Answers

There are two systems that contain only the fundamental frequency and they are the systems C and D.

What is fundamental frequency?

The term fundamental frequency refers to the lowest frequency of a vibrating body. It does not include the overtones or the harmonics.

From the image shown in the question, there are two systems that contain only the fundamental frequency and they are the systems C and D.

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Warren is a professional triathlete when doing an
Ironman, Warren swims 3.86km in 45 mins, then
bikes for 180.5 km in 5 hours and finishes by
running a marathon 42.2km in 2.75 hours. What is
Warren's average speed in Km/hr and m/s

Answers

Answer:26.7 and 7.4

Explanation:

So, first you add all the time up then the area travelled.

Firstly; 45 mins + 300 minutes(5 hours) + 165 minutes(2.75 minutes)= 510 minutes

Secondly; 42.2KM + 180.5KM + 3.86KM= 226.56KM

Finally: For hourly you would do: 510 divided by 60 to get 510 mins in terms of hours: so, 8.5 hours then you would do 226.56KM divided by 8.5 hours to get: 26.7Km/hr

For m/s: 7.4m/s

Inboard gasoline boats built after july 31st, 1981 must have what type of ventilation system?.

Answers

Inboard gasoline boats built after July 31st, 1981 must have a mechanical type of ventilation system.

What is a mechanical ventilation system?

A mechanical ventilation system can be defined as a device in which circulates fresh/cold currents of air.

A mechanical ventilation system is based on the use of systems of ducts capable of ventilating the device.

In conclusion, inboard gasoline boats built after July 31st, 1981 must have a mechanical type of ventilation system.

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A metal artifact with a mass of 814.0 lbs and a length of 6.25 ft is recovered from the Queen Anne's Revenge wreckage site. It is believed to be a cannon. Unfortunately, the base of the cannon was not recovered, so it is a perfectly symmetrical metal tube. The outer circumference is 23.9 inches and the inner diameter of the bore is 11.5 cm. In order to care for it properly, it must be determined what type of metal it is composed of. What is the artifacts density in g/cm3

Answers

Answer:

discovered as obisdan

Explanation:

me ginus brooo

A car is travelled at 8m/s. The mass of the car is 750 kg.

Calculate the force required to stop the car in 8s

Answers

Answer:

F = 750N

Explanation:

We know that F(force) = mass(m) × acceleration(a)

And that Acceleration(a) = velocity(V) ÷ time(t)

So we'll first calculate the acceleration

a = V = 8m/s = 1m/s²

     t        8

Next we'll calculate the force

F = ma = 750kg × 1m/s² = 750N

Question 12 A wave has a wavelength of 7.96 m and travels at 30.67 m/s. What is the frequency of the wave?​

Answers

Answer:

0.2597hertz

Explanation:

first of all we have to calculate time.

time is given by speed/distance

hence=30.67/7.96

=3.85s

frequency is given by 1/time

=1/3.85

=0.2597hertz

Types of Forces Lab Report
Instructions: In the Types of Forces lab, you will experiment with the contact force friction. Use the following lab report to record your hypothesis, materials, procedures, observations, and conclusion. You will submit your completed report.

Name and Title

Name of Lab:

Student Name:

Instructor:

Date:


Objective

The purpose is to test whether the surface texture of the ground affects the distance an object can roll.


Hypothesis

If an object rolls over _______________ (type of material), then it will _____________ (describe the prediction of distance it will travel).


Materials

For this lab, I used the following items:


Procedure

Short summary of what I did:

I experienced the following errors while doing my experiment:

Test (independent) variable (What was different about my test groups?):

Outcome (dependent) variable (What was I measuring?):


Data

Record the distance traveled for each of the trials for the three floor surfaces in the table below.

Distance Object Traveled
Floor Surface Trial 1 Trial 2 Trial 3




Data Analysis

Calculate the average distance traveled for each floor surface. Use the following guidelines for calculating averages, and show your work.

Floor Covering Calculation of the Average Average Distance Traveled
Example (trial 1 measurement + trial 2 measurement + trial 3 measurement) / 3 (number of trials) Your answer from the calculation, showing the average distance the ball rolled for that floor covering.

Answers

Frictional force is reduced in smooth surfaces but is large in rough surfaces.

What is Force?

Force is defined as an agent which causes a change in the motion or state of an object.

Forces are of two types:

Contact forces and Non-contact forces

Contact forces include frictional force.

Frictional forces refers to the force which acts between two surfaces in contact by opposing the relative motion of one over the other

Frictional force depends on the nature of surfaces in contact where rough surfaces produce greater frictional force than smooth surfaces.

Therefore, frictional force is reduced in smooth surfaces but is large in rough surfaces.

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Transverse waves travel at in a string that is subjected to a tension of if the string is long, what is its mass?

Answers

The mass of the string is 0.515 kg.

Calculations and Parameters:

Given that:

Tension= 60.5NLength of string= 15.9mv= 43.2 m/sm=?

To solve for the mass of the string,

v=√(T/ρ) ,(v=43.2m/s , T=60.5N , L=15.9m )43.2= √(60.5/ρ)60.5/ρ= 1866.24ρ= 0.032418

Therefore, the mass would be[tex]15.9*0.03242= 0.515448= 0.515[kg][/tex]

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Calculate the power if work is 9000 joules and time is 60 seconds

Answers

Answer:

150w

Explanation:

power = workdone/time

9000/60

150w

Question 7.
When can a mouse have the same momentum as an elephant?
د ن ه ه
A. when the mouse has a large velocity and the elephant has a small velocity
when the mouse has a small velocity and the elephant has a large velocity
a mouse cannot have the same momentum as an elephant
D. when they both have the same velocity

Answers

A mouse have the same momentum as an elephant when the mouse has a large velocity and the elephant has a small velocity. The correct option is A.

What is momentum?

The momentum is the product of the mass of the object and its velocity.

Mouse has mass very less than the elephant. In order to make their momentum same, the velocity of the mouse must be greater than the elephant.

Mm x Vm = Me x Ve

A mouse have the same momentum as an elephant when the mouse has a large velocity and the elephant has a small velocity.

Thus,  the correct option is A.

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A stone is thrown horizontally at 15 m/s from the top of a cliff. It takes it 2.4 s to hit the ground. How far from the base of the cliff does the stone hit the ground

Answers

Speed=Distance/Time
Distance=Speed*Time
Distance=15*2.4
Distance=36m

what is the difference between reflection and refraction? What changes and what does not change.

Answers

Answer:

Reflection involves a change in direction of waves when they bounce off a barrier. Refraction of waves involves a change in the direction of waves as they pass from one medium to another.

Explanation:

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