The P(a, b and c) is 0.0432 when P(a) = 0.90, p(b) = 0.96, p(c) = 0.05.
From the given question, we know that
Probability of event 'a' occurring, P(a) = 0.90
Probability of event 'b' occurring, P(b) = 0.96
Probability of event 'c' occurring, P(c) = 0.05
We have been told that these three events are independent.
Thus, we can use the multiplication rule of probability, which states that the probability of three independent events a, b, and, c occurring is equal to the products of the probability of each individual event occurring.
p(a, b and c) = p(a) × p(b) × p(c)
= 0.90 × 0.96 × 0.05
= 0.0432
Hence, the probability(a, b, and c) is 0.0432.
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What is the measure of ZD in the parallelogram below?
Check the picture below.
Solve each equation.
9^(x+2)=2^(5x-4)
Value of x is 1.411
Given Eq.
[tex]9^{x+2} = 2^{5x-4} \\\\[/tex]
Applying exponent rules
[tex](x+2)ln(9) = (5x-4)ln(2)\\[/tex]
Solving for x
[tex]x = \frac{4ln(6)}{5ln(2)-2ln(3)}[/tex]
[tex]x = \frac{1.791}{5(0.693)-2(1.098)}[/tex]
[tex]x = \frac{1.791}{3.465-2.196} \\[/tex]
[tex]x = \frac{1.791}{1.269}[/tex]
[tex]x = 1.411[/tex]
Value of x is 1.411
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Elaine roll 2 fair dice . What i the probability of both dice howing a prime number
The probability of both the dice showing prime numbers is 1/4.
Prime numbers:
The numbers which have only two factors, one and itself are known as prime numbers.
A dice has 6 faces numbering from 1 to 6.
Prime numbers from 1 to 6 are 2, 3, and 5.
Probability of one dice showing a prime number
= (number of favorable outcomes) / (total number of outcomes)
= 3/6
= 1/2
Probability of two dice showing a prime number = (1/2) x (1/2)
= 1/4
Therefore, the probability of both the dice showing a prime number is 1/4.
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teacher: how can we change the base of a logarithm? student:
We can change the base formula by:
logₐ b = logₓ a /logₓ b
OR
logₓ a, logₓ b = logₓ a
The change of base formula is used to change the base of a logarithm. We know that "log" stands for a logarithm of base 10 and "ln" stands for a logarithm of base e. But there is no option to calculate the logarithm of a number with any other bases other than 10 and e.
The change of base formula solves this issue of changing base from e to 10, and from base 10 to e. Also, it is used in solving several logarithms problems.
Base Formula: -
The change of base formula is used to write a logarithm of a number with a given base as the ratio of two logarithms each with the same base that is different from the base of the original logarithm. This is a property of logarithms. You can see the change of base formula here.
Change of base formula
logₐ b = logₓ a /logₓ b
OR
logₓ a, logₓ b = logₓ a
Change of Base Formula
Change of base formula can be represented as follows. Here the base of the given logarithm is also changed to a logarithm with a new base. The basic logarithm with a base is transformed to two logarithms with a new and same base. The change of base formula is:
logₐ b = [logₐ x] / [logₐ y]
In this formula,
The argument of the logarithm in the numerator is the same as the argument of the original logarithm.The argument of the logarithm in the denominator is the same as the base of the original logarithm.The bases of both logarithms of numerator and denominator should be the same and this base can be any positive number other than 1.Change of Base Formula Derivation
Change of base formula derivation can be understood from the following steps. Let us assume that
log ₐ b = p, logₙ a = q, and logₙ b = r.
By converting each of these into exponential form, we get,
a = [tex]b^{p}[/tex], a = [tex]x^{q}[/tex], and b = [tex]n^{r}[/tex]
From the first two equations,
[tex]x^{q}[/tex] = [tex]n^{r}[/tex]
Substituting b = [tex]n^{r}[/tex] (which is from third equation) here,
([tex]n^{r}[/tex])[tex]^{p}[/tex] = [tex]x^{q}[/tex]
[tex]n^{r}[/tex])[tex]^{p}[/tex] = [tex]x^{q}[/tex](Using a property of exponents)
p r = q
p = q / r
Substituting the values, we get,
logₐ b = [logₐ x] / [logₐ y]
For Example:
Evaluate the value of log₆₄ 8 using the change of base formula.
Solution:
We will apply the change of base formula (by changing the base to 10). Note that log₁₀ is same as log.
log₆₄ 8 = [log 8] / [log 64]
= [log 8] / [log 82]
= [log 8] / [2 log 8] [∵ log am = m log a]
= 1 / 2
Answer: log₆₄ 8 = 1 / 2
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aaliyah went into a grocery store and bought 5 peaches and 6 mangos, costing a total of $17.75. tristan went into the same grocery store and bought 2 peaches and 3 mangos, costing a total of $8. write a system of equations that could be used to determine the price of each peach and the price of each mango. define the variables that you use to write the system.
Answer:
Step-by-step explanation:
Define Variables:
Let p= the price of each peach
Let m=the price of each mango
One peach costs $p, so 5 peaches cost 5p. One mango costs $m, so 6 mangos cost 6m. The total cost 5p+6m equals $17.75:
5p+6m=17.75
Likewise, if 2 peaches and 3 mangos cost $8, then:
2p+3m=8
Write System of Equations:
5p+6m=17.75
2p+3m=8
System of equations that could be used to determine the price of each peach and the price of each mango is 5p + 6m = 17.75 and 2p + 3m = 8.
Let p= the price of each peach
Let m=the price of each mango
One peach costs $p, so 5 peaches cost 5p. One mango costs $m, so 6 mangoes cost 6m. The total cost 5p+6m equals $17.75:
5p+6m=17.75
Likewise, if 2 peaches and 3 mangoes cost $8, then:
2p+3m=8
System of Equations:
5p+6m=17.75
2p+3m=8
Therefore System of equations that could be used to determine the price of each peach and the price of each mango is 5p + 6m = 17.75 and 2p + 3m = 8.
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Mrs. Singh is making snack packs for her class to eat on their field trip. She estimates that she will need 35 snack packs. The day of the field trip 4 students are absent and Mrs. Singh actually only needs 31 snack packs. What is Mrs. Singh's percent error?
Singh percent error is approximately 13%.
What is percent error?Percent error is the difference between estimated value and the actual value in comparison to the actual value and is expressed as a percentage.
Mrs. Singh is making snack packs for her class to eat on their field trip. She estimates that she will need 35 snack packs. The day of the field trip 4 students are absent and Mrs. Singh actually only needs 31 snack packs.
Therefore, Singh's percent error can be calculated as follows:
percent error = 35 - 31 / 31 × 100
percent error = 4 / 31 ×100
percent error = 400 / 31
percent error = 12.9032258065
percent error ≈ 13%
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-3/10 + 1 = 10 plsss
Please help me!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
-24
Step-by-step explanation:
-3[-4(3-10)-12]/-2(-1)
-3[-4(-7)-12]/2
-3[28-12]/2
-3[16]/2
-48/2
-24
Hopes this helps
What is the value of (−13)4?
52
−52
28,561
−28,561
PLEASE HELP I DONR UNDERSTAND DENSITY CURVES AT ALL
As per the given graph, the correct statement is option (A) The median of the density curve is 3.
Median:
Basically, median refers the middle value in a set of data.
And it can be obtained by organize and order the data from smallest to largest. And to find the midpoint value, divide the number of observations by two. And then if there are an odd number of observations, round that number up, and the value in that position is the median.
Given,
Here we have the graph.
Now, we have to identify in with of the option is correct according to the given graph.
While we looking into the given graph,
We have identified that it form the triangle and as the middle point as 3.
So, based on this fact me have identified that the median density of the curve is 3.
Therefore, the option (A) The median of the density curve is 3.
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PLEASE HELP ME I FEEL LIKE THIS SHOULD BE SUPER EASY BUT MY BRAIN CAN NOT RN
Answer:
x = 62
y = 41
Step-by-step explanation:
y + 21 = x
x + y + 77 = 180
2y+77 = 180
2y = 82
y = 41
x = 62
Every complex number can be written in the form a+bi. For the complex numbers 8-4i, identify the values of a and b
Answer:
C
Step-by-step explanation:
Describe the transformations that map the
function y = 8* onto each function.
b) y = 84x
d) y = 8-2x
a) y = ( 1⁄2 8×18x
c) y = -8x
In the first function have vertical compression by 1/2, in second function have horizontal compresion by 1/4, in third compression have Vertical reflection and in fourth function have Horizontal reflection and horizontal compression by 1/2.
In the given question we have to find the transformations that map the function y = [tex]8^x[/tex] onto each function.
Since we have to find the transformation, so we know that in a transformation;
The transformation from the first equation to the second one can be found by finding a, h and k for each equation.
[tex]y=ab^{x-h}+k[/tex]
The horizontal is define by the value of h. The horizontal shift is defined as:
g(x)=f(x+h) - The graph is shifted to the left h units.
g(x)=f(x−h) - The graph is shifted to the right h units.
Horizontal Shift: None
The vertical shift define on the value of k. The vertical shift is defined as:
g(x)=f(x)+k - The graph is shifted up k units.
g(x)=f(x)−k - The graph is shifted down k units.
Vertical Shift: None
The value of a describes the vertical stretch or compression of the graph.
a>1 is a vertical stretch
0<a<1 is a vertical compression.
(a) The given first function is [tex](\frac{1}{2})8^{x}[/tex].
y = [tex]8^x[/tex]
Combine [tex]8^x[/tex] and 1/2.
y = [tex]8^x[/tex]/2
Assume that
y = [tex]8^x[/tex] is f(x)=[tex]8^x[/tex] and y= [tex](\frac{1}{2})8^{x}[/tex] is g(x)= [tex](\frac{1}{2})8^{x}[/tex].
On comparing the equation [tex]y=ab^{x-h}+k[/tex]
The value of a, h, and k for f(x)=[tex]8^x[/tex].
a=1, h=0, k=0
The value of a, h and k for g(x)=[tex](\frac{1}{2})8^{x}[/tex].
a=1/2, h=0, k=0
Since the value of h and k so tnere is no horizontal and vertical shift.
SInce the value of a changes from 1 to 1/2 and 1/2 is greater that 0 but less than 1 so there is vertical compression by 1/2.
(b) The given second function is [tex]8^{4x}[/tex].
y= [tex]8^{4x}[/tex] is g(x)= [tex]8^{4x}[/tex].
On comparing the equation [tex]y=ab^{x-h}+k[/tex]
The value of a, h and k for g(x)=[tex]8^{4x}[/tex].
a=1/4, h=0, k=0
Parent Function: f(x)=8^x
So, Horizontal Shift: None, Vertical Shift: None, Reflection about the x-axis: None, Vertical Compression or Stretch: None, horizontal compresion by 1/4.
(c) The given third function is [tex]-8^{x}[/tex].
y= [tex]-8^{x}[/tex] is g(x)= [tex]-8^{x}[/tex].
The value of a, h and k for g(x)=[tex]-8^{x}[/tex].
a=-1, h=0, k=0
Parent Function: f(x)=8^x
So, Horizontal Shift: None, Vertical Shift: None, Reflection about the x-axis: Reflected, Vertical Compression or Stretch: None.
Vertical reflection
(d) The given fourth function is [tex]8^{-2x}[/tex].
y= [tex]8^{-2x}[/tex] is g(x)= [tex]8^{-2x}[/tex].
The value of a, h and k for g(x)=[tex]8^{-2x}[/tex].
a=-1/2, h=0, k=0
Parent Function: f(x)=8^x
So, Horizontal Shift: None, Vertical Shift: None, Reflection about the x-axis: Reflected, Vertical Compression or Stretch: None.
Horizontal reflection and horizontal compression by 1/2.
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If f (x) = 2x2 + 4x − 3, then the quantity f of the quantity x plus h end quantity minus f of x end quantity all over h is equal to which of the following?
The difference quotient for the given quadratic equation is:
d = (2h + 4x + 4)
How to get the difference quotient for f(x)?Here we have the quadratic function:
f(x)= 2x² + 4x - 3
And we want to get the difference quotient that is defined as:
d = ( f(x + h) - f(x))/(h)
Replacing our function there, we get:
d = ( 2(x + h)² + 4*(x + h) - 3 - (2x² + 4x - 3)/h
d = (2x² + 2h² + 4xh + 4x + 4h - 3 - 2x² - 4x + 3)/h
d = (2h² + 4xh + 4h)/h
d = (2h + 4x + 4)
That is the difference quotient.
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I need help ASAP!!!!!!!
Step-by-step explanation:
in that setup they will both explode after traveling the same distance.
A is just going faster and has to launch therefore a little bit later.
so, we need to make an equation based on distance traveled and find in that process the number of seconds needed to travel that distance.
speed is distance/time, so we need to multiply speed by time to get distance.
x = seconds for B
x - 0.25 = seconds for A
A is launched after B but explodes at the same time.
so, A's trip is of shorter time than B's trip.
(x - 0.25)×360 = x×320
360x - 90 = 320x
40x - 90 = 0
40x = 90
4x = 9
x = 9/4 = 2.25 seconds
both fireworks will explode 2.25 seconds after B launches (and 2.25 - 0.25 = 2 seconds after A launches).
the explosion will be at
320×2.25 = 360×2 = 720 feet height.
1) How long will it take for the population of a certain country to double if its annual growth rate is 2%? Round to the nearest year.
Answer:
For example, a population with a 2% annual growth would have a doubling time of 35 years.Mar 24, 2015
Step-by-step explanation:
there are 32 students in categories a and b combined; 24 are in a, and 24 are in b. how many are in both a and b?
The number of students that are in both the Categories A and B are 16 students.
In the question ,
it is given that ,
the total number of students in category A and category B is 32 students .
which is represented as A union B ,
that is n(AUB) = 32 ,
the number of students in category A = n(A) = 24
the number of students in category B = n(B) = 24
we need to find the number of students that are in both category ,
that is n(A∩B) .
we know that ,
n(AUB) = n(A) + n(B) - n(A∩B)
Substituting the values , we get
n(A∩B) = 24 + 24 - 32
= 48 - 32
= 16
Therefore , The number of students that are in both the Categories are 16 students.
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13) You have $80 and your sister has $160. You are saving
$7 per week and your sister is saving $5 per week. In
how many weeks you and your sister will have the same
amount of money? Write an equation and solve.
Answer: 30 weeks
Step-by-step explanation:
let w = number of weeks
you have = 60 + 7w
she has = 120 + 5w
60+7w = 120 + 5w
7w-5w = 120-60
2w = 60
w = 30 weeks
What is one over four to the fifth power?
one over one thousand twenty-four
one over six hundred twenty-five
five over twenty
six over nine
Drag the numbers below to put them in order from least to greatest:
6.426.42 6.536.53 6.4976.497 6.66.6 6.4536.453 6.486.48
The numbers below to put them in order from least to greatest will be 6.42, 6.453, 6.486, 6.497, 6.53, and 6.66.
What is number?A number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56, etc. are the numbers.
It is given that the numbers are,6.42,6.53,6.497,6.66,6.453,6.486.
Ascending order refers to a list of numbers that are arranged from least to greatest. The numbers are arranged in ascending order in this form. The first figure must be less than the second figure. It is referred to in descending order when the numbers are listed from greatest to least.
Thus, the numbers below to put them in order from least to greatest will be 6.42, 6.453, 6.486, 6.497, 6.53, and 6.66.
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On a straight road, Jorge is 7 kilometers east of Peter, Jason is
10 kilometers west of Juan, and Juan is 13 east of Peter. how
many miles is Jorge from Jason?
Answer:
7x10x13=910=910 kilograms
Step-by-step explanation:
What is the rectangular form of Θ = 3π/4?
x − y = 0
x − y = 1
x + y = 0
x + y = 1
The rectangular form of Θ = 3π/4 will be; y + x = 0.
What are Complex value?Complex value z is written in a rectangular form as z = x+iy where (x, y) is the rectangular coordinates.
On converting the rectangluar to polar form of the complex number;
x = rcosθ and y = rsinθ
z = r(cosθ+isinθ)
r is the modulus of the complex number and θ is the argument
r =√x²+y² and θ = tan⁻¹y/x
Given the Θ = 3π/4
Therefore, θ = tan⁻¹y/x = 3π/4
y/x = tan (3π/4)
Now multiply both side by x
yx/x = tan (3π/4) x
y = tan (3π/4) x
Thus, y = -x
in rectangular form y + x = 0
Hence, the rectangular form of Θ = 3π/4 will be; y + x = 0.
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a baseball diamond is a square with side 90 feet. if a batter hits the ball and runs towards first base with a speed of 25 ft/sec, at what speed is his distance from second base decreasing when he is two thirds of the way to first base?
The rate when his distance from second base changes and it is two third of the way to first base is - 13.86 feet/s.
let us consider the following values
distance between batter to Second base = d feet
distance between batter to First base
= x feet
distance between first to second base
= 90 feet
Using the Pythagorean theorem:
d² = x² + 90²
Knowing that the velocity of the bat to first base is 25 ft/s,
the distance x can be written as: x
= 90 - 25t
The equation for is,d² = 90²+(90 -25t)²--(1)
we want to find the rate of change of d.
let it be d' and from implicit differentiation:
2d.d' = 2(90-24t) × (-25)
d' = -50(90 - 25t) / (2d)
d' = -25 (90 - 24t) / d ---(*)
We can determine t and d from the fact that the batter is two third to his first base: d = √90^2 + 60^2 = √1 = 108.2 feet
putting the values of d in (1) we get,
=> 90 - 25t = 60 => 25t = 30 => t = 6/5.
Substitute d' in the formula equation (*)
d' = -25 (90 - 24t) / d = -25(90-30)/108.2
d'= - 13.86
d' = - 13.86 feet/s
negative sign means decreasing distance from second base (as it approaches the first
bases, it approaches the second base).
Hence,The required speed is 13.86 feet/s
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Finding Angle Measures When Parallel Lines Are Cut By a Transversal
which of the following is not true of a chi squared test?(a) a chi-squared test can be used if one of the sample cells has a value of less than five
(b) the Chi-square test can be used to test how likely it is that an observed distribution is due to chance.
(c) a chi-square test can be used to analyze nominal data
(d) a chi-squared test can be used to test the probability of independence of a distribution of data
A) Chi-square test can be used if one of the samples has a value of less than five is the correct option.
Chi-square distribution and Chi-square test for independence:
A Chi-square distribution is the sum of squares of the standard normal deviates. The Chi-square test can be used for checking the association between categorical variables.The test can be used to decide whether the effect of one categorical data is dependent on the other variable or not on the basis of the critical value and p-value. The expected frequency of each categorical variable is calculated to compute the test statistic.The assumptions for the chi-square test are:
The frequency of each cell should be at least or more than 5.The variables should be categorical in nature and the observations should be independent of each other.Chi-square test can be used to analyze the nominal or categorical data. It can be used to test whether the observed data fits well with the expected frequency or not. It is used to test the independence of the data distribution by calculating probability.Hence, options (b), (c), and (d) are the assumptions that are true for chi-square test. Therefore, the options (b), (c), and (d) are considered incorrect.
The Chi-square test of independence can be used only if none of the frequencies of the sample cell is less than five.Hence, option (a), that is, “a Chi-square test can be used if one of the samples has a value of less than five” is the correct option.
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a pole that is 3m tall casts a shadow that is 1.4m long. at the same time, a nearby tower casts a shadow that is 39.5m long. how tall is the tower? round your answer to the nearest meter.
The nearby tower that casts a shadow that is 39.5 m long is 85 m tall.
Ratio is the relationship between two quantities, normally expressed as the quotient of one divided by the other.
The ratio of the shadow of a pole to its length is 1.4 m : 3 m.
At the same time, the ratio of the shadow of a tower to its length should also be equal to the ratio of the shadow of a pole to its length, which is 1.4 : 3.
Let x = length of the tower
Using proportion, determine the length of the tower by solving for x.
1.4 : 3 = 39.5 m : x
x = 39.5(3)/1.4
x = 84.64
Round off to the nearest meter.
length of the tower = 85 meters
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In the function y = |x² - 4|, for
how many values of x does y = 3?
Answer:
4 answers
Step-by-step explanation:
y = |x² - 4|
3 = |x² - 4|
3 = x² - 4 and -3 = x² - 4
3+4=x² - 4 + 4 and -3+4=x² - 4 + 4
7=x² and 1=x²
x=[tex]\sqrt{7}[/tex] and x=-[tex]\sqrt{7}[/tex] since x²=7
x=-1 and x=1 since x²=1
x= -[tex]\sqrt{7}[/tex], [tex]\sqrt{7}[/tex], -1, 1 ==> 4 answers
Select the correct answer.
Which graph represents this equation?
y − 4 = -3(x + 5)
A. The first graph
B. The second graph
C. The third graph
D. The last graph
( I know it is not the third graph)
A rectangular dining room has a perimeter of 24 meters. Its area is 35 square meters. What are the dimensions of the dining room? IN NEED ASAP CLASS IS ABOUT TO END
The dimensions of the rectangle which form the dining room is 7 by 5 meters.
The perimeter of the rectangle is 24 meters.
The total length of a shape's boundaries is its perimeter. The total lengths of all other edges and sides are added to find a shape's perimeter.
Let the length be a and the width be b.
Hence 2(a + b) = 24
or, a+b = 12
Now the area of the rectangle is given as 35 square meters.
Therefore ab = 35
now we will use these two equations to find the dimension of the rectangle
a+b = 12
or, a = 12 - b
again:
ab = 35
or, (12 - b)b = 35
or, 12 b - b² = 35
or, - b² +12b -35 = 0
or, b² - 12b + 35 = 0
or, (b-7) (b-5) = 0
either b = 7 or b = 5 .
Therefore the value of a from the equations is 5 or 7.
Therefore the dimensions of the dining room are 7 by 5 meters.
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the average starting salary of graduates of a large university (lu) is $20,000 with a standard deviation of $8,000. furthermore, it is known that the starting salaries are normally distributed. if 189 of the graduates have salaries of at least $32,240, how many students graduated from this university?
Total students who graduated this year from this university is 3000.
This is a normal distribution problem with
Mean , μ = $20,000
Standard deviation, σ = $8,000
If 189 of the recent graduates have salaries of at least $32240.
Then, We first find the percentage of LU graduates with salaries more than $32240.
Required probability = P(x ≥ 32240)
We first normalize or standardize $32,240, then as we know,
z = (x - μ)/σ
= (32240 - 20000)/8000 = 1.53
The required probability:
P(x ≥ 32240) = P(z ≥ 1.53)
We'll use data from the normal probability table for these probabilities
P(x ≥ 32240) = P(z ≥ 1.53) = 1 - P(z < 1.53)
= 1 - 0.93699
= 0.06301
= 6.301%
So, 6.301% of the graduates this year = 189
Total Number of graduates this year = (189/0.06301) = 2999.5 = 3000 graduates this year.
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