Given that the lines are parallel, what would be the value of angle "a" in the diagram found below?

Given That The Lines Are Parallel, What Would Be The Value Of Angle "a" In The Diagram Found Below?

Answers

Answer 1

Explanation:

Hey there!!

a = 40° { corresponding angles on a parallel lines are equal}.

As A and B are parallel, a and 40° are corresponding angles.

Hope it helps...

Answer 2

The value of angle "a" will be 40°

What is corresponding angle ?

The angles which are on the same side of one of two lines cut by a transversal and are on the same side of the transversal is called corresponding angles.

since , angle a and angle B = 40° (given) are on the same relative position at the intersection where a straight line crosses two others and since both the lines are parallel to each other hence ,both the angles are said to be corresponding angles .This implies both the angles must be equal .

angle a = 40°

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Related Questions

If a gannet hits the water at 32 m/s, what height did it dive from? Assume that the gannet was motionless before starting its dive.

Answers

Answer:

The value  is  [tex]h =  52.2 \  m[/tex]

Explanation:

From the question we are told that

 The  velocity  at which he hit the water  is  [tex]v  =  32 \  m/s[/tex]

   

Generally from kinematic equation

     [tex]v^2 =  u^2  + 2gh[/tex]

Here the initial velocity u = 0 m/   given that the gannet started the jump from rest.

  =>   [tex]32^2  =  0^2  +  2*(9.8)h[/tex]

 =>     [tex]h =  52.2 \  m[/tex]

A flag pole is attached to the side of a building 5.00 ft off the ground and it hangs down 30 degrees from the vertical. If the pole is 6.00 ft in length, how high in feet is the top of the pole at its highest point (sticking out from building)? (Hint: draw a picture) E​

Answers

Answer:

   h ’= 0.6963 m

this is the height of the part of the post it supports.

Explanation:

For this exercise we can use the trigonometric relationships

Let's start by finding the vertical component of the height of the pole

             cos 30 = x / L

             x = L cos 30

             x = 6 cps 30

             x = 5.196 m

with this length, the post has the same height as the building, so there are

               Aₓ = L -x

               Δx = 6 -5.196

               Δx = 0.804 ft

the height of this section is

               cos 30 = h ’/ Dx

               h ’= 0.804 cos30

               h ’= 0.6963 m

this is the height of the part of the post it supports.

How does diet affect diabetes

Answers

Answer:

A diet high in fat, calories, and cholesterol increases your risk of diabetes. A poor diet can lead to obesity (another risk factor for diabetes) and other health problems. A healthy diet is high in fiber and low in fat, cholesterol, salt, and sugar. Also, remember to watch your portion size.

Lower sugar levels for you have a healthier diet

Two vectors of magnitudes |A| = 8 units and |B| = 5 units make an angle that can vary from 0° to 180°. The magnitude of the resultant vector A + B CANNOT have the value of:

Answers

The question is missing the alternatives. Here is the complete question.

Two vectors of magnitude |A| = 8units and |B| = 5units make an angle that can vary from 0° to 180°. The magnitude of the resultant vector A+B CANNOT have the value of:

A. 2 units

B. 5 units

C. 8 units

D. 12 units

Answer: A. 2 units

Explanation: Vector is an entity that has characteristics as magnitude and direction. Resultant vector is the "sum" of 2 or more vectors.

In this question, the vectors have magnitude and angle varies from 0° to 180°.

When angle between vectors A and B is 0°, they are parallel and pointing to the same direction, so:

[tex]V_{R} = |A| + |B|[/tex]

[tex]V_{R}=8+5[/tex]

[tex]V_{R}[/tex] = 13

When the angle is 180°, it means vectors are in opposing directions, so:

[tex]V_{R} = |A| - |B|[/tex]

[tex]V_{R} = 8-5[/tex]

[tex]V_{R}[/tex] = 3

From the calculations, we can conclude the magnitude of resultant vector varies between 3 and 13.

The least value is 3, so it cannot have a value of 2 units.

The fastest land animal is the cheetah. A cheetah can run 100 meter dash in 5.95 seconds, calculate the cheetahs average speed in meters per second

Answers

Answer:

16.80672269 m/s

Explanation:

100 divide by 5.95 seconds

Answer:

16.8m/s

Explanation:

S=D/T

=

[tex] \frac{100}{5.95} [/tex]

=16.80672269

=16.8

Trevor and Nick are taxi drivers. Trevor drives a taxi using diesel oil while Nick drives a taxi using LPG. Whose taxi will cause higher levels of air pollution and why?

Answers

Answer:

Trevor's taxi would cause higher levels of air pollution

Explanation:

Trevor's taxi use diesel oil.

Diesel is less cleaner than LPG.

Compared to automotive pollution from petrol and diesel, pollutants from LPG-driven cars include lower amounts of petroleum hydrocarbons, nitrogen oxides , sulphur oxides, ozone contamination and particulate matter.

A particle makes 240 revolutions per minute on a circle of radius 2m. Find I. its period ii. angular velocity III. linear velocity.​

Answers

Answer:

(i) The period, T is 0.25 s

(ii) The angular velocity, ω is 25.136 rad/s

(iii) The linear velocity is, v is 50.27 m/s

Explanation:

Given;

number of revolution of the particle, N = 240 revolutions per minutes

radius of the circle, R = 2m

(i) The period is given by;

[tex]T = \frac{2\pi}{\omega}[/tex]

where;

ω is angular velocity  

[tex]\omega = (240 \frac{rev}{min}) *(\frac{1 \ min}{60 \ s} )*(2\pi \frac{rad}{rev})\\\\ \omega = 25.136 \ rad/s[/tex]

[tex]T = \frac{2\pi }{\omega}\\\\ T = \frac{2\pi}{25.136}\\\\T = 0.25 \ s[/tex]

(ii) angular velocity, ω  = 25.136 rad/s

(iii) linear velocity is given by;

v = ωR

v = (25.136 rad/s) x (2 m)

v = 50.27 m/s

Which is true for a car moving around a circular track with constant speed? 1. It has zero acceleration2. it has an acceleration directed toward the center of its path3. it has an acceleration directed away fromt he center of its path4. it has an acceleration with a direction that cannot be determined from the information given5. it has an acceleration component in the direction of its velocity.

Answers

Answer:

2. it has an acceleration directed toward the center of its path

Explanation:

For a car moving with constant velocity around a circular track, there is a a change in the direction of the velocity at every point on the path taken by the car around the track. This change in direction generates an acceleration on the car which will be directed towards the center of the track. This is why the inertia force on a person inside the car when it is driven around a circular track is usually away from the center of the track, since the inertia force acts in an opposite direction to the acceleration on a body.

What is the equation of the line on the graph?

Answers

Position = (4 m/s)(time) +5

Maddie Cat can ride her tricycle at an amazing speed of 3.75 meters per second.
How far can she go in 5.0 seconds?

Answers

Distance = (speed) x (time)

Distance = (3.75 m/s) x (5.0 s)

Distance = 18.75 meters

Answer: 3.75 x 5.0= 18.75 meters

Explanation:

How does society shape reality?

Answers

Society shapes us through our gender, it dictates what jobs would be suitable for us, what we should wear, how we should look, who we are to socialise with and what is acceptable or not.

To practice Problem-Solving Strategy 22.1 for electric force problems. Two charged particles, with charges q1=qq1=q and q2=4qq2=4q, are located on the x axis separated by a distance of 2.00cm2.00cm . A third charged particle, with charge q3=qq3=q, is placed on the x axis such that the magnitude of the force that charge 1 exerts on charge 3 is equal to the force that charge 2 exerts on charge 3.Find the position of charge 3 when qqq = 2.00 nCnC .

Answers

Answer:

x₂ = 0.01336

Explanation:

In this exercise we use the translational equilibrium equation

          F₁₃ - F₂₃ = 0

          F₁₃ = F₂₃

at the point where charge 3 is placed the two electric forces have the same magnitude

let us use the expression of Coulomb's law for the electric force

         F₁₃ = ka q₁ q₃ / r₁₃²

         F₂₃ = ka q₂ q₃ / r₂₃²

we substitute

         k q₁ q₃ / r₁₃² = k q₂ q₃ / r₂₃²

now imprescriptibility suppose that particle 1 is at the origin of the coordinate system, particle 2 is at a distance d = 2.00cm = 2 10-2 m, therefore let's call the distance from particle 1 to particle 3 as x

            r₁₃ = x

            R₂₃ = d-x

In the exercise we are given the charges for the particle1 q1 = q, for the particle 2 the charge is q2 = 4q the distance between them is d = 2.00cm = 0.0200 m, the value of q = 2.00 nC = 2.00 10⁻⁹ C

let's substitute these values

              q₁ / x₂ = q₂ / (d-x)²

let's clear x

              (d-x)² = q₂ / q₁    x²

              d² - 2dx + x₂ = q₂ /q₁   x²

               x² (1-q₂ / q₁) - 2d x + d² = 0

               

let's substitute the values ​​and solve the quadratic equation

              x² (1 - 4q / q) - 2 0.02 x + 0.02² = 0

              -3 x² - 0.04 x + 0.0004 = 0

               

                x² + 0.0133 x - 0.0001333 = 0

               x = [-0.0133 ±√(0.0133² + 4 0.00013333)] / 2

                x = [-0.0133 + - 0.026664] /2

              x₁ = -0.01998 m

              x₂ = 0.01336 m

Since load 3 must be between charged 1 and 2 the correct answer is

x₂ = 0.01336

Tony completed a 720 km journey with an average speed of 90 km/h for the first 285 km he travelled at an average speed of 95 Km/h what was the average speed for the remaining journey

Answers

Answer:

[tex]Speed = 87 km/h[/tex]

Explanation:

Given

Total Distance = 720km

Average Speed = 90km/h

Average Speed (285km) = 95km/h

Required

Determine the average speed for the rest of the journey

First we need to determine the time taken to complete the journey using

[tex]Speed = \frac{Distance}{Time}[/tex]

[tex]90 = \frac{720}{Time_1}[/tex]

Make Time the subject of formula

[tex]Time_1 = \frac{720}{90}[/tex]

[tex]Time_1 = 8 hour[/tex]

Next, we determine the time taken to complete 285km of the journey using

[tex]Speed = \frac{Distance}{Time}[/tex]

[tex]95 = \frac{285}{Time_2}[/tex]

Make Time the subject of formula

[tex]Time_2 = \frac{285}{95}[/tex]

[tex]Time_2 = 3 hours[/tex]

The difference between these calculated times is the time taken to complete the rest of the journey

[tex]Time = Time_1 - Time_2[/tex]

[tex]Time = 8\ hour - 3\ hour[/tex]

[tex]Time = 5\ hour[/tex]

Also, we need to calculate the distance of the rest of the journey

[tex]Distance = 720\ km - 285\ km[/tex]

[tex]Distance = 435\ km[/tex]

The average speed can then be calculated;

[tex]Speed = \frac{Distance}{Time}[/tex]

[tex]Speed = \frac{435}{5}[/tex]

[tex]Speed = 87 km/h[/tex]

Hence, the average speed of the rest of the journey is 87km/h

What two processes are involved in the formation of Earth’s magnetic field?

Answers

Answer:

i. Geodynamo

ii. Gravitational energy conversion

Explanation:

The outer core of the Earth is believed to be in molten form, consisting of mainly iron and nickel. The reaction (mixture) between these components or elements generates conventional currents which is maintained by the gravitational energy produced in the process. Thus, magnetic fields are generated continuously due to the continuous flow of electric current during the processes.

the four strings of a bass guitar are 0.865 m long and are tuned to the notes g (98 hz), d (73.4 hz), a (55 hz), and e (41.2 hz). in one bass guitar, the g and d strings have a linear mass density of 4.8 g/m, and the a and e strings have a linear mass density of 29.8 g/m.what is the total force exerted by the strings on the neck?​

Answers

Answer: Total force = 636,554.55N

Explanation: To determine tension of strings, wave speed on a string is necessary. Speed is found by:

v = f.λ

f is frequency

λ is wavelength

For the strings, wavelength equals to:

[tex]\lambda = 2L[/tex]

L is the length of the bass guitar string

Then, wave speed:

[tex]v=f.2L[/tex]

Tension on a string is

[tex]v=\sqrt{\frac{F_{T}}{\mu} }[/tex]

[tex]v^{2}=\frac{{F_{T}} }{\mu}[/tex]

[tex]F_{T} = v^{2}\mu[/tex]

[tex]F_{T} = (2f\lambda)^{2}\mu[/tex]

[tex]F_{T} = 4(f\lambda)^{2}\mu[/tex]

μ is linear mass density

For g string:

[tex]F_{T} = 4(98.0.865)^{2}.4.8[/tex]

[tex]F_{T}[/tex] = 137970.3N

For d string:

[tex]F_{T} = 4(73.4.0.865)^{2}.4.8[/tex]

[tex]F_{T}=[/tex] 77397.25N

For a string:

[tex]F_{T} = 4(55.0.865)^{2}.29.8[/tex]

[tex]F_{T}=[/tex] 269795N

For e string:

[tex]F_{T} = 4(41.2.0.865)^{2}.29.8[/tex]

[tex]F_{T}=[/tex] 151392N

Total force = 137,970.3 + 77,397.25 + 269,795 + 151,392

Total force = 636,554.55N

Total force exerted on the neck by the strings is 636,554.55N.

This question involves the concepts of the tension force in strings, linear mass density, and frequency.

The total force exerted by strings on the guitar is "359.4 N".

The tension force exerted by each string is given as:

[tex]F_T=v^2\mu[/tex]

where,

F_T = tension force = ?

v = speed = (frequency)(wavelength) = fλ

μ = linear mass density

Therefore,

[tex]F_T=f^2\lambda^2\mu[/tex]

but for strings in this case:

[tex]\lambda = 2(Length of string) = 2(0.865\ m)=1.73\ m[/tex]

Therefore,

[tex]F_T=f^2(1.3\ m)^2\mu[/tex]

For string g:

[tex]F_{Tg}=(98\ Hz)^2(1.3\ m)^2(4.8\ x\ 10^{-3}\ kg/m)\\F_{Tg}=77.9\ N[/tex]

For string d:

[tex]F_{Td}=(73.4\ Hz)^2(1.3\ m)^2(4.8\ x\ 10^{-3}\ kg/m)\\F_{Td}=43.7\ N[/tex]

For string a:

[tex]F_{Ta}=(55\ Hz)^2(1.3\ m)^2(29.8\ x\ 10^{-3}\ kg/m)\\F_{Ta}=152.3\ N[/tex]

For string e:

[tex]F_{Te}=(41.2\ Hz)^2(1.3\ m)^2(29.8\ x\ 10^{-3}\ kg/m)\\F_{Te}=85.5\ N[/tex]

So, the total force will be the sum of all tension forces:

[tex]F=F_{Tg}+F_{Td}+F_{Ta}+F_{Te}[/tex]

F = 77.9 N + 43.7 N + 152.3 N + 85.5 N

F = 359.4 N

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a) An electric circuit is rates, 240V, 13Ω calculate the amount of current that can be used by this appliance.​

Answers

Answer:

18.4615385 amps

Explanation:

The voltage V in volts (V) is equal to the current I in amps (A) times the resistance R in ohms (Ω):

What is the magnitude of total charge of all the electrons in 1.2 L of liquid water?

Answers

Answer:

6.416*10^ 8C

Explanation:

First we find mass of the water

Mass= density x volume

=1.2*1000= 1200g

To find number of moles we use

N= mass/ molar mass

= 1200/18.02= 66.6mol

So the total number of water molecules is

66.6* 6.022*10^23= 401.07x 10^23moles

But each h20 moles has 10 electrons so it will be 4.01*10^26electrons

Then finally total charge will be

4.01*10^26electrons x 1.6*10^-19

= 6.416*10^ 8C

The magnitude of total charge will be "6.416×10⁸ C".

Electrons:

According to the question,

Density, d = 1.2 L

Volume, V = 1000

The mass will be:

→ Mass = Density × Volume

By substituting the values,

            = [tex]1.2\times 1000[/tex]

            = [tex]1200[/tex] g

Now,

The number of moles will be:

→ N = [tex]\frac{Mass}{Molar \ mass}[/tex]

      = [tex]\frac{1200}{18.02}[/tex]

      = [tex]66.6[/tex] mol

The total no. of water molecules be:

= [tex]66.6\times 6.022\times 10^{23}[/tex]

= [tex]401.07\times 10^{23}[/tex] moles

hence,

The total charge be:

= [tex]4.01\times 10^{26}\times 1.6\times 10^{-19}[/tex]

= [tex]6.416\times 10^8[/tex] C

Thus the above response is correct.

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Calculate the displacement traveled (in m) from start to finish.

Answers

Answer:

nnkn

Explanation:

nkn

Answer 10000 m
Explanation:
Displacement means the shortest distance.
So, from point a to b the total displacementis 10 km and converting into metres its 10000 metre

What net force is needed to accelerate a 1.25 kg book 5.00 m/s2?

Answers

Answer:

F = 6.25 N

Explanation:

Given that,

Mass of the book is 1.25 kg

Acceleration of the book is 5 m/s²

We need to find the net force needed to accelerate the book. Net force is given by :

F = ma

[tex]F=1.25\times 5\\\\F=6.25\ N[/tex]

So, 6.25 N of force is acting on the book.

assume this car is driven off a cliff. How many arrows of force need to be drawn in the free body diagram? Assum no air resistance

Answers:
five
one
four
three

Answers

Answer:

4

Explanation:

friction

weight

normal reaction

force to overcome inertia

Answer:

1

Explanation:

--->

Can an objects displacement be greater than or equal to the objects distance?

Answers

If you say displacement is greater than distance, you will contradict the above statement. Displacement is always less than or equal to distance. Note that distance is a scalar whereas displacement is a vector.So' displacement cannot be more than distance.

Explain why a golf ball has a higher density than a ping pong ball, even though they are similar in size and shape.

Answers

Answer:

The ping pong ball is hollow.

Explanation:

Since a ping pong ball, unlike the golf ball, is only filled with air, it is less dense. Air is notably LESS dense than solids, which is what comprises the inside of a golf ball.

If you want to replicate another scientist's experiment, which sections of their laboratory report will provide you with the most valuable information?

Answers

If research results can be replicated, it means they are more likely to be correct. Replication is important in science so scientists can “check their work.” The result of an investigation is not likely to be well accepted unless the investigation is repeated many times and the same result is always obtained.

A container weighs 450 lb when filled with 4 ft3 of fluid. If the empty container weighs 50 lb, determine the specific weight, mass density and specific gravity of this fluid.

Answers

Answer:

112.5 lb/ft³

405.93 kg/m³

0.406

Explanation:

given that

Weight of the container, w(c) = 450 lb

Volume of fluid, v(f) = 4 ft³

Weight of empty container, w(e) = 50 lb

Specific weight is said to be the weight per unit volume. Thus, the specific weight of this fluid is

w(s) = 450 / 4

w(s) = 112.5 lb/ft³

Mass density is the ratio of the mass of the fluid, with respect to the volume.

ρ = m/v

Since the question gives us the mass in weight, we'd have to convert it to mass from weight.

mass = weight / acceleration due to gravity

mass = 450 / 9.81

mass = 45.87 kg

Also, since the mass is going to be in kg, the volume also has to be in m³, thus needing a conversion.

4 ft³ = 0.113 m³

Mass density = 45.87 / 0.113

Mass density = 405.93 kg/m³

Specific gravity of the fluid is simply given as mass density / 1000. Therefore,

g(s) = 405.93 / 1000

g(s) = 0.406

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which is an accurate description of what occurs when a log burns

Answers

Answer:

charcoal

Explanation:

Answer:

charcoal

Explanation:

Mark as Brainliest

A model rocket accelerates upward from the ground with a constant acceleration, reaching a height of 50 m in 8 s.What is the speed (in m/s) at a height of 50 m?A: 1.07×101 B: 1.25×101 C: 1.46×101 D: 1.71×101 E: 2.00×101

Answers

Answer:

The  value is  [tex]v =  12.5 \  m/s[/tex]

Explanation:

From the question we are told that

    The  height is  [tex]h  =  50 \  m[/tex]

    The  time taken is  [tex]t =  8 \ s [/tex]

   

From the equation of motion we have  that

 [tex]s =  ut + \frac{1}{2}  * a * t^2[/tex]

Here u = 0  because the rocket started at rest

  [tex]50 =  0 + \frac{1}{2} * a  * 8^2[/tex]

=>   [tex]a =  \frac{100}{64}[/tex]

=>    [tex]a =  1.5625 \ m/s^2[/tex]

Also from the kinematic equation we have that

    [tex]v  =  u + at[/tex]

=>  [tex]v =  0 +  (8  *  1.5625)[/tex]

=>   [tex]v =  12.5 \  m/s[/tex]

       

How does the Coriolis effect impact ocean currents in the Northern and Southern Hemispheres?

Answers

The Coriolis effect describes the pattern of deflection taken by objects not firmly connected to the ground as they travel long distances around the Earth.The key to the Coriolis effect lies in Earth’s rotation. Specifically, Earth rotates faster at the Equator than it does at the poles. Earth is wider at the Equator, sThe Coriolis effect bends the direction of surface currents to the right in the Northern Hemisphere and left in the Southern Hemisphere.

Let’s pretend you’re standing at the Equator and you want to throw a ball to your friend in the middle of North America. If you throw the ball in a straight line, it will appear to land to the right of your friend because he’s moving slower and has not caught up.

 

Now let’s pretend you’re standing at the North Pole. When you throw the ball to your friend, it will again to appear to land to the right of him. But this time, it’s because he’s moving faster than you are and has moved ahead of the ball.

Everywhere you play global-scale "catch" in the Northern Hemisphere, the ball will deflect to the right.

Starting from rest, a panther accelerates at 3 m/s/s for 10 seconds. What is the final velocity of the panther

Answers

Answer:

Final velocity = 30 m/s

Explanation:

We are given;

Initial velocity; u = 0 m/s

Acceleration; a = 3 m/s²

Time; t = 10 seconds

From Newton's first law of motion, the final velocity is given by the formula;

v = u + at

Plugging in the relevant values gives;

v = 0 + (3 × 10)

v = 30 m/s

If an X-ray tube is operating at a current of 30.0 mA:a) How many electrons are striking the target per second? b) If the potential difference between the anode and cathode of this tube is 100.0 kV, how much power is expended

Answers

Answer:

Explanation:

A. Q= It

30E-3A=q

Ne = q

30E-3/1.6*10-19= N

N= 1.8*10^16 electrons

B. Power= I x v

= 30*10^-3A x 100*10^3v

= 3000watts

If you do not have enough time to complete a full workout, you should:
A. Cut the cool-down portion short.
B. Skip the warm-up and cool-down portions altogether.
C. Cut the warm-up portion short.
D. Cut the exercise portion short.

Answers

Answer:

the answer to this question would be cut the exercise portion down (D)

this is because warm ups and cooling down during exercise are more important than the exercise itself

Explanation:

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