GIVEN: An exterior stud wall with brick veneer is 11 ft tall and 40 ft long. 25 % of the area of the wall is windows (glass, frame and sash). FIND: Total weight of the wall and the average dead load in lb/ft of the length of the wall (per foot of wall length) that the wall exerts on the floor.

Answer:

894 mi²

Step-by-step explanation:

the area of parallelogram= base x height= 24mi x 37.25mi = 894 mi²

We require median, interquartile range, outliers, minimum and maximum value.

What are statistics?

Statistics is a branch of mathematics that deals with the collection, analysis, interpretation, presentation, and organization of data.

From the upper box plot representing the top 12 men's long jumpers at the U.S. Qualifying meet, we can gather the following pieces of information:

The median (middle value) of the data is around 7.6 meters, as indicated by the line in the center of the box.

The interquartile range (IQR), which is the range between the first and third quartiles, is approximately 0.4 meters, as indicated by the height of the box.

There are some outliers or values that fall outside the range of the box, which is represented by the dots or asterisks outside the box.

The minimum and maximum values for the data are around 7.3 meters and 8.0 meters, respectively, as indicated by the lower and upper ends of the whiskers.

From the lower box plot representing the distances achieved in the men's long jump at the 2012 Olympic games, we can gather the following pieces of information:

The median (middle value) of the data is around 8.0 meters, as indicated by the line in the center of the box.

The interquartile range (IQR), which is the range between the first and third quartiles, is approximately 0.5 meters, as indicated by the height of the box.

There are some outliers or values that fall outside the range of the box, which is represented by the dots or asterisks outside the box.

The minimum and maximum values for the data are around 7.5 meters and 8.4 meters, respectively, as indicated by the lower and upper ends of the whiskers.

The main difference between the two box plots is the median value, which is 0.4 meters apart and the IQR for the Olympic games is slightly bigger than the Qualifying meet.

Hence, we require median, interquartile range, outliers, and minimum and maximum values.

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We require median, interquartile range, outliers, and minimum and maximum values.

What are statistics?

Statistics is a branch of mathematics that deals with the collection, analysis, interpretation, presentation, and organization of data.

From the upper box plot representing the top 12 men's long jumpers at the U.S. Qualifying meet, we can gather the following pieces of information:

The median (middle value) of the data is around 7.6 meters, as indicated by the line in the center of the box.

The interquartile range (IQR), which is the range between the first and third quartiles, is approximately 0.4 meters, as indicated by the height of the box.

There are some outliers or values that fall outside the range of the box, which is represented by the dots or asterisks outside the box.

The minimum and maximum values for the data are around 7.3 meters and 8.0 meters, respectively, as indicated by the lower and upper ends of the whiskers.

From the lower box plot representing the distances achieved in the men's long jump at the 2012 Olympic games, we can gather the following pieces of information:

The median (middle value) of the data is around 8.0 meters, as indicated by the line in the center of the box.

The interquartile range (IQR), which is the range between the first and third quartiles, is approximately 0.5 meters, as indicated by the height of the box.

There are some outliers or values that fall outside the range of the box, which is represented by the dots or asterisks outside the box.

The minimum and maximum values for the data are around 7.5 meters and 8.4 meters, respectively, as indicated by the lower and upper ends of the whiskers.

The main difference between the two box plots is the median value, which is 0.4 meters apart and the IQR for the Olympic games is slightly bigger than the Qualifying meet.

Hence, we require median, interquartile range, outliers, and minimum and maximum values.

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Answer:  15cm2

Step-by-step explanation:

5cm+4cm+6cm=15cm2

The number of groups of like terms is 3

An algebraic expression is defined as an expression made up of terms, variables, coefficients, constants, and factors.

These algebraic expressions are also composed of mathematical operations, such as;

A term can be described a single variable, number or numbers and variables that are multiplied together.

From the information given, we have the terms;

3x¹³, 9x¹⁰, -1x¹³, -16x¹³, 3x¹⁰, 3¹³, 10x¹⁰, 13x¹⁰

The similar terms are;

3x¹³,  3x¹⁰,  3¹³

Hence, the number is 3

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Answer:

12%

Step-by-step explanation:

The y-intercept in this situation means A. When the cab travels 0 miles, the total fee will be $14.00.

The formula to find the y-intercept is y = f(x), where x = 0, and then solve for y.

The equation for a linear relationship is y = mx + b, where x is the independent variable, y is the dependent variable, m is the slope of the line, and b is the y-intercept.

Cab Fare

Number of Miles Total Fee

2                             $17.00

5                             $21.50

7                            $24.50

10                          $29.00

15                          $36.50

Difference between 7 and 5 = 2

Difference between $24.50 and $21.50 = $3

Variable cost per mile (Slope) = Rise/Run

= $1.50 ($3/2)

y = mx + b

y-intercept, b = 24.50 - 7(1.5)

= 14

= $14.00

Thus, the y-intercept in this situation means Option A while the slope shows that for every additional mile, the total fee increases by $1.50.

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Answer:

The y-intercept in this situation means A. When the cab travels 0 miles, the total fee will be $14.00.

Step-by-step explanation:

Answer:

[tex] \displaystyle{ y= - \dfrac{ 3}{2} x+ 1}[/tex]

Step-by-step explanation:

Slope-intercept is in form of y = mx + b where m is slope and b is y-intercept. We simply solve for y in term of x and then we will obtain the slope-intercept form.

Given the linear equation:

[tex] \displaystyle{3x + 2y = 2}[/tex]

First, subtract both sides by 3x:

[tex] \displaystyle{3x + 2y - 3x= - 3x + 2} \\ \\ \displaystyle{2y = - 3x + 2}[/tex]

Then divide both sides by 2:

[tex] \displaystyle{ \dfrac{2y}{2} = \dfrac{ - 3x + 2}{2}} \\ \\ \displaystyle{ y = \dfrac{ - 3x + 2}{2}}[/tex]

Separate fractions (Simplify):

[tex] \displaystyle{ y= \dfrac{ - 3x}{2} + \dfrac{2}{2}} \\ \\ \displaystyle{ y= - \dfrac{ 3}{2} x+ 1}[/tex]

And we have finally converted the equation to slope-intercept form.

The interquartile range of the data decreases when the eighth day's amount is included in the data is true.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

Joanna set a goal to drink more water daily.

The number of ounces of water she drank each of the last seven days is

60, 58, 64, 64, 68, 50, 57

On the eighth day, she drinks 82 ounces of water.

Raw data:      [60,58,64,64,68,50,57,82],

Sorted data:  [50,57,58,60,64,64,68,82]

Sample size = 8 (even)

mean  = 62.875

median  = (60+64)/2 = 62

1st quartile   = (57+58)/2 = 57.5

3rd quartile  = (64+68)/2 =  66

IQR = 66 - 57.5 = 8.5

Data without the eight day's measurement.

Raw data:      [60,58,64,64,68,50,57]

Sorted data:  [50,57,58,60,64,64,68]

Sample size = 7 (odd)

mean            = 60.143

median         = 60

1st quartile   = 57

3rd quartile = 64

IQR = 64 -57 = 7

Hence, the interquartile range of the data decreases when the eighth day's amount is included in the data is true.

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Answer: It's just

The interquartile range of the data decreases when the eighth day's amount is included in the data.

Step-by-step explanation: The question asks you to select ALL correct answers, but there is only one correct answer.

The number of units that tile will he need to surround his pool is 19.82units.

this question is of quadratic equation ,

The number of units of tile simply refers to the perimeter.

So, we need to find all the sides of the rectangle.

Now, we have,

AB = 4.24 units

BD = 7.07 units.

So, we can find AD using pythagoras theorem.

So,

(AD)² + 4.24² = 7.07²

(AD)² + 17.978 = 49.985

(AD)² = 49.985 - 17.978

AD = √32.007

AD = 5.66 units

AD = BC = 5.66 units

Likewise, AB = DC = 4.24 units

Thus,

perimeter = 2(5.66) + 2(4.24) = 19.8 units.

The number of units that tile will he need to surround his pool is 19.82units.

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Answer:

9 in.

Step-by-step explanation:

the sum of two sides in a triangle is always longer than the 3rd side. so 9 is the only answer that fits this condition.

Answer:

It will take him 9 weeks to be able to buy the bike.

Cristiano is saving money to buy a bike that costs $189. He saved $99 so far. He plans on saving $10 each week. The correct answer is 9 weeks.

So, we have:

- Cost of the bike = $189

- Money saved = $99

- Money saving each week = $10

We are trying to find how many weeks will he have enough money to the bike.

So, we are going to multiply and add the numbers to find are answer:

→ (n × $ 10) + $ 99 = $ 189

→ n × $ 10 = $ 90 n = $ 90 $ 10 n=9 weeks.

Therefore, Cristiano is saving money to buy a bike that costs $189. He saved $99 so far. He plans on saving $10 each week. The correct answer is 9 weeks.

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The complement of the event: "drawing a red card" is the last option:

"Selecting a black card"

The complement of an event is the set of all the outcomes such that the original event is false.

For example, the complement of drawing a red card, would be "not drawing a red card"

We know that there are two types of coloes, black and red.

Then "drawing a black card" is equivalent to "not drawing a red card"

Thus, the complement is the last option:

"Selecting a black card"

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The number that belongs to both sequences is 26.

The formula known as the nth term allows us to locate any term in a series. The letter "n" stands for "number."

By changing the term number's value, we can create a series that uses the nth term (n).

To find the 10th term we would follow the formula for the sequence but substitute 10 instead of ‘n‘; to find the 50th term we would substitute 50 instead of n.

We have two sequences, let's call one as A and the other as B.

The n-th term of sequence A is written as:

aₙ = 3*n^2 - 1

the nth term of sequence B is written as:

bₙ = 30 - n^2

We want to find a term that belongs to both sequences, (it can be for different integers, we can use n for sequence A and x for sequence B)

Then we want to find:

aₙ = bₓ

where n and x are integer numbers.

Then we will heave:

3*n^2 - 1 = 30 - x^2

To find the pair, we could isolate one of the variables, then input different integers in the other variable and see if the outcome is also an integer.

Let's isolate n.

3*n^2 = 30 - x^2 + 1

3*n^2 = 31 - x^2

n^2 = (31 - x^2)/3

n = √(  (31 - x^2)/3)

Now let's input different values for x, and see if the outcome is also an integer, notice that x is in a negative term inside a square root, then we have only a few values of x such that the equation can be true.

Then let's start with x = 1.

n(1) = √(  (31 - 1^2)/3) = √(30/3) = √10

We know that √10 is not an integer.

now with x = 2,

n(2) = √(  (31 - 2^2)/3)  = √( (31 - 4)/3) = √(27/3) = √9 = 3

then if x = 2, we have n = 3.

Both of them are integers, then we get:

a₂ = 3*(3)^2 - 1 = 27 - 1 = 26

b₃ = 30 - 2^2 = 30 - 4 = 26

Therefore, The number that belongs to both sequences is 26.

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Answer:

x = 2[tex]\sqrt{6}[/tex]

Step-by-step explanation:

[tex]\sqrt{24}[/tex] = [tex]\sqrt{(2)(2)(2)(3)}[/tex]  We can pull out a pair of 2's

2[tex]\sqrt{(2)(3)\\}[/tex] = 2[tex]\sqrt{6}[/tex]

The 30th term of the arithmetic sequence is 265

What is an arithmetic sequence in math?

This is an arithmetic sequence since there is a common difference between each term. In this case, adding 9 to the previous term in the sequence gives the next term. In other words,   [tex]a_{n}[/tex]= [tex]a_{1}[/tex]+ d ( n - 1 )

Arithmetic Sequence: d = 9

This is the formula of an arithmetic sequence.

[tex]a_{n}[/tex] =  [tex]a_{1}[/tex] + d ( n - 1 )

Substitute in the values of   [tex]a_{1}[/tex] = 4 and  d = 9

 [tex]a_{n}[/tex]= 4 + 9 ( n - 1 )

[tex]a_{n}[/tex]= 4 + 9n - 9

[tex]a_{n}[/tex] = 9n - 5

.30th term =   [tex]a_{n}[/tex] =   [tex]a_{1}[/tex]+ d ( n - 1 )

=  [tex]a_{30}[/tex]= 4 + 9 ( 30 -1 )

   [tex]a_{30}[/tex]=   4 + 9 x 29

  [tex]a_{30}[/tex]= 265

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The side lengths of a right-angle triangle can be calculated using the Pythagorean Theorem. Which states that the square of the hypotenuse is equal to the sum of squares of the other sides in the triangle.

[tex]a^2+b^2=c^2[/tex]

rearranging the equation can help calculate the third side:

[tex]c^2-a^2=b^2[/tex]

[tex](5)^2-(4)^2=b^2[/tex]

[tex]25-16=b^2[/tex]

[tex]9=b^2[/tex]

[tex]\sqrt{9}=\sqrt{b^2}[/tex]

[tex]{ {{b_1=+3} \atop {b_2=-3}} \right.[/tex]  

note: a length can never be negative so never take into account a negative answer

b = 3

Based on the data, the statement that is most likely correct is D. In Grade 9, 18% of students liked running.

The ratio (fraction or proportion) of the number of times a data value appears in the set of all outcomes to the total number of outcomes is known as the relative frequency.

From the information, the Dean collected data on the favorite sports of the students of two grades.

Here, the table shows the relative frequencies of rows for the data collected:

Swimming      Running Volleyball Row     totals

Grade 8          0.17       0.24              0.05     0.46

Grade 9           0.14       0.18             0.22      0.54

Column totals 0.31      0.42              0.27        1

In the table, Grade 9, 18% of students liked running. This is Illustrated above. The correct option is D.

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The general rule is power of power. It can be represented by (x^m)^n = x^mn.

What is an exponent?

The way of representing huge numbers in terms of powers is known as an exponent. Exponent, then, is the number of times a number has been multiplied by itself.

Now complete the given table:

Problem to           First repeated        second repeated               Power of

simplify                 multiplication         multiplication              the form of a^n

(2²)³                         2²×2²×2²               2×2×2×2×2×2                           2⁶

(5³)⁴                     5³ × 5³ × 5³ × 5³      5×5×5×5×5×5×5×5×5×5×5×5    5¹²

(7³)⁴                     7³ × 7³ × 7³ × 7³      7×7×7×7×7×7×7×7×7×7×7×7        7¹²

((3x)²)³                   (3x)²×(3x)²×(3x)²    3x×3x×3x×3x×3x×3x                    (3x)⁶

(4y²)³                   (2y)²×(2y)²×(2y)²    2y×2y×2y×2y×2y×2y                    (2y)⁶

The general rule is  (x^m)^n = x^mn. The name of the rule is power of power.

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The height of vase b is 34.56 cm.

In mathematics, volume is the space taken by an object.

V=pi*r²*h

Here, given that,

vase A has height 20cm =H

and volume 1500^3. =V

And, A & B similar vases.

Again, vase B has volume 2592cm^3 =v

let, h, the height of vase b.

both radius are equal

so, we get,  V/pi*H = v/pi*h

i.e. 1500/20=2592/h

so, h= 34.56 cm

Hence, the height of vase b is 34.56 cm.

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The partial fraction expansion of (x³ + 4)/ ((x² - 1)(x² + 3x + 2)) is -3/ 4(x + 1) + 5/12(x - 1) + 4/3(x + 2) - 3/ 2(x + 1)². So the coefficients A = -3/4, B = 5/ 12, C = 4/3 and D = -3/2.

A partial fraction expansion is a way of expressing a rational function (a function that can be written as the ratio of two polynomials) as the sum of simpler fractions, each with a numerator that is a constant or a simple polynomial. The process of finding the partial fraction expansion of a rational function is also known as partial fraction decomposition.

The denominator is

(x² - 1)(x² + 3x + 2) = (x² - 1)(x² + x + 2x + 2)

(x² - 1)(x² + 3x + 2) = (x + 1)(x - 1)(x + 1)(x + 2)

So by  partial fraction expansion

(x³ + 4)/ ((x² - 1)(x² + 3x + 2)) = (x³ + 4)/ ((x + 1)(x - 1)(x + 1)(x + 2))

(x³ + 4)/ ((x + 1)(x - 1)(x + 1)(x + 2)) = A/ (x + 1) + B/(x - 1) + C/(x + 2) + D/ (x + 1)²

A(x - 1)(x + 1)(x + 2) + B(x + 1)²(x + 2) + C(x + 1)²(x - 1) + D(x - 1)(x + 2) = x³ + 4

(A + B + C)x³ + (2A + 4B + C + D)x² + (-A + 5B - C + D)x + (-2A + 2B - C - 2D) = x³ + 4

Thus from coefficients of x³, x², x and 1,

A + B + C = 1

2A + 4B + C + D = 0

-A + 5B - C + D = 0

-2A + 2B - C - 2D = 4

Solving

A = -3/4, B = 5/ 12, C = 4/3 and D = -3/2

--The question is not clear, the question is given below--

"Enter (A,B,C,D) in order below if A, B, C, and D are the coefficients of the partial fractions expansion of

[tex]$$12\cdot\frac{x^3 + 4}{(x^2-1)(x^2 +3x+ 2)}[/tex]  "

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Yes, if the value of y = 0 then it makes the horizontal line.

The term horizontal line is defined as one that goes from left to right.

And here we also know that they are parallel to the x –axis in the coordinate plane.

And the horizontal line has a slope of zero.

While we looking into the move along the right of the line, then it does not rise or fall at all.

Here we have to the that the following factors are also included in feature:

In as the horizontal line is parallel to the x-axis and it is parallel to the horizon.

Where as the horizontal line is a sleeping line and it is also defined as can be a sleeping, standing, or a slanting line.

Where the horizontal line is perpendicular to the y-axis.

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Answer:The Surface Area of Pyramid is 105 cm².

Step-by-step explanation:

What is Surface Area of Pyramid?

If “P” is the base perimeter, “l” is the slant height, and “B” is the base area, then the total surface area of the regular pyramid formula is given by (½)Pl + B Square units.

Given:

slant height, l= 8 cm

So, the base Perimeter = 4 x 5

                                     = 20 cm

Now, area of the base = 5 cm x 5 cm

                                    = 25 cm²

Then,  surface area of a square pyramid

= 1/2 x slant height x base perimeter + area of base

= 1/2 x 8 x 20 + 25

= 80 + 25

= 105 cm²

Answer:

The hundreds place

Step-by-step explanation:

143, first digit is , 1 is in the hundreds place

8x-12+3x+5=180(sum of straight angles)

8x+3x-12+5=180

11x-19=180

11x=180-19

11x=161

x=161÷11

Step-by-step explanation:

sum of straight angles are 180

A guy wire is attached to an upright pole 6 meters above the ground. If the wire is anchored to the ground 5 meters from the base of the pole 7.81 m long is the wire. This can be solved by using the concept of Pythagoras theorem.

The widely accepted geometric principle known as the Pythagorean Theorem states that the square on the hypotenuse of a right triangle equals the sum of the squares on its legs (the side opposite the right angle).

The hypotenuse side of a right-angled triangle's square is equal to the sum of its other two sides, according to Pythagoras' Theorem. The perpendicular, base, and hypotenuse of this triangle are its three designated sides.

Let, assume ΔABC is a right-angled triangle

where, AC = 6m be the pole.

AB = 5m is the length of a guy wire and is attached to stake B

By Pythagoras theorem,

BC² = AB² + AC²

or, BC² = (5)² + (6)²

or, BC² = 36 + 25

or, BC =  √61 m

or, BC = 7.81 m

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2x 11 is congruent to 13 mod 16, if 3x 7 is congruent to 2 mod 16.

If 3x 7 is congruent to 2 mod 16, then 2x 11 is congruent mod 16 to what integer between 0 and 15, is inclusive.

To find the solution of 2x 11 congruent mod 16, given 3x 7 congruent to 2 mod 16, we can first use the given equation to find the value of x and then substitute it into the second equation.

First, we can solve for x in the given equation:

3x 7 is congruent to 2 mod 16

3x is congruent to 2 mod 16

x is congruent to 6 mod 16

Now that we know that x is congruent to 6 mod 16, we can substitute it into the second equation:

2x 11 is congruent to 2(6) 11 which is congruent to 13 mod 16

So the solution is that 2x 11 is congruent to 13 mod 16.

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Answer:

9 days

Step-by-step explanation:

We know

Elizabeth has 214 gallons of milk; she drinks 23 of the quantity each day.

We take

214 / 23 = 9 days

So, she can drink in 9 days

The side length of each square represent for the rectangle to correctly represent (0, 3) · (0, 5) is 1 units.

A rectangle represented by (0, 3) · (0, 5) has length 3 units and breadth 5 units. To represent that rectangles with minimum number of squares of same size, we calculate the highest common factor.

Highest Common Factor is a mathematical concept used to find the greatest number that divides two or more numbers without leaving a remainder. It is also known as the greatest common divisor (GCD) or the greatest common factor (GCF).

Highest common factor of 3 and 5 is 1 as both are prime numbers. So squares with side length 1 unit best represent the rectangle to correctly represent (0, 3) · (0, 5).

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