given: AB is congruent to CD and BC is congruent to AD Prove: AB ll CD and BC ll AD

Given: AB Is Congruent To CD And BC Is Congruent To AD Prove: AB Ll CD And BC Ll AD

Answers

Answer 1
Given

A quadrilateral ABCD with opposite pairs of sides being congruent.

To prove

Opposite sides are parallel.

Solution

We'll prove first the triangles formed by diagonal are congruent then we'll prove the angles on either side of diagonal are congruent.

The steps are:

Step  ⇒   Statement  ⇒   Reason

=============================================================

1   ⇒  AB ≅ CD and BC ≅ AD     ⇒     Given2  ⇒  AC = CA                              ⇒    Common side3  ⇒  ΔABC ≅ ΔCDA                   ⇒    Side-side-side congruence4  ⇒  ∠BAC ≅ ∠DCA                   ⇒    Corresponding angles of congruent triangles5  ⇒  ∠BAC and ∠DCA are alternate interior angles  ⇒  Definition of alternate interior angles6  ⇒  AB║CD                               ⇒   The converse of alternate interior angles theorem 7  ⇒  ∠BCA ≅ ∠DAC                   ⇒   Corresponding angles of congruent triangles8  ⇒  ∠BCA & ∠DAC are alternate interior angles  ⇒  Definition of alternate interior angles9  ⇒ BC║AD                                ⇒   The converse of alternate interior angles theorem

Related Questions

PLS HELP ME ASAP FIRST CORECT ANSWER GETS BRAINLEIST​

Answers

Answer:

The area of the shape is 68 cm².

Step-by-step explanation:

We have to calculate the areas of the rectangle and triangle separately, and then add them together.

• Area of rectangle = length × breadth

                                = 30 cm × 2 cm

                                = 60 cm²

• Area of triangle = [tex]\frac{1}{2}[/tex] × base × perpendicular height

                             = [tex]\frac{1}{2}[/tex] × 2 cm × 8 cm

                             = 8 cm²

Adding the areas together = 60 cm² + 8 cm²

                                             = 68 cm²

Belinda is thinking about buying a car for $18,500. The table below shows the projected value of two different cars for three years:
Number of years
1
2
3
Car 1 (value in dollars) 17,390 16,346.60 15,365.80
Car 2 (value in dollars) 17,500 16,500 15,500
Part A: What type of function, linear or exponential, can be used to describe the value of each of the cars after a fixed number of years? Explain your answer. (2 points)
Part B: Write one function for each car to describe the value of the car f(x), in dollars, after x years. (4 points)
Part C: Belinda wants to purchase a car that would have the greatest value in nine years. Will there be any significant difference in the value of either car after nine years?
Explain your answer, and show the value of each car after nine years. (4 points)

Answers

There is a significant value in the difference in the value of the car after nine years

The type of function (linear or exponential)?

The table of values is given as:

Years     1     2     3

Car 1 17,390 16,346.60 15,365.80

Car 2 17,500 16,500 15,500

The values of car 1 have a common ratio of 0.94; this is calculated by dividing the terms of the function

The common ratio implies that the function of car 1 is a geometric function.

The values of car 2 have a common difference of -1000.

The common difference implies that the function of car 2 is a linear function.

The function of each car type

Car 1

In (a), we have:

Common ratio, r = 0.94

The initial value is given as:

a = 18,500

So, the function of car 1 is

f(x) = 18500 * 0.94^x

Car 2

In (a), we have:

Common difference, d = -1000

The initial value is given as:

a = 18,500

So, the function of car 2 is

f(x) = 18500 - 1000x

The car with the greatest value after 9 years

This means that

x = 9

So, we have:

Car 1

f(9) = 18500 * 0.94^9

f(9) = 10600

Car 2

f(9) = 18500 - 1000 *9

f(9) = 9500

10600 is greater than 9500

Hence, there is a significant value in the difference in the value of the car after nine years

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In the formula V = s²h, if s is doubled and
h tripled, then V multiplied by

Answers

This shows that if s is doubled and h tripled, then V multiplied by 12

Volume of a cuboid

Given the formula below expressed as:

V = s²h

If s is doubled and h tripled, the new volume will ne:

V1 = (2s)² * 3h

V2 = 4s² * 3h

V2 = 12s²h

V2 = 12V

This shows that if s is doubled and h tripled, then V multiplied by 12

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Can you guys please help? The image is attached.

Answers

See below for the description of changes when the dependent and the independent variables are switched

How to determine the changes?

The table of values

When the dependent and the independent variables are switched, the values also become switched on the table.

This means that the table becomes an inverse table of the function

The scatter plot

Switching the variables implies that the original function is being reflected across the line y = x

The description in words

This description is an inverse relation of the original function

The equation

This description is an inverse equation of the original function.

If the initial equation is y = ax + c, the new equation becomes x = ay + c

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RATING BRAINLIEST Which of the following demonstrates the Distributive Property?

4(2a + 3) = 8a + 3
4(2a + 3) = 2a + 12
4(2a + 3) = 6a + 7
4(2a + 3) = 8a + 12

Answers

Answer:

D: 4(2a+3)=8a+3

Step-by-step explanation:

4x2a = 8a and 4x3 = 12

Answer:

just saying this so other can get brainliest

Step-by-step explanation:

d

can someone please help mee (20 points will give brainliest!!!)

Answers

Answer:

Step-by-step explanation:

The is a factor of -3 which makes a vertical stretch on the y-axis of the original f(x) equation making a new g(x) equation.

g(x) = a * f(b(x-h)) + k

a - vertical stretch/shrink y-axis

b - horizontal stretch/shirink x-axis

h - horizontal shift right/left

k - vertical shift up/down.

Desmos

write a quadratic function F whose zeros are 12 and 1

Answers

Answer:

[tex]f(x) = (x-12)(x-1)[/tex]

Step-by-step explanation:

So when you have a quadratic equation it can usually be expressed as: [tex]a(x-b)(x-c)[/tex] where b and x are the roots of the equation. Since it's just asking for a function whose zeroes are 12 and 1, I'm assuming it doesn't care about the stretch/compression (value of a determines that), so I'll just assume a=1. if 12 and 1 are zeroes, that means it makes one of the factors equal to 0 because is x-b = 0 then no matter the value of x-c the value of y is 0 because 0 * (x-c) will be 0. So the equation becomes [tex]f(x) = (x-12)(x-1)[/tex] plugging in 12 or 1 as x will make one of the factors 0 thus making f(x) equal to 0

(05.02)The area of the parallelogram below is ___ square meters
Numerical Answers Expected!
Answer for Blank

Answers

Step-by-step explanation:

the area of a parallelogram is

baseline × height

which is in our case

9 × 7 = 63 m²

Answer:

ayo give the other guy brainilest

Step-by-step explanation:

NOTE: Angles not necessarily drawn to scale.

Answers

Answer: 60°

Step-by-step explanation:

- the two angles created by CD and EF are vertical angles so they are equal

- one angle is 30° so the other one is 30° and it splits an existing 90° angle so 90-30 = 60 so x is 60°

hope this helps :)

Answer:

∠x=60°

Step-by-step explanation:

Add 90° and 30° then subtract by 180 to find ∠x.

How I got 30 degrees is because of the vertical angle. Vertical angles are always equal.

I got the 90 degrees from the left top side.

180 degrees is the degrees of a straight angle.

90+30=120

180-120=60

Hope this helps!

If not, I am sorry.

Please help with this!!!!

Answers

Answer:

1)

Let the number of guests = x

∴ Pin hall total charge = 500 + 15x

Bloom place total charge = 350 + 18x

2)

The charges are equal.

∴  500 + 15x = 350 + 18x

⇒ 150 = 3x

⇒ 50 = x

x = 50

This means that the charges for both halls will be equal when there are 50 guests.

Please help!!! A phone company offers two long-distance plans. The first charges a flat value of $5.00 per month plus $0.99 for each minute used, and the second charges $10.00 a month plus $0.79 for each minute used.

If x represents the number of minutes used each month, which system of equations represents the total amount of money, y, you would spend for each long-distance plan?

Answers

Answer:

C

Step-by-step explanation:

Given y = amount of money spend for the long distance plan per month

and x = minutes used each month

Note these 2 plans are in per month basis.

Plan A: Flat $5 + $0.99 Per min used (variable cost)

transform into an equation:

y = 0.99x + 5

Plan B: Flat $10 + $0.79 per min used (variable cost)

transform into equation:

y = 0.79x + 10

Put these 2 equations together, will give you the answer as C.

I need help please!!!

Answers

Based on the number of coins in the jar, the probability that Nina would not pick a penny or dime is a. 0.36.

The cost of the entire trip to the Cross family should they use the two cars is c. $107.07.

What is the probability to Nina?

This can be found as:

= Number of quarters, and nickels) / (Number of quarters, nickels, dimes, and pennies)

= (13 + 18) / (13 + 25 + 18 + 30)

= 0.36

What is the cost of gasoline to the Cross family?

= Cost of gas to first car + Cost of gas to second car

= (450/18 x 2.49) + (450 / 25 x 2.49)

= 62.25 + 44.82

= $107.07

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Solve the problems. Write the complete proof.


ONLY HAVE TO PROVE HOW BD IS PERPENDICULAR TO AC!

Answers

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. An isosceles triangle is one with two equal-length sides.

What is a triangle?

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angle of a triangle is always equal to 180°.

In ΔBAD and ΔBDC,

m∠ADB = m∠CDB {Given}

BD = BD {Common side in two triangles}

AD ≅ DC {Given}

Using the ASA postulate the two triangles are congruent. Therefore,

m∠BAD= m∠BCD.........equation 1

m∠ABD= m∠CBD

In ΔADC, AD ≅ DC {Given}, therefore, the triangle is an isosceles triangle. Thus,

m∠DAE = m∠DCE.......equation 2

Adding two of the equation 1 and 2,

m∠BAD + m∠DAE = m∠DCE + m∠BCD

∠BAC = ∠BCA

Since in ΔABC, ∠BAC = ∠BCA therefore, the triangle is an isosceles triangle, thus, AB = BC,

BE is the common side between ΔAEB and ΔCEB

Also, m∠ABD= m∠CBD

Therefore, ΔAEB ≅ ΔCEB

Now as ΔAEB ≅ ΔCEB, therefore, AE=EC,

Thus, BE is the median of the isosceles triangle ABC, and for an isosceles triangle, the median opposite to the non-common sides is the perpendicular bisector to the opposite side.

Hence, BD⊥AC.

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VERBAL
3. Explain how to interpret the initial value in a word problem that uses a linear function.

Answers

Answer:

The initial value in the word problem is the output value when input value is set to zero.

Step-by-step explanation:

In the question, it is given that a problem uses a linear function.It is required to explain how to interpret the initial value in a word problem.In order to find the initial value in a world problem, find the output value when input value is set to zero.If the initial value is marked as b for a linear function f(x), find it as follow,b = f (x=0)

Someone please help me out with this one. If LM=XY, then LM-GH=

Answers

LM=XY, then LM-GH= XY - GH and this illustrates the subtraction property of equality.

How to illustrate the information?

It should be noted that the subtraction property of equality simply implies that when the same number is subtracted form both sides, then the two sides will still remain equal.

In this case, when LM=XY, then LM-GH= XY - GH. This illustrates the subtraction property.

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Analyzing Exponential Decay Graphs
On a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases into quadrant 2. It goes through (2, one-ninth), (1, one-third), (0, 1), and (negative 1, 3).

Analyze the graph of the exponential decay function.

The initial value is
.



The base, or rate of change, is
.



The domain is

Answers

Considering the given exponential function, we have that:

The initial value is of 1.The base is of [tex]\frac{1}{3}[/tex].The domain is of all real values.

What is an exponential function?

An exponential function is modeled by:

[tex]y = ab^x[/tex].

In which:

a is the initial value, that is, the value of y when x = 0.b is the rate of change.

When x = 0, y = 1, hence the initial value is of 1. When x changes by 1, y changes by 1/3, hence the base is of 1/3. Exponential functions have no restrictions, hence the domain is of all real values.

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Answer:

On a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases into quadrant 2. It goes through (2, one-ninth), (1, one-third), (0, 1), and (negative 1, 3).

Analyze the graph of the exponential decay function.

The initial value is

✔ 1

The base, or rate of change, is

✔ 1/3

The domain is

✔ all real numbers

Step-by-step explanation:

Question 4 of 10; can someone help me.

Answers

B. Similar SSS.
they are all connecting on sides making ABC congruent to DEF.

If nicolai earns an 8 percent after tax rate of return, 9,500 today would be worth how much to nicolai in five years?

Answers

Nicolai would get worth of 13958.62 in five years for an 8% rate of return.

What is the rate of return?

The net gain or loss of an investment over a given period stated as a percentage of the investment's starting cost is known as a rate of return (RoR).

Any type of investment instrument, including real estate, bonds, equities, and fine art, can be subject to a rate of return.

You determine the percentage change from the start of the period to the end when computing the rate of return.

Initial amount=9500

Rate of return=8%

Amount after 5 years=[tex]9500*(1+\frac{8}{100}) ^{5}[/tex]

                                    [tex]=9500*(\frac{108}{100} )^{5}[/tex]

                                   [tex]\\=13958.62[/tex]

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pls help asap.............

Answers

The First graph does not have an initial Value

The second graph's solution is (3, -4)

What is Quadratic graph?

A quadratic graph is a pictorial representation of quadratic functions.

It shows the relationship between a variable on the x-axis and a variable on the y-axis.

Analysis:

The First graph did not either start from the x or y-axis so it does not have an initial value.

The second graph each mark is 0.5 on both axes so the point of intersection of the two graphs is the solution of the graphs which the x- value is 3 and the y-value is -4.

Therefore (3, -4) is the solution of the graph.

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Isla is dividing 3x3 + x2 – 12x – 4 by x + 2 using a division table.

Quotient



Divisor

3x2
– 5x
– 2
x
3x3
–5x2
–2x
+ 2
6x2
A
B

What are the missing values in the table?

Answers

The value of A and B are -10x and -4 respectively.

Division involves gathering a number of expressions into smaller forms.

The quotient is represented by the expression

Quotient= Dividend /Divisor

We have the value of the Dividend from the division table given in the question

Dividend of the Operation= A

Divisor of the Operation=2

Quotient of the Operation= -5x

As we know Quotient= Dividend /Divisor

So, -5x= A/2

multiplying 2 on both sides

⇒(-5x)2= A/2*2

⇒ A= -10x

Similarly, We have the value of the Dividend from the division table given in the question

Dividend of the Operation= B

Divisor of the Operation=2

Quotient of the Operation = -2

As we know Quotient= Dividend /Divisor

So, -2= B/2

multiplying 2 on both sides

⇒(-2)2= AB2*2

⇒ B= -4

Therefore the value of A and B are -10x and -4 respectively.

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Multiply a Polynomial by a Monomial
In the following exercises, multiply.
236. (8b − 1)b

Answers

Answer:

The given expression is (8b − 1)b.We have to multiply the given expression.Distribute the expression then simplify to determine the answer.

         (8b − 1)b = 8b*b - 1*b

                        = 8b2 - b

                         

Step-by-step explanation:

Hence the expression (8b − 1)b=8b2 - b.

what are the rates of the cyclists?​

Answers

Answer:

24 km/h and 17 km/h

Step-by-step explanation:

We know that when two cyclists are traveling together, they will meet in the same time as if one cyclist with the combined speed of the two cyclists travelled the whole length. We don't know the speeds of the cyclists, so let's assign the one with the slower speed "x", and the one with the faster speed "x+7" the combined speeds is "2x+7"

Since the speed = distance / time, we can plug in the values

2x+7=205/5
2x+7=41
2x=34
x=17
We substitute x into the equation for the speed of the cyclists

Cyclist 1's speed: x, so their speed is 17 km/h
Cyclist 2's speed: x+7, so their speed is 17 + 7, or 24 km/h

500 soldiers in a fort had enough food for 30 days if 125 more soldiers joined them then for how many days will the food last​

Answers

Answer:

500+125=625625÷30=21 days

G
E
H
LF
Each isosceles triangle had the same vertex angle as triangle EJF. The sum of the
vertex angles equals 180°. (2 points, one for the correct equation, one for the correct
solution.)
Let x = the number of isosceles triangles.
Fill in the equation with your answer from Q12 and solve for x.
- x = 180

Answers

The value of x in the triangle will be 30°

How to calculate the value?

Let the base angles be x. The vertex angle will be:

= 2(x + x) = 4x

Since the sum of the angles in a triangle is 180°, therefore, 4x + x + x = 180°

6x = 180°

x = 180°/6

x = 30°

Therefore, the angles are 30°, 30°, and 120°. This makes up 180°.

Complete question:

In an isosceles triangle, the vertex angle is twice the sum of the base angles. Fund the angles of the triangle.

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Find the decay factor from the equation y = 453(0.87)^4

Answers

The decay factor of the equation given in the task content is; 0.87.

What is the decay factor from the equation?

According to the task content; the equation given is; y = 453(0.87)^4.

By comparison with exponential decay functions, it follows that the decay factor from the equation given is; 0.87 which insinuates that the factor of change after each decay is 0.87.

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what is the area of a polygone with vertices (-3,4) (2,4) (4,2) (2,-3) and (-3,-3)

Answers

By summing the areas of minor rectangles and triangles, the area of the irregular polygon whose vertices are (- 3, 4), (2, 4), (4, 2), (2, - 3) and (- 3, - 3) is equal to 42 square units.

How to determine the area of a irregular polygon

In this problem we have to determine the area of a irregular polygon, whose calculation is defined as a sum of the areas of triangles and rectangles. To determine the combination of squares and triangles, we need first to plot the vertices and construct the figure on a Cartesian plane.

The area of the irregular figure is:

A = (5) · (7) + 0.5 · 2² + 0.5 · (2) · (5)

A = 35 + 2 + 5

A = 42

By summing the areas of minor rectangles and triangles, the area of the irregular polygon whose vertices are (- 3, 4), (2, 4), (4, 2), (2, - 3) and (- 3, - 3) is equal to 42 square units.

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I need the answers can u help me please

Answers

Answer:

`1) 2.5cm, 2)1.25inches 3)2.25inches 4)1.25inches

Step-by-step explanation:

1) This is a centimeter rule, one small line represents 0.1cm and 1 long line represent 1cm, the line in between two long lines represent 0.5 cm

As you can see from A to B, is 2 cm + 0.5cm = 2.5cm.

2)This is found on the other side of rulers, inches.

1 small line represent 0.25 inches, line in between 2 long lines is 0.5 inches.

From S to T, is 1 inch + 0.25 inches = 1.25inches

3)Similar to Question 2.

Length of Pencil= 2 inches + 0.25 inches = 2.25 inches

4)This is a more detailed inch rule.

But length of heart shape = 1 inch + 0.25 inches = 1.25 inches

For the data in the table, tell whether y varies directly with x . If it does, write an equation for the direct variation.

x y
2 -6.6
3 -9.9
4 -13.2
5 -16.5

yes; y = x – 3.3

no

yes;

yes; y = –3.3x

Answers

Answer:

yes , y = - 3.3x

Step-by-step explanation:

if y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation , then

k = [tex]\frac{y}{x}[/tex]

checking k for each ordered pair in the table

[tex]\frac{-6.6}{2}[/tex] = - 3.3

[tex]\frac{-9.9}{3}[/tex] = - 3.3

[tex]\frac{-13.2}{4}[/tex] = - 3.3

[tex]\frac{-16.5}{5}[/tex] = - 3.3

thus k = - 3.3

so y varies directly with x and the equation of direct variation is

y = - 3.3x

I NEED HELP ASAP!!!!!!!!!!!!!!!!!!!! PLS COME QUICK! Question 4 (Essay Worth 10 points)
(01.07 MC)

The dimensions of a rectangular prism are shown below:

Length: 2 and 1 over 4 feet
Width: 1 foot
Height: 1 and 1 over 4 feet
The lengths of the sides of a small cube are 1 over 4 foot each.

Part A: How many small cubes can be packed in the rectangular prism? Show your work. (5 points)

Part B: Use the answer obtained in part A to find the volume of the rectangular prism in terms of the small cube and a unit cube. (5 points)

Answers

The number of cube that can be packed in the rectangular prism is 30 cubes

Volume of the rectangular prism in terms of small cube and unit cube = 30(1 / 8) ft³

How to find the volume of rectangular prism and cube?

volume of rectangular prism = lwh

where

l = lengthw = widthh = height

Therefore,

volume of rectangular prism = 3 / 2 × 1 × 5 / 2  = 15 / 4 ft³

volume of cube = 1 / 2 × 1 / 2 × 1 / 2  = 1 / 8 ft³

number of cube that can be packed in the rectangular prism = 15 / 4 × 8 =  30 cubes

Volume of the rectangular prism in terms of small cube and unit cube = 30(1 / 8) ft³

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Given: Triangle ADE~
Triangle CBF, ED bisects Angle ADC and F B bisects Angle ABC.
Prove: DF BE is a parallelogram.

Answers

Answer:

See proof below

Step-by-step explanation:

Given [tex]\triangle ADE \cong \triangle CBD[/tex]

Then, [tex]\angle AED \cong \angle CFB[/tex] because corresponding parts of congruent triangles are congruent.

Since [tex]\angle AED \text{ and } \angle DEB \text{ form a linear pair}[/tex], by the linear pair postulate, [tex]\angle AED \text{ and } \angle DEB \text{ are supplementary}[/tex].

Similarly, [tex]\angle CFB \text{ and } \angle BFD \text{ form a linear pair}[/tex], so by the linear pair postulate,  [tex]\angle CFB \text{ and } \angle BFD \text{ are supplementary}[/tex].

By the Congruent supplements theorem, since [tex]\angle AED \text{ and } \angle DEB \text{ are supplementary}[/tex], [tex]\angle CFB \text{ and } \angle BFD \text{ are supplementary}[/tex], and [tex]\angle AED \cong \angle CFB[/tex] , then [tex]\angle DEB \cong \angle BFD[/tex]. (note, this is one pair of opposite angles inside quadrilateral DFBE)

Recalling that [tex]\overline {ED} \text{ bisects } \angle ADC, \text{ and } \overline {FB} \text{ bisects } \angle ABC[/tex], then, [tex]\angle ADE \cong \angle CDE[/tex], and [tex]\angle CBF \cong \angle FBA[/tex] by definition of angle bisector.

Note that [tex]\angle ADE \cong \angle CBF[/tex] because corresponding parts of congruent triangles are congruent.

Also, note that [tex]\angle EDF \cong \angle EDC[/tex] and [tex]\angle FBA \cong \angle FBE[/tex] because B, E, A are colinear, and D, F, C are colinear.

So, by the transitive property of angle congruence, [tex]\angle EDF \cong \angle FBE[/tex]  (This is the other pair of opposite angles inside quadrilateral DFBE)


So, since both pairs of opposite angles are congruent, quadrilateral DFBE is a parallelogram, by a theorem about quadrilateral properties (your book may or may not have a name for it.  It may just have a number).

Other Questions
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