GK = 24, HJ = 10, and GH = HI = IJ. Find each length.

GK = 24, HJ = 10, And GH = HI = IJ. Find Each Length.

Answers

Answer 1

Greetings from Brasil....

Let us call X the equal distances GH = HI = IJ

GH = X

HI = X

IJ = X

Note that HJ = HI + IJ, so

HJ = X + X

10 = 2X

X = 5

Looking at the figure we can conclude that:

GJ + JK = GK

GJ = GH + HI + IJ

GJ = 15

GJ + JK = GK

15 + JK = 24

JK = 9

GH = X = 5HI = X = 5IJ = X = 5JK = 9
GK = 24, HJ = 10, And GH = HI = IJ. Find Each Length.
Answer 2

Each length of the line segments GH = HI = IK and JK will be 5 and 9.

What is a line segment?

A line segment in mathematics has two different points on it that define its boundaries.

A line segment is sometimes referred to as a section of a path that joins two places.

GK = 24, HJ = 10, and GH = HI = IJ.

Then the length HI will be

HJ = HI + IJ

10 = HI + HI

2HI = 10

HI = 5

Then the length of the line segments GH, HI, and IJ will be

GH = HI = IJ = 5

The length of the JK will be

GK = GJ + JK

24 = 3GH + JK

24 = 3 * 5 + JK

JK = 24 - 15

JK = 9

Then each length of the line segments GH = HI = IK and JK will be 5 and 9.

More about the line segment link is given below.

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Selena and Drake are evaluating the expression (StartFraction r s Superscript negative 2 Baseline Over r squared s Superscript negative 3 Baseline EndFraction) Superscript negative 1, when r = negative 1 and s = negative 2.


Selena’s Work
Drake’s Work

(StartFraction r s Superscript negative 2 Baseline Over r squared s Superscript negative 3 Baseline EndFraction) Superscript negative 1 Baseline = (r Superscript negative 1 Baseline s) Superscript negative 1 Baseline = StartFraction r Over s EndFraction = StartFraction negative 1 Over negative 2 EndFraction = one-half

(StartFraction (negative 1) (negative 2) Superscript negative 2 Baseline Over (negative 1) squared (negative 2) Superscript negative 3 EndFraction) Superscript negative 1 = (StartFraction (negative 1) (negative 2) cubed Over (negative 1) squared (negative 2) squared EndFraction) Superscript negative 1 = (StartFraction negative 8 Over 4 Endfraction) Superscript negative 1 Baseline = StartFraction 4 Over negative 8 EndFraction = negative one-half


Who is correct and why?
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Selena is correct because she simplified correctly and then evaluated correctly after substituting the values for the variables.
Drake is incorrect because he should have simplified first, before substituting the values for the variables.
Drake is correct because he substituted the values for the variables first, and simplified correctly

Answers

Answer:

Selena is correct because she simplified correctly and then evaluated correctly after substituting the values for the variables.

Step-by-step explanation:

Move. After the origin, (0,0), set the equation of EF is y=x. no record the coordinates of the vertices of a polygon ABCD. what are the coordinates of the vertices of the reflected polygon AefBefCefDef where EF is the line of reflection? enter the coordinates on the table

Answers

Answer:

Vertex Coordinate  Vertex Coordinate

A (1, 1)  AEF (1, 1)

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D (2, 1)  DEF (1, 2)

Step-by-step explanation:

Plato sample

We have wrote the coordinates.

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We have

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A (1, 1)  AEF (1, 1)

B (2, 3)  BEF (3, 2)

C (3, 2)  CEF (2, 3)

D (2, 1)  DEF (1, 2)

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Step-by-step explanation:

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Step-by-step explanation:

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here, we have,

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Answers

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Step-by-step explanation:

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